2018届黄浦区高考数学二模试卷(附答案).pdf

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2018届黄浦区高考数学二模试卷(附答案).pdf

第 1 页黄浦区 2018 年高考模拟考数学试卷(完卷时间：120 分钟总分值：150 分)2018.4考生注意：1每位考生应同时收到试卷和答题卷两份材料，解答必须在答题卷上进行，写在试卷上的解答一律无效；2答卷前，考生务必将等相关信息在答题卷上填写清楚，并在规定的区域贴上条形码；3本试卷共21 道试题，总分值150 分；考试时间120 分钟一、填空题本大题共有12 题，总分值 54 分考生应在答题纸相应编号的空格内直接填写结果，每个空格填对前6 题得 4 分、后 6 题得 5 分，否则一律得零分.1已知集合1,2,31,ABm，假设3mA，则非零实数m 的数值是2不等式|1|1x的解集是3假设函数2()82f xaxx是偶函数，则该函数的定义域是4已知ABC的三内角ABC、所对的边长分别为abc、，假设2222sinabcbcA，则内角A的大小是5已知向量a在向量b方向上的投影为2，且3b，则a b=(结果用数值表示)6方程33log(3 25)log(41)0 xx的解x7已知函数2sincos2()1cosxxf xx，则函数()f x的单调递增区间是8已知是实系数一元二次方程22(21)10 xmxm的一个虚数根，且|2，则实数m的取值范围是9已知某市A 社区 35 岁至 45 岁的居民有450 人，46 岁至 55 岁的居民有750 人，56 岁至 65 岁的居民有900 人为了解该社区35 岁至 65 岁居民的身体健康状况，社区负责人采用分层抽样技术抽取假设干人进行体检调查，假设从 46 岁至 55 岁的居民中随机抽取了50 人，试问这次抽样调查抽取的人数是人10将一枚质地均匀的硬币连续抛掷5 次，则恰好有3 次出现正面向上的概率是(结果用数值表示)11 已知数列na是共有k个项的有限数列，且满足11(2,1)nnnnaanka，假设1224,51,0kaaa，则k12 已知函数2()(02)f xaxbxcab对任意Rx恒有()0f x成立，则代数式(1)(0)(1)fff的最小值是第 2 页二、选择题本大题总分值20 分本大题共有4 题，每题有且只有一个正确答案，考生应在答题卷的相应编号上，将代表答案的小方格涂黑，选对得5 分，否则一律得零分13在空间中，“直线m平面”是“直线m与平面内无穷多条直线都垂直”的答()(A)充分非必要条件(B)必要非充分条件(C)充要条件(D)非充分非必要条件14 二项式4031xx的展开式中，其中是有理项的项数共有答().(A)4 项(B)7 项(C)5 项(D)6 项15实数xy、满足线性约束条件3,0,0,10,xyxyxy则目标函数23wxy的最大值是答()(A)0(B)1(C)2(D)3 16在给出的以下命题中，是假命题的是答()(A)设OABC、是同一平面上的四个不同的点，假设(1)(R)OAm OBmOC m，则点ABC、必共线(B)假设向量ab和是平面上的两个不平行的向量，则平面上的任一向量c都可以表示为(R)cab、，且表示方法是唯一的(C)已知平面向量OA OB OC、满足|(0)OAOBOCr r|=|，且0OAOBOC，则ABC是等边三角形(D)在平面上的所有向量中，不存在这样的四个互不相等的非零向量a b c d、，使得其中任意两个向量的和向量与余下两个向量的和向量相互垂直三、解答题本大题总分值76 分本大题共有5 题，解答以下各题必须在答题卷的相应编号规定区域内写出必要的步骤17.此题总分值14 分此题共有2 个小题，第1 小题总分值4 分，第2 小题总分值10 分在四棱锥PABCD中，PAABCD平面，文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6第 3 页,1,ABAD BCAD BC02,45CDCDA(1)画出四棱锥PABCD的主视图；(2)假设PABC，求直线PB与平面PCD所成角的大小(结果用反三角函数值表示)18.此题总分值14 分此题共有2 个小题，第1 小题总分值6 分，第 2 小题总分值8 分某企业欲做一个介绍企业发展史的铭牌，铭牌的截面形状是如下图的扇形环面(由扇形OAD挖去扇形OBC后构成的)已知10,(010)OAOBxx米米，线段 BACD、线段与弧BC、弧AD的长度之和为30米，圆心角为弧度(1)求关于x的函数解析式；(2)记铭牌的截面面积为y，试问x取何值时，y的值最大？并求出最大值19.此题总分值14 分此题共有2 个小题，第1 小题总分值6 分，第 2 小题总分值8 分已知动点(,)M x y到点(2,0)F的距离为1d，动点(,)M x y到直线3x的距离为2d，且1263dd.(1)求动点(,)M x y的轨迹C的方程；(2)过点F作直线:(2)(0)lyk xk交曲线C于 PQ、两点，假设OPQ的面积3OPQS(O是坐标系原点)，求直线l的方程.20.此题总分值16 分此题共有2 个小题，第1 小题总分值4 分，第 2 小题总分值6 分，第 3 小题总分值 6 分文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6第 4 页已知函数22,10,()=1,01.xxf xxx(1)求函数()f x的反函数1()fx；(2)试问:函数()f x的图像上是否存在关于坐标原点对称的点，假设存在，求出这些点的坐标；假设不存在，说明理由；(3)假设方程22()2 1|()2 1|240f xxf xxax的三个实数根123xxx、满足:123xxx，且32212()xxxx，求实数a的值 21.