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    2016全国1卷物理.pdf

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    2016全国1卷物理.pdf

    2016 年普通高等学校招生全国统一考试(新课标I 卷)理科综合(物理部分)二、选择题:本题共8 小题,每小题6 分。在每小题给出的四个选项中,第1417 题只有一项符合题目要求,第1821 题有多项符合题目要求。全部选对的得6 分,选对但不全的得 3 分。有选错的得0 分。14.一平行板电容器两极板之间充满云母介质,接在恒压直流电源上。若将云母介质移出,则电容器()A.极板上的电荷量变大,极板间电场强度变大B.极板上的电荷量变小,极板间电场强度变大C.极板上的电荷量变大,极板间电场强度不变D.极板上的电荷量变小,极板间电场强度不变【答案】D 由4rSCkd可知,当云母介质抽出时,r变小,电容器的电容C变小;因为电容器接在恒压直流电源上,故U不变,根据 QCU 可知,当C减小时,Q减小。再由UEd,由于U与d都不变,故电场强度E不变,答案为D【考点】电容器的基本计算15.现代质谱仪可用来分析比质子重很多倍的离子,其示意图如图所示,其中加速电压恒定。质子在入口处从静止开始被加速电场加速,经匀强磁场偏转后从出口离开磁场。若某种一价正离子在入口处从静止开始被同一加速电场加速,为使它经匀强磁场偏转后仍从同一出口离开磁场,需将磁感应强度增加到原来的12 倍。此离子和质子的质量比约为()A.11 B.12 C.121 D.144【答案】D 设质子的质量数和电荷数分别为1m、1q,一价正离子的质量数和电荷数为2m、2q,对于任意粒子,在加速电场中,由动能定理得:2102qUmv得2qUvm在磁场中应满足2vqvBmr由题意,由于两种粒子从同一入口垂直进入磁场,从同一出口垂直离开磁场,故在磁场中做匀速圆周运动的半径应相同由 式联立求解得匀速圆周运动的半径12mUrBq,由于加速电压不变,故1212212111rBmqrBmq其中211212BBqq,可得121144mm故一价正离子与质子的质量比约为144【考点】带电粒子在电场、磁场中的运动、质谱仪。16.一含有理想变压器的电路如图所示,图中电阻12RR、和3R的阻值分别是31、和4,A为理想交流电流表,U为正弦交流电压源,输出电压的有效值恒定。当开关S断开时,电流表的示数为I;当S闭合时,电流表的示数为4I。该变压器原、副线圈匝数比为()A.2 B.3 C.4 D.5【答案】B 解法一:当 S 断开时,电路如右图所示由闭合电路欧姆定律,原线圈两端电压11UUIR得13UUI根据变压器原副边电压关系:1122UnUn副线圈中的电流:222235UUIRR联立 得:21235nUInI当 S 闭合时,电路如右图所示由闭合电路欧姆定律,原线圈两端电压114UUIR=得112UUI=根据变压器原副边电压关系:1122UnUn副线圈中的电流得:22221UUIR=联立 得212124nUInI联立 解得123nn解法二:设开关S断开前后,变压器的等效电阻为R和R,由于变压器输入功率与输出功率相同,S闭合前:2223()()IIRRRn,得232RRRnS闭合后:2224(4)()IIRRn,得22RRn根据闭合电路欧姆定律:文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9S闭合前:1UIRRS闭合后:14UIRR根据以上各式得:212223122131=543RRnnRRRnn解得,3n【考点】变压器的计算【难点】由于原边回路有电阻,原线圈两端电压不等于电源电压17.利用三颗位置适当的地球同步卫星,可使地球赤道上任意两点之间保持无线电通讯。目前,地球同步卫星的轨道半径约为地球半径的6.6倍。假设地球的自转周期变小,若仍仅用三颗同步卫星来实现上述目的,则地球自转周期的最小值约为()A.1hB.4hC.8hD.16h【答案】B 地球自转周期变小,卫星要与地球保持同步,则卫星的公转周期也应随之变小,由2224MmGmrrT可得234rTGM,则卫星离地球的高度应变小,要实现三颗卫星覆盖全球的目的,则卫星周期最小时,由数学几何关系可作出右图。