2015版高中数学(人教版必修5)配套练习：3.3二元一次不等式组与简单的线性规划问题第3课时.pdf

1/12 封面2/12 作者：PanHongliang 仅供个人学习第三章 3.3 第 3 课时一、选择题文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M103/12 1若变量x、y 满足约束条件y1xy0 xy20，则 zx2y 的最大值为()A4B3 C2D1 答案 B 解读 先作出可行域如图作直线 x2y0 在可行域内平移，当x2y z0 在 y 轴上的截距最小时z值最大当移至 A(1，1)时，zmax12(1)3，故选 B2 设变量 x、y 满足约束条件2xy44x y 1x2y2，则目标函数z3xy 的取值范围是()A32，6B32，1 C1,6D6，32 答案 A 解读 本题考查了线性规划的基础知识及数形结合的思想根据约束条件，画出可行域如图，作直线l0：3xy 0，将直线平移至经过点A(2,0)处 z 有最大值，经过点B(12，3)处 z有最小值，即32z6.3设 zxy，式中变量x 和 y 满足条件xy3 0 x2y0，则 z的最小值为()A1B 1 C3D 3 答案 A 解读 作出可行域如图中阴影部分直线 z xy 即 yxz.经过点 A(2,1)时，纵截距最大，z 最小 zmin1.文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M104/12 4变量 x、y 满足下列条件2xy122x9y362x3y24x0y0，则使 z3x2y 最小的(x，y)是()A(4,5)B(3,6)C(9,2)D(6,4)答案 B 解读 检验法：将A、B、C、D 四选项中x、y 代入 z3x2y 按从小到大依次为A、B、D、C然后按 ABDC 次序代入约束条件中，A 不满足 2x 3y24，B 全部满足，故选 B5已知 x、y 满足约束条件2xy4x 2y4x 0，y0，则 zxy 的最大值是()A43B83C2D4 答案 B 解读 画出可行域为如图阴影部分由x2y42xy4，解得 A(43，43)，当直线 z xy 经过可行域内点A 时，z最大，且zmax83.6(2014 广东理，3)若变量 x，y 满足约束条件yxxy 1y 1，且 z 2xy 的最大值和最小值分别为m 和 n，则 mn()A5B6 C7D8 答案 B 解读 作出可行域如图，文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M105/12 由yx，y 1，得x 1，y 1，A(1，1)；由xy1，y 1.得x2，y 1，B(2，1)；由yx，xy1，得x12，y12.C(12，12)作直线 l：y 2x，平移 l 可知，当直线y 2xz，经过点 A 时，z 取最小值，当ymin 3；当经过点B 时，z 取最大值，zmax3，m3，n 3，mn6.二、填空题7已知 x、y 满足约束条件x 0 x y2xy1，则 z3x2y 的最大值为 _答案 5 解读 作出可行域如图，当直线z3x2y 平移到经过点(1,1)时，z 最大zmax5.8已知 x、y 满足y20 x30 xy10，则 x2y2的最大值为 _答案 25 解读 画出不等式组表示的平面区域，如图中的阴影部分所示由图知，A(3，4)，B(3,2)，C(3,2)，则|OA|9165，|OB|9413，|OC|9413.设 P(x，y)是不等式组表示的平面区域内任意一点，文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M106/12 则 x2y2(x2y2)2|OP|2，由图知，|OP|的最大值是|OA|5，则 x2y2最大值为|OA|225.三、解答题9制造甲、乙两种烟花，甲种烟花每枚含A 药品 3g、B 药品 4g、C 药品 4g，乙种烟花每枚含A 药品 2g、B 药品 11g、C 药品 6g已知每天原料的使用限额为A 药品 120g、B药品 400g、C 药品 240g甲种烟花每枚可获利2 元，乙种烟花每枚可获利1 元，问每天应生产甲、乙两种烟花各多少枚才能获利最大解读 设每天生产甲种烟花x枚，乙种烟花 y 枚，获利为 z元，则3x2y1204x11y4004x6y240 x0y0，作出可行域如图所示目标函数为：z2xy.作直线 l：2xy0，将直线 l 向右上方平移至l1的位置时，直线经过可行域上的点A(40,0)且与原点的距离最大此时z2xy 取最大值故每天应只生产甲种烟花40 枚可获最大利润10某运输公司接受了向抗洪抢险地区每天至少运送180t 支援物资的任务，该公司有8辆载重为6t 的 A 型卡车和4 辆载重为 10t 的 B 型卡车，有 10 名驾驶员，每辆卡车每天往返的次数为 A 型卡车 4 次，B 型卡车 3 次，每辆卡车每天往返的成本费A 型车为 320 元，B 型车为 504 元，请你给该公司调配车辆，使公司所花的成本费最低解读 设每天调出A 型车 x 辆，B 型车 y 辆，公司所花的成本为z 元，则由题意知x8，y4，xy10，4x6 3y10180，x0，y0，目标函数为z320 x504y(其中 x，y N)作出可行域如图文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M107/12 所示由图易知，当直线 z320 x 504y 在可行域内经过的整数点中，点(8,0)使 z320 x504y取得最小值，zmin320850402560，每天调出 A 型车 8 辆，B 型车 0 辆，公司所花成本费最低一、选择题1已知 x、y 满足x2y50 x1y0 x2y30，则yx的最值是()A最大值是2，最小值是1B最大值是1，最小值是0 C最大值是2，最小值是0D有最大值无最小值答案 C 解读 作出不等式组x2y5 0 x1y 0 x 2y30表示的平面区域如图yx表示可行域内点与原点连线的斜率显然在 A(1,2)处取得最大值2.在 x 轴上的线段BC上时取得最小值0，选C2若实数x、y 满足不等式组x2y5 02xy7 0 x0，y0，则 3x4y 的最小值是()A13B15 C20D28 答案 A 解读 作出可行域如图所示，令 z 3x4y，y34xz4文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M108/12 求 z 的最小值，即求直线y34xz4截距的最小值经讨论知点M 为最优解，即为直线 x2y 50 与 2x y70 的交点，解之得 M(3,1)zmin9413.3已知变量x、y 满足约束条件yx10y3x10yx10，则 z2xy 的最大值为()A4B2 C1D 4 答案 B 解读 作出可行域如图，作直线 l0：2x y0，平移直线l0可见，当l0经过可行域内的点B(1,0)时，z 取得最大值，zmax21 02.4为支援灾区人民，某单位要将捐献的100 台电视机运往灾区，现有4 辆甲型货车和8 辆乙型货车可供使用每辆甲型货车运输费用400 元，可装电视机20 台；每辆乙型货车运输费用300 元，可装电视机10 台，若每辆车至多只运一次，则该厂所花的最少运输费用为()A2800 元B2400 元C2200 元D2000 元答案 C 解读 设调用甲型货车x 辆，乙型货车y 辆，则 0 x4,0 y8,20 x10y100，即2x y10，设运输费用为t，则 t400 x300y.线性约束条件为0 x40y82xy10，作出可行域如图，则当直线y43xt300经过可行域内点A(4,2)时，t 取最小值2200，故选 C二、填空题文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 HK2X8Y1O6A5 ZA8S4V5Z3M10文档编码:CX1D5H8Y8L9 H