2022年2022年结构力学矩阵位移法上机实践报告 .pdf

结构力学矩阵位移法上机实践报告指导老师：班级：姓名：学号：名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 1 页，共 17 页 - - - - - - - - - 矩阵位移法上机实践报告一、实践目的学会使用矩阵位移法 , 掌握 PF程序的使用并用来计算给定的平面刚架、桁架和连续粱的内力。二、实践要求（1）用 PF程序计算给定的平面钢架、桁架和连续粱的内力；（2）绘制给出上述结构的内力图。三、实践步骤（1）编号：对杆件和结点编号，选定局部坐标系和整体坐标系。（2）建立输入文件：根据题目已给数据，建立格式为.txt的输入数据文件。（3）运行计算：运行程序，得到输出文件。（4）绘图：手绘内力图。四、实践收获（1） 对于各杆弹模不同的情况， 可以取统一的 E 值，将其截面积 A 和二次矩 I 均乘以（EEi/）输入。（2）在内力图的绘制的过程中，应注意弯矩受拉边及剪力、轴力图正负号的判定。（3）平面桁架各杆截面二次矩I 取很小的值，如实际值的10-3至 10-9倍。（4）遇到集中力偶作用时，集中力偶作用点也要单独为一个结点。名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 2 页，共 17 页 - - - - - - - - - 土木工程 2007 级结构力学矩阵位移法上机题解题报告一作图示刚架的NF、SF、M图，已知各杆截面均为矩形，柱截面宽 0.4m,高 0.5m, 梁截面宽 0.3m,高 0.5m，各杆 E=3.25 104 Mpa。1.1 对结点和单元进行编号，选定整体坐标系和局部坐标系，如下：名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 3 页，共 17 页 - - - - - - - - - 1.2 输入文件数据表弹性模量杆件数结点数已知位移数荷载情况数325e5 12 11 12 1 杆件始端结点号末端结点号截面面积面积矩1 2 3 4 5 6 7 8 9 10 11 12 1 2 0.2 41.67e-4 2 3 0.15 31.25e-4 3 4 0.15 31.25e-4 4 5 0.15 31.25e-4 3 6 0.2 41.67e-4 6 7 0.15 31.25e-4 4 7 0.2 41.67e-4 7 8 0.15 31.25e-4 5 8 0.2 41.67e-4 9 3 0.2 41.67e-4 10 4 0.2 41.67e-4 11 5 0.2 41.67e-4 结点号X 坐标Y 坐标1 2 3 4 5 6 7 8 9 10 11 0 0 0 8 10 8 20 8 30 8 10 16 20 16 30 16 10 0 20 0 30 0 已知位移标号位移名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 4 页，共 17 页 - - - - - - - - - 1 9 10 11 0 12 0 13 0 91 0 92 0 93 0 101 0 102 0 103 0 （承上）已知位移标号位移11 111 0 112 0 113 0 结点荷载2 LJ FX FY FM 2 100 0 0 3 0 0 -25 非结点荷载7 LM LT VF DST 1 3 20 8 2 2 -150 5 3 2 -150 5 4 4 -10 10 5 3 20 8 6 4 -10 10 8 2 -150 5 1.3、输出文件* * * * title jglx200701 * * * * The Input Data The General Information E NM NJ NS NLC 3.250E+07 12 11 12 1 The Information of Members member start end A I 1 1 2 2.000000E-01 4.167000E-03 2 2 3 1.500000E-01 3.125000E-03 3 3 4 1.500000E-01 3.125000E-03 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 5 页，共 17 页 - - - - - - - - - 4 4 5 1.500000E-01 3.125000E-03 5 3 6 2.000000E-01 4.167000E-03 6 6 7 1.500000E-01 3.125000E-03 7 4 7 2.000000E-01 4.167000E-03 8 7 8 1.500000E-01 3.125000E-03 9 5 8 2.000000E-01 4.167000E-03 10 9 3 2.000000E-01 4.167000E-03 11 10 4 2.000000E-01 4.167000E-03 12 11 5 2.000000E-01 4.167000E-03 The Joint Coordinates joint X Y 1 .000000 .000000 2 .000000 8.000000 3 10.000000 8.000000 4 20.000000 8.000000 5 30.000000 8.000000 6 10.000000 16.000000 7 20.000000 16.000000 8 30.000000 16.000000 9 10.000000 .000000 10 20.000000 .000000 11 30.000000 .000000 The Information of Supports IS VS 11 .000000 12 .000000 13 .000000 91 .000000 92 .000000 93 .000000 101 .000000 102 .000000 103 .000000 111 .000000 112 .000000 113 .000000 ( NA= 345 ) ( NW= 1063 ) Loading Case 1 The Loadings at Joints 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 6 页，共 17 页 - - - - - - - - - NLJ= 2 ILJ PX PY PM 2 100.0000 .0000 .00000 3 .0000 .0000 -25.00000 The Loadings at Members NLM= 7 ILM ITL PV DST 1 3 20.0000 8.000000 2 2 -150.0000 5.000000 3 2 -150.0000 5.000000 4 4 -10.0000 10.000000 5 3 20.0000 8.000000 6 4 -10.0000 10.000000 8 2 -150.0000 5.000000 The Results of Calculation The Joint Displacements joint u v phi 1 7.113882E-21 -2.165102E-21 -3.700088E-20 2 4.260413E-02 -2.664741E-05 -5.047929E-03 3 4.238082E-02 -2.388042E-04 -3.749206E-03 4 4.213046E-02 -3.155841E-04 -2.440829E-03 5 4.204038E-02 -2.189643E-04 -4.271584E-03 6 6.894263E-02 -2.736428E-04 -1.307312E-03 7 6.881978E-02 -4.814999E-04 -2.294239E-03 8 6.874738E-02 -3.259022E-04 3.746726E-04 9 8.691905E-21 -1.940284E-20 -4.111444E-20 10 1.027360E-20 -2.564121E-20 -4.522632E-20 11 7.920618E-21 -1.779085E-20 -3.891360E-20 The Terminal Forces member N(st) Q(st) M(st) N(en) Q(en) M(en) 1 21.651 151.139 476.675 -21.651 8.861 92.435 2 108.861 21.651 -92.435 -108.861 128.349 -441.055 3 122.052 37.373 -13.923 -122.052 112.627 -362.347 4 43.912 8.978 -103.181 -43.912 91.022 -307.035 5 28.306 100.110 145.770 -28.306 59.890 15.111 6 59.890 28.306 -15.111 -59.890 71.694 -201.825 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 7 页，共 17 页 - - - - - - - - - 7 134.807 24.596 95.903 -134.807 -24.596 100.866 8 35.294 63.113 100.959 -35.294 86.887 -219.829 9 86.887 35.294 62.521 -86.887 -35.294 219.829 10 194.028 86.919 411.144 -194.028 -86.919 284.208 11 256.412 102.736 452.263 -256.412 -102.736 369.624 12 177.909 79.206 389.136 -177.909 -79.206 244.513 ( NA= 345 ) ( NW= 1091 ) 1.4 刚架内力图绘制名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 8 页，共 17 页 - - - - - - - - - 二、计算图示桁架各杆的轴力。已知A=500mm2,E=2.1 105 MPa。2.1 对结点和单元进行编号，选定整体坐标系和局部坐标系，如下：名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 9 页，共 17 页 - - - - - - - - - 2.2 输入文件数据表弹性模量杆件数结点数已知位移数荷载情况数210e6 17 10 4 1 杆件始端结点号末端结点号截面面积面积矩1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 1 2 500e-6 2e-18 2 3 500e-6 2e-18 3 4 500e-6 2e-18 4 5 500e-6 2e-18 5 6 500e-6 2e-18 7 6 500e-6 2e-18 5 7 500e-6 2e-18 8 7 500e-6 2e-18 8 5 500e-6 2e-18 9 8 500e-6 2e-18 4 8 500e-6 2e-18 9 4 500e-6 2e-18 10 9 500e-6 2e-18 10 4 500e-6 2e-18 10 3 500e-6 2e-18 1 10 500e-6 2e-18 1 3 500e-6 2e-18 结点号X 坐标Y 