122全等三角形的判定ASA和AAS教案.pdf
精品教学教案课 时 教 案课型新授课日期2013 年 9 月日课题12.2 全等三角形的判定(3)ASA和 AAS 教材分析1本节的主要内容是探索三角形全等的条件,及利用全等三角形进行证明2为了让学生经历一个完整地探索三角形全等的过程,教科书给了两个探究。探究一让学生从满足六个条件中的一个或两个入手,探究在这样的情形下能否保证两个三角形全等.从探究二开始让学生探究满足六个条件中的三个能否保证两个三角形全等,本次课主要探究ASA的情形.学情分析学生刚刚认识了全等三角形以及全等三角形的性质,对判定两个三角形全等暂时还不太熟悉,所以让孩子们通过自己的探究来得出两个角和一条边对应相等,两三角形全等的结论还是非常有必要的.教学目标目标达成度:二()班:当堂检测达标率80%二()班:当堂检测达标率90%知识技能1.让学生掌握已知三角形两个内角和一条边的长度怎么画三角形;2.掌握三角形全等的证明方法:ASA和 AAS;3.熟练掌握证明的标准步骤;4.体会分类讨论的数学思想.过程方法探究式教学,让学生通过探究,体会分类讨论的思想.情感态度通过探究全等三角形的证明方法,体会分类讨论的思想,有助于学生形成严谨的学习习惯以及形成较强的逻辑推理能力.重点难点分析:解决:中考样题教学手段投影仪、三角板、多媒体辅助教学教学方法1教师教法:启发式引导发现法2学生学法:独立思考,主动发现教学内容及过程教学环节教学内容学习内容设计意图复习回顾1.什么是全等三角形?精品教学教案2.判定两个三角形全等要具备什么条件?边边边(SSS)边角边(SAS)思考:如果两个三角形中只有一组对应边相等,那么还需要什么条件能够判断两个三角形全等呢?问题 1:如果已知一个三角形的两角及一边,那么有几种可能的情况呢?角边角(ASA)角角边(AAS)设置情境引入课题探究 1:一张教学用的三角形硬纸板不小心被撕坏了(如下图),你能制作一张与原来同样大小的新教具吗?能恢复原来三角形的原貌吗?分析问题探究新知文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 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HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8文档编码:CM10N1Y6Z9Z6 HQ10V3T2Q3K6 ZA7T9H7T1E8精品教学教案分析问题探究新知探究 1 反映的规律是:两角和它们的夹边对应相等的两个三角形全等.(可以简写成“角边角”或“ASA”)用数学符号表示:举一反三巩固新知例 1.已知:点 D 在 AB上,点 E在 AC上,BE和 CD相交于点O,AB=AC,B=C.求证:(1)AD=AE;(2)BD=CE 练习 1:已知:如图,1=2,3=4 求证:AC=AD 文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 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ZL3D8Z1U1E2精品教学教案探究 2:如下图,在 ABC和DEF中,A D,BE,BC EF,ABC与DEF全等吗?能利用角边角条件证明你的结论吗?证明:在 ABC和DEF中,A+B+C1800,D+E+F=1800,A D,BE,CF,BE,BC EF,CF,ABC DEF(ASA)探究 2 反映的规律是:两个角和其中一个角的对边对应相等的两个三角形全等(可以简写成“角角边”或“AAS”)用数学符号表示:例 2:如图,O是 AB的中点,A=B,AOC与BOD全等吗?为什么?文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2精品教学教案变式:如图,O是 AB的中点,C=D,AOC与BOD全等吗?为什么?练习 2:已知如图,1=2,C=D,求证:AC=AD 1、如图,BE=CD,1=2,则 AB=AC吗?为什么?2.已知:如图 B=DEF,BC=EF,求证:ABC DEF(1)若要以“SAS”为依据,还缺条件;(2)若要以“ASA”为依据,还缺条件;(3)若要以“SSS”为依据,还缺条件;(4)若要以“AAS”为依据,还缺条件文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 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HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2精品教学教案3.图中的两个三角形全等吗?请说明理由.课堂小结本节课你的收获是什么?文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 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HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2精品教学教案检测题1.已知:如图,在ABC中,D、E、F分别是 AB、AC、BC上的点,连接DE、EF,AB EF,DE BC,DE=FC.求证:ADEEFC2、已知:如图,1=2,3=4.求证:ABCABD板书设计背投作 业数学新目标检测:P25 抽 测数学新目标检测:P25 T5 教学反思文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 ZL3D8Z1U1E2文档编码:CT5X6S7E9X6 HY6E3R5C4N4 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