2022年2020届中考化学必备知识点归纳复习资料19 .pdf
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2022年2020届中考化学必备知识点归纳复习资料19 .pdf
一、复习内容和要求1化学计算的常用方法(1)守恒法:包括原子个数守恒、得失电子守恒、电荷守恒法、质量守恒法等。(2)极值法:从问题的极端去思考、去推理、判断,使问题得到解决。(3)讨论法:当题中含有不确定的因素时,对每一种可能情况进行的讨论。(4)十字交叉法:已知混合中某一量的平均值,求混合物中两物质的质量比。(5)差量法:运用前后量的差,根据方程式中的计量数的关系直接求解。2化学计算的常用技巧(1)定量问题定性化;(2)近似估算;(3)运用整体思维,化繁为简;(4)利用图象解题等等。二、解题方法和技巧:1守恒法:例 1、由 Mg(OH)2和 MgO 组成的混合物,测得其中含镁元素的质量分数为 48。取该混合物10g,将其投入 110g的稀硫酸中恰好完全反应,所得溶液中溶质的质量分数为()A 12B24C20D30解析:根据在化学反应中Mg 元素的质量守恒,建立Mg 元素和MgSO4的质量关系可求得反应后所得溶液中的溶质MgSO4的质量,即可求得所得溶液中溶质的质量分数。Mg MgSO424 120 10g48%=4.8g x 2平均值法例 1锌、铁、镁三种金属中的两种混合物13 g,与足量的盐酸反应产生的氢气在标准状况下为1g,则混合物中一定含有的金属是。(A)锌(B)铁 (C)镁(D)无法推断解析:根据锌、铁、镁三种金属与足量的盐酸反应,均生成二价金属阳离子得:(R 为金属,设平均式量M)R+2HCl=RCl2+H2M 2g 13 1g M:13=2:1 M=26 则必须有相对原子质量大于26 和小于 26 的金属存在,又因为锌、铁的相对原子质量均大于26,只有镁的相对原子质量小于26,故答案为 C。2十字交叉法例 2.用向下排气法在容积为V mL 的集气瓶中收集氨气,由于空气尚未排净,最后瓶内气体的平均式量为19,将此盛满气体的集气瓶倒置于水中,瓶内水马上升到一定高度后,即停止上升,则在同温同压下,瓶内剩余气体的体积 为()A.V/4 mL B.V/5 mL C.V/6 mL.D.无法判断解析:用十字交叉法计算氨气与空气的体积比:所以氨气占 5/6,空气占 1/6;由于氨气易溶于水,故剩余气体为空气。3极值法例 4.取 5.4 g由某碱金属 R 及其氧化物 R2O 组成的混合物。该混合物与足量的水反应。反应完毕,蒸发反应后得到的溶液,得到8 g无水晶体。试通过计算,判断该金属是哪一种碱金属?解析:(i)设 5.4 克混合物都是碱金属R,则由(ii)设 5.4 g 混合物都是碱金属 R 的氧化物 R2O,则由综(i)和(ii)所述,碱金属R 的式量 k 的范围为(10.7,35.3)。在碱金属中,只有金属Na 的式量 23 在(10.7,35.3)中,所以该碱金属是金属钠。4、差量法例 3.把 22.4g 铁片投入到 500gCuSO4溶液中,充分反应后取出铁片,洗涤、干燥后称其质量为22.8g,计算(1)析出多少克铜?(2)反应后溶液的质量分数多大?解析:“充分反应”是指 CuSO4中 Cu2+完全反应,反应后的溶液为FeSO4溶液。分析下面的化学方程式可知:每溶解56gFe,就析出 64g 铜,使铁片质量增加 8g(64-56=8),反过来看:若铁片质量增加8g,就意味文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9着溶解 56gFe、生成 64gCu,即“差量”8 与方程式中各物质的质量(也可是物质的量)成正比。所以就可以根据题中所给的已知“差量”22.8-22.4=0.4g 求出其他有关物质的量。5、讨论法:例 4、将 5g 某物质完全溶解在95g 水中,所得溶液中溶质的质量分数为()A、等于 5%B、小于 5%C、大于 5%D、无法确定解析:对于 5g 某物质要进行讨论:这5 g 某物质若是 CaO、Na2O或 SO2等物质,则溶于水后其溶质质量分数会大于5%;这 5g 某物质若是 CuSO45H2O 等物质溶于水后其溶质质量分数则会小于5%;若是 NaCl 等物质,则其溶质质量分数等于5%。