坐标1 2 3 4 5 6 7 8 9 10 0 0 0 5 5 5 10 5 15 5 20 5 20 0 15 0 10 0 5 0 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 10 页，共 17 页 - - - - - - - - - 已知位移标号位移1 9 7 11 0 12 0 92 0 72 0 结点荷载5 LJ FX FY FM 2 50 -50 0 3 0 -50 0 4 0 -50 0 5 0 -50 0 6 0 -50 0 非结点荷载0 2.3、输出文件* * * * title jglx200702 * * * * The Input Data The General Information E NM NJ NS NLC 2.100E+08 17 10 4 1 The Information of Members member start end A I 1 1 2 5.000000E-04 2.000000E-18 2 2 3 5.000000E-04 2.000000E-18 3 3 4 5.000000E-04 2.000000E-18 4 4 5 5.000000E-04 2.000000E-18 5 5 6 5.000000E-04 2.000000E-18 6 7 6 5.000000E-04 2.000000E-18 7 5 7 5.000000E-04 2.000000E-18 8 8 7 5.000000E-04 2.000000E-18 9 8 5 5.000000E-04 2.000000E-18 10 9 8 5.000000E-04 2.000000E-18 11 4 8 5.000000E-04 2.000000E-18 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 11 页，共 17 页 - - - - - - - - - 12 9 4 5.000000E-04 2.000000E-18 13 10 9 5.000000E-04 2.000000E-18 14 10 4 5.000000E-04 2.000000E-18 15 10 3 5.000000E-04 2.000000E-18 16 1 10 5.000000E-04 2.000000E-18 17 1 3 5.000000E-04 2.000000E-18 The Joint Coordinates joint X Y 1 .000000 .000000 2 .000000 5.000000 3 5.000000 5.000000 4 10.000000 5.000000 5 15.000000 5.000000 6 20.000000 5.000000 7 20.000000 .000000 8 15.000000 .000000 9 10.000000 .000000 10 5.000000 .000000 The Information of Supports IS VS 11 .000000 12 .000000 92 .000000 72 .000000 ( NA= 294 ) ( NW= 1014 ) Loading Case 1 The Loadings at Joints NLJ= 5 ILJ PX PY PM 2 50.0000 -50.0000 .00000 3 .0000 -50.0000 .00000 4 .0000 -50.0000 .00000 5 .0000 -50.0000 .00000 6 .0000 -50.0000 .00000 The Loadings at Members NLM= 0 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 12 页，共 17 页 - - - - - - - - - The Results of Calculation The Joint Displacements joint u v phi 1 5.000000E-21 -6.079431E-21 -2.287952E-03 2 1.058488E-02 -2.380952E-03 -1.940167E-03 3 8.203932E-03 -9.657786E-03 -6.684104E-04 4 5.308965E-03 -4.924351E-03 2.748874E-05 5 3.604474E-03 -7.872072E-03 4.062047E-04 6 3.604474E-03 -2.380952E-03 8.310469E-04 7 6.655518E-03 -8.579431E-21 1.394905E-03 8 4.951027E-03 -7.195611E-03 -2.054584E-04 9 3.922997E-03 -1.034114E-20 -4.704160E-05 10 2.894967E-03 -7.790849E-03 -1.421908E-05 The Terminal Forces member N(st) Q(st) M(st) N(en) Q(en) M(en) 1 50.000 .000 .000 -50.000 .000 .000 2 50.000 .000 .000 -50.000 .000 .000 3 60.794 .000 .000 -60.794 .000 .000 4 35.794 .000 .000 -35.794 .000 .000 5 .000 .000 .000 .000 .000 .000 6 50.000 .000 .000 -50.000 .000 .000 7 50.621 .000 .000 -50.621 .000 .000 8 -35.794 .000 .000 35.794 .000 .000 9 14.206 .000 .000 -14.206 .000 .000 10 -21.589 .000 .000 21.589 .000 .000 11 -20.090 .000 .000 20.090 .000 .000 12 103.411 .000 .000 -103.411 .000 .000 13 -21.589 .000 .000 21.589 .000 .000 14 -55.445 .000 .000 55.445 .000 .000 15 39.206 .000 .000 -39.206 .000 .000 16 -60.794 .000 .000 60.794 .000 .000 17 15.265 .000 .000 -15.265 .000 .000 ( NA= 294 ) ( NW= 1014 ) 2.4桁架轴力图绘制名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 13 页，共 17 页 - - - - - - - - - 三作图示连续梁的SF、M图，已知各杆截面均为矩形， 截面宽 0.3m,高 0.5m，各杆 E=3.25 104MPa。3.1 对结点和单元进行编号，选定整体坐标系和局部坐标系，如下：3.2 输入文件数据表弹性模量杆件数结点数已知位移数荷载情况数325 e5 4 5 5 1 杆件始端结点号末端结点号截面面积面积矩名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 14 页，共 17 页 - - - - - - - - - 1 2 3 4 1 2 0.15 3.125e-3 2 3 0.15 3.125e-3 3 4 0.15 3.125e-3 4 5 0.15 3.125e-3结点号X 坐标Y 坐标1 2 3 4 5 0 0 3 0 7 0 8.5 0 10 0 已知位移标号位移1 2 3 5 11 0 12 0 22 0 32 0 52 0 结点荷载2 LJ FX FY FM 3 0 0 -50 4 0 -100 50 非结点荷载2 LM LT VF DST 1 4 -50 3 2 4 -30 2 3.3、输出文件* * * * title jglx200703 * * * * The Input Data 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 15 页，共 17 页 - - - - - - - - - The General Information E NM NJ NS NLC 3.250E+07 4 5 5 1 The Information of Members member start end A I 1 1 2 1.500000E-01 3.125000E-03 2 2 3 1.500000E-01 3.125000E-03 3 3 4 1.500000E-01 3.125000E-03 4 4 5 1.500000E-01 3.125000E-03 The Joint Coordinates joint X Y 1 .000000 .000000 2 3.000000 .000000 3 7.000000 .000000 4 8.500000 .000000 5 10.000000 .000000 The Information of Supports IS VS 11 .000000 12 .000000 22 .000000 32 .000000 52 .000000 ( NA= 66 ) ( NW= 297 ) Loading Case 1 The Loadings at Joints NLJ= 2 ILJ PX PY PM 3 .0000 .0000 -50.00000 4 .0000 -100.0000 50.00000 The Loadings at Members NLM= 2 ILM ITL PV DST 1 4 -50.0000 3.000000 2 4 -30.0000 2.000000 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 16 页，共 17 页 - - - - - - - - - The Results of Calculation The Joint Displacements joint u v phi 1 0.000000E+00 9.194445E-22 -4.180513E-04 2 0.000000E+00 1.493055E-22 2.822564E-04 3 0.000000E+00 -7.913194E-21 -5.628718E-04 4 0.000000E+00 -5.243077E-04 1.165128E-04 5 0.000000E+00 -3.155556E-21 4.660513E-04 The Terminal Forces member N(st) Q(st) M(st) N(en) Q(en) M(en) 1 .000 65.806 .000 .000 84.194 -27.583 2 .000 38.063 27.583 .000 21.938 -55.333 3 .000 68.444 5.333 .000 -68.444 97.333 4 .000 -31.556 -47.333 .000 31.556 .000 ( NA= 66 ) ( NW= 305 ) 3.4 连续梁内力图绘制名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 17 页，共 17 页 - - - - - - - - -