C语言学习知识上机练习进步题.doc

-!1. 输入一个不超过五位的正整数，输出其逆数。例如输入12345，输出应为54321。#include "stdio.h"main() long n; int ww,qw,bw,sw,gw; printf("Please input:n"); scanf("%ld",&n); while(n<=0|n>99999) printf("nThe number is too little or too large.Retry please!n"); scanf("%ld",&n); if(n>=10000&&n<=99999) ww=n/10000; qw=n/1000%10; bw=n/100%10; sw=n/10%10; gw=n%10; printf("The old number is:%ldn",n); printf("The new number is:%d%d%d%d%dn",gw,sw,bw,qw,ww); else if(n>=1000&&n<=9999) qw=n/1000; bw=n/100%10; sw=n/10%10; gw=n%10; printf("The old number is:%ldn",n); printf("The new number is:%d%d%d%dn",gw,sw,bw,qw); else if(n>=100&&n<=999) bw=n/100; sw=n/10%10; gw=n%10; printf("The old number is:%ldn",n); printf("The new number is:%d%d%dn",gw,sw,bw); else if(n>=10&&n<=99) sw=n/10; gw=n%10; printf("The old number is:%ldn",n); printf("The new number is:%d%dn",gw,sw); else printf("The old number equals the new number:%ld",n); 2. 计算1+2+3+n的值，n是从键盘输入的自然数。/* Note:Your choice is C IDE */#include "stdio.h"main() int n,i; long sum=0; printf("1+2+3+.+nn"); printf("Please input n:n"); scanf("%d",&n); for(i=1;i<=n;i+) sum+=i; printf("sum=%ld",sum); 3. 从终端（键盘）读入20个数据到数组中，统计其中正数的个数，并计算这些正数之和。、/* Note:Your choice is C IDE */#include "stdio.h"#define N 20main()int aN,i,sum=0,count=0;printf("Please input numbers :n");for(i=0;i<N;i+)scanf("%d",&ai);if(ai>0)sum+=ai; count+;printf("count=%d,sum=%d",count,sum);4. 从终端（键盘）将5个整数输入到数组a中，然后将a逆序复制到数组b中，并输出b中各元素的值。/* Note:Your choice is C IDE */#include "stdio.h"#define N 5main()int aN,bN,i;printf("Please input numbers:n");for(i=0;i<N;i+)scanf("%d",&ai);bN-i-1=ai;printf("nThe old numbers are:n");for(i=0;i<N;i+)printf("%-4d",ai);printf("nThe new numbers are:n");for(i=0;i<N;i+)printf("%-4d",bi); 5. 要将五张100元的大钞票，换成等值的50元，20元，10元，5元一张的小钞票，每种面值至少1张，编程输出所有可能的换法，程序应适当考虑减少重复次数。/* Note:Your choice is C IDE */#include "stdio.h"main()int i,j,k,n;for(i=1;i<=10;i+)for(j=1;j<=25;j+)for(k=1;k<=50;k+)for(n=1;n<=100;n+)if(i*50+j*20+k*10+n*5=500)printf("num50=%d,num20=%d,num10=%d,num5=%dn",i,j,k,n);6. 求n以内（不包括n）同时能被3和7整除的所有自然数之和的平方根s，n从键盘输入。例如若n为1000时，函数值应为：s=153.909064。/* Note:Your choice is C IDE */#include "stdio.h"#include "math.h"main()int n,s,i;float sum=0;printf("Please input n:n"); scanf("%d",&n); while(n<=0) printf("nError input.Retry please:n"); scanf("%d",&n); for(i=1;i<n;i+) if(i%3=0&&i%7=0) sum+=i;printf("The number is:%4.2f",sqrt(sum);7. 一辆卡车违反交通规则，撞人后逃跑。现场有三人目击事件，但都没有记住车号，只记下车号的一些特征。甲说：牌照的前两位数字是相同的；乙说：牌照的后两位数字是相同的，但与前两位不同；丙是数学家，他说：四位的车号刚好是一个整数的平方。请根据以上线索找出车号。/* Note:Your choice is C IDE */#include "stdio.h"#include "math.h"main() int i,qw,bw,sw,gw; for(i=1122;i<=9988;i+) if(sqrt(i)!=(int)sqrt(i) continue; qw=i/1000; bw=i/100%10; sw=i/10%10; gw=i%10; if(qw=bw&&sw=gw) printf("nThe number is:%dn",i); break; 8. 输入110之间的一个数字，输出它对应的英文单词。