2022年2018学年高中物理人教版必修2习题：第五章曲线运动第2节平抛运动2Word版含答案 .pdf

名师精编优秀教案第 2 节平抛运动（满分 100 分，60 分钟完成）班级 _姓名 _ 第卷(选择题共 48 分)一、选择题：本大题共6 小题，每小题8 分，共 48 分。在每小题给出的四个选项中，至少有一个选项正确，选对的得8 分，对而不全得4 分。选错或不选的得0 分。1如图 1 所示，以9.8 m/s的初速度水平抛出的物体，飞行一段时间后，垂直地撞在倾角为30的斜面上，则物体完成这段飞行的时间是（）图 1 A33s B332s C3s D2 s 2如图 2 所示，为物体做平抛运动的xy图象，此曲线上任意一点P（x，y）的速度方向的反向延长线交于x轴上的A点，则A点的横坐标为（）A0.6 x B0.5 x C0.3 x D无法确定3如图 3 所示，在光滑的水平面上有一小球a以初速度v0运动，同时刻在它的正上方有小球b也以初速度v0水平抛出，并落于c点，则（）图 3 A小球a先到达c点B小球b先到达c点C两球同时到达c点D不能确定4火车以1 m/s2的加速度在轨道上加速行驶，车厢中一乘客把手伸到窗外，从距地面2.5 m高处自由释放一物体，不计空气阻力，则物体落地时与乘客的水平距离（g10 m/s2）（）P(x,y)xAy0图 2 名师精编优秀教案A0 B0.50 m C0.25 m D因不知火车速度，故无法判断5在高度为h的同一位置向水平方向同时抛出两个小球A和B，若A球的初速度vA大于B球的初速度vB，则下列说法中正确的是（）AA球比B球先落地B在飞行过程中的任一段时间内，A球的水平位移总是大于B球的水平位移C若两球在飞行中遇到一堵墙，A球击中墙的高度大于B球击中墙的高度D在空中飞行的任意时刻，A球的速率总是大于B球的速率6如图 4 所示，从一根空心竖直钢管A的上端边缘，沿直径方向向管内水平抛入一钢球，球与管壁多次相碰后落地（球与管壁相碰时间不计），若换一根等高但较粗的钢管B，用同样的方法抛入此钢球，则运动时间（）图 4 A在A管中的球运动时间长 B在B管中的球运动时间长C在两管中的运动时间一样长 D无法确定第卷（非选择题，共52 分）二、填空、实验题：本大题共3 小题，每小题8 分，共 24 分。把正确答案填写在题中横线上或按要求作答。7某一物体以一定的初速度水平抛出，在某1s 内其速度与水平方向成37变成 53，则此物体初速度大小是_m/s，此物体在这1s 内下落的高度是_m（g取 10 m/s2）8如图 5 所示，A、B是两块竖直放置的薄纸片，子弹m以水平初速度穿过A后再穿过B，在两块纸片上穿的两个洞高度差为h，A、B间距离为l，则子弹的初速度是_。文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3文档编码:CK1Q3B9B5Y4 HL1V8N9N6B10 ZR4T2E2B9A3名师精编优秀教案图 5 9A、B两物体距地面高度均为10 m，它们在同一水平线上相距33.6 m，现将两物体以相同大小的初速度21 m/s 相向水平方向抛出，它们在空中相遇，相遇时离地面的高度为_m。三、计算题：本大题共2 小题，计28 分。解答应写出必要的文字说明、方程式和重要演算步骤。只写出最后答案的不能得分。有数值计算的题，答案中必须明确写出数值和单位。10（12 分）如图6 所示，排球场总长为18m，设球网高为2m，运动员站在离网3m的线上（图中虚线所示）正对网前跳起将球水平击出，球在飞行过程中所受空气附阻力不计。（1）设击球点在3m线的正上方高度为2.5m，试求击球速度在什么范围内才能使球既不触网也不越界。（2）若击球点在3m线的正上方的高度小于某个值时，则无论水平击球的速度多大，球不是触网就是越界，试求这个高度。（210/gm s）11（16 分）如图 7 所示，物体分别由A、B点水平抛出，OBh，AB3h时，水平射程之比为3221ss。若保持AB3h不变，平抛初速度亦不变，欲使两水平射程相等，则AB应上移还是下移？移动多少？x y OssAB3hh1 2图 7 3m 18m 图 6 文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 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ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5名师精编优秀教案参考答案一、选择题：1【答案】C【点拨】将速度v分解为水平方向的vx。