2017-2018学年山东省青岛市市北区八年级(下)期末数学模拟试卷.pdf
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2017-2018学年山东省青岛市市北区八年级(下)期末数学模拟试卷.pdf
1 2017-2018 学年山东省青岛市市北区八年级下期末数学模拟试卷题号一二三四总分得分一、选择题本大题共5 小题,共分1.以下分解因式,正确的选项是A.(?+1)(?-1)=?2+1B.-9+?2=(3+?)(?-3)C.?2+2?+?=?(?+2)+1D.?2-4?2=(?+4?)(?-4?)2.如图,AD 是 ABC 的角平分线,DF AB,垂足为 F,DE=DG,ADG 和 AED 的面积分别为51 和 38,则 EDF 的面积为A.6.5B.5.5C.8D.133.在ABC 中,已知 A、B、C 的度数之比是1:1:2,BC=4,ABC 的面积为A.2B.125C.4D.84.用三块正多边形的木板铺地,拼在一起并相交于一点的各边完全吻合,其中两块木板的边数都是8,则第三块木板的边数应是A.4B.5C.6D.85.如图,ABC中,C=90,E、F分别是AC、BC上两点,AE=8,BF=6,点P、Q、D分别是AF、BE、AB 的中点,则PQ 的长为A.4B.5C.6D.82 二、填空题本大题共6 小题,共分6.已知关于x 的方式方程?-1?+4=?+4会产生增根,则m=_7.如图,在平面直角坐标系xOy 中,RtOA1C1,Rt OA2C2,RtOA3C3,Rt OA4C4的斜边OA1,OA2,OA3,OA4都在坐标轴上,A1OC1=A2OC2=A3OC3=A4OC4=30 假设点 A1的坐标为3,0,OA1=OC2,OA2=OC3OA3=OC4,则依此规律,点A2018的纵坐标为 _8.已知一次函数y=-x+1与y=kx+b的图象在同一直角坐标系中的位置如图直线 l1和 l2,它们的交点为P,那么关于 x的不等式-x+1kx+b的解集为 _9.如图,在?ABCD 中,B=50,CE 平分 BCD,交 AD 于 E,则 DCE 的度数是 _10.如图,在 ABC 中,ACB=90,AC=4,BC=3,将 ABC 绕点 A 顺时针旋转得到 ADE其中点B 恰好落在AC 延长线上点D 处,点 C 落在点 E 处,连接 BD,则四边形AEDB 的面积为 _11.如图,将边长为 12的正方形 ABCD 沿其对角线AC 剪开,再把 ABC 沿着 AD 方向平移,得到 ABC,当两个三角形重叠部分的图形面积为36 时,它移动的距离AA等于 _文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T8文档编码:CN4P8D5J10Y2 HL10W9W5R8F10 ZF3W5Z2V2T83 三、计算题本大题共2 小题,共分12.分解因式:1xx+y x-y-xx+y2 2 x-12+21-x?y+y213.计算题:1解不等式组2?+5 3(?+2)1-2?3+1502先化筒,再求值1?-?2-2?+1,其中 m=323解方程1?-1=1-32?-2四、解答题本大题共6 小题,共分14.已知,线段a,直线 1及 1 外一点 A,求作:ABC,使 AB=AC,BC=a,且点 B、C 在直线 1 上文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 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ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S24 15.一个工程队修一条3000米的公路,由于开始施工时增加了人员,实际每天修路比原来多50%,结果提前2 天完成,求实际每天修路多少米?16.如图,Rt ABC 中,ACB=90,D 是 AB 上一点,BD=BC,过点 D 作 AB 的垂线交AC 于点 E,求证:BE垂直平分CD文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S25 17.某学校在商场购买甲、乙两种不同足球,购买甲种足球共花费2000 元,购买乙种足球共花费1400 元,购买甲种足球数量是购买乙种足球数量的2 倍且购买一个乙种足球比购买一个甲种足球多花20 元1求购买一个甲种足球、一个乙种足球各需多少元?2为响应习总书记“足球进校园”的号召,这所学校决定再次购买甲、乙两种足球共50 个并且购进乙种足球的数量不少于甲种足球数量的56,学校应如何采购才能使总花费最低?18.已知:如图,?ABCD 的对角线AC 与 BD 相交于点O,过点 O 的直线与AD,BC 分别相交于点E,F1求证:OE=OF;2楚接 BE,DF,求证:BE=DF 19.如图 1,在等边 ABC 中,AB=BC=AC=8cm,现有两个动点E,P 分别从点 A 和点 B 同时出发,其中点E以 1cm/秒的速度沿AB 向终点 B 运动;点P 以 2cm/秒的速度沿射线BC 运动过点E 作 EF BC 交 AC 于点 F,连接 EP,FP设动点运动时间为t 秒 0t8 1当点 P在线段 BC 上运动时,t为何值,四边形PCFE 是平行四边形?请说明理由;2设 EBP 的面积为ycm2,求 y 与 t之间的函数关系式;3当点 P在射线 BC 上运动时,是否存在某一时刻t,使点 C 在 PF 的中垂线上?假设存在,请直接给出此时t 的值无需证明,假设不存在,请说明理由文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S26 文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S27 答案和解析1.【答案】B【解析】解:A、x+1x-1=x2-1,是整式乘法,故此选项错误;B、-9+y2=3+yy-3,正确;C、x2+2x+l=x+12,故此选项错误;D、x2-4y2=x+2yx-2y,故此选项错误;故选:B利用平方差公式以及完全平方公式分别分解因式得出答案此题主要考 查了公式法分解因式,正确 应用公式是解 题关键2.【答案】A【解析】解:设 EDF 的面积为 x,作 DH AC 于 H,AD 是ABC 的角平分 线,DFAB,DHAC,DF=DH,在 Rt DFE 和 Rt DHG 中,Rt DFERt DHG,由题意得,38+x=51-x,解得,EDF 的面积为,故选:A作 DH AC 于 H,根据角平分线的性质得到 DF=DH,证明 Rt DFE Rt DHG,根据题意列出方程,解方程即可此题考查的是角平分线的性质,掌握角的平分线上的点到角的两边的距离相等是解题的关键文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S2文档编码:CF4D4U10I2X10 HR2R5P7A6A6 ZR5N6H9P10S28 3.【答案】D【解析】解:A、B、C的度数之比是 1:1:2,A=B=45,C=90,BC=AC=4,SABC=4 4=8,故选:D依据 A、B、C 的度数之比是 1:1:2,即可得到 A=B=45 ,C=90 ,再根据 BC=AC=4,即可得出 S ABC=4 4=8此题主要考 查了等腰直角三角形的性 质,等腰直角三角形是一种特殊的三角形,具有所有三角形的性 质,还具备等腰三角形和直角三角形的所有性质4.【答案】A【解析】解:正八 边形的每个内角 为:180-360 8=135,两个正八 边形在一个 顶点处的内角和 为:2 135=270,那么另一个多边