2013年南京市中考数学试卷及答案(Word解析版).pdf

20XX 年江苏省南京市中考数学试卷及答案(Word 解析版)南京市 20XX 年初中毕业生学业考试数学注意事项：1.本试卷共6 页。全卷满分120 分。考试时间为120 分钟。考生答题全部答在答题卡上，答在本试卷上无效。2.请认真核对监考教师在答题卡上所黏贴条形码的姓名、考试证号是否与本人相符，再将自己的姓名、准考证号用0.5 毫米黑色墨水签字笔填写在答题卡及本试卷上。3.答选择题必须用2B 铅笔将答题卡上对应的答案标号涂黑。如需改动，请用橡皮擦干净后，再选涂其他答案。答非选择题必须用0.5 毫米黑色墨水签字笔写在答题卡上的指定位置，在其他位置答题一律无效。4.作图必须用2B 铅笔作答，并请加黑加粗，描写清楚。一、选择题(本大题共 6 小题，每小题2 分，共 12 分。在每小题所给出的四个选项中，恰有一项是符合题目要求的，请将正确选项前的字母代号填涂在答题卡相应位置上)1.计算的结果是答案：D 解析：原式 12 284 36，选 D。1 22.计算 a3(a)的结果是(A)a(B)a5(C)a6(D)a9 答案：A 解析：原式，选 A。2a 3.设边长为3 的正方形的对角线长为a，下列关于a的四种说法：是无理数；可以用数轴上的一个点来表示；是 18 的算术平方根。其中，所有正确说法的序号是答案：C 解析：由勾股定理，得：，所以，错误，其它都正确。4.如图，圆 O1、圆 O2 的圆心 O1、O2 在直线 l 上，圆 O1 的半径为2 cm，圆 O2 的半径为3 cm，O1O2=8 cm。圆 O1 以 1 cm/s 的速度沿直线l 向右运动，7s 后停止运动，在此过程中，圆 O1 与圆 O2 没有出现的位置关系是(A)外切(B)相交(C)(D)x 点，则答案：C 解析：当 k1>0，k2<0 时，正比函数经过一、三象限，反比函数在二、四象限，没有交点；当 k10，k20 时，正比函数经过二、四象限，反比函数在一、三象限，没有交点；所以，选 C。6.如图，一个几何体上半部为正四棱椎，下半部为立方体，且有一个面涂有颜色，下列图形中，是该几何体的表面展开图的是答案：B 解析：涂有颜色的面在侧面，而A、C 还原后，有颜色的面在底面，故错；D 还原不回去，故错，选 B。二、填空题(本大题共10 小题，每小题2 分，共 20 分)的相反数是；的倒数是1 答案：3；解析：负数的相反数为正数，绝对值相等，一个数的倒数是将原数分子与分母对换位置。3 1 8.计算的结果是。答案：2 解析文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2：原式9.使式子的取值范围是。答案：解析：当x1 时，分母为0 没有意义，故10.第二届亚洲青年运动会将于20XX 年 8 月 16 日至 24 日在南京举办，在此期间约有13000 名青少年志愿者提供服务，将13000 用科学记数法表示为答案：n 解析：科学记数法的表示形式为a 10 的形式，其中1|a|10，n 为整数确定n 的值时，要看把原数变成a时，小数点移动了多少位，n 的绝对值与小数点移动的位数相同当原数绝对值 1 时，n 是正数；当原数的绝对值1 时，n 是负数1300011.如图，将矩形ABCD 绕点 A 顺时针旋转到矩形ABCD的位置，D 旋转角为。若，则。答案：20 B 解析：，延长 CD 交 CD 于 E，则，C 由四边形的内角和为，可得12.如图，将菱形纸片ABCD 折迭，使点A 恰好落在菱形的对称中心O 处，折痕为EF。若菱形 ABCD 的边长为2 cm，则 EF=cm。答案：3 解析：点A 恰好落在菱形的对称中心O 处，如图，P 为 AO 中点，所以E 为 A 职点，AE1，EP，所以，EF文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U213.OAB 是以正多边形相邻的两个顶点A、B 与它的中心O 为顶点的三角形。若OAB的一个。答案：9 解析：若 OAB OBA 70，则 BOA 40，边数为：若 BOA 70，则边数为：360 9；40360 不可能，因此，边数为9。70 14.已知如图所示的图形的面积为24，根据图中的条件，可列出方程：。答案：本题答案不唯一，如；解析：把缺口补回去，得到一个面积25 的正方形，边长为x 1。15.如图，在梯形ABCD 中，AD/BC，AB=DC，AC 与 BD 相交于点 P。已知 A(2,3)，B(1,1)，D(4,3)，则点 P 的坐标为（。7 答案：3；3 解析：如图，由对称性可知P的横坐标为3，PEBEPE244 7，即，所以，PE，1 3 DFBF2333 7 故 P 的坐标为（3，3 16.计算的结果是1 答案：6 1 1 1 1 111 解析：设xx）（x）（1x）x2 3 4 5 666 三、解答题(本大题共 11 小题，共 88 分。