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    2021年2020版高考物理新导学浙江选考大一轮精讲讲义:第六章动量守恒定律本章学科素养提升含答案.pdf

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    2021年2020版高考物理新导学浙江选考大一轮精讲讲义:第六章动量守恒定律本章学科素养提升含答案.pdf

    滑块模型可分为两类:单一滑块模型和多个滑块模型单一滑块模型是指一个滑块在水平面、斜面或曲面上运动的问题,主要运用牛顿运动定律、动能定理或动量定理进行分析多个滑块模型是指两个或两个以上的滑块组成的系统,如滑块与滑块、小车与滑块、子弹与滑块等,对于此类问题应着重分析物体的运动过程,明确它们之间的时间、空间关系,并注意临界、隐含和极值等条件,然后用能量守恒和动量守恒等规律求解例 1如图 1 所示,水平地面上有两个静止的小物块a 和 b,其连线与墙垂直;a 和 b 相距 l,b 与墙之间也相距l;a 的质量为m,b 的质量为34m.两物块与地面间的动摩擦因数均相同现使a 以初速度 v0向右滑动此后a 与 b 发生弹性碰撞,但b 没有与墙发生碰撞重力加速度大小为g.求物块与地面间的动摩擦因数满足的条件图 1 答案32v02113gl mgl 即 v022gl设在 a、b 发生弹性碰撞前的瞬间,a 的速度大小为v1.由能量守恒定律得12mv0212mv12mgl 设在 a、b 碰撞后的瞬间,a、b 的速度大小分别为v1、v2,以向右为正方向,由动量守恒和能量守恒有mv1mv134mv212mv1212mv121234mv22联立 式解得|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 1 页,共 7 页v287v1由题意,b没有与墙发生碰撞,由功能关系可知1234mv22 3m4gl联立 式,可得 32v02113gl联立 式得,a 与 b 发生弹性碰撞,但b 没有与墙发生碰撞的条件为32v02113gl v022gl.弹簧模型是指由物体与弹簧组成的系统,此类问题的关键在于分析物体的运动过程,认清弹簧的状态及不同能量之间的转化,由两个或两个以上物体与弹簧组成的系统,应注意弹簧伸长或压缩到最大程度时弹簧两端连接的物体具有相同的速度;弹簧处于自然长度时,弹性势能最小(为零)等隐含条件例 2如图 2 所示,小球A 质量为 m,系在细线的一端,线的另一端固定在O 点,O 点到光滑水平面的距离为h.物块 B 和 C 的质量分别是5m 和 3m,B 与 C 用轻弹簧拴接,置于光滑的水平面上,且 B 物块位于O 点正下方现拉动小球使细线水平伸直,小球由静止释放,运动到最低点时与物块 B 发生正碰(碰撞时间极短),反弹后上升到最高点时到水平面的距离为h16.小球与物块均视为质点,不计空气阻力,重力加速度为g,求碰撞过程B 物块受到的冲量大小及碰后轻弹簧获得的最大弹性势能图 2 答案54m 2gh15128mgh解析设小球运动到最低点与物块B 碰撞前的速度大小为v1,根据机械能守恒定律有:mgh12mv12解得:v12gh设碰撞后小球反弹的速度大小为v1,同理有:mgh1612mv12解得:v12gh4设碰撞后物块B 的速度大小为v2,取水平向右为正方向,由动量守恒定律有:mv1 mv15mv2|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 2 页,共 7 页文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1解得:v22gh4由动量定理可得,碰撞过程B 物块受到的冲量为:I5mv254m2gh碰撞后当B 物块与 C 物块速度相等时轻弹簧的弹性势能最大,据动量守恒定律有5mv28mv3根据机械能守恒定律:Epm125mv2212 8mv32解得:Epm15128mgh.悬绳模型是指由悬绳或通过弧形滑槽将不同的物体连在一起组成的系统此类问题应认清物体的运动过程状态注意物体运动到最高点或最低点时速度相同的隐含条件及系统机械能守恒定律的应用例 3如图 3 所示,在光滑的水平杆上套有一个质量为m 的滑环滑环上通过一根不可伸缩的轻绳悬挂着一个质量为M 的物块(可视为质点),绳长为 L.将滑环固定时,给物块一个水平冲量,物块摆起后刚好碰到水平杆;若滑环不固定时,仍给物块以同样的水平冲量,求物块摆起的最大高度图 3 答案mmML解析滑环固定时,根据机械能守恒定律,有:MgL12Mv02,v02gL.滑环不固定时,物块初速度仍为v0,在物块摆起最大高度h 时,它们速度都为v,在此过程中物块和滑环组成的系统机械能守恒,水平方向动量守恒,则:Mv0(mM)v,12Mv0212(mM)v2Mgh,由以上各式,可得:hmmML.|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 3 页,共 7 页文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 HB4O5N9A5O5 ZR1S1N8S5S1文档编码:CK1T5U4Z6B1 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