2022年2018年大连市中考数学试卷 .pdf

2018 年辽宁省大连市中考数学试卷一、选择题（本题共10 小题，每小题3 分，共 30 分，在每小题给出的四个选项中，只有一个选项正确）1（3.00 分）（2018?大连）3 的绝对值是（）A3 B3 C D2（3.00 分）（2018?大连）在平面直角坐标系中，点（3，2）所在的象限是（）A第一象限B第二象限C 第三象限D第四象限3（3.00 分）（2018?大连）计算（x3）2的结果是（）Ax5B2x3C x9Dx64（3.00 分）（2018?大连）如图是用直尺和一个等腰直角三角尺画平行线的示意图，图中 的度数为（）A45B60C 90D1355（3.00 分）（2018?大连）一个几何体的三视图如图所示，则这个几何体是（）A圆柱B圆锥C三棱柱D长方体6（3.00 分）（2018?大连）如图，菱形ABCD中，对角线 AC，BD相交于点 O，若 AB=5，AC=6，则 BD的长是（）A8 B7 C 4 D37（3.00分）（2018?大连）一个不透明的袋子中有三个完全相同的小球，把它们分别标号为 1，2，3，随机摸出一个小球，记下标号后放回，再随机摸出一个小球并记下标号，两次摸出的小球标号的和是偶数的概率是（）ABC D8（3.00 分）（2018?大连）如图，有一张矩形纸片，长10cm，宽 6cm，在它的四角各减去一个同样的小正方形，然后折叠成一个无盖的长方体纸盒若纸盒的底面（图中阴影部分）面积是32cm2，求剪去的小正方形的边长设剪去的小正方形边长是 xcm，根据题意可列方程为（）A10646x=32 B（102x）（62x）=32 C（10 x）（6 x）=32D1064x2=329（3.00 分）（2018?大连）如图，一次函数 y=k1x+b 的图象与反比例函数y=的图象相交于 A（2，3），B（6，1）两点，当 k1x+b时，x 的取值范围为（）Ax2 B2x6 Cx6 D0 x2 或 x610（3.00 分）（2018?大连）如图，将 ABC绕点 B 逆时针旋转 ，得到 EBD，若点 A 恰好在 ED的延长线上，则 CAD的度数为（）文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4文档编码:CT3V8V7X7K4 HA9F5U5X9Y7 ZB4O6G2M7C4A90 BC180 D2二、填空题（本题共6 小题，每小题 3 分，共 18 分）11（3.00分）（2018?大连）因式分解：x2x=12（3.00 分）（2018?大连）五名学生一分钟跳绳的次数分别为189，195，163，184，201，该组数据的中位数是13（3.00 分）（2018?大连）一个扇形的圆心角为120，它所对的弧长为 6cm，则此扇形的半径为cm14（3.00 分）（2018?大连）孙子算经中记载了一道题，大意是：100 匹马恰好拉了 100 片瓦，已知 1 匹大马能拉 3 片瓦，3 匹小马能拉 1 片瓦，问有多少匹大马、多少匹小马？设有x 匹大马，y 匹小马，根据题意可列方程组为15（3.00 分）（2018?大连）如图，小明为了测量校园里旗杆AB 的高度，将测角仪 CD竖直放在距旗杆底部B点 6m 的位置，在 D处测得旗杆顶端 A 的仰角为53，若测角仪的高度是1.5m，则旗杆 AB的高度约为m（精确到 0.1m 参考数据：sin53 0.80，cos53 0.60，tan53 1.33）16（3.00 分）（2018?大连）如图，矩形ABCD中，AB=2，BC=3，点 E为 AD 上一点，且 ABE=30 ，将ABE沿 BE翻折，得到 ABE，连接 CA 并延长，与 AD相交于点 F，则 DF的长为三、解答题（本题共 4 小题，其中 17、18、19 题各 9 分，20 题 12分，共 39 分）17（9.00分）（2018?大连）计算：（+2）2+22文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R418（9.00分）（2018?大连）解不等式组：19（9.00 分）（2018?大连）如图，?ABCD的对角线 AC，BD相交于点 O，点 E、F在 AC上，且 AF=CE 求证：BE=DF 20（12.00 分）（2018?