(完整word版)2014年高考数学(文)试题分类汇编：专题3三角函数,推荐文档.pdf

2014 年高考数学（文）试题分类汇编三角函数C1 角的概念及任意角的三角函数22014 全国卷 已知角 的终边经过点(4，3)，则 cos()A.45B.35C35D452DC2 同角三角函数的基本关系式与诱导公式182014 福建卷 已知函数f(x)2cos x(sin x cos x)(1)求 f54的值；(2)求函数 f(x)的最小正周期及单调递增区间18解：方法一：(1)f542cos54sin54cos54 2cos4sin4cos42.(2)因为 f(x)2sin xcos x2cos2xsin 2xcos 2x1 2sin2x41，所以 T22，故函数f(x)的最小正周期为.由 2k22x42k2，kZ，得 k38xk8，kZ.所以 f(x)的单调递增区间为k38，k8，kZ.方法二：f(x)2sin xcos x2cos2xsin 2x cos 2x1 2sin2x41.(1)f542sin1141 2sin41 2.精品资料-欢迎下载-欢迎下载 名师归纳-第 1 页，共 31 页 -(2)因为 T22，所以函数f(x)的最小正周期为.由 2k22x42k2，kZ，得 k38xk8，kZ.所以 f(x)的单调递增区间为k38，k8，kZ.22014 全国新课标卷 若 tan 0，则()Asin 0 Bcos 0 Csin 20 Dcos 20 2C172014 山东卷 ABC 中，角 A，B，C 所对的边分别为a，b，c.已知 a3，cos A63，BA2.(1)求 b 的值；(2)求 ABC 的面积17解：(1)在ABC 中，由题意知，sin A1cos2A33.又因为 BA2，所以 sin BsinA2cos A63.由正弦定理可得，basin Bsin A363333 2.(2)由 BA2得 cos BcosA2sin A33.由 ABC，得 C(AB)，所以 sin Csin(AB)sin(AB)sin Acos Bcos Asin B3333636313.因此 ABC 的面积 S12absin C1233213322.C3 三角函数的图象与性质162014 安徽卷 设 ABC 的内角 A，B，C 所对边的长分别是a，b，c，且 b3，c1，ABC 的面积为2.求 cos A 与 a 的值精品资料-欢迎下载-欢迎下载 名师归纳-第 2 页，共 31 页 -文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 ZE3K4V5S4C6文档编码:CF9Q2C5R5Z6 HH9P10D2Y4M3 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ZE3K4V5S4C616解：由三角形面积公式，得1231sin A2，故 sin A2 23.因为 sin2Acos2A1，所以 cos A 1sin2A18913.当 cos A13时，由余弦定理得a2b2c22bccos A32 1221313 8，所以 a2 2.当 cos A13时，由余弦定理得a2b2c22bccos A32 12 213 1312，所以 a2 3.72014 福建卷 将函数 ysin x 的图像向左平移2个单位，得到函数yf(x)的图像，则下列说法正确的是()Ayf(x)是奇函数Byf(x)的周期为Cyf(x)的图像关于直线x2对称Dyf(x)的图像关于点2，0 对称7D图 1-2 52014 江苏卷 已知函数ycos x 与 ysin(2x)(0)，它们的图像有一个横坐标为3的交点，则的值是 _5.672014 全国新课标卷 在函数 y精品资料-欢迎下载-欢迎下载 名师归纳-第 3 页，共 31 页 -文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7cos|2x|，y|cos x|，ycos 2x6，ytan2x4中，最小正周期为的所有函数为()ABCD7AC4 函数sin()yAx的图象与性质82014 天津卷 已知函数f(x)3sin xcos x(0)，xR.