2022年lingo常用程序例子 .pdf

model: sets: id/1.30/:y1; team/1.10/boy,girl; sex/1.2/; pnum(id,sex):y2 num(id,team,sex):x,y; endsets min=556000+50*sum(num(i,j,k):x)+20*sum(ID(i):(y1(i)-sum(sex(j,k):y(i,j,k)*x(i,j,k); for(id(i):sum(sex(j,k):x(i,j,k)=1); for(team(j):sum(sex(j,k):x(i,j,k)=1); for(num(i,j):y=y2(i,j); sum(id(i):y(i,1)*x(i,1)=30; sum(id(i):y(i,2)*x(i,2)=40; sum(id(i):y(i,1)=30; sum(id(i):y(i,2)=40; for(num:bin(x); for(num:gin(y); for(id(i):sum(sex(j):y(i,j)=y1(i); data: y1=file(y1.txt); y2=file(y2.txt); enddata end model: sets: id/1.30/:y1; sex/1.2/; num(id,sex):x,y,y2; endsets min=100*sum(num:x*y)+50*sum(num:x)+20*sum(ID(i):(y1(i)-sum(sex(j):y(i,j)*x(i,j); for（id(i):sum(sex(j):x(i,j)=1 ）; for（id(i):sum(sex(j):y(i,j)=y2(i,j) ）; sum(id(i):y(i,1)*x(i,1)=30; sum(id(i):y(i,2)*x(i,2)=40; data: y1=file(y1.txt); 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 1 页，共 8 页 - - - - - - - - - y2=file(y2.txt); enddata end for i=1:200 if a(2,i)=0 b(1,i)=a(1,i); b(2,i)=a(1,i); elseif a(2,i)=1 b(1,i)=a(1,i); b(2,i)=0; elseif a(2,i)=2 b(1,i)=0; b(2,i)=a(1,i); end end for j=1:200 for i=1:2 c(i+2*(j-1)=b(i,j); end end 问题 3 model: sets: id/1.200/:y1; team/1.10/:boy,girl; sex/1.2/; pnum(id,sex):y2; num(id,team,sex):x,y; endsets min=556000+50*sum(num(i,j,k):x)+20*sum(ID(i):(y1(i)-sum(team(j):sum(sex(k):y(i,j,k)*x(i,j,k); for(team(j):sum(id(i):sum(sex(k):y(i,j,2)=girl(j);名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 2 页，共 8 页 - - - - - - - - - for(team(j):sum(id(i):sum(sex(k):y(i,j,1)*x(i,j,1)=boy(j); for(id(i):sum(team(j):sum(sex(k):y(i,j,k)*x(i,j,k)=1);for(team(j):sum(id(i):sum(sex(k):y(i,j,1)=boy(j); for(team(j):sum(id(i):sum(sex(k):y(i,j,2)*x(i,j,2)=girl(j);for(num:bin(x); for(num:gin(y); for(id(i):for(sex(k):sum(team(j):y(i,j,k)=y2(i,k); for(id(i):sum(team(j):sum(sex(k):y(i,j,k)=y1(i);data: boy=file(boy.txt); y1=file(y1.txt); girl=file(girl.txt); y2=file(y2.txt); enddata end 问题 2 新 1 model: sets: id/1.30/:y1; sex/1.2/; num(id,sex):x,y,y2; endsets min=7000+50*sum(num(i,j):x)+20*sum(ID(i):(y1(i)*sum(sex(j):x(i,j)-sum(sex(j):y(i,j)*x(i,j); for(id(i):sum(sex(j):x(i,j)=1); for(num(i,j):y(i,j)=y2(i,j); for(num(i,j):y(i,j)=y(i,j)*x(i,j); for(id(i):sum(sex(j):x(i,j)=if(sum(sex(j):y(i,j)#eq#0,0,sum(sex(j):x(i,j);sum(id(i):y(i,1)*x(i,1)=30; sum(id(i):y(i,2)*x(i,2)=40; sum(id(i):y(i,1)=30; sum(id(i):y(i,2)=40; for(num:bin(x); for(num:gin(y); for(id(i):sum(sex(j):y(i,j)=y1(i); 