2022年中考云南省临沧市数学卷 .pdf

2011年云南省临沧市中考数学试卷一、填空题（本大题共8 个小题，每个小题3 分，满分24 分）1、-2011 的相反数是2011 2、如图，l1l2，1=120，则 2=60 3、在函数21yxx中，自变量x 的取值范围是x1 4、计算101()(12)2=35、如图，在菱形ABCD 中，BAD=60，BD=4，则菱形ABCD 的周长是166、如图，O 的半径是2，ACD=30，则?AB的长是23（结果保留）7、若 a+b=3，ab=2，则 a2b+ab2=68、下面是按一定规律排列的一列数：24 816,35 79，那么第 n 个数是12(1)21nnn二、选择题（本大题共7 个小题，每个小题只有一个正确选项，每小题3 分，满分21 分）9、第六次全国人口普查结果公布：云南省常住人口约为46000000 人，这个数据用科学记数法可表示为（B）人A 46 106B4.6 107C0.46 108D4.6 10810、下列运算，结果正确的是（C）A a2+a2=a4 B（a-b）2=a2-b2C2（a2b）（ab）=2aD（3ab2）2=6a2b411、下面几何体的俯视图是（D）ABCD12、为了庆祝建党90 周年，某单位举行了“颂党”歌咏比赛，进入决赛的7 名选手的成绩分别是：9.80，9.85，9.81，9.79，9.84，9.83，9.82（单位：分），这组数据的中位数和平均数是（A）A9.82，9.82 B9.82，9.79 C9.79，9.82 D9.81，9.82 13、据调查，某市2011 年的房价为4000 元/m2，预计 2013 年将达到4840 元/m2，求这两年的年平均增长率，设年平均增长率为x，根据题意，所列方程为（B）A 4000（1+x）=4840 B4000（1+x）2=4840 C4000（1-x）=4840 D4000（1-x）2=4840 14、如图，已知OA=6，AOB=30，则经过点A 的反比例函数的解析式为（B）A9 3yxB9 3yxC9yxD9yx15、如图，已知B 与 ABD 的边 AD 相切于点 C，AC=4，B 的半径为3，当 A 与 B 相切时，A 的半径是（D）A2 B7 C2 或 5 D2 或 8 三、解答题（本大题共9 个小题，满分75 分）16、解方程组29325xyxy解：29325xyxy，+得，4x=14，解得 x=72，把 x=72代入得，7292y，解得 y=114故原方程组的解为：72114xy17、先化简211()111xxxx，再从-1、0、1 三个数中，选择一个你认为合适的数作为x 的值代入求值解，=，文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8文档编码:CB8F3K8J9I10 HD6W7H5J7O9 ZC9W2Y3V3H8=，=，取 x=0 代入上式得，=02+1，=218、如图，在平行四边形ABCD 中，点 P 是对角线AC 上的一点，PEAB，PFAD，垂足分别为 E、F，且 PE=PF，平行四边形ABCD 是菱形吗？为什么？解：是菱形理由如下：PEAB，PFAD，且 PE=PF，AC 是 DAB 的角平分线，DAC=CAE，四边形 ABCD 是平行四边形，DCAB，DCA=CAB，DAC=DCA，DA=DC，平行四边形ABCD 是菱形19、如图，下列网格中，每个小方格的边长都是1（1）分别作出四边形ABCD 关于 x 轴、y 轴、原点的对称图形；（2）求出四边形ABCD 的面积文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8解（1）如图所示：（2）四边形ABCD 的面积=20、如图，甲、乙两船同时从港口出发，甲船以60 海里/时的速度沿北偏东60 方向航行，乙船沿北偏西30 方向航行，半小时后甲船到达C 点，乙船正好到达甲船正西方向的B 点，求乙船的速度(31.7)解：由已知可得：AC=60 0.5=30，又已知甲船以60 海里/时的速度沿北偏东60 方向航行，乙船沿北偏西30，BAC=90 ，又乙船正好到达甲船正西方向的B 点，C=30 ，AB=AC?tan30=30 33=17，所以乙船的速度为：17 0.5=34，答：乙船的速度为34 海里/小时文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M821、为贯彻落实云南省教育厅提出的“三生教育”，在母亲节来临之际，某校团委组织了以“珍爱生命，学会生存，感恩父母”为主题的教育活动，在学校随机调查了50 名同学平均每周在家做家务的时间，统计并制作了如下的频数分布和扇形统计图：组别做家务的时间频数频率A1 t2 3 0.06 B2 t4 20 0.40 C4 t6 A0.30 D6 t8 8 BEt84 0.08 根据上述信息回答下列问题：（1）a=15，b=0.16；（2）在扇形统计图中，B 组所占圆心角的度数为144；（3）全校共有 2000 名学生，估计该校平均每周做家务时间不少于4小时的学生约有多少人？