/* Note:Your choice is C IDE */#include "stdio.h"main()int n;printf("Please input n:n");scanf("%d",&n);while(n<1|n>10)printf("Error input!Retry please:n");scanf("%d",&n);switch(n)case 1:printf("One!");break;case 2:printf("Two!");break;case 3:printf("Three!");break;case 4:printf("Four!");break;case 5:printf("Five!");break;case 6:printf("Six!");break;case 7:printf("Seven!");break;case 8:printf("Eight!");break;case 9:printf("Nine!");break;case 10:printf("Ten!");break; 9. 个位数为6且能被3整除但不能被5整除的三位自然数共有多少个，分别是哪些？/* Note:Your choice is C IDE */#include "stdio.h"main() int i,count=0; for(i=106;i<596;i=i+10) if(i%3=0&&i%5!=0) printf("%-4d",i); count+; printf("count=%-4d",count);10. 用自然语言描述程序逻辑如下，试写程序。设置环境；定义变量i、j、s，以及用于放置结果的变量sum，并令sum初值为0；i=1；如果i100，则转，否则转；令s=0，求前i个自然数之和，并放于变量s之中；sum=sum+s；i增加1，转； 输出和sum，结束。/* Note:Your choice is C IDE */#include "stdio.h"main() int i,j; long s=0,sum=0; printf("1+1+2+1+2+3+1+2+3+4+.1+2+3+.+nn"); i=1; while(i<=3) s+=i; sum+=s; i+; printf("sum=%ld",sum);11. 用自然语言描述的程序逻辑为：设置环境；定义变量i、flag和password，并令flag=0，i=0；用户回答口令，将其赋于password变量；口令正确？如果是，则flag=1，转。否则转；回答三次口令了吗？如果没有，计数器加1后（i+），转，否则转； 根据flag之值输出相应信息。/* Note:Your choice is C IDE */#include "stdio.h"#include "string.h"#define N 6main() int i=0,flag=0; char passwordN; printf("The password is:123456n"); while(i<3) gets(password); if(strlen(password)!=6) printf("The string length is wrong!Retry please!n"); i+; continue; if(strcmp("123456",password)=0)flag=1;break;else printf("Wrong input!Retry please!n"); i+; if(flag=1) printf("Right password!n"); else printf("Wrong password!n");12. 用自然语言描述的程序逻辑如下：设置环境；定义变量digit、x、y分别表示原始数、原始数的个位数和逆数；输入原始正整数x；从x中分解出个位数字digit；合并个位digit至逆数y中；原始数x缩小10倍：x=x/10；如果x非零，则转； 输出逆数y，结束/* Note:Your choice is C IDE */#include "stdio.h"main()long digit,x,y;/*个位数、原始数、逆数*/printf("Please input the old number:n");scanf("%ld",&x);digit=x%10;y=digit;while(x!=0)x=x/10;digit=x%10;y=y*10+digit;printf("x=%ld,y=%ld",x,y/10); 13. 输入某三角形的三个边的长度，判断出这是个什么三角形（等腰、等边、任意，或不能构成）。/* Note:Your choice is C IDE */#include "stdio.h"main() float a,b,c,flag;/*flag=0不能，flag=1等边,flag=2等腰，flag=3任意*/ printf("Please input angles:n"); scanf("%f,%f,%f",&a,&b,&c); if(a+b<=c|a+c<=b|b+c<=a) flag=0; else if(a=b&&b=c) flag=1; else if(a=b|b=c|c=a) flag=2; else flag=3; if(flag=0) printf("nCan not!n"); if(flag=1) printf("nDeng Bian.n"); if(flag=2) printf("nDeng Yao.n"); if(flag=3) printf("nPu tong.n");14. 输入10个数，分别统计其中正数、负数、零的个数。#include "stdio.h"#define N 10main()int aN;int i,count1=0,count2=0,count3=0;/*count1记录正数个数，count2记录负数个数，count3记录0的个数*/printf("Please input numbers:n");for(i=0;i<N;i+) scanf("%d",&ai); if(ai>0) count1+; if(ai<0)count2+; if(ai=0)count3+; printf("count1=%-4d,count2=%-4d,count3=%-4d",count1,count2,count3);15. 先随机产生N个三位自然数输出，然后再输出其中同时是3、5、7倍数的数。（设N为100）/* Note:Your choice is C IDE */#include "stdio.h"#define N 100#include <time.h>#include <stdlib.h>main()int aN,i;printf("Please input numbers:n");randomize();for(i=0;i<N;i+) ai=random(900)+100; printf("%-4d",ai); printf("n-n"); printf("n3,5,7:n"); for(i=0;i<N;i+) if(ai%3=0&&ai%5=0&&ai%7=0) printf("%-4d",ai);16. 