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 3 页，共 8 页 - - - - - - - - - data: y1=file(y1.txt); y2=file(y2.txt); enddata end 问题 3 新model: sets: id/1.200/:y1; team/1.10/boy,girl; sex/1.2/; pnum(id,sex):y2 num(id,team,sex):x,y; endsets min=556000+50*sum(num(i,j,k):x)+20*sum(ID(i):(y1(i)-sum(sex(j,k):y(i,j,k)*x(i,j,k); for(id(i):sum(sex(j,k):x(i,j,k)=1); for(team(j):sum(id(i):y(i,j,1)=boy(j); for(team(j):sum(id(i):y(i,j,2)=girl(j);for(team(j):sum(sex(j,k):x(i,j,k)=1); for(num(i,j):y=y2(i,j); sum(id(i):y(i,1)*x(i,1)=30; sum(id(i):y(i,2)*x(i,2)=40; sum(id(i):y(i,1)=30; sum(id(i):y(i,2)=40; for(num:bin(x); for(num:gin(y); for(id(i):sum(sex(j):y(i,j)=y1(i); data: y1=file(y1.txt); y2=file(y2.txt); enddata end 问题 2 成功 1：model: sets: 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 4 页，共 8 页 - - - - - - - - - id/1.30/:y1; sex/1.2/; !x(i,j)表示 id 为 i 的家庭性别为j 的是否寄宿 ; num(id,sex):x,y,y2; endsets min=7000+50*sum(num(i,j):x(i,j)+20*sum(id(i):y1(i)*sum(sex(j):x(i,j)-sum(sex(j):y(i,j); !定义 x 数组 0-1 变量 ; for(num:bin(x); !定义 y 数组为整型变量; for(num:gin(y); !实现男女不能混住的限定; for(id(i):sum(sex(j):x(i,j)=1); for(num(i,j):x(i,j)=if(y(i,j)#eq#0,0,1); for(num(i,j):y(i,j)=if(x(i,j)#eq#0,0,y(i,j); !对 id 为 i 的家庭寄宿人数的限定; for(num(i,j):y(i,j)=y2(i,j); sum(id(i):y(i,1)=30; sum(id(i):y(i,2)=40; sum(id(i):y(i,1)*x(i,1)=30; sum(id(i):y(i,2)*x(i,2)=40; data: y1=3,3,4,3,4,3,3,4,3,3,4,3,3,2,2,5,1,3,3,2,4,2,1,4,1,4,5,4,3,1; y2=3,3,3,3,0,4,3,0,4,0,3,0,0,3,4,0,3,3,3,3,4,4,3,3,0,3,0,2,2,2,0,5,0,1,3,3,3,3,2,2,0,4,2,2,1,1,4,4,1,1,4,0,5,0,0,4,3,3,1,1; enddata end 问题 3 新 2 model: sets: id/1.200/:y1; team/1.10/boy,girl; sex/1.2/; pnum(id,sex):y2 num(id,team,sex):x,y; endsets min=556000+50*sum(num(i,j,k):x)+20*sum(ID(i):(y1(i)*sum(team(j):sum(sex(k):x(i,j,k)-名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 5 页，共 8 页 - - - - - - - - - sum(team(j):sum(sex(k):y(i,j,k); !定义 x 数组 0-1 变量 ; for(num:bin(x); !定义 y 数组为整型变量; for(num:gin(y); !实现男女不能混住的限定; for(id(i):sum(sex(j,k):x(i,j,k)=1); for(num(i,j,k):x(i,j,k)=if(y(i,j,k)#eq#0,0,1); for(num(i,j):y(i,j,k)=if(x(i,j,k)#eq#0,0,y(i,j,k);!