2022年八年级数学相似三角形同步练习 .pdf

精编学习资料欢迎下载2.4 相似三角形同步练习第 1 题.你能用 4 个全等的正三角形拼出一个大正三角形吗？这个大正三角形与每一个小正三角形相似吗？为什么？答案：解：能并出一个大正三角形，如图所示：ABCAFEFBDEDCDEF下面以ABCAFE为例说明：由于正三角形每个角都等于60，所以6060BACFAEABCAFEBCAFEA，60.由于正三角形三边相等，所以AFFEAEABBCAC所以ABCAFE第 2 题.如图，已知ACEBDE，1173763ACACBD，12AB，18CD（1）求B和D的度数（2）AE和DE的长答案：解：（1）因为BDEACE，所以由相似三角形对应角相等，得11737BADC，（2）因为BDEACE，所以由相似三角形对应边成比例，得BEBDDEAEACCE，即123618AEDEAEDE由1236AEAE，解得8AE由3186DEDE，解得6DE精编学习资料欢迎下载第 3 题.如图，AOBDOC，求xy，的值答案：2822xy，第 4 题.如图，328ABCADEAEECAB，求AD及DB的长答案：241655ADDB，第5 题.若ABCA B C，且:3:2ABA BBCB C，则ABC与A B C的相似比k，A B C与ABC的相似比k答案：3 22 3，第6 题.两个三角形相似，其中一个三角形的两个内角分别为50 60，则另一个三角形的最大内角为度，最小内角为度答案：70，50 第7 题.一个三角形的长分别为3，5，7，另一个与它相似的三角形的最长边是21，则其余两边之和为 19 17 24 21 答案：第8 题.如图，在大小为44的正方形网格上，有一ABC，现要求在网格上再画A B C，使ABCA B C（相似比不为1），且点A B C都在单位正方形的顶点上30 20 33 A C D B x y O 42 文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 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题.如图是巴西FURNAS电力公司的标志及结构图，作者用一大一小两颗星巧妙地重叠组合，自然地把高压输电塔与五角星这一光明的象征联系在一起，那么结构图中的两个阴影三角形的面积之比SS小大为A.13 B.12 C.512 D.352答案：D 第 11 题.如图 5，若CD是 Rt ABC斜边上的高，AD=3，CD=4，则BC=_.O lA C B 方格纸方格纸S大S小图 5 文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 ZO7Y9A6J8O8文档编码:CD3G3M8Q7S6 HB10X10A5T3C2 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