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    2016届河北省衡水中学高三下学期二模考试数学(理)试题.pdf

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    2016届河北省衡水中学高三下学期二模考试数学(理)试题.pdf

    2016 届河北省衡水中学高三下学期二模考试数学(理)试题理数试卷第卷(共 60 分)一、选择题:本大题共 12 个小题,每小题 5 分,共 60 分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.已知集合01xxA,1,0,1,2B,则BACR)(等于()A1,2B2C1,0,1D1,02.已知复数iiz12,z为 z 的共轭复数,则zz的值为()A-2 B0 C2D2 3.执行如图所示的程序框图,若输入n 的值为 8,则输出s 的值为()A 4 B8 C10 D12 4.若实数数列:1,a,81 成等比数列,则圆锥曲线122ayx的离心率是()A10或322B3或36C322D31或 10 5.在平面 xOy 内,向图形422yx内投点,则点落在由不等式组0,0yxyx所确定的平面区域的概率为()A43B52C21D416.在 ABC 中,角 A,B,C 所对边的长分别为a,b,c,若 acosB+bcosA=csinC,且bcacb3222,则角 B 的值为()A6B3C2D327.已知,052,04,02yxyxyx则112xyz的取值范围为()A27,43B47,83C47,43D27,838.已知某几何体的三视图如图所示,则该几何体的体积等于()A3160B160 C23264D60 9.如图,21,FF为双曲线C 的左右焦点,且221FF,若双曲线C 右支上存在点P,使得21PFPF,设直线2PF与 y 轴交于点 A,且1APF的内切圆半径为21,则双曲线的离心率为()A 2 B4 C3D3210.在平行四边形ABCD 中,AC 与 BD 交于点 O,E 是线段 OD 的中点,AE 的延长线与CD 交于点 F,若bBDaAC,,则AF()Aba2141Bba4121Cba3132Dba322111.函数3sin)(xxxf.数列na的前 n 项和qnpnSn2(p,q 为常数,且p0),)2,2(na,若0)(10af,则)()()()()(1918321afafafafaf取值()文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2文档编码:CM10C9C7E7X10 HZ3G3N5V6Z9 ZZ2Y4V9Q4Z2A恒为正数B恒为负数C恒为零D可正可负12.函数)(xf是定义在),0(内的单调函数,1ln)(),0(exxffx,给出下面四个命题:不等式0)(xf恒成立;函数)(xf存在唯一零点0 x,且)1,0(0 x;方程xxf)(有且仅有一个根;方程1)()(exfxf(其中 e 为自然对数的底数)有唯一解0 x,且)2,1(0 x.其中正确的命题个数为()A 1 个B2 个C3 个D4 个第卷(共 90 分)二、填空题(每题5分,满分 20 分,将答案填在答题纸上)13.若将函数6)(xxf表示为662210)1()1()1()(xaxaxaaxf,其中621,aaa为实数,则3a等于 _.14.已知三棱锥D-ABC 的四个顶点都在球O 的表面上,若 AB=3,AC=4,AB AC,DB 平面 ABC,DB=12,则球 O 的半径为 _.15.已知点 A 是抛物线241xy的对称轴与准线的交点,点F 为该抛物线的焦点,点P 在抛物线上且满足PAmPF,当 m 取最小值时,点P 恰好在以 A,F 为焦点的双曲线上,则该双曲线的离心率为_.16.已知函数,0),1ln(,0,121)(2xxxxxf若函数kxxfxF)()(有且只有两个零点,则k 的取值范围为_.三、解答题(本大题共 6 小题,共 70 分.解答应写出文字说明、证明过程或演算步骤.)17.(本小题满分12 分)已知函数21cos)cossin3()(xxxxf(其中0),若)(xf的一个条对称轴离最近的对称中心的距离为4.(1)求)(xfy的单调递增区间;(2)在 ABC 中,角 A,B,C 的对边分别是a,b,c,满足(2b-a)cosC=ccosA,且 f(B)恰是 f(x)的最大值,试判断 ABC 的形状.18.(本小题满分12 分)文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4如图,棱柱1111DCBAABCD的所有棱长都为2,ABC=60,平面CCAA11平面 ABCD,601ACA.(1)证明:1AABD;(2)求锐二面角CAAD1的平面角的余弦值;(3)在直线1CC上是否存在点P,使得 BP平面11CDA,若存在,求出P的位置.19.(本小题满分12 分)某大学的一个社会实践调查小组,在对大学生的良好“光盘习惯”的调查中,随机发放了120 份问卷.