在曲线 yf(x)与直线 y1 的交点中，若相邻交点距离的最小值为3，则 f(x)的最小正周期为()A.2B.23CD28C72014 安徽卷 若将函数 f(x)sin 2xcos 2x 的图像向右平移个单位，所得图像关于 y 轴对称，则的最小正值是()A.8B.4C.38D.347C132014 重庆卷 将函数 f(x)sin(x )0，22图像上每一点的横坐标缩短为原来的一半，纵坐标不变，再向右平移6个单位长度得到ysin x的图像，则 f6_13.22162014 北京卷 函数 f(x)3sin 2x6的部分图像如图1-4 所示精品资料-欢迎下载-欢迎下载 名师归纳-第 4 页，共 31 页 -文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7图 1-4(1)写出 f(x)的最小正周期及图中x0，y0的值；(2)求 f(x)在区间2，12上的最大值和最小值16解：(1)f(x)的最小正周期为.x076，y03.(2)因为 x2，12，所以 2x6 56，0.于是，当 2x60，即 x12时，f(x)取得最大值0；当 2x62，即 x3时，f(x)取得最小值 3.18，2014 福建卷 已知函数 f(x)2cos x(sin xcos x)(1)求 f54的值；(2)求函数 f(x)的最小正周期及单调递增区间18解：方法一：(1)f542cos54sin54cos54 2cos4sin4cos42.(2)因为 f(x)2sin xcos x2cos2xsin 2xcos 2x1 精品资料-欢迎下载-欢迎下载 名师归纳-第 5 页，共 31 页 -文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S72sin2x41，所以 T22，故函数f(x)的最小正周期为.由 2k22x42k2，kZ，得 k38xk8，kZ.所以 f(x)的单调递增区间为k38，k8，kZ.方法二：f(x)2sin xcos x2cos2xsin 2x cos 2x1 2sin2x41.(1)f542sin1141 2sin41 2.(2)因为 T22，所以函数f(x)的最小正周期为.由 2k22x42k2，kZ，得 k38xk8，kZ.所以 f(x)的单调递增区间为k38，k8，kZ.92014 广东卷 若空间中四条两两不同的直线l1，l2，l3，l4满足 l1l2，l2l3，l3l4，则下列结论一定正确的是()Al1l4Bl1l4Cl1与 l4既不垂直也不平行Dl1与 l4的位置关系不确定9D解析 本题考查空间中直线的位置关系，构造正方体进行判断即可如图所示，在正方体ABCD-A1B1C1D1中，设 BB1是直线 l1，BC 是直线 l2，AD 是直线l3，则 DD1是直线 l4，此时 l1l4；设 BB1是直线 l1，BC 是直线 l2，A1D1是直线 l3，则 C1D1是直线 l4，此时 l1l4.故 l1与 l4的位置关系不确定精品资料-欢迎下载-欢迎下载 名师归纳-第 6 页，共 31 页 -文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7182014 湖北卷 某实验室一天的温度(单位：)随时间 t(单位：h)的变化近似满足函数关系：f(t)103cos12tsin12t，t0，24)(1)求实验室这一天上午8 时的温度；(2)求实验室这一天的最大温差18解：(1)f(8)103cos128 sin128 103cos23 sin23103123210.故实验室上午8 时的温度为10.(2)因为 f(t)10232cos12t12sin12t 102sin12t3，又 0t24，所以312t373，所以 1sin12t31.当 t2 时，sin12t31；当 t14 时，sin12t3 1.于是 f(t)在0，24)上取得最大值12，最小值 8.故实验室这一天最高温度为12，最低温度为8，最大温差为4.112014 辽宁卷 将函数 y 3sin 2x3的图像向右平移2个单位长度，所得图像对应的函数()A在区间12，712上单调递减B在区间12，712上单调递增C在区间6，3上单调递减D在区间6，3上单调递增11B142014 新课标全国卷 函数 f(x)sin(x )2sin cos x 的最大值为 _精品资料-欢迎下载-欢迎下载 名师归纳-第 7 页，共 31 页 -文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T10I1U7D1 ZU5M8R2S1S7文档编码:CS9V6U10L7C8 HT2T1