由几何关系得,卫星的轨道半径为2sin30RrR由开普勒第三定律33122212rrTT,代入题中数据,得33222(6.6)24RrT由 解得24Th【考点】(1)卫星运行规律;(2)开普勒第三定律的应用【难点】做出最小周期时的卫星空间关系图18.一质点做匀速直线运动。现对其施加一恒力,且原来作用在质点上的力不发生改变,则()A.质点速度的方向总是与该恒力的方向相同B.质点速度的方向不可能总是与该恒力的方向垂直C.质点加速度的方向总是与该恒力的方向相同D.质点单位时间内速率的变化量总是不变【答案】BC 质点一开始做匀速直线运动,处于平衡状态,施加恒力后,则该质点的合外力为该恒力若该恒力方向与质点原运动方向不共线,则质点做曲线运动,质点速度方向时刻与恒力方向不同,故A 错;若F的方向某一时刻与质点运动方向垂直,之后质点作曲线运动,力与运动方向夹角会发生变化,例如平抛运动,故B 正确;由牛顿第二定律可知,质点加速度方向与其所受合外力方向相同;根据加速度的定义,相等时间内速度变化量相同,速率变化量不一定相同,故 D错。30R卫星卫星卫星文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9【考点】牛顿运动定律;力和运动的关系;加速度的定义;【易错点】B 选项易错误地以“匀速圆周运动”作为反例来推翻结论19.如图,一光滑的轻滑轮用细绳OO悬挂于O点;另一细绳跨过滑轮,其一端悬挂物块a,另一端系一位于水平粗糙桌面上的物块b。外力F向右上方拉b,整个系统处于静止状态。若F方向不变,大小在一定范围内变化,物块b仍始终保持静止,则()A.绳OO的张力也在一定范围内变化B.物块b所受到的支持力也在一定范围内变化C.连接a和b的绳的张力也在一定范围内变化D.物块b与桌面间的摩擦力也在一定范围内变化【答案】BD 由题意,在F 保持方向不变,大小发生变化的过程中,物体a、b均保持静止,各绳角度保持不变;选a受力分析得,绳的拉力aTm g,所以物体a受到绳的拉力保持不变。由滑轮性质,滑轮两侧绳的拉力相等,所以b受到绳的拉力大小、方向均保持不变,C 选项错误;a、b受到绳的拉力大小方向均不变,所以OO的张力不变,A 选项错误;对b进行受力分析,并将各力沿水平方向和竖直方向分解,如上图所示。由受力平衡得:xxTfF,yybFNTm g。T 和bm g始终不变,当F 大小在一定范围内变化时;支持力在一定范围内变化,B 选项正确;摩擦力也在一定范围内发生变化,D选项正确;故答案选BD。【考点】考查动态平衡分析、力的正交分解和力的平衡方程。20.如图,一带负电荷的油滴在匀强电场中运动,其轨迹在竖直面(纸面)内,且相对于过轨迹最低点P的竖直线对称。忽略空气阻力。由此可知()A.Q 点的电势比P点高B.油滴在Q 点的动能比它在P点的大C.油滴在Q 点的电势能比它在P点的大D.油滴在Q 点的加速度大小比它在P点的小【答案】AB 由于匀强电场中的电场力和重力都是恒力,所以合外力为恒力,加速度恒定不变,所以 D 选项错。由于油滴轨迹相对于过P 的竖直线对称且合外力总是指向轨迹弯曲内侧,所以油滴所受合外力沿竖直方向,电场力竖直向上。当油滴得从P 点运动到 Q 时,电场力做正功,电势能减小,C 选项错误;油滴带负电,电势能减小,电势增加,所以 Q点电势高于P 点电势,A 选项正确;在油滴从 P 点运动到 Q的过程中,合外力做正功,动能增加,所以Q 点动能大于P点,B 选项正确;所以选AB。【考点】带电粒子在复合场中运动、曲线运动中物体受力特点、带电粒子电场力做功与电势能的关系、电势能变化与电势变化的关系。gfTxTyNmb TFxFyF文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R921.甲、乙两车在平直公路上同向行驶,其vt图像如图所示。已知两车在3ts时并排行驶,则()A.在1st时,甲车在乙车后B.在0t时,甲车在乙车前7.5mC.两车另一次并排行驶的时刻是2stD.甲、乙车两次并排行驶的位置之间沿公路方向的距离为40m【答案】BD 根据vt图,甲、乙都沿正方向运动。3st时,甲、乙相遇,=30m/sv甲,=25m/sv乙,由位移和vt图面积对应关系,0-3s内位移1=330m=45m2x甲,1=310+25 m=52.5m2x乙。故0t时,甲乙相距1-=7.5mxxx乙甲,即甲在乙前方7.5m,B选项正确。