解：（1）a=50-3-4-8-20=15，b=8 50=0.16；（2）B 组所占圆心角的度数为20 50 360=144；（3）2000（0.3+0.08+0.16）=1080（人），即该校平均每周做家务时间不少于4 小时的学生约有 1080 少人故答案为15，0.16，144 22、小华和小丽两人玩数字游戏，先由小丽心中任意想一个数字记为x，再由小华猜小丽刚才想的数字，把小华猜的数字记为y，且他们想和猜的数字只能在1，2，3，4 这四个数中文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8（1）请用树状图或列表法表示了他们想和猜的所有情况；（2）如果他们想和猜的数相同，则称他们“心灵相通”求他们“心灵相通”的概率；（3）如果他们想和猜的数字满足|x-y|1，则称他们“心有灵犀”求他们“心有灵犀”的概率想数1 1 1 1 2 2 2 2 3 3 3 3 4 4 4 4 猜数1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 解：（1）列表法如下：想数1 1 1 1 2 2 2 2 3 3 3 3 4 4 4 4 猜数1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4（2）根据（1）得所以可能的情况有16 中，想和猜的数相同的情况有4 种，P（心灵相通）；（3）根据（1）得所以可能的情况有16 中，数字满足|x-y|1 的情况有10 种，P（心有灵犀）=23、随着人们节能环保意识的增强，绿色交通工具越来越受到人们的青睐，电动摩托成为人们首选的交通工具，某商场计划用不超过140000 元购进 A、B 两种不同品牌的电动摩托40辆，预计这批电动摩托全部销售后可获得不少于29000 元的利润，A、B 两种品牌电动摩托的进价和售价如下表所示：品牌价格A 品牌电动摩托B 品牌电动摩托进价（元/辆）4000 3000 售价（元/辆）5000 3500 设该商场计划进A 品牌电动摩托x 辆，两种品牌电动摩托全部销售后可获利润y 元（1）写出 y 与 x 之间的函数关系式；（2）该商场购进A 品牌电动摩托多少辆时？获利最大，最大利润是多少？文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8解：（1）设该商场计划进A 品牌电动摩托x 辆，则进B 品牌电动摩托（40-x）辆，由题意可知每辆 A 品牌电动摩托的利润为1000 元，每辆B 品牌电动摩托的利润为500 元，则y=1000 x+500（40-x）=20000+500 x，（2）由题意可知；解得 18x20；当 x=20 时，y=30000 该商场购进A 品牌电动摩托20 辆时，获利最大，最大利润是3000024、如图，四边形 OABC 是矩形，点 B 的坐标为（8，6），直线 AC 和直线 OB 相交于点M，点 P 是 OA 的中点，PDAC，垂足为D（1）求直线AC 的解析式；（2）求经过点O、M、A 的抛物线的解析式；（3）在抛物线上是否存在Q，使得 S PAD：SQOA=8：25，若存在，求出点 Q 的坐标，若不存在，请说明理由解：（1）由题意四边形 OABC 是矩形，点 B 的坐标为（8，6）可知：A、C 两点坐标为 A（8，0），C（0，6），设直线 AC 的解析式 y=kx+b，将 A（8，0），C（0，6）两点坐标代入 y=kx+b，解得，故直线 AC 的解析式为；（2）由题意可知 O（0，0），M（4，3），A（8，0），设经过点 O、M、A 的抛物线的解析式为y=ax2+bx，将 M（4，3），A（8，0），两点坐标代入 y=ax2+bx，文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I1J10 HZ8L7Q8X1W2 ZE3F5S10G10M8文档编码:CF3A3U7I