2018-2019学年青岛版七年级数学下册第14章位置与坐标达标检测卷.pdf

第 10 章达标检测卷（时间：90 分钟满分：100 分）一、选择题1.在平面直角坐标系中，点P的坐标为（-2，a2+1），则点P所在的象限是（）A.第一象限B.第二象限C.第三象限D.第四象限2.与平面直角坐标系中的点具有一一对应关系的是（）A.实数B.有理数C.有序实数对D.有序有理数对3.在坐标平面内，点P（4-2a，a-4）在第三象限则a的取值范围是（）A.a2 B.a4 C.2 a4 D.2a44.已知点A（-1，-3）和点B（3，m），且AB平行于x轴，则点B坐标为（）A.（3，-3）B.（3，3）C.（3，1）D.（3，-1）5.在平面直角坐标系xOy中，已知点P(2，2)，点Q在y轴上，PQO是等腰三角形，则满足条件的点Q共有()A.5个B.4 个C.3 个D.2 个6.如图，点A（2，0），B（0，2），将扇形AOB沿x轴正方向做无滑动的滚动，在滚动过程中点O的对应点依次记为点O1，点O2，点O3，则O10的坐标是（）A.（16+4，0）B.（14+4，2）C.（14+3，2）D.（12+3，0）7.平面直角坐标系中点P（x，-x2-4x-3），则点P所在的象限不可能是（）A.第一象限B.第二象限C.第三象限D.第四象限8.正方形A1B1C1O，A2B2C2C1，A3B3C3C2，按如图所示放置，点A1，A2，A3，和点C1，C2，C3，分别在直线y=kx+b（k0）和x轴上，已知点B1，B2，B3，B4的坐标分别为（1，1）（3，2），（7，4），（15，8），则Bn的坐标是（）A.（2n-1，2n-1）B.（2n，2n-1）C.（2n-1，2n）D.（2n-1-1，2n-1）9.如图，等边OAB的边长为2，则点B的坐标为（）第 1 页，共 10 页A.（1，1）B.（，1）C.（，）D.（1，）10.如图，在33 的正方形网格中由四个格点A，B，C，D，以其中一点为原点，网格线所在直线为坐标轴，建立平面直角坐标系，使其余三个点中存在两个点关于一条坐标轴对称，则原点是（）A.A点B.B点C.C点D.D点二、填空题11.点P（x-2，x+3）在第一象限，则x的取值范围是_ 12.如图，将平行四边形ABCO放置在平面直角坐标系xOy中，O为坐标原点，若点A的坐标是（6，0），点C的坐标是（1，4），则点B的坐标是 _13.在平面直角坐标系中，点P（x，y）经过某种变换后得到点P（-y+1，x+2），我们把点P（-y+1，x+2）叫做点P（x，y）的终结点已知点P1的终结点为P2，点P2的终结点为P3，点P3的终结点为P4，这样依次得到P1、P2、P3、P4、Pn、，若点P1的坐标为（2，0），则点P2017的坐标为 _14.在平面直角坐标系中，将点（-b，-a）称为点（a，b）的“关联点”（例如点（-2，-1）是点（1，2）的“关联点”）如果一个点和它的“关联点”在同一象限内，那么这一点在第_象限15.如图，平面直角坐标系中O是原点，?ABCD的顶点A，C的坐标分别是（8，0），（3，4），点D，E把线段OB三等分，延长CD、CE分别交OA、AB于点F，G，连接FG则下列结论：F是OA的中点；OFD与BEG相似；四边形DEGF的面积是；OD=其中正确的结论是_（填写所有正确结论的序号）第 2 页，共 10 页文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5三、解答题16.已知：P（4x，x-3）在平面直角坐标系中（1）若点P在第三象限的角平分线上，求x的值；（2）若点P在第四象限，且到两坐标轴的距离之和为9，求x的值17.在直角坐标系中，画出三角形AOB，使A、B两点的坐标分别为A（-2，-4），B（-6，-2）试求出三角形AOB的面积18.