2019上海高考数学试卷及答案.pdf

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2019上海高考数学试卷及答案.pdf

精心整理2019 年上海市高考数学试卷2019.06.07 一.填空题（本大题共12 题，满分 54 分，第 16题每题 4 分，第 712题每题 5 分）1.已知集合(,3)A，(2,)B，则AB2.已知zC，且满足1i5z，求z3.已知向量(1,0,2)a，(2,1,0)b，则a与b的夹角为4.已知二项式5(21)x，则展开式中含2x项的系数为5.已知x、y满足002xyxy，求23zxy的最小值为6.已知函数()f x周期为 1，且当01x，2()logf xx，则3()2f7.若,x yR，且123yx，则yx的最大值为8.已知数列na前n项和为nS，且满足2nnSa，则5S9.过曲线24yx的焦点F并垂直于x轴的直线分别与曲线24yx交于A、B，A在B上方，M为抛物线上一点，(2)OMOAOB，则10.某三位数密码，每位数字可在09 这 10个数字中任选一个，则该三位数密码中，恰有两位数字相同的概率是11.已知数列na满足1nnaa（*nN），若(,)nnP n a(3)n均在双曲线22162xy上，则1lim|nnnP P12.已知2()|1f xax（1x，0a），()f x与x轴交点为A，若对于()f x图像上任意一点P，在其图像上总存在另一点Q（P、Q异于A），满足APAQ，且|APAQ，则a二.选择题（本大题共4 题，每题 5 分，共 20 分）13.已知直线方程20 xyc的一个方向向量d可以是（）A.(2,1)B.(2,1)C.(1,2)D.(1,2)14.一个直角三角形的两条直角边长分别为1 和 2，将该三角形分别绕其两个直角边旋转得到的两个圆锥的体积之比为（）精心整理A.1B.2C.4D.8 15.已知R，函数2()(6)sin()f xxx，存在常数aR，使得()f xa为偶函数，则的值可能为（）A.2B.3C.4D.516.已知tantantan()，有下列两个结论：存在在第一象限，在第三象限；存在在第二象限，在第四象限；则（）A.均正确 B.均错误 C.对错 D.错对三.解答题（本大题共5 题，共 14+14+14+16+18=76分）17.如图，在长方体1111ABCDA BC D中，M为1BB上一点，已知2BM，3CD，4AD，15AA.（1）求直线1AC与平面ABCD的夹角；（2）求点 A到平面1A MC的距离.18.已知1()1f xaxx，aR.（1）当1a时，求不等式()1(1)f xf x的解集；（2）若()f x在1,2x时有零点，求a的取值范围.19.如图，ABC为海岸线，AB为线段，BC为四分之一圆弧，39.2BDkm，22BDC，68CBD，58BDA.（1）求BC的长度；（2）若40ABkm，求 D到海岸线ABC的最短距离.（精确到 0.001km）20.已知椭圆22184xy，1F、2F为左、右焦点，直线l过2F交椭圆于 A、B两点.（1）若直线l垂直于 x 轴，求|AB；（2）当190F AB时，A在 x 轴上方时，求 A、B的坐标；（3）若直线1AF交 y 轴于 M，直线1BF交 y 轴于 N，是否存在直线 l，使得11F ABF MNSS，若存在，求出直线l 的方程，若不存在，请说明理由.21.数列na()n*N有 100 项，1aa，对任意2,100n，存在niaad，1,1in，若ka与前 n 项中某一项相等，则称ka具有性质 P.（1）若11a，2d，求4a所有可能的值；（2）若na不是等差数列，求证：数列na中存在某些项具有性质P；（3）若na中恰有三项具有性质P，这三项和为 c，请用 a、d、c 表示12100aaa.文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8精心整理参考答案一.填空题1.(2,3)2.5i，155iiz3.2arccos5，22cos5|55a bab4.40，2x的系数为325240C5.6，线性规划作图，后求出边界点代入求最值，当0 x，2y时，min6z6.1，2311()()log1222ff7.98，法一：113222yyxx，239()82 2yx；法二：由132yx，2(32)23yyyyyx（302y），求二次最值max9()8yx8.3116，由1122(2)nnnnSaSan得：112nnaa（2n），na为等比数列，且11a，12q，5511 1()31211612S9.3，依题意求得：(1,2)A，(1,2)B，设M坐标为(,)M x y，有：(,)(1,2)(2)(1,2)(22,4)x y，带入24yx有：164(22)，即310.27100，法一：121103932710100CCCP（分子含义：选相同数字选位置选第三个数字）；法二：131010327110100CPP（分子含义：三位数字都相同+三位数字都不同）11.2 33，法一：由22182nan得：22(1)6nna，2(,2(1)6nnP n，21(1)(1,2(1)6nnPn，利用两点间距离公式求解极限：12lim|33nnnP P；法二（极限法）：当n时，1nnP P与渐近线平行，1nnP P在x轴投影为 1，渐近线斜角满足：3tan3，112 33cos6nnP P12.2a二.选择题13.选 D，依题意：(2,1)为直线的一个法向量，方向向量为(1,2)文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8精心整理14.选 B，依题意：21142133V，22121233V15.选 C，法一：依次代入选项的值，检验()f xa的奇偶性；法二：2()(6)sin()fxaxaxa，若()f xa为偶函数，则6a，且sin(6)x也为偶函数（偶函数偶函数=偶函数），62k，当1k时，416.选 D，取特殊值检验法：例如：令1tan3和1tan3，求tan是否存在（考试中，若有解时则认为存在，取多组解时发现没有解，则可认为不存在）三.解答题17.（1）4；（2）103.18.（1）(2,1)x；（2）11,26a.19.（1）22sin2216.3102224BCRBCBDkm；（2）35.752km.20.（1）2 2；（2）(0,2)A，82(,)33B；（3）320 xy.21.（1）3、5、7；（2）略；（3）974656adc.文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8文档编码:CD10V10G1N1M9 HX9L7X3O6Z3 ZG6M6T9X5A8

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