此题总分值18 分此题共有3 个小题，第1 小题总分值3 分，第 2 小题总分值6 分，第 3 小题总分值 9 分定义：假设数列nc和nd满足*1220,0,Nnnnnnnncdcdncd且c，则称数列nd是数列nc的“伴随数列”.已知数列nb是数列na的伴随数列，试解答以下问题：(1)假设*(N)nnban，12b，求数列na的通项公式na；(2)假设*11(N)nnnbbna，11ba为常数，求证：数列2nnba是等差数列；(3)假设*12(N)nnnbbna，数列na是等比数列，求11ab、的数值文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6第 5 页黄浦区 2018 年高考模拟考数学试卷参考答案和评分标准2018.4说明：1本解答仅列出试题的一种解法，如果考生的解法与所列解答不同，可参考解答中的评分精神进行评分2评阅试卷，应坚持每题评阅到底，不要因为考生的解答中出现错误而中断对该题的评阅，当考生的解答在某一步出现错误，影响了后继部分，但该步以后的解答未改变这一题的内容和难度时，可视影响程度决定后面部分的给分，这时原则上不应超过后面部分应给分数之半，如果有较严重的概念性错误，就不给分一、填空题.122(,0)(2,)3 2,244566273,Z88kkk83(,349140105161150123.二、选择题13()A14()B15()D16()D三、解答题17 此题总分值14 分此题共有2 个小题，第1 小题总分值4 分，第 2小题总分值10 分解(1)主视图如下：(2)根据题意，可算得1,2ABAD.又1PABC，按如下图建立空间直角坐标系，可得，(0,0,0),(1,0,0),(1,1,0),(0,2,0),(0,0,1)ABCDP.于是，有(1,0,1),(1,1,0),(0,2,1)PBCDPD.设平面PCD的法向量为(,)nx y z，则0,0,n CDn PD即0,20.xyyz令2z，可得1,1yx，故平面PCD的一个法向量为(1,1,2)n.文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6第 6 页设直线PB与平面PCD所成角的大小为，则|3sin6|n PBnPB.所以直线PB与平面PCD所成角的大小为3arcsin6.18 此题总分值14 分此题共有2 个小题，第1 小题总分值6 分，第 2小题总分值8分解(1)根据题意，可算得弧BCx(m)，弧10AD(m).又30BACDBCCD弧弧，于是，10101030 xxx，所以，210(010)10 xxx.(2)依据题意，可知22111022OADOBCySSx扇扇化简，得2550yxx25225()24x.于是，当52x(满足条件010 x)时，max2254y(2m).答所以当52x米时铭牌的面积最大，且最大面积为2254平方米.19 此题总分值14 分此题共有2 个小题，第1 小题总分值6 分，第 2 小题总分值8 分解(1)结合题意，可得2212(2),|3|dxydx.又1263dd，于是，22(2)6|3|3xyx，化简得22162xy.因此，所求动点(,)M x y的轨迹C的方程是22162xy.(2)联立方程组221,62(2),xyyk x得2222(13)121260kxk xk.文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6第 7 页设点1122(,)(,)P xyQ xy、，则2122212212,13126,130.kxxkkx xk于是，弦22222212122212126|()()141313kkPQxxyykkk，点O到直线l的距离2|2|1kdk.由3OPQS，得21|2|21kk22222212126141313kkkkk3，化简得42210kk，解得1k，且满足0，即1k都符合题意.因此，所求直线的方程为2020 xyxy或.20 此题总分值16 分此题共有3 个小题，第1 小题总分值4 分，第 2 小题总分值6 分，第 3 小题总分值 6 分解(1)22,10,()=1,01.xxf xxx当10 x时，()2,0()2f xxf x且.由2yx，得12xy，互换xy与，可得11()(02)2fxxx.当01x时，2()1,()0fxxfx且-1.由21yx，得1+xy，互换xy与，可得1()1+(10)fxxx.11,02,2()1,10.xxfxxx(2)答函数图像上存在两点关于原点对称.设点00000(,)(01)(,)A xyxBxy、是函数图像上关于原点对称的点，则00()()0f xfx，即200120 xx，解得0021(21,)xx舍去，且满足01x.文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 HX4B8T6P8Z5 ZE1W3E1M1N6文档编码:CD7R1P10J5Q5 H

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