合肥工业大学工程力学练习册答案1—4章.pdf
理论力学习题册解答1 第一篇静力学一、受力图1 1 下列习题中假定接触处都是光滑的，物体的重量除图上注明者外均略去不计。画出下列指定物体的受力图。O G R N D(a)杆 AB B A NB A C P B T NA(b)杆 ABA C B P(d)杆 AC,杆 AB,销 CA C B C FAC FCA FBC FCB C FCB P FCA q A D C(c)杆 ABB YA A D q XA SCD B(e)杆 AC,杆 BC,销 CA D B C E A E C P XA YA FDE XC YC XCYC P FCB FCBFEDRB B C C D 理论力学习题册解答2 A C O E B D Q(a)AB,CDD Q E C RE SC XA A YA REE B YB XB XB YB XO YO 1 2 出下列各物系中指定物体的受力图。未画重力的物体重量均不计。C A B D P(c)AC,BDFC FA C A P D C FC B FB FBFAA C B D E Q F G A B FB FA(d)AB,BCD,DEFB C D FBFD RC D E Q FDRE FARCREFG FF文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5理论力学习题册解答3 A C B D 30 30 FAB FCB P T P 二、平面汇交力系2 1 五个力作用于一点，如图所示图中方格的边长为 1cm，求力系的合力。解 由解析法有NXRX3.549cos800cos750450cos500cos10004321NYRY8.382sin800sin750sin500sin00014321所以合力R 大小为：NRRRYX5.66922R 方向为：2534XYRRarctg2 2 物体重 P=20KN，用绳子挂在支架的滑轮B 上，绳子的另一端接在绞车D 上，如图所示，转动绞车物体便能升起。设滑轮的大小及其中的摩擦略去不计，A、B、C 三处均为铰链连接。当物体处于平衡态时，试求拉杆AB 和支杆 CB 所受的力。解 取滑轮 B 为研究对象,受力如图所示,列平衡方程：030sin30cos:0TFFXCBAB030cos30sin:0TPFYCBPT联立上述方程可解得：（压）拉）;64.74(;64.54KNFKNFCBAB500N x y 1000N 800N 750N 450N 4 123文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5理论力学习题册解答4 2 3 构件的支撑及荷载情况如图，求支座A、B 的约束反力。解(a)AB 梁受力如图：(b)构件受力如图：02415,0ABRmAi045sin,0PalRmAi解得：KNRRBA5.1解得：;2PaRRBA2 4 四连杆机构OABO1，在图示位置平衡，已知OA=40cm，O1B=60cm，作用在曲柄 OA 上的力偶矩大小为m2=1NM,不计杆重,求力偶矩m1的大小及连杆AB 所受的力。解 AB 为二力杆，受力如图：以 AO1杆为对象，030sin:02mOAFmAi可解得：;5NFA即;5NFBBO1杆受力如图,0:011mBOFmBi解得：m1=3 Nm24KNm RB 15KNm 6m B A RA B P PL RA RB 45 a A m2 O1 B O 30 m1 m2 O1 m1 FA A B FB A FA O FB B NO NO1 文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5第六章空间力系三、平面任意力系3 1 简明回答下列问题；试用力系向已知点简化的方法说明图所示的力F 和力偶(F1，F2)对于轮的作用有何不同？在轮轴支撑A 和 B 处的约束反力有何不同？设F1=F2=F/2，轮的半径为r。答：考虑约束，则力和力偶对轮的作用相同；而A 处的约束反力大小等于F，B 处的约束反力大小等于0。怎样判定静定和静不定问题？图中所示的六种情况那些是静定问题，那些是静不定问题？为什么？静定问题：(c)、(e)静不定问题：(a)、(b)、(d)、(f)P P P(a)(b)(c)B A B A B A F F F(d)(e)(f)B A F F1F2 A F M=Fr B M=Fr RA 文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5第六章空间力系10cm 20cm 1 1 1 2 P3 P2 3 1 P1 y x 3 2 图示平面力系，其中P1=150N，P2=200N，P3=300N，。力偶的臂等于8cm，力偶的力F=200N。试将平面力系向O点简化，并求力系合力的大小及其与原点O的距离d。解 NXXXXRX6.4373005220010115022321NYYYYRY6.1613005120010315022321合力R大小为：NRRRYX5.466)6.161()6.437(2222方向：3.2037.0arctgRRarctgXY合力偶矩大小为：NmFMMOO44.2108.02002.0513001.022150)(与原点距离为：cmRMdO96.453 3 求下列各图中平行分布力系的合力和对于A点之矩。解(a)对A点之矩为:(b)对A点之矩为:(c)对A点之矩为：22121qaaqaMA2313221qLLqLMA2211221)2(61)(3121LqqLqqLqMAL A q a(a)q L(b)A B q1 q2 A B L(c)文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5第六章空间力系3 4 求下列各梁和刚架的支座反力，长度单位为m。解(a)AB梁受力如图(a)所示：045cos2:0AXX045sin2:0BANYY0645sin245.1:0BANM联立方程组可解得：;KN50.2;KN09.1;KN41.1BAANYX(b)AB 梁受力如图(b)所示:0:0AXX031212:0BANYY013121212:0BANM解得：;KN25.0;KN75.3;KN0BAANYX(C)AC 梁受力如图(c)所示:0:0AXX0534:0AYY05.13435:0AAMM由上述方程可解得：;KNm33;KN17;KN0AAAMYX3 5 重物悬挂如图，已知G=1.8KN，其它重量不计，求铰链A 的约束反力和杆BC 所受的力。解 整体受力如图：F=G 60cm 10cm F G A B YA XA r 45TBC D 20cm YA 1.5KNm 2KN 45XA NBA B 4cm 2cm(a)4KN/m 5KN C 3m A YAXA MA 4m(C)2KN 1KN/m A YA XA NB B(b)1m 2m 1m 文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10Y1W9N8Q1 ZX5T7O10T7B5文档编码:CH9I8H2B1Z10 HK10