用for编程找出100200中的完全平方数。#include "stdio.h"#include "math.h"main() int i; for(i=100;i<=200;i+) if(sqrt(i)=i%100) printf("%-4d",i);17. 从终端输入三个正实数，判断这三个数能否构成直角三角形。#include "stdio.h"main() float a,b,c,flag;/*flag=0不能，flag=1能*/ printf("Please input angles:n"); scanf("%f,%f,%f",&a,&b,&c); while(a<=0|b<=0|c<=0) printf("Wrong input!Retry please:n"); scanf("%d,%d,%d",&a,&b,&c); if(a+b<=c|b+c<=a|a+c<=b) flag=0; else if(a*a=b*b+c*c|b*b=a*a+c*c|c*c=a*a+b*b) flag=1; else flag=0; if(flag=1) printf("nCan!"); else printf("nCan not!");18. 输入一行字符，统计其中有多少个字母（包括大写字母和小写字母）。/* Note:Your choice is C IDE */#include "stdio.h"#define N 10#include "stdlib.h"#include "ctype.h"#include "string.h"main() char cN; int i,count=0; gets(c); i=0; while(i!=strlen(c) if(isupper(ci)|islower(ci) count+; i+; printf("count=%-4d",count); getch();19. 输入一个字串，判断它是否是对称串。如”abcdcba”是对称串，”123456789”不是。/* Note:Your choice is C IDE */#include "stdio.h"#include "string.h"#include "ctype.h"#include "stdlib.h"#define N 10main()char aN,bN,i;printf("Please input the string:n");gets(a);if(strlen(a)>N)printf("Wrong input!Retry please!n");gets(a);strcpy(b,a);strrev(a);if(strcmp(a,b)=0)printf("nYes!n");else printf("nNo!n"); 20. 随机产生N个大写字母输出，然后统计其中共有多少个元音字符。（设N为200）/* Note:Your choice is C IDE */#include "stdio.h"#include <stdlib.h>#include <time.h>#define N 200main()int cN,i,count=0;randomize(); for(i=0;i<N;i+)ci=random(27)+65;printf(" %c",ci);if(ci=A|ci=E|ci=I|ci=O|ci=U)count+; printf("n-n"); printf("ncount=%-4d",count);找出三位自然数中的所有素数，要求判断x素数用自定义函数data(x)实现。#include "stdio.h"int data(int x);main()int i,flag=0;/*1是，0否*/ for(i=101;i<=999;i+) flag=data(i); if(flag=1) printf("%-4d",i); int data(int x)int i;for(i=2;i<x/2;i+)if(x%i=0)return 0;if(i=x/2)return 1;else return 0;21. 输出n行由“#”组成的矩形，每行“#”的个数为m个，其中n、m由终端（键盘）输入。要求输出m个“#”功能由函数satr(m)函数实现。#include "stdio.h"void satr(int m);main()int i,n,m;printf("Please input n&m:n");printf("n=");scanf("%d",&n);printf("m=");scanf("%d",&m); printf("n-n"); for(i=1;i<=n;i+) satr(m); printf("n"); void satr(int m)int i;for(i=1;i<=m;i+)printf("#");22. 若ax2+bx+c=0有实根，则求之。#include "stdio.h"#include "math.h"main() int a,b,c; float derta,x1,x2; printf("Please input a,b,c:n"); printf("a="); scanf("%d",&a);printf("b=");scanf("%d",&b);printf("c=");scanf("%d",&c);derta=b*b-4*a*c;if(derta<0)printf("NO!n");if(derta=0)printf("One!n");x1=-b/(2*a);x2=x1;printf("x=%-4.2f",x1);if(derta>0)printf("Two!n");x1=(-b+sqrt(derta)/(2*a);x2=(-b-sqrt(derta)/(2*a);printf("x1=%-4.2f,x2=%-4.2f",x1,x2);23. 从键盘输入两个字串，判断它们是否相同。#include "stdio.h"#include "string.h"#define N 20main()char c1N,c2N;printf("Please input two string below:n");gets(c1);gets(c2);printf("-n");printf("The answer is:");if(strcmp(c1,c2)=0)printf("Equal!n");else printf("Not equal!n"); 24. 