对收回的 100 份有效问卷进行统计,得到如下22 列联表:做不到光盘能做到光盘合计男45 10 55 女30 15 45 合计75 25 100(1)现按女生是否能抽到光盘进行分层,从45 份女生中问卷中抽取了9 份问卷,若从这9 份问卷中随机抽取 4 份,并记其中能做到光盘的问卷的份数为,试求随机变量的分布列和数学期望;(2)若在犯错误的概率不超过P 的前提下认为良好“光盘习惯”与性别有关,那么根据临界值表最精确的 P 的值应为多少?请说明理由.附:独立性检验统计量)()()()(22dbcadcbabcadnK,其中 n=a+b+c+d.独立性检验临界表:20.(本小题满分12 分)已知椭圆 C 的中点在原点,焦点在 x 轴上,离心率等于21,它的一个顶点恰好是抛物线yx382的焦点.(1)求抛物线C 的标准方程;文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4(2)直线 x=-2 与椭圆交于P,Q 两点,A,B 是椭圆上位于直线x=-2 两侧的动点.若直线 AB 的斜率为21,求四边形APBQ 面积的最大值;当动点 A,B 满足 APQ=BPQ 时,试问直线AB 的斜率是否为定值,请说明理由.21.(本小题满分12 分)设函数)1ln()(,)4(31)(23xaxgxmmxxf,其中 a0.(1)若函数y=g(x)图象恒过定点T,且点 T 关于直线23x的对称点在y=f(x)的图象上,求m 的值;(2)当 a=8 时,设)1()()(xgxfxF,讨论 F(x)的单调性;(3)在(1)的条件下,设,2),(,2),()(xxgxxfxG曲线 y=G(x)上是否存在两点P,Q,使 OPQ(O 为原点)是以 O 为直角顶点的直角三角形,且斜边的中点在y 轴上?如果存在,求a 的取值范围;如图不存在,说明理由.请考生在 22、23、24三题中任选一题作答,如果多做,则按所做的第一题记分.-22.(本小题满分10 分)选修4-1:几何证明选讲如图,已知圆O 是 ABC 的外接圆,AB=BC,AD 是 BC 边上的高,AE 是圆 O 的直径.过点 C 作圆 O 的切线交 BA 的延长线于点F.(1)求证:AEADBCAC;(2)若 AF=2,22CF,求 AE 的长.23.(本小题满分10 分)选修4-4:坐标系与参数方程在平面直角坐标系xOy 中,直线l过点 P(2,6),且倾斜角为43,在极坐标系(与平面直角坐标系zOy取相同的长度,以原点O 为极点,x 轴的非负半轴为极轴)中,曲线C 的极坐标方程为)24cos()24sin(20.(1)求直线l的参数方程与曲线C 的直角坐标方程;(2)设曲线C 与直线l交于点 A,B,求PBPA.24.(本小题满分10 分)选修4-5:不等式选讲文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4已知函数3212)(xxxf.(1)求不等式6)(xf的解集;(2)若关于x 的不等式2)3(log)(22aaxf恒成立,求实数a 的取值范围.参考答案及解析一、选择题1.A 2.D 3.B 4.A 5.D 6.B 7.A 8.A 9.A 10.C 11.B 12.A 二、填空题13.-20 14.2315.1216.)1,21(三、解答题17.解:(1)21coscossin3)(2xxxxf)1cos2(212sin232xx)62sin(2cos212sin23xxx.文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4所以函数)(xf的单调递增区间为)(3,6Zkkk.(2)因为(2b-a)cosC=ccosA,由正弦定理,得(2sinB-sinA)cosC=sinCcosA,即 2sinBcos=sinAcosC+sinCcosA=sin(A+C)=sinB,因为 sinB 0,所以21cosC,所以3C.所以67626,3420,320BBB.根据正弦函数的图象,可以看出f(x)的最大值为f(B)=1,此时262B,即3C,所以3A,所以 ABC 为等边三角形.18.解:连接BD 交 AC 于点 O,则 BD AC,连接OA1.在OAA1中,60,1,211AOAAOAA,360cos2122121AOAAAOAAOA.21221AAAOAA,OA1AO.平面CCAA11平面 ABCD,OA1底面 ABCD.分别以 OB,OC,1OA所在直线为x 轴,y 轴,z 轴建立如图所示的空间直角坐标系,则)3,0,0(),0,0,3(),0,1,0(),0,0,3(),0,1,0(1ADCBA.文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L3T4文档编码:CZ10F4W7J10H3 HT10W6X10V10G10 ZH4M8K1L

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