如图，直角坐标系中，ABC的顶点都在网格点上，其中，C点坐标为（1，2）（1）写出点A、B的坐标：A（_，_）、B（_，_）（2）将ABC先向左平移2 个单位长度，再向上平移1 个单位长度，得到ABC，则ABC的三个顶点坐标分别是A（_，_）、B（_，_）、C（_，_）（3）ABC的面积为 _ 19.若点P（x，y）为坐标平面上的一个点，我们规定P=|x|+|y|，P 为点P（x，y）的标志符则A（-3，2）的标志符为 _；若点M（m+1，m2-4m）的标志符为 M=3，求符合条件的点的坐标20.如图，写出平面直角坐标系中点A，B，C，D，E，F的坐标第 3 页，共 10 页文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 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ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5参考答案1.B2.C3.C4.A5.B6.C7.A8.A9.D10.B11.x 2 12.（7，4）13.（2，0）14.二、四15.16.解：（1）由题意，得4x=x-3，解得x=-1 点P在第三象限的角平分线上时，x=-1（2）由题意，得4x+-（x-3）=9，则 3x=6，解得x=2，此时点P的坐标为（8，-1），当点P在第四象限，且到两坐标轴的距离之和为9 时，x=217.解：三角形的面积是64-4-6-4=10 18.（1）2；-1；4；3；（2）0；0；2；4；-1；3；（3）5.19.5 20.解：点A，B，C，D，E，F的坐标分别为：A（5，2），B（0，4），C（-3，3），D（-5，0），E（-3，-4），F（4，-3）【解析】1.解：a2为非负数，a2+1 为正数，点P的符号为（-，+）点P在第二象限故选：B先判断出点P的纵坐标的符号，再根据各象限内点的符号特征判断点P所在象限即可本题考查了象限内的点的符号特点，注意a2加任意一个正数，结果恒为正数牢记点在各象限内坐标的符号特征是正确解答此类题目的关键第 4 页，共 10 页文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X52.解：有序实数对与平面直角坐标系中的点具有一一对应关系，故选：C根据平面直角坐标系与有序实数对的关系，可得答案本题考查了点的坐标，平面直角坐标系与有序实数对是一一对应关系3.解：点P（4-2a，a-4）在第三象限，解得 2a4故选：C根据第三象限点的坐标特点列出不等式组，再解此不等式组即可本题主要考查了点在第三象限时点的坐标的符号以及解不等式组的问题，牢记四个象限的符号特点分别是：第一象限（+，+）；第二象限（-，+）；第三象限（-，-）；第四象限（+，-）4.解：AB平行于x轴，点A（-1，-3）和点B（3，m），m=-3 点B的坐标为（3，-3）故选项A正确，选项B错误，选项C错误，选项D错误故选：A根据AB平行于x轴，点A（-1，-3）和点B（3，m），可知点A、B的纵坐标相等，从而可以得到点B的坐标本题考查坐标和图形的性质，解题的关键是明确与x轴平行的直线上的所有点的纵坐标都相等5.试题分析：根据题意，画出图形，由等腰三角形的判定找出满足条件的Q点，选择正确答案如上图：满足条件的点Q共有(0，2)(0，2)(0，-2)(0，4)故选B6.解：点A（2，0），B（0，2），OA=2，OB=2，AOB=90，的长度=，将扇形AOB沿x轴正方向做无滑动的滚动，O1O2=的长度=，点O1（2，2），点O2（2+，2），点O3（4+，0），点O4（6+，2），103=31，O10的（14+3，2）故选C由点A（2，0），B（0，2），得到OA=2，OB=2，AOB=90，根据弧长的计算公式得到的长度=，第 5 页，共 10 页文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5得到O1O2=的长度=，于是得到结论本题考查了规律型：点的坐标，主要考查了从滚动中找出规律，根据规律确定坐标对应点是解本题的关键7.