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    2021年2017-2018年广州市荔湾区八上期末考试数学试卷和答案.pdf

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    2021年2017-2018年广州市荔湾区八上期末考试数学试卷和答案.pdf

    本文为 word 版资料,可以任意编辑修改2017-2018学年荔湾区初二级期末考数学科试卷一、选择题(本题共有10 小题,每小题 2 分,共 20 分)1、在角、等边三角形、平行四边形、梯形中是轴对称图形的是()A、B、C、D、2、计算 4x2?x3的结果是()A、4x6B、4x5C、4x4D、4x33、若 x、y 的值均扩大为原来的2 倍,则下列分式的值保持不变的是()A、错误!未找到引用源。B、错误!未找到引用源。C、错误!未找到引用源。D、错误!未找到引用源。4、下列计算中,正确的是()A、2a3a3=6 B、(a-b)2=a2-b2C、2a3a3=a3D、(-ab)2=a2b25、长度分别为7,2,x 的三条线段能组成一个三角形,x 的值可以是()A、4 B、5 C、6 D、9 6、内角和等于外角和的多边形是()A、三角形B、四边形C、五边形D、六边形7、如图,点P 是 AOB 平分线 OC 上一点,PDOB,垂足为D,若 PD3,则点 P 到边 OA 的距离是()A、错误!未找到引用源。B、2 C、3 D、4 8、如图,ABCAOC BOD,点 A 与点 B 事对应点,那么下列结论中错误的是()A、AB=CD B、AC=BD C、AO=BO D、A=B 9、如图,(在 ABC 中,B=30,BC 的垂直平分线交AB 于 E,垂足为D,如果 DE=5,则 EC 的长为()A、5 B、8 C、9 D、10 10、如图,AD 是 ABC 的中线,E、F 分别是 AD 和 AD 延长线上的点,且DE=DF,连接 BF、CE,下列说法:ABD 和 ACD 面积相等;BAD=CAD;BDF CDE;BFCE;CE=AE,其中正确的有()A、B、C、D、|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 1 页,共 8 页|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 1 页,共 8 页二、填空题(本题共有6 小题,每小题 3 分,共 18 分)11、计算:40+2-1=。12、使分式 错误!未找到引用源。有意义的x 的取值范围是。13、要使 x2-2ax+16 是完全平方式,那么a 的值是。14、若一个等腰三角形的周长为26,一边长为6,则它的腰长为。15、如图,在锐角ABC 中,CD、BE 分别是 AB、AC 边上的高,且CD、BE 相交于点P,若 A=70,则 BPC=。16、如图,在锐角ABC 中,AC=6,ABC 的面积为15,BAC 的平分线交BC 于点 D、M、N 分别是 AD 和 AB 上的动点,则BM+MN的最小值是。三、解答题(本小题共有7 小题,共 62 分)17、(每小题4 分,本题满分8 分)计算:(x+2)(2x-1)(-2x3)2-3x2(x4-y2)18、(每小题4 分,本题满分8 分)分解因式:2a2-8(x-1)2-2(x-1)-3|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 2 页,共 8 页|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 2 页,共 8 页文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S119、(每小题4 分,本题满分8 分)计算:错误!未找到引用源。错误!未找到引用源。20、(本题满分8 分)如图,平面直角坐标系中,ABC 的三个顶点坐标分别为A(1,3),B(3,3),C(4,-1)。画出 ABC 关于 x 轴对称的 A1B1C1,写出点A1、B1、C1的坐标;求 A1B1C1的面积。21、(本题满分10 分)如图,AE DB,CFDB,垂足分别是点E、F,DE=BF、AE=CF,求证:A=C|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 3 页,共 8 页|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 3 页,共 8 页文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S122、(本题满分10 分)列方程解应用题:某美术社团为练习素描需要购买素描本,第一次用600 元购买了若干本素描本,用完后再花了1200 元继续在同一家商店购买同样的素描本,但这次的单价是第一次单价的1.2 倍,购买的数量比第一次多了40 本。求第一次购买的素描本单价是多少元?23、(本题满分10 分)如图,在等腰Rt ABC 中,ACB=90,P 是线段 BC 上一动点(与点B、C 不重合),连接 AP 延长 BC 至点 Q,使 CQ=CP,过点 Q 作 QHAP 于点 H,交 AB 于点 M。若 APC=a,求 AMQ 的大小(用含a 的式子表示);在 的条件下,过点M 作 MEQB 于点 E,试说明PC 与 ME 之间的数量关系,并证明。|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 4 页,共 8 页|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 4 页,共 8 页文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S12017-2018学年荔湾区初二级期末考数学科试卷参考答案一、选择题题号1 2 3 4 5 6 7 8 9 10 答案A B D D C B C A D C 二、填空题11、错误!未找到引用源。12、x-3 13、414、10 15、11016、5三、解答题17、(8 分)解:原式=2x2-x+4x-2=2x2+3x-2 解:原式=4x6-3x6+3x2y2=x6+3x2y218、(8 分)解:原式=2(a2-4)=2(a+2)(a-2)解:原式=(x-1-3)(x-1+1)=x(x-4)19、(8 分)解:原式=错误!未找到引用源。|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 5 页,共 8 页|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 5 页,共 8 页文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1=错误!未找到引用源。解:原式=错误!未找到引用源。?错误!未找到引用源。=错误!未找到引用源。?错误!未找到引用源。=错误!未找到引用源。?错误!未找到引用源。=错误!未找到引用源。20、(8 分)解:如图所示,A1B1C1即为所求。A1(1,-3),B1(3,-3),C1(4,1)A1B1C1的面积=34-错误!未找到引用源。14-错误!未找到引用源。34=4 21、(10 分)证明:DE=BF DE+EF=BF+EF 即 DF=BE AEDB,CFDB AEB=CFD=90在 AEB 和 CFD 中AE=CF AEB=CFD BE=DF AEB CFD(SAS)A=C|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 6 页,共 8 页|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 6 页,共 8 页文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S122、(10 分)解:设第一次购买的素描本单价为x 元,则第二次的单价为1.2x 元。错误!未找到引用源。=错误!未找到引用源。-40 错误!未找到引用源。1.2x=错误!未找到引用源。1.2x-40 1.2x720=1200-48x x=10 经检验:x=10 是方程的解答:第一次购买的素描本单价为10 元。23、(10 分)解:QHAP QHP=90在 QHP 中,APC=a HQP-90-a ACB 为等腰直角三角形 B=45 AMQ 为 QMB 的外角 AMQ=B+MQB=45+90-a=135-a PC=ME 证明:连接AQ AC PQ 且 QC=CP AQ=AP AQP=APQ=a 在 AQB 中,QAB=180-AQB-B=180-a-45=135-a 由 可得 AMQ=QAB AQ=MQ|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 7 页,共 8 页|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 7 页,共 8 页文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1A10N10 ZP8V4G8O5S1文档编码:CB9Z7A2D2P4 HC5Y5C1

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