则vxv09.8 m/s，竖直方向为vy，则vyvxcot30o，而vygt，所以gt3vx39.8，所以t3s。2【答案】B【点拨】如下图所示，速度矢量三角形与APx相似，对应边成比例：yvv0yOAx；因为y21gt2，vygt，则：2021gtOAxvvy，得20tvxOA；又因为xv0t，t0vx，所以OA2x。3【答案】C【点拨】b小球的水平分运动为匀速直线运动且速度为v0，a球也是沿水平方向做匀速直线运动，它们同时以相同的水平速度从同一竖直线上开始运动，必然同时到达c点，C正确。4【答案】C【点拨】以乘客为参考系，小球在竖直方向做自由落体运动，水平方向做初速为零，加速度为 1 m/s2的匀加速运动，由h21gt2，所以tgh2，21120.2522hxatamg。5【答案】BCD【点拨】平抛物体的落地时间由高度决定，因高度相同，两球同时落地，故A错；水平位移等于v0t，时间相同，初速度大的水平位移大，故B正确；又因为经过同样的水平位移，初文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5名师精编优秀教案速度大的时间短，下落高度小，故C 正确；在空中飞行任意时刻，v220)(gtv，v0Av0B，所以vAvB，D正确。6【答案】C【点拨】小球做平抛运动，平抛运动可分解为水平方向的匀速运动和竖直方向的自由落体运动，球跟管壁碰撞中受水平方向弹力作用，只改变水平方向速度大小，而竖直方向始终仅受重力作用，保持自由落体运动，由公式h21gt2，得tgh2，因A、B管等高，故t相同。二、填空、实验题：7【答案】17.1；17.9【点拨】物体在竖直方向的速度大小分别为gt及g（t+1），所以gtv0tan37，g（t 1）v0tan53解方程组得：t79s，v017.1m/s。物体在这1 s 内下落的高度2211(1)22hg tgt17.9m。8【答案】lhg2【点拨】由竖直分运动得h21gt2，tgh2，由水平分运动得lv0t，v0ltlhg2。9【答案】6.8【点拨】物体相遇所经历的时间为t，则：因为xv0t+v0t2v0t，所以t2126.3320vx0.8 s。物体相遇时离地面的高度为：hH21gt21021100.826.8 m。三、计算题：10【答案】（1）3 10m/sv12 2m/s；（2）2.13m【解析】（1）如图所示，球擦网而过时，设击球速度为v1，根据平抛运动的规律有：v0 6m 3m hH文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5名师精编优秀教案2112Hhgt，11 1sv t解得：13 10vm/s。球恰好落在边界线时，设击球速度为v2，根据平抛运动的规律有：2212Hgt，22 2sv t解得：212 2vm/s。所以，球既不触网也不越界的速度范围是：3 10m/sv12 2m/s；（2）当球刚好触网又压底线时，设此时击球的高度为h，击球速度为0v，球刚好触网时有：2312hhgt，0 33v t球刚好压底线时有2412hgt，0 439v t消去v0，代入数值解得：3215hm 2.13m。即击球高度小于2.13m 时，无论水平击球的速度多大，球不是触网就是越界。11【答案】下移58h【解析】题目中要求“两水平射程相等”，当两图线的交点正好位于地面上时，则两物体的水平射程相等。根据平抛运动规律可知，两物体初速度分别为：ghsv42101、ghsv2202。设AB下移的距离为x，根据移动后两物体的水平位移相等列方程：v01 t1 v02 t2代入数据得到：文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5名师精编优秀教案ghs421ghsgxh2)4(22gxh)(2解得：hx85。文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 ZZ4J3A5P4V5文档编码:CW10D4K7Z7M3 HA2K4C10V6W10 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