各地市高考数学联考试题分类汇编三角函数.pdf
学习好资料欢迎下载天津市各地市 20XX年高考数学最新联考试题分类汇编（5）三角函数一、选择题:6.（天津市十二区县重点中学20XX年高三毕业班联考一理）在 钝角 ABC中，已知 AB=3，AC=1，B=30，则 ABC的面积是（）A23B43C23D436.(天津市六校20XX 届高三第二次联考文)若把函数sinyx图象向左平移3个单位，则与函数cosyx的图象重合，则的值可能是A13 B32 C23 D12【答案】B(2)（天津市和平区20XX 届高三第二学期第一次质量调查文）若f(x)a sin xb(a，b为常数)的最大值是3，最小值是-5，则ab的值为(A)、-4 (B)、4或-4(C)、14（D）、14【答案】B 1（天津市新华中学20XX届高三第一次月考文）若角600的终边上有一点a,4，则a的值是（）A.34B.34C.34D.3【答案】B 精品资料-欢迎下载-欢迎下载 名师归纳-第 1 页，共 9 页 -学习好资料欢迎下载【解析】因为000600360240为第三象限，所以0a，00tan600tan240tan6034a，所以4 3a，选 B.2（天津市新华中学20XX届高三第一次月考文）下图是函数RxxAysin在区间65,6上的图象，为了得到这个函数的图象，只要将Rxxysin的图象上所有的点（）A.向左平移3个单位长度，再把所得各点的横坐标缩短到原来的21倍，纵坐标不变B.向左平移3个单位长度，再把所得各点的横坐标伸长到原来的2 倍，纵坐标不变C.向左平移6个单位长度，再把所得各点的横坐标缩短到原来的21倍，纵坐标不变D.向左平移6个单位长度，再把所得各点的横坐标伸长到原来的2 倍，纵坐标不变【答案】A【解析】由图象知1A，5()66T，又2T，所以2，所以函数为sin(2)yx，当3x时，23，解得3，所以函数为sin(2)3yx所以要得到函数sin(2)3yx，则只要sinyx先向左平移3单位，然后再把所得各点的横坐标缩短到原来的21倍，纵坐标不变，选A.3（天 津 市 新 华 中 学20XX届 高 三 第 二 次 月 考 文）ABC中，若2lgsinlglglgBca且)2,0(B，则ABC的形状是A.等边三角形 B.等腰三角形 C.等腰直角三角形 D.直角三角形精品资料-欢迎下载-欢迎下载 名师归纳-第 2 页，共 9 页 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ZH2Z8B9A7J5学习好资料欢迎下载6.（天 津 市 南 开 中 学20XX届 高 三 第 四 次 月 考 理）为 了 得 到 函 数xxxy2cos21cossin3的图象，只需将函数xy2sin的图象（）A.向左平移12个长度单位B.向右平移12个长度单位C.向左平移6个长度单位D.向右平移6个长度单位【答案】A 6.（天津市 20XX年滨海新区五所重点学校高三毕业班联考理）在ABC中，内角,A B C所对 的 边 分 别 为,a b c，其 中120,1Ab，且ABC面 积 为3,则sinsinabAB()A.21 B.2 393 C.221 D.2 7【答 案】D01sin12032ABCSbc，即13322c，所 以4c，所 以22202cos12021abcbc，所 以21a。因 为2s i ns i nabRAB，所 以2122 7sin32aRA，所以2(sinsin)22 7sinsinsinsinabRABRABAB,选 D.二、填空题:(13)（天津市和平区20XX届高三第二学期第一次质量调查文）在ABC中，角 A，B，C所对的 边分别是 a，b，c，若 bcosC+ccosB=3acosB，则 cosB 的值为精品资料-欢迎下载-欢迎下载 名师归纳-第 3 页，共 9 页 -文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 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ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5学习好资料欢迎下载三、解答题:15（天津市十二区县重点中学20XX年高三毕业班联考一理）（本小题满分13 分）设函数22()(sincos)2cos(0)f xxxx的最小正周期为23（）求的值；（）求fx在区间-63，上的值域；（）若函 数()yg x的图像是 由()yf x的图像向右平移2个单位长度得到，求()yg x的单调增区间解：（）22=sin+cos+2cosfxxxx22=sin+cos+sin 2+1+cos 2xxxx 2 分sin 2cos222 sin(2)24xxx 4 分依题意得2223，故的值为32.5 分（）因为-,63x所以5-3+444x，6 分-12 sin 3+24x 8 分12+2fx，即fx的值域为1,2+2 9 分（）依题意得:5()2 sin 3()22 sin(3)2244g xxx11 分由5232()242kxkkZ 12 分精品资料-欢迎下载-欢迎下载 名师归纳-第 5 页，共 9 页 -文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5学习好资料欢迎下载解得227()34312kxkkZ故()yg x的单调增区间为:227,()34 312kkkZ 13 分16（天津市十二区县重点中学20XX年高三毕业班联考一文）（本小题满分13 分）已知函数2()2 3sincos2cos1f xxxx（）求函数)(xf的最小正周期及单调递增区间；（）在ABC中，若()22Af,1b，2c，求a的值.（）22Af(),则2sin()26Asin()16A 9 分22,2,623AkAkkZ 10 分又20,3AA11 分2222cos7abcbcA 12 分7a13 分15（天 津 市 新 华 中 学20XX届 高 三第 二 次月 考 文）已知 函 数)0)(2sin(21coscossin2sin21)(2xxxf，其图象过点)21,6(；（1）求的值；精品资料-欢迎下载-欢迎下载 名师归纳-第 6 页，共 9 页 -文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 HV9H1P3J8N4 ZH2Z8B9A7J5文档编码:CJ1B4M5M6C10 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分)ABC中，已知45A，4cos5B.（）求sinC的值；（2）若10,BCD为AB的中点，求AB、CD的长.16.（1）三角 形中,54cosB,所以 B锐角53sin B-3分所以1027sincoscossin)sin(sinBABABAC-6分(2)三角形 ABC中，由