从键盘输入两个字串，输出其中较短的那个字串，并输出它的长度。#define N 20#include "stdio.h"#include "string.h"main()char c1N,c2N;printf("Please input two string below:n");gets(c1);gets(c2);printf("-n");printf("The answer is:");if(strlen(c1)=strlen(c2)puts(c1);puts(c2);printf("The length is:%dn",strlen(c1);if(strlen(c1)<strlen(c2)puts(c1);printf("The length is:%dn",strlen(c1);if(strlen(c1)>strlen(c2)puts(c2);printf("The length is:%dn",strlen(c2);25. 从键盘输入长度不等的两个字串，将短串连接于长串之后输出。#include "stdio.h"#include "string.h"#define N 20main()char c1N,c2N;printf("Please input two string below:n");gets(c1);gets(c2);while(strlen(c1)=strlen(c2)printf("Wrong input!Retry please:n");gets(c1);gets(c2);printf("-n");printf("The answer is:");if(strlen(c1)<strlen(c2)puts(strcat(c2,c1);if(strlen(c1)>strlen(c2)puts(strcat(c1,c2);26. 从键盘输入长度不等的两个字串，将长串连接于短串之后输出#include "stdio.h"#include "string.h"#define N 20main()char c1N,c2N;printf("Please input two string below:n");gets(c1);gets(c2);while(strlen(c1)=strlen(c2)printf("Wrong input!Retry please:n");gets(c1);gets(c2);printf("-n");printf("The answer is:");if(strlen(c1)<strlen(c2)puts(strcat(c1,c2);if(strlen(c1)>strlen(c2)puts(strcat(c2,c1);27. 随机产生N个两位自然数，降序排列后输出。（设N为20）#include "stdio.h"#include "stdlib.h"#include "time.h"#define N 20main()int aN,i,j,temp;randomize();for(i=0;i<N;i+)ai=random(900)+100;for(i=0;i<N-1;i+)for(j=i+1;j<N;j+)if(aj>ai)temp=ai;ai=aj;aj=temp;for(i=0;i<N;i+)printf("%-4d",ai); 28. 从键盘输入两个字串，输出其中较长的那个字串，并输出它的长度。#define N 20#include "stdio.h"#include "string.h"main()char c1N,c2N;printf("Please input two string below:n");gets(c1);gets(c2);printf("-n");printf("The answer is:");if(strlen(c1)=strlen(c2)puts(c1);puts(c2);printf("The length is:%dn",strlen(c1);if(strlen(c2)<strlen(c1)puts(c1);printf("The length is:%dn",strlen(c1);if(strlen(c2)>strlen(c1)puts(c2);printf("The length is:%dn",strlen(c2);29. 从键盘输入10个战士的身高，输出平均身高，并找出哪些身高低于平均身高。#include "stdio.h"#define N 11main()float aN,sum=0;int i;printf("Please input heigths:n"); for(i=0;i<N-1;i+) scanf("%f",&ai); sum+=ai; aN-1=sum/(N-1); printf("The average is:%-6.2fn",aN-1); printf("-n"); printf("The answer are:n"); for(i=0;i<N-1;i+) if(ai<aN-1) printf("%-8.2f",ai);30. 从键盘输入10个战士的身高，输出平均身高，并找出哪些身高高于平均身高。#include "stdio.h"#define N 11main()float aN,sum=0;int i;printf("Please input heigths:n"); for(i=0;i<N-1;i+) scanf("%f",&ai); sum+=ai; aN-1=sum/(N-1); printf("The average is:%-6.2fn",aN-1); printf("-n"); printf("The answer are:n"); for(i=0;i<N-1;i+) if(ai>aN-1) printf("%-8.2f",ai);31. 从键盘输入10个战士的身高，输出最高、最低的身高#include "stdio.h"#define N 10main()float aN,min=99999,max=-99999;int i;printf("Please input heigths:n"); for(i=0;i<N;i+) scanf("%f",&ai); printf("-n"); for(i=0;i<N;i+) if(ai>max) max=ai; if(ai<min) min=ai; printf("max=%-6.2f,min=%-6.2f",max,min);。32. “百钱百鸡”问题。百钱买百鸡，鸡翁一值钱三，鸡母一值钱二，鸡雏三值钱一，问鸡翁、鸡母、鸡雏各几何？#include "stdio.h"main()int jw,jm,jc;/*公鸡最多100/3=33只，母鸡最多1