三、习题精练:1某硫酸钠溶液中,Na+与 H2O 分子个数比为 1:50 时,此溶液中硫酸钠质量分数为()A、32.4%B、1.96%C、7.3%D、88.75%2用 60%酒精溶液甲与 25%酒精溶液乙混合,配制成45%酒精,所3用甲、乙溶液的质量比为()A、12 B、23 C、43 D、31 3要使 50g 某物质溶液含水量由98%增加到 99%,应加水()A、1g B、5g C、50g D、100g 4海水中 Na+的质量分数为 1.42%,如全部以 NaCl 计算,则海水中NaCl 的质量分数为()A、3.61%B、39.3%C、14.2%D、55.81%6.现有铁,锌,镁,铝四种金属分别与足量稀硫酸反应,生成氢气质量相等时,消耗金属质量最小的是:()A铁B.锌C.镁D.铝7.质量相同的一氧化碳,甲烷和酒精分别燃烧,消耗氧气最多的是:()A.一氧化碳B.甲烷C.酒精D.无法判断8.一定质量的 Fe2O3分别被 CO、C 和 H2三种还原剂完全还原成铁,所生成的纯铁的质文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9量是:()A.一样多B.CO 多C.C 多D.H2多9.两份质量相同的碳分别生成二氧化碳和一氧化碳,消耗氧气的质量比是:()A.1:1 B.1:2 C.2:1 D.3:2 10.质量相同,质量分数也相同的硫酸溶液,分别与足量的下列物质完全反应,所得MgSO4质量分数最大的是:()A.MgCO3B.MgO C.Mg D.Mg(OH)211.Cu 和 Fe的混合粉末若干克,与足量盐酸反应后,过滤。将滤渣在空气中充分加热,加热后的质量恰好等于原混合物的质量,则原混合物中铁的质量分数:()A.20B.40C.50.4D.8012.在托盘天平的两盘上分别放一个盛有100毫升质量分数为 20的稀硫酸的等质量的烧杯,调节天平至平衡,然后分别加入等质量铁片(左盘)和锌片(右盘),反应完全后,天平可能出现的情况是:()1.仍保持平衡2.右盘下沉3.左盘下沉4.无法判断A.B.C.D.14.把 A、B 两块等重的铁片,分别浸入稀硫酸和硫酸铜溶液中,过一段时间后取出烘干,冷却。如果把它们分别放入已经平衡的天平两个托盘下,可以推测:()A.放 A 铁片的托盘上升B.放 B 铁片的托盘上升C.天平仍保持平衡D.哪一边托盘上升不一定,这需根据原铁片消耗的程度而定15.在天平两端各放一个盛有等质量等质量分数的稀硫酸的烧杯,调天平至平衡,若分别投入镁粉和铁粉,且全部溶解,天平仍保持平衡,则投入镁粉和铁粉的质量比为:()A.37 B.73 C.7781 D.8177 16.在托盘天平两端各放一只烧杯,调节到至平衡,向烧杯中分别注入等质量,等质量分数的稀硫酸,然后向一只烧杯里加入一定质量的镁,向另一只烧杯里加入等质量的铜铝合金,两烧杯中的反文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9应恰好完全且天平保持平衡,铜铝合金中铜与铝的质量比为:()A.13 B.12 C.34 D.23 17.在托盘天平两边各放一只烧杯,调节至平衡,在烧杯里分别注入质量相等,质量分数相同的稀硫酸,若在右盘投入一定量的铁,恰好完全反应,为使天平保持平衡,应向左盘投入与铁质量相同的纯净金属是:()A.Mg B.Al C.Zn D.Ag 18等物质的量的 NaHCO3和 KHCO3的混合物 9.20g与 100mL 盐酸反应。(1)试分析,欲求标准状况下生成的CO2的体积时,还需什么数据(用 a、b 等表示,要注明单位)。(2)利用所确定的数据,求标准状况下生成的CO2的体积:所 需 数 据的 取值范围生成 CO2的体积(标准状况)盐酸不足时盐酸过量时(3)若 NaHCO3和 KHCO3不是等物质的量混合,则9.2g 固体与盐酸完 全反 应时,在 标准状 况下 生成CO2气体 的 体积 大 于L,小于L。文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 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