请在答题卡指定区域b a 17.(6 分)化简。解析：解：文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U21。2x 1 18.(6 分)解方程解析：方程两边同乘，得。解这个方程，得。检验：时，是原方程的解。(6 分)19.(8 分)如图，在四边形ABCD 中，AB=BC，对角线BD 平分BC，P 是 BD 上一点，过点P 作，垂足分别为M、N。(1)求证：；(2)若，求证：四边形MPND 是正方形。解析：证明：(1)BD 平分，。又 BA=BC，BD=BD，CBD。(4 分)(2)，。又，四边形MPND 是矩形。，PM=PN。四边形MPND 是正方形。(8 分)D 20.(8 分)(1)一只不透明的袋子中装有颜色分别为红、黄、蓝、白的球各一个，这些球除颜色外都相同。求下列事件的概率：搅匀后从中任意摸出1 个球，恰好是红球；搅匀后从中任意摸出1 个球，记录下颜色后放回袋子中并搅匀，再从中任意摸出1 个球，两次都是红球；(2)某次考试有6 道选择题，每道题所给出的4 个选项中，恰有一项是正确的，如果小明从每道题的4 个选项中随机地选择1 个，那么他6 道选择题全部选择正确的概率是1 1 解析：(1)解：搅匀后从中任意摸出1 个球，所有可能出现的结果有：红、黄、蓝、白，共有4 种，它们出现的可能性相同。所有的结果中，满足“恰好是红球”(记为事件1 A)的结果只有1 种，所以P(A)=4。搅匀后从中任意摸出1 个球，记录下颜色后放回袋子中并搅匀，再从中任意摸出 1 个球，所有可能出现的结果有：(红，红)、(红，黄)、(红，蓝)、(红，白)、(黄，红)、(黄，黄)、(黄，蓝)、(黄，白)、(蓝，红)、(蓝，黄)、(蓝，蓝)、(蓝，白)、(白，红)、(白，黄)、(白，蓝)、(白，白)，共有16 种，它们出现的可能性相同。所有的结果中，满足“两次都是红球”(记为事件B)的结果只有1 种，1 所以 P(B)=16(6 分)(2)B(8 分)21.(9 分)某校有 2000 名学生，文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2某校 150 名学生上学方式频数分布表某校 150 名学生上学方式扇形统计图步行乘私家车 20%骑车34%乘公共交通工具30%(1)抽样是否合理？请说明理由：(2)根据抽样调查的结果，将估计出的全校2000 名学生上学方式的情况绘制成条形统计图；某校 2000 名学生上学方式条形统计图乘私家车(3)交通工具学生数约占全校的34%，建议学校合理安排自行车停车场地。请你结合上述统计的全过程，再提出一条合理化建议：。解析：解：(1)不合理。因为如果150 名学生全部在同一个年级抽取，那么全校每个学生被抽到的机会不相等，样本不具有代表性。(2 分)某校 2000 名学生上学方式条形统计图乘私家车交通工具(3)本题答案不唯一，下列解法供参考。乘私家车上学的学生约400 人，建议学校与交通部门协商安排停车区域。(9 分)22.(8 分)已知不等臂跷跷板AB 长 4m。如图，当 AB 的一端碰到地面时，AB 与地面的夹角为；如图，当 AB 的另一端B 碰到地面时，AB 与地面的夹角为。求跷跷板AB 的支撑点O 到地面的高度OH。(用含、的式子表示)解析：解：在RtAHO 中，文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2OB=OH OH OH OA=。在 RtBHO 中，AB=4，即。OH=(m)。(8 分)23.(8 分)某商场促销方案规定：商场(2 分)(2)设该商品的标价为x 元。当，即时，顾客获得的优惠额不超过；当，即时，。解 得。所以。当，即时，顾客获得的优货额大于。综上，顾客购买标价不超过800 元的商品，要使获得的优或额不少于226 元，那么该商品的标价至少为630 元。(8 分)24.(8 分)小丽驾车从甲地到乙地。设她出发第x min 时的速度为y km/h，图中的折线表示她在整个驾车过程中y 与 x 之间的函数关系。(1)小丽驾车的最高速度是；(2)当时，求 y 与 x 之间的函数关系式，并求出小丽出发第22 min 时的速度；(3)如果汽车每行驶100 km 耗油 10 L，那么小丽驾车从甲地到乙地共耗油多少升？y 0 0 0 0 0 解析：解：(1)60；(1 分)(2)当时，设 y 与 x 之间的函数关系式为。根据题意，当x=20 时，y=60；当 x=30 时，y=24。所以，解得。所以，y 与 x 之间的函数关系式为y=。当 x=22 时，。所以，小丽出发第22min 时的速度为52.8km/h。(5 分)(3)小丽驾车从甲地到乙地行驶的路程为文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档编码:CV4Q5F7X8D4 HR6P10S4H7V3 ZH1U9H4C7U2文档