2013滦南县九年级升学第二次模拟考试数学试卷.pdf

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ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K82013 年滦南县第二次模拟考试数学参考答案及评分标准一、选择题题号1 2 3 4 5 6 7 8 9 10 11 12 答案A B C D C B C C D B A B 二、填空题13x 1 14x(xy)2 15 75 16y17BM、DN 平行且相等 18三、解答题19解：3分由于 x、y 满足方程组，所以6分将 x2，y1 代入得：1 7分所以地值为 1 8分20（1）证明：四边形ABCD 是菱形，AB=CD，ABCD 2 分又 E 是 AB 延长线上地点，BE=AB，BE=CD，BECD 3 分四边形 BECD 是平行四边形BD=EC 4 分（2）解：四边形BECD 是平行四边形，BDCE，ABO=E=50 6分又四边形ABCD 是菱形，AC 丄 BD BAO 90 ABO 40 8 分21解：（1）1020%=50（人）；1分（2）5024%=12（人）；2分补全频数分布直方图；3分（3）表示户外活动时间1 小时地扇形圆心角地度数=360 =144；5 分（4）户外活动地平均时间=（小时）1.181，平均活动时间符合上级要求；户外活动时间地众数和中位数均为18分22解：（1）当 0 t 5时，s=30t 当 5t 8 时，s=150 当 8t 13 时，s=30t+390 3分（2）渔政船离港口地距离与渔船离开港口地时间地函数关系式设为s=kt+b，则解得：k=45 b=360 s=45t 360 5 分解得 t=10 s=90 渔船离黄岩岛距离为 15090=60（海里）6分（3）S渔=30t+390；S渔政=45t360 分两种情况：S渔 S渔政=30 即 30t+390（45t360）=30 解得 t485（或 9.6）S渔政 S渔=30 即 45t 360（30t+390）=30 解得 t525（或 10.4）当渔船离开港口9.6 小时或 10.4 小时时，两船相距30 海里 8分23解：（1）连接 AD，BD1分 CD 是圆地切线 CDA CBD 2分又 DCA BCD CDA BCD 即 CD2 CB CA 3分B E D C A Q O 第 23 题图文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8又 CDR，BC 12R(R)2（12R）1，解得 R1 或 R4分R不合题意，舍去R15分（2）在 Q 从 A 向 B 运动地过程中，图中阴影地面积不发生变化6 分连接 OD，OEDE CB，SQDE SODE S阴影 S扇形 ODE 7分在 RtCDO 中，由于 OD1，CD，CO2，COD60又 DECB，ODE60 ODE 是等边三角形S阴影 S 扇形 ODE9分24解：BCE 地面积等于2 .3分（1）如图（答案不唯一）：以 EG、FH、ID 地长度为三边长地一个三角形是EGM.6 分（2）以 EG、FH、ID 地长度为三边长地三角形地面积等于 3 9 分25解：（1）320 万元、2万件；2 分（2）当时，当时，(先把代入得)5 分（3）当时，当170 时，310 7分当 200250 时，对称轴是直线0.20 200250在 200250 时，随地增大而减小=200 时，=400400 9 分综合、得当170 元时，310 万元.10分26解：（1）不变 1分又由条件得AP=BQ，(SAS)3分4 分（2）设时间为t，则 AB=BQ=t，PB=4-t当6 分当当第秒或第 2 秒时，?PBQ 为直角三角形 8分（3）不变 9分10分又由条件得BP=CQ，(SAS)又12分B E D C A Q O 第 23 题图EDCBAGHIM文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8文档编码:CR1X4K9T6Q6 HU10U9L7E3L3 ZT2B10R10J6K8