大连）某校为了解学生最喜欢的球类运动情况，随机选取该校部分学生进行调查，要求每名学生只写一类最喜欢的球类运动以下是根据调查结果绘制的统计图表的一部分类别ABCDEF类型足球羽毛球乒乓球篮球排球其他人数10462根据以上信息，解答下列问题：（1）被调查的学生中，最喜欢乒乓球的有人，最喜欢篮球的学生数占被调查总人数的百分比为%；（2）被调查学生的总数为人，其中，最喜欢篮球的有人，最喜欢足球的学生数占被调查总人数的百分比为%；（3）该校共有 450 名学生，根据调查结果，估计该校最喜欢排球的学生数四、解答题（本题共3 小题，其中 21、22 题各 9 分，23 题 10 分，共 28分）21（9.00 分）（2018?大连）甲、乙两名学生练习打字，甲打135 个字所用时间与乙打 180 个字所用时间相同已知甲平均每分钟比乙少打20 个字，求甲平均每分钟打字的个数文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R422（9.00 分）（2018?大连）【观察】149=49，248=96，347=141，2327=621，2426=624，2525=625，2624=624，2723=621，473=141，282=96，491=49【发现】根据你的阅读回答问题：（1）上述内容中，两数相乘，积的最大值为；（2）设参与上述运算的第一个因数为a，第二个因数为b，用等式表示a 与 b的数量关系是【类比】观察下列两数的积：159，258，357，456，mn，564，573，582，591猜想 mn 的最大值为，并用你学过的知识加以证明23（10.00 分）（2018?大连）如图，四边形ABCD内接于 O，BAD=90 ，点 E在 BC的延长线上，且 DEC=BAC（1）求证：DE是O的切线；（2）若 ACDE，当 AB=8，CE=2时，求 AC的长五、解答题（本题共3 小题，其中 24 题 11分，25、26 题各 12 分，共 35 分）24（11.00 分）（2018?大连）如图 1，直线 AB与 x 轴、y 轴分别相交于点A、B，将线段 AB绕点 A 顺时针旋转 90，得到 AC，连接 BC，将ABC沿射线 BA平移，当点 C到达 x 轴时运动停止 设平移距离为 m，平移后的图形在 x 轴下方部分的面积为 S，S关于 m 的函数图象如图 2 所示（其中 0ma，amb 时，函数的解析式不同）（1）填空：ABC的面积为；（2）求直线 AB的解析式；（3）求 S关于 m 的解析式，并写出m 的取值范围文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R425（12.00分）（2018?大连）阅读下面材料：小明遇到这样一个问题：如图 1，ABC中，ACB=90 ，点 D 在 AB上，且BAC=2 DCB，求证：AC=AD 小明发现，除了直接用角度计算的方法外，还可以用下面两种方法：方法 1：如图 2，作 AE平分CAB，与 CD相交于点 E方法 2：如图 3，作 DCF=DCB，与 AB相交于点 F（1）根据阅读材料，任选一种方法，证明AC=AD 用学过的知识或参考小明的方法，解决下面的问题：（2）如图 4，ABC中，点 D 在 AB上，点 E在 BC上，且 BDE=2 ABC，点 F在 BD上，且 AFE=BAC，延长 DC、FE，相交于点 G，且 DGF=BDE 在图中找出与 DEF相等的角，并加以证明；若 AB=kDF，猜想线段 DE与 DB的数量关系，并证明你的猜想26（12.00 分）（2018?大连）如图，点 A，B，C都在抛物线 y=ax22amx+am2+2m5（其中a0）上，ABx 轴，ABC=135 ，且 AB=4（1）填空：抛物线的顶点坐标为（用含 m 的代数式表示）；（2）求 ABC的面积（用含 a 的代数式表示）；（3）若 ABC的面积为 2，当 2m5x2m2 时，y 的最大值为 2，求 m 的值文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 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ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L5 HR6D10S5B5T9 ZD10H2E6H3R4文档编码:CG4Z2V1X2L