(完整word版)完全平方公式专项练习题.pdf

资源ID：55056693 资源大小：64.60KB 全文页数：6页
资源格式： PDF 下载积分：4.3金币

快捷下载

会员登录下载

微信登录下载

三方登录下载：

微信扫一扫登录

下载资源需要4.3金币

邮箱/手机：
温馨提示：	快捷下载时，用户名和密码都是您填写的邮箱或者手机号，方便查询和重复下载（系统自动生成）。如填写123，账号就是123，密码也是123。
支付方式：
验证码：	换一换

账号：
密码：
验证码：	换一换
当日自动登录忘记密码？

友情提示

1、下载资料失败解决办法

2、PDF文件下载后，可能会被浏览器默认打开，此种情况可以点击浏览器菜单，保存网页到桌面，就可以正常下载了。

3、本站不支持迅雷下载，请使用电脑自带的IE浏览器，或者360浏览器、谷歌浏览器下载即可。

4、本站资源下载后的文档和图纸-无水印,预览文档经过压缩，下载后原文更清晰。

5、试题试卷类文档，如果标题没有明确说明有答案则都视为没有答案，请知晓。

网站客服

侵权投诉

(完整word版)完全平方公式专项练习题.pdf

-1-平方差公式专项练习题一、基础题1平方差公式（a+b）（ab）=a2b2中字母 a，b 表示（）A只能是数B只能是单项式C只能是多项式D以上都可以2下列多项式的乘法中，可以用平方差公式计算的是（）A（a+b）（b+a）B（a+b）（ab）C（13a+b）（b13a）D（a2b）（b2+a）3下列计算中，错误的有（）（3a+4）（3a 4）=9a2 4；（2a2b）（2a2+b）=4a2 b2；（3x）（x+3）=x29；（x+y）（x+y）=（xy）（x+y）=x2y2A1 个B2 个C 3 个D4 个4若 x2y2=30，且 xy=5，则 x+y 的值是（）A5 B6 C 6 D 5 二、填空题5（2x+y）（2x y）=_4x2-y2_6（3x2+2y2）（_3x2-2y2_）=9x44y47（a+b1）（ab+1）=（_a_）2（_b-1_）28两个正方形的边长之和为5，边长之差为2，那么用较大的正方形的面积减去较小的正方形的面积，差是_10_三、计算题9利用平方差公式计算：2023 2113已解决10计算：（a+2）（a2+4）（a4+16）（a2）二、提高题1计算：（1）（2+1）（22+1）（24+1）（22n+1）+1（n 是正整数）；已解决（2）（3+1）（32+1）（34+1）（32008+1）401632已解决2利用平方差公式计算：2009 200720082已解决（1）利用平方差公式计算：22007200720082006已解决（2）利用平方差公式计算：22007200820061已解决-2-3解方程：x（x+2）+（2x+1）（2x1）=5（x2+3）此题较简单，略三、实际应用题4广场内有一块边长为2a米的正方形草坪，经统一规划后，南北方向要缩短3 米，东西方向要加长3 米，则改造后的长方形草坪的面积是多少？4a2-9 四、经典中考题5下列运算正确的是（）Aa3+a3=3a6B（a）3（a）5=a8C（2a2b）4a=24a6b3D（13a4b）（13a 4b）=16b219a26计算：（a+1）（a 1）=_a2-1_拓展题型1（规律探究题）已知x1，计算（1+x）（1x）=1x2，（1 x）（1+x+x2）=1x3，（1x）（?1+x+x2+x3）=1 x4（1）观察以上各式并猜想：（1x）（1+x+x2+xn）=_1-xn+1_（n 为正整数）（2）根据你的猜想计算：（12）（1+2+22+23+24+25）=_1-26_2+22+23+2n=_2（2n-1）_（n 为正整数）（x1）（x99+x98+x97+x2+x+1）=_x100-1_（3）通过以上规律请你进行下面的探索：（ab）（a+b）=_a2-b2_（ab）（a2+ab+b2）=_a3-b3_（ab）（a3+a2b+ab2+b3）=_a4-b4_2（结论开放题）请写出一个平方差公式，使其中含有字母m，n 和数字 4自己发挥3.从边长为a 的大正方形纸板中挖去一个边长为b 的小正方形纸板后，?将剩下的纸板沿虚线裁成四个相同的等腰梯形，如图 1 71 所示，然后拼成一个平行四边形，如图172 所示，分别计算这两个图形阴影部分的面积，结果验证了什么公式？请将结果与同伴交流一下没见到图完全平方公式变形的应用完全平方式常见的变形有:abbaba2)(222abbaba2)(222文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7-3-abbaba4)(22）（bcacabcbacba222)(22221、已知 m2+n2-6m+10n+34=0，求 m+n的值（m-3）2+（n+5）2=0 得出 m=3，n=-5 2、已知0136422yxyx，yx、都是有理数，求yx的值。（X+2）2+（y-3）2=0 得出 x=-2，y=3 xy=-8 3已知2()16,4,abab求223ab与2()ab的值。此题太简单，自己解决练一练 1 已知()5,3abab求2()ab与223()ab的值。2 已知6,4abab求 ab与22ab的值。3、已知224,4abab求22a b与2()ab的值。4、已知(a+b)2=60，(a-b)2=80，求 a2+b2及 ab 的值5已知6,4abab，求22223a ba bab的值。（a+b）*（ab）=a2b+ab2=24 所求=24+3*42=72 6已知222450 xyxy，求21(1)2xxy的值。和前面 1、2 一个类型，自己解决7已知16xx，求221xx的值。太简单，自己解决8、0132xx，求（1）221xx（2）441xx9、试说明不论x,y 取何值，代数式226415xyxy的值总是正数。（学习我步骤的书写格式）解：原式=（x+3）2+（y-2）2+1 无论 x,y 取何值，（x+3）2=0，（y-2）2=0 故（x+3）2+（y-2）2+10,即原式总为正数10、已知三角形ABC的三边长分别为a,b,c且 a,b,c满足等式22223()()abcabc，请说明该三角形是什么三角形？