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    2022年《复变函数与积分变换A》期末考试题A-A参考答案 .pdf

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    2022年《复变函数与积分变换A》期末考试题A-A参考答案 .pdf

    北京交通大学2008-2009 学年第一学期复变函数与积分变换B期末考试试卷A 学院_ 专业_ 班级 _ 学号_ 姓名_ 题号一二三四五六七八九十11 12 总分得分阅卷人一填空题(本题满分 16 分,每空 1 分),请将合适的答案填在空中.1 复 数iiiz2)52)(43(,则)Re(z-27;)Im(z-13;|z2925;)arg(z26arctan()7;复数 z的三角表达式为529(cos(arg()sin(arg()2ziz指数表达式为a r g()5292ize.2612622cossin,0,1,2,3,4,566kikkeik3ii(2)2kekZ4.)1(Ln(21)kikZ5函数zarg在复平面上的连续性为除去原点和负实轴上的点外都连续。6幂级数12nnnnz的收敛半径为 _2_.7映射zew将带形域2)Im(0z映照成除去正实轴(包含原点)的全平面.8幂函数3zw,把角形域6)arg(0z映照为 w平面的 第一象限.90,Re1zes1.10变换52zw在iz1的旋转角为4,伸缩率为2 2二判断下列命题的真假(本题满分 10 分,每道小题 1 分),对的填“”,错的填“”.1zikzee2.()2当 z 为复数时,1|sin|z仍然成立.()30z是zzf1sin1)(的孤立奇.()4如果)(0zf存在,则)(zf在0z 解析.()5 解 析 函 数 一 定 是 调 和 函 数,但 调 和 函 数 不 一 定 是 解 析 函 数()6当 C 是一条不通过原点的简单闭曲线时,积分Cdzz01.()7每一个幂级数的和函数在收敛圆内可能有奇点.()8LnzLnz22.()9如 果 幂 级 数0)2(nnnzc在0z收 敛,则 在3z也 收 敛.()10映射2zw在 z 平面上每一点都具有伸缩率和旋转角的不变性.()文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2三(本题满分 6 分)讨论函数)Re()(zzzf的连续性、可导性、解析性.解:22,()(),2,0,0,0,()Re()0zxiyf zxiy xxixyuxvxyuuxxyvvyxxyuvuvxyxyyxf zzzz设则又设则时,在复平面内连续,在可导,但在复平面内任一点都不解析。四(本题满分 6 分)将函数11zz在10z展成泰勒级数,并求出泰勒级数的收敛半径.解:111222122zzzzzzzzzz11(1)()111 11 111设即1时,2 分22312112221222nnnnnzzzzzzzzz-1-1-1z-1=(-1)-1-1-1-1=(-1)-2 分收敛半径2R2 分文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2五(本题满分 8 分)在扩充复平面上找出函数442)(sin)2)(1()(zzzzf的孤立奇点并加以分类,若是极点,指出其级数.解:4sincos0,1,2,0,1,2,sinsin112zzzzzzf z在都不为零是的一级零点,从而是的四级零点,这些点中除去,外都是的四级极点。3 分24242422242404111132,122limlimlim1sinsin1lim21sin3zzzzzzzfzzzzzfzzzz又是的 级极点,至于因为42641221121,sin111;122,2112010nnnzfzzfnnznznfnnfzfz是的可去奇点关于因为可知=0,使分母为零,当时,=1,即当时,即这两点上面已讨论过,当时,为的极点,当时,不是的孤立奇点,即不是的孤立奇点。5 分文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2六(本题满分 18分)1分别沿xy与2xy计算积分idziyx2202)((6 分);解:(1)沿xy,原式iiiixixiixxdixx238142381|23120232023 分(2)沿2xy原式iidxixxidxxiixixxdixx83812121120322022220223 分2 计算积分Cndzzz10)(1,其中C为包含0z 的任意一条正向简单闭曲线,n为整数.(6 分);解:根据闭路变形原理,原式0,00,21010nnidzzzrzzn3已知调和函数yxu)1(2,求解析函数ivuzf)(,且if)2(.(6 分)解:yxuxyu2,12,由RC条件2212xxyuxV。2 分设yxxV22,则CyyyxuyyV22,2分所 以CyxxV222,Cyxxyxzf22212,有 已 知if 2,则izfyx,0,2,iCiCf0442,所 以iyxxyxzf21222 分文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2七(本题满分6 分)将函数)2()1(1)(zzzf分别在圆环1|1|0z与|2|1z内展成洛朗级数.解:(1)在110z,内2111211111111111111111111111nnnnzzzzzzzzzzzzf3 分(2)在21z内nnzzzzzzzzzf21121211212111211212112223 分八(本题满分 6 分)计算dzzzzz3|34215)2)(1(.解:原式=0,11Re2,Re22,Re,Re,Re,Re,Re224321zzfsizfsizfszzfszzfszzfszzfsi4 分因为10,11Re2zzfs。所以原式2 i2 分文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2九(本题满分 6 分)计算)0(,sin1022ada.解:原式012212220202,Re21122221121cos1222cos2121zzfsizazdziizdzzzaxadxxadzz令4 分其中1212220aaaz,所以原式=11412222aaaaii2 分十(本题满分 6 分)计算)0,0(,cos022amdxxamx解:原式aeaieiaizaesidxxaedxxamxamammixmix222Re21,Re2Re21Re21cos21222222十一.(本题满分 6 分)讨论在映射izw2下,以1,1,321zziz为顶点的三角形被映成什么图形.解:因为izeizw222为旋转变换(旋转角为2)且02iw,2分所以它将1,1,321zziz为顶点的三角形映射为以iwiww2,2,2321为文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9T7 HP4G7Z7I1G10 ZN1P7H3S6J2文档编码:CL3F2N6B9

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