2015-2016学年高二下学期期中考试数学试题.pdf
2015/2016 学年度第二学期期中考试高二年级数学试题（文科）一、填空题：（70 分）1xR，sin1x的否定是 2若复数(1 bi)(2 i)是纯虚数(i是虚数单位)，则实数b=3已知集合 3,1,1,2A，集合0,)B，则ABI .4.数列 1，4，7，10，的第 8 项等于5计算：234iiii .6.已知函数()21,(1)f xxf x则7若将复数212ii表示为(,abi a bR i是虚数单位）的形式，则ab8用反证法证明命题“三角形的内角中至少有一个角不大于60o”时应假设.9若函数,1,12,1),1()(xxxxfxf则)23(f的值等于 .10已知条件:3p a,条件:(3)0q a a,则p是q条件.11已知函数f(x)=2x+2(a-1)x+2在区间（,6 上递减，则a 的取值范围是 .12现有一个关于平面图形的命题：如图，同一个平面内有两个边长都是 a 的正方形，其中一个的某顶点在另一个的中心，则这两个正方形产生重叠部分的面积恒为42a，类比到空间，有两个棱长均为a 的正方体，其中一个的某顶点在另一个的中心,则这两个正方体重叠部分的体积恒为 .13已知偶函数()f x在0,)上是增函数，则不等式1(21)()3fxf的解集是14一同学在电脑中打出如下若干个圈:若将此若干个圈依此规律继续下去,得到一系列的圈,那么在前 160 个圈中的的个数是。二、解答题（90 分）15.（本题满分 14 分）把复数z的共轭复数记作z，i为虚数单位，若1zi（1）求复数(1)zz；（2）求2(1)zz的模16（本题满分 14 分）若集合2280Ax xx，0Bx xm（1）若3m，全集UR,试求UAC B；（2）若AB,求实数m的取值范围；17（本题满分 14 分）已知x，yR+，且x+y2，求证:xyyx11与中至少有一个小于 2。18、（本题满分 16 分）设命题:p实数x满足03422aaxx，其中0a，命题:q实数x满足2280 xx文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5(1)若1a，且qp为真，求实数x的取值范围；(2)若q是p的充分不必要条件，求实数a 的取值范围19（本题满分 16 分）已知数列na满足条件111nnaa.(1)若112a，求234,a a a的值.(2)已知对任意的nN，都有1na，求证：3nnaa对任意的正整数n都成立；(3)在(1)的条件下，求2 015a.20（本题满分 16 分）已知函数2()(4)2f xxaxb，2log(1)3f，且()()2g xf xx为偶函数.(1)求函数()f x的解析式；(2)若函数()f x在区间,)m的最大值为1 3m，求m的值.文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5 2015/2016 学年高二年级期中考试数 学 答 题 纸（文科）2020-2-8一、（本题共 14 小题，共 70 分）1、xR，sinx1 2、2 3、1,2 4、22 5、0 6、2x-3 7、1 8、三角形的三个内角都大于 60o9、2 10、充分不必要11、(-,-5 12、38a13、1 23 3(,)14、16 二、（本题共 6 小题，共 90 分）1520班级姓名考试号16(1)UAC B=3,4)(2)m-217证明:(反证法):假设xyyx11与均不xy12，1+x2y，1+y2x。将两式相加得:x+y故xyyx11与中至少有一个小于2。18(1)2x3(2)a219(1)2341212,aaa；(2)111nnaa，文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5文档编码:CM9F4O6J2U10 HO4F2X9T1K7 ZT10D9K9A2H5