原式化简为 2a2+2b2+2c2-2ab-2bc-2ac=0 a2-2ab+b2+a2-2ac+c2+b2-2bc+c2=0（a-b）2+（b-c）2+（a-c）2=0 a=b=c，因此为等边三角形整式的乘法、平方差公式、完全平方公式、整式的除法文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7-4-一、请准确填空1、若 a2+b22a+2b+2=0,则 a2004+b2005=_和上一页的 1、2、6 都是一个类型，自己要学会归纳同类型题目_.2、一个长方形的长为(2a+3b),宽为(2 a3b),则长方形的面积为_略_.3、5(ab)2的最大值是 _5_，当 5(ab)2取最大值时，a与 b 的关系是 _a=b_.4.要使式子 0.36x2+41y2成为一个完全平方式，则应加上_3/5*xy_.5.(4 am+16am)2am 1=_.6.2931(302+1)=_略_.7.已知 x25x+1=0,则 x2+21x=_和上页第 8 题一个类型，题目考点还是比较好的，建议归纳总结在重点题本_.8.已知(2005a)(2003 a)=1000,请你猜想(2005a)2+(2003a)2=_2004_.二、相信你的选择9.若 x2xm=(xm)(x+1)且 x0,则 m等于A.1 B.0 C.1 D.210.(x+q)与(x+51)的积不含 x 的一次项，猜测 q 应是A.5 B.51C.51D.5 11.下列四个算式:4x2y441xy=xy3;16a6b4c8a3b2=2a2b2c;9x8y23x3y=3x5y;(12m3+8m24m)(2m)=6m2+4m+2，其中正确的有（我眼睛不行了，看不到上标）A.0 个B.1 个C.2 个D.3 个12.设(xm1yn+2)(x5my2)=x5y3,则 mn的值为A.1 B.1 C.3 D.3 13.计算(a2b2)(a2+b2)2等于A.a42a2b2+b4 B.a6+2a4b4+b6 C.a62a4b4+b6 D.a82a4b4+b814.已知(a+b)2=11,ab=2,则(ab)2的值是A.11 B.3 C.5 D.19 15.若 x27xy+M是一个完全平方式，那么M是A.27y2 B.249y2 C.449y2 D.49y216.若 x,y 互为不等于 0 的相反数，n 为正整数,你认为正确的是A.xn、yn一定是互为相反数 B.(x1)n、(y1)n一定是互为相反数C.x2n、y2n一定是互为相反数 D.x2n1、y2n1一定相等三、考查你的基本功17.计算(1)(a2b+3c)2(a+2b3c)2;(2)ab(3b)2a(b21b2)(3a2b3);(3)21000.5100(1)2005(1)5;(4)(x+2y)(x2y)+4(xy)26x6x.文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7-5-18.(6 分)解方程x(9x5)(3x1)(3 x+1)=5.四、生活中的数学19.(6 分)如果运载人造星球的火箭的速度超过11.2 km/s(俗称第二宇宙速度)，则人造星球将会挣脱地球的束缚，成为绕太阳运行的恒星.一架喷气式飞机的速度为1.8 106 m/h,请你推算一下第二宇宙速度是飞机速度的多少倍？略五、探究拓展与应用 20.计算.(2+1)(22+1)(24+1)=(21)(2+1)(22+1)(24+1)=(221)(22+1)(24+1)=(241)(24+1)=(281).根据上式的计算方法，请计算(3+1)(32+1)(34+1)(332+1)2364的值.“整体思想”在整式运算中的运用1、当代数式532xx的值为 7 时,求代数式2932xx的值.提示：无需解的x，整体替换即可2、已知2083xa，1883xb，1683xc，求：代数式bcacabcba222的值。3、已知4yx，1xy，求代数式)1)(1(22yx的值自己算4、已知2x时，代数式10835cxbxax，求当2x时，代数式835cxbxax的值整体替换5、若123456786123456789M，123456787123456788N试比较 M 与 N 的大小略5、已知012aa，求2007223aa的值.已知条件知：a2+a=1 a3+2a2+2007=a（a2+2a）+2007=a（a2+a+a）+2007=a（1+a）+2007=a2+a+2007+1+2007=2008 文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7-6-用适当的方法计算（1）20022003200220022略（2）2222221247484950解法见右侧（3）2222200411411311211提示：和第二题思路一样，展开消项（4）1212121264842提示：此类型多次出现，建议统一归纳整合与拓展一变号后运用：2525555522bbbbbb二交换位置后运用：2255555bbbbb三连续运用：4222111111xxxxxx四整体运用：1111222babababa五逆向应用：2222221247484950 =12124748474849504950 =127525050112484950六先拆项再运用：99964100002100210021009810222七先添因式再运用：1212121264842 =1212121212264422=31231212312121212864646444文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7文档编码:CH2P1S2O4R9 HA3E8T1Z8S8 ZV10V9R5J1T7

注意事项

本文（(完整word版)完全平方公式专项练习题.pdf）为本站会员（H****o）主动上传，淘文阁 - 分享文档赚钱的网站仅提供信息存储空间，仅对用户上传内容的表现方式做保护处理，对上载内容本身不做任何修改或编辑。若此文所含内容侵犯了您的版权或隐私，请立即通知淘文阁 - 分享文档赚钱的网站（点击联系客服），我们立即给予删除！

温馨提示：如果因为网速或其他原因下载失败请重新下载，重复下载不扣分。