2022年10月浙江省普通高中学业水平考试 .pdf
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2022年10月浙江省普通高中学业水平考试 .pdf
vip 会员免费20XX 年 10 月浙江省普通高中学业水平考试数学试题一、选择题(本大题共18 小题,每小题3 分,共 54 分。每小题列出的四个备选项中只有一个是符合题目要求的,不选、多选、错选均不得分)1、已知集合A=1,2,3,B=1,3,4,则 AB=()A.1,3 B.1,2,3 C.1,3,4 D.1,2,3,4 2、已知向量a=(4,3),则|a|=()A.3 B.4 C.5 D.7 3、设为锐角,sin=13,则 cos=()A.23B.23C.63D.2 234、log214=()A.2 B.12C.12D.2 5、下列函数中,最小正周期为的是()A.y=sinx B.y=cosx C.y=tanx D.y=sin2x6、函数 y=121xx的定义域是()A.(1,2 B.1,2 C.(1,2)D.1,2)7、点(0,0)到直线 x+y 1=0 的距离是()A.22B.32C.1 D.2vip 会员免费8、设不等式0,240,xyxy所表示的平面区域为M,则点(1,0),(3,2),(1,1)中在 M 内的个数为()A.0 B.1 C.2 D.3 9、函数 f(x)=xln|x|的图象可能是()10、若直线l 不平行于平面,且 l,则()A.内的所有直线与l 异面B.内只存在有限条直线与l 共面C.内存在唯一直线与l 平行D.内存在无数条直线与l 相交11、图(1)是棱长为1 的正方体ABCD A1B1C1D1截去三棱锥A1AB1D1后的几何体,将其绕着棱DD1逆时针旋转45,得到如图(2)的几何体的正视图为()12、过圆 x2+y22x8=0 的圆心,且与直线x+2y=0 垂直的直线方程是()A.2xy+2=0 B.x+2y 1=0 C.2x+y2=0 D.2xy2=0 13、已知 a,b 是实数,则“|a|1 且|b|1”是“a2+b2bc)的一个零点。若存在实数x0,使得 f(x0)0,则 f(x)的另一个零点可能是()A.x03 B.x012C.x0+32D.x0+2 18、等腰直角ABC 斜边 CB 上的一点P满足 CP14CB,将 CAP 沿 AP 翻折至 C AP,使二面角 C APB 为 60,记直线CA,CB,CP与平面 APB 所成角分别为,则()A.B.C.D.二、填空题(本大题共4 小题,每空3 分,共 15 分)19、设数列 an 的前 n 项和为 Sn,若 an=2n1,nN*,则 a1=,S3=20、双曲线221916yx的渐近线方程是21、若不等式|2xa|+|x+1|1的解集为R,则实数a 的取值范围是22、正四面体A BCD 的棱长为2,空间动点P 满足|PBPC=2,则AP AD的取值范围是文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9vip 会员免费三、解答题(本大题共3 小题,共31 分)23、(本题 10 分)在 ABC 中,内角 A,B,C 所对的边分别为a,b,c。已知 cosA=12.(1)求角 A 的大小;(2)若 b=2,c=3,求 a 的值;(3)求 2sinB+cos(6+B)的最大值。24、(本题 10 分)如图,抛物线 x2=y 与直线 y=1 交于 M,N 两点。Q 为该抛物线上异于M,N 的任意一点,直线MQ 与 x 轴、y 轴分别交于点A,B,直线 NQ 与 x 轴、y 轴分别交于点 C,D。(1)求 M,N 两点的坐标;(2)证明:B,D 两点关于原点O 对称;(3)设 QBD,QCA 的面积分别为S1,S2,若点 Q 在直线 y=1 的下方,求S2S1 的最小值。文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9vip 会员免费25、(本题 11 分)已知函数g(x)=t 2x+13x+1,h(x)=t 2x3x,其中 x,tR.(1)求 g(2)h(2)的值(用 t 表示);(2)定义 1,+)上的函数f(x)如下:f(x)=(),21,2),(),2,21)g x xkkh x xkk(kN*).若 f(x)在1,m)上是减函数,当实数m 取最大值时,求t 的取值范围。文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9vip 会员免费文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 ZQ6U6Q8A2N9文档编码:CU1L3H9B4E8 HL1O10K3H4Q7 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