0-1s内,1=1 10m=5m2x甲,1=110+15 m=12.5m2x乙,2=7.5mxxx乙甲,说明甲、乙第一次相遇。A、C 错误。乙两次相遇地点之间的距离为=45m5m=40mxxx甲甲,所以 D 选项正确;【考点】vt图的解读和位移的计算、追击相遇问题【难点】根据位移判断两车在不同时刻的位置关系文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9三、非选择题:本卷包括必考题和选考题两部分。第2232题为必考题,每个试题考生都必须作答。第3340题为选考题,考生根据要求作答。(一)必考题22.(5 分)某同学用图(a)所示的实验装置验证机械能守恒定律,其中打点计时器的电源为交流电源,可以使用的频率有20Hz30Hz、和40Hz。打出纸带的一部分如图(b)所示。该同学在实验中没有记录交流电的频率f,需要用实验数据和其它题给条件进行推算。(1)若从打出的纸带可判定重物匀加速下落,利用f 和图(b)中给出的物理量可以写出:在打点计时器打出B点时,重物下落的速度大小为 _,打出 C 点时重物下落的速度大小为_,重物下落的加速度大小为_。(2)已测得1238.89cm9.50cm10.10cmSSS,当地重力加速度大小为29.80m/s,实验中重物受到的平均阻力大小约为其重力的1%,由此推算出f为_Hz。【答案】12()2fSS,23()2fSS,231()2fSS;40 由于重物匀加速下落,ABCD、各相邻点之间时间间隔相同,因此B点应是从A运动到C的过程的中间时刻,由匀变速直线运动的推论可得:B点的速度Bv等于AC段的平均速度,即122BSSvt由于1tf,故12()2BfvSS同理可得23()2CfvSS匀加速直线运动的加速度vat故2231231()()2()12CBfSSSSvvfaSStf重物下落的过程中,由牛顿第二定律可得:gmF=ma阻由已知条件0.01gF=m阻由 得0.99ga代入 得:231()2faSS,代入数据得40Hzf【考点】利用运动学公式和推论处理纸带问题文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R923.(10 分)现要组装一个由热敏电阻控制的报警系统,要求当热敏电阻的温度达到或超过60 C时,系统报警。提供的器材有:热敏电阻,报警器(内阻很小,流过的电流超过cI时就会报警),电阻箱(最大阻值为999.9),直流电源(输出电压为U,内阻不计),滑动变阻器1R(最大阻值为1000),滑动变阻器2R(最大阻值为2000),单刀双掷开关一个,导线若干。在室温下对系统进行调节。已知U约为18V,cI约为10mA;流过报警器的电流超过20mA时,报警器可能损坏;该热敏电阻的阻值随温度升高而减小,在60 C时阻值为650.0。(1)在答题卡上完成待调节的报警系统原理电路图的连线。(2)电路中应选用滑动变阻器_(填“1R”或“2R”)。(3)按照下列步骤调节此报警系统:电路接通前,需将电阻箱调到一固定的阻值,根据实验要求,这一阻值为_;滑动变阻器的滑片应置于_(填“a”或“b”)端附近,不能置于另一端的原因是_。将开关向 _(填“c”或“d”)端闭合,缓慢移动滑动变阻器的滑片,直至_。(4)保持滑动变阻器滑片的位置不变,将开关向另一端闭合,报警系统即可正常使用。【答案】(1)如下图(2)2R(3)650.0,b,接通电源后,流过报警器的电流会超过20mA,报警器可能损坏c,报警器开始报警热敏电阻工作温度达到60 C时,报警器报警。故需通过调节电阻箱使其电阻为60 C时的热敏电阻的阻值,即调节到阻值650.0,光使报警器能正常报警,电路图如上图18VU,当通过报警器的电流10mA20mAcI,故电路中总电阻cURI,9001800R,故滑动变阻器选2R。热敏电阻为650.0时,报警器开始报警,模拟热敏电阻的电阻器阻值也应为650.0为防止通过报警器电流过大,造成报警器烧坏,应使滑动变阻器的滑片置于 b 端【考点】滑动变阻器在电路中的作用及其规格选择、串并联电路相关计算、等效替代思想文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ7X6P1H4S6 HL6H1L2E8N9 ZE4Y2D2N3R9文档编码:CQ

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