解：-x2-4x-3=-（x+2）2+1，当x0 时，-（x+2）2+1-3 0，点P所在象限不可能是第一象限，故选：A由-x2-4x-3=-（x+2）2+1知当x0 时，-（x+2）2+1-3 0，据此可得答案本题主要考查点的坐标，解题的关键是掌握各象限内点的坐标符号特点及配方法的应用8.解：设Bn的坐标为（xn，yn），y1=1，y2=2，y3=4，y4=8，yn=2n-1；1=21-1，3=22-1，7=24-1，15=28-1，xn=2yn-1=2n-1 Bn的坐标为（2n-1，2n-1）故选A设Bn的坐标为（xn，yn），根据点B1，B2，B3，B4坐标的变化找出变化规律“Bn的坐标为（2n-1，2n-1）”，此题得解本题考查了规律型中点的坐标的变化，根据点的坐标的变化找出变化规律是解题的关键9.解：如图所示，过B作BCAO于C，则AOB是等边三角形，OC=AO=1，RtBOC中，BC=，B（1，），故选：D先过B作BCAO于C，则根据等边三角形的性质，即可得到OC以及BC的长，进而得出点B的坐标本题主要考查了等边三角形的性质以及勾股定理的运用，解题的关键是作辅助线构造直角三角形10.解：当以点B为原点时，A（-1，-1），C（1，-1），则点A和点C关于y轴对称，符合条件，故选：B以每个点为原点，确定其余三个点的坐标，找出满足条件的点，得到答案本题考查的是关于x轴、y轴对称的点的坐标和坐标确定位置，掌握平面直角坐标系内点的坐标的确定方法和对称的性质是解题的关键11.解：点P（x-2，x+3）在第一象限，解得：x2故答案为：x2直接利用第一象限点的坐标特征得出x的取值范围即可此题主要考查了点的坐标，正确得出关于x的不等式组是解题关键12.【分析】第 6 页，共 10 页文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5本题考查了平行四边形的性质、坐标与图形性质；熟练掌握平行四边形的性质是解决问题的关键根据平行四边形的性质及A点和C的坐标求出点B的坐标即可【解答】解：四边形ABCO是平行四边形，O为坐标原点，点A的坐标是（6，0），点C的坐标是（1，4），BC=OA=6，6+1=7，点B的坐标是（7，4）；故答案为（7，4）13.【分析】本题考查了学生发现点的规律的能力，本题中找到Pn坐标得规律是解题的关键求得点P2、P3、P4、P5的值，即可发现其中规律，即可解题【解答】解：P1坐标为（2，0），则P2坐标为（1，4），P3坐标为（-3，3），P4坐标为（-2，-1），P5坐标为（2，0），Pn的坐标为（2，0），（1，4），（-3，3），（-2，-1）循环，2017=2016+1=4 504+1，P2017坐标与P1点重合，故答案为（2，0）14.解：若a，b同号，则-b，-a也同号且符号改变，此时点（-b，-a），点（a，b）分别在一三象限，不合题意；若a，b异号，则-b，-a也异号，此时点（-b，-a），点（a，b）都在第二或第四象限，符合题意；故答案为：二、四依据点（-b，-a）称为点（a，b）的“关联点”，一个点和它的“关联点”在同一象限内，可得这两点的坐标中，横坐标与纵坐标异号本题主要考查了点的坐标，解题时注意：第一三象限内点的横坐标纵坐标同号，而第二四象限内点的横坐标纵坐标异号15.解：四边形OABC是平行四边形，BCOA，BC=OA，CDBFDO，D、E为OB的三等分点，=，BC=2OF，OA=2OF，F是OA的中点；所以结论正确；如图 2，延长BC交y轴于H，由C（3，4）知：OH=4，CH=3，OC=5，AB=OC=5，A（8，0），OA=8，OAAB，AOBEBG，第 7 页，共 10 页文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编码:CM6D4J5N8P5 HR7H3X8X6P7 ZI5K5R2F6X5文档编