对 id 为 i 的家庭寄宿人数的限定; for(num(i,j,k):y(i,j,k)=y2(i,j,k); for(team(j):sum(id(i):y(i,j,1)=boy(j);for(team(j):sum(id(i):y(i,j,2)=girl(j);for(team(j):sum(id(i):y(i,j,1)*x(i,j,1)=boy(j); for(team(j):sum(id(i):y(i,j,2)*x(i,j,2)=girl(j);data: y1= y2= enddata end for(id(i):for(sex(k):sum(team(j):x(i,j,k)=if(sum(team(j):y(i,j,k)#eq#0,0,1); for(id(i):for(sex(k):sum(team(j):y(i,j,k)=if(sum(team(j):x(i,j,k)#eq#0,0,sum(team(j):y(i,j,k); 问题 3 成功 1：model: sets: id/1.200/:y1; team/1.10/:boy,girl; sex/1.2/; pnum(id,sex):y2; num(id,team,sex):x,y; endsets min=55600+50*sum(num(i,j,k):x)+20*sum(ID(i):(y1(i)*sum(team(j):sum(sex(k):x(i,j,k)-sum(team(j):sum(sex(k):y(i,j,k); !定义 x 数组 0-1 变量 ; for(num:bin(x); 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 6 页，共 8 页 - - - - - - - - - !定义 y 数组为整型变量; for(num:gin(y); !实现男女不能混住的限定; for(id(i):sum(team(j):sum(sex(k):x(i,j,k)=1); for(num(i,j,k):x(i,j,k)=if(y(i,j,k)#eq#0,0,1); for(num(i,j,k):y(i,j,k)=if(x(i,j,k)#eq#0,0,y(i,j,k);!对 id 为 i 的家庭寄宿人数的限定; for(num(i,j,k):y(i,j,k)=y2(i,k); for(team(j):sum(id(i):y(i,j,1)=boy(j); for(team(j):sum(id(i):y(i,j,2)=girl(j); for(team(j):sum(id(i):y(i,j,1)*x(i,j,1)=boy(j); for(team(j):sum(id(i):y(i,j,2)*x(i,j,2)=girl(j);data: y1=33 4 3 4 3 3 4 3 3 4 3 3 2 2 5 1 3 3 24 2 1 4 1 4 5 4 3 1 2 3 2 4 3 5 3 3 35 5 3 5 2 3 4 3 3 3 5 3 5 1 2 2 3 2 52 3 1 4 2 2 2 2 4 4 2 3 3 5 1 5 5 4 15 1 4 5 3 4 3 2 5 4 3 2 1 2 3 1 1 4 31 5 4 1 3 5 3 3 1 2 2 3 4 2 2 4 4 4 32 1 5 3 2 2 5 1 3 2 4 4 2 2 2 1 5 3 33 1 3 4 2 3 3 5 2 5 3 3 2 2 5 1 5 4 25 1 4 4 3 5 4 1 2 4 2 3 2 2 2 4 2 3 32 3 2 3 3 4 3 1 3 4 2 4 3 5 1 2 3 3 23 2 3 2 4 4 3 3 1; boy=12 30 23 35 5 35 58 9 0 45; girl=8 40 44 58 26 55 3 9 32 29; y2=33 3 3 0 4 3 0 4 0 3 0 0 3 4 0 3 3 3 34 4 3 3 0 3 0 2 2 2 0 5 0 1 3 3 3 3 22 0 4 2 2 1 1 4 4 1 1 4 0 5 0 0 4 3 31 1 2 0 0 3 2 2 0 4 0 3 5 5 3 0 3 3 30 5 0 5 5 0 3 5 5 2 0 3 3 0 4 3 0 0 30 3 5 0 0 3 0 5 1 0 2 0 0 2 0 3 2 0 05 0 2 3 0 1 0 4 0 0 2 0 2 2 2 2 2 4 04 4 2 2 3 0 3 0 5 5 0 1 5 5 0 5 4 0 11 0 5 0 1 0 4 5 0 3 3 4 4 3 0 2 2 5 04 4 3 3 0 2 0 1 2 0 3 3 1 1 1 0 4 4 03 1 1 0 5 0 4 1 0 3 3 0 5 3 0 3 0 0 10 2 2 0 3 3 0 4 0 2 2 0 4 0 4 4 4 4 03 2 2 1 1 5 5 3 0 2 2 0 2 5 5 0 1 3 02 0 4 4 0 4 0 2 2 0 2 0 0 1 5 5 3 3 33 3 0 1 0 3 3 4 4 2 0 3 3 0 3 0 5 0 20 5 0 3 0 3 0 2 0 2 5 5 0 1 5 0 4 0 2名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 7 页，共 8 页 - - - - - - - - - 0 5 5 1 1 0 4 4 0 0 3 0 5 4 4 1 0 2 00 4 2 2 3 0 2 0 2 0 2 2 0 4 2 0 0 3 03 0 2 0 3 2 2 0 3 3 0 4 0 3 3 1 1 0 30 4 0 2 4 0 0 3 5 5 1 0 2 2 3 0 0 3 02 3 3 2 0 0 3 0 2 4 0 4 4 0 3 3 0 0 1; enddata end 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 8 页，共 8 页 - - - - - - - - -