2022年中考数学必考知识点三角形 .pdf
名师整理精华知识点中考数学必考知识点三角形知识点回顾:(一)三边关系:三角形的任意两边之和大于第三边(二)内角与外角:三角形三个内角的和为180;直角三角形的两个锐角互余;三角形的一个外角等于与它不相邻的两个内角的和;n 边形的内角和等于(n-2)180;任意多边形的外角和等于360。(三)特殊线段:三角形的中线、高线、角平分线都是_(线段、射线、直线)_叫三角形的中位线中位线的性质:_(四)三角形的分类:1三角形按角分为_,_,_2三角形按边分为_,_(五)三角形的内心是_,外心是 _,重心是 _,垂心是 _。知识点一:三角形三边关系三角形中任意两边之和_第三边。例 1:选择题:(1)(2009 黑龙江大兴安岭)如图,为估计池塘岸边A、B两点的距离,小方在池塘的一侧选取一点O,测得15OA米,10OB米,A、B间的距离不可能是()A5 米B 10 米C 15 米D20 米【解】由ABABAB151010151510得到 5AB25 所以,答案:A(2)(20XX年湖南长沙)已知三角形的两边长分别为3cm和 8cm,则此三角形的第三边的长可能是()A4cm B5cm C6cm D 13cm 名师整理精华知识点答案:C同步检测一:1(20XX 年温州)下列长度的三条线段能组成三角形的是()A 1cm,2cm,3 5cm B4cm,5cm,9cm C5cm,8cm,15cm D6cm,8cm,9cm 2.(20XX年崇左)一个等腰三角形的两边长分别为2 和 5,则它的周长为()A7 B9 C12 D9或 12 3.(07 深圳)已知三角形的三边长分别为3、8、x,若 x 的值为偶数,则x 的值有()A.6个 B.5个 C.4 个 D.3个【答案】1D,2C,3D。知识点二:三角形的内角和外角三角形的 3 个内角和为 _,外角与不相邻内角的关系:_。例 2:(1)(07 济南)已知一个三角形三个内角度数的比是1:5:6,则其最大内角度数为()A.60 B.75 C.90 D.120【解】设其中的一份为x,根据三角形的 3 个内角和为1800 得到 x+5x+6x=1800 所以 x=150,最大内角度数为90答案:C(2)(09 娄底)如图 1,已知ACED,C=26,CBE=37,则BED的度数是 ()A63B83C73D53【解】因为 AC ED 所以CAEBED因为CA是ABC的外角,所以000633726CBECCAE所以BED=63答案:A 同步检测二:4.(20XX年广西梧州)如图,ABC中,A60,C40,延长CB到D,则ABD度5.如图,在 ABC中,D是 BC边上一点,1=2,3=4,BAC=63 求 DAC的度数【答案】4.1000 ,5.240 A B C D 4321DCBA文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5名师整理精华知识点知识点三:三角形的中线、高线、角平分线,直角三角形的两个锐角互余。如图,在 ABC中,AD是高线,AE是角平分线,AF中线.则(1)ADC 90;(2)CAE 12;(3)CF 12;例 3 如图,AD、AF分别是 ABC的高和角平分线,已知 B=36,C=76,则DAF=_ 度【解】AD是 ABC的高,所以090ADC,090CADC,000147690CADAF是 ABC的角平分线,所以000034)7636180(2121BACFACDAF=000201434CADFAC例 4如图,在ABC中,AABC与ACD的平分线交于点A1,得A1;A1BC与A1CD的平分线相交于点A2,得A2;A2008BC与A2008CD的平分线相交于点A2009,得A2009则A2009【解】:根据外角的性质A=ACD-ABC,A1=A1CD-A1BC,而且ACD=2A1CD,ABC=2 A1BC,所以A=2A1,同理A1=2A2,以此类推.答案:20092知识点四:多边形的内角和外角 n 边形的内角和等于_;任意多边形的外角和等于_。例 5(20XX年龙岩市)一个凸多边形的内角和与外角和相等,它是边形。答案:4 随堂检测:1(2009山西太原市)如果三角形的两边分别为3 和 5,那么连接这个三角形三边中点所文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 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ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5名师整理精华知识点得的三角形的周长可能是()A4 B4.5 C5 D 5.5 2(2009福建龙岩市)将一副三角板按图中方式叠放,则角等于()A30B45C60D753(2009辽宁铁岭市)如图所示,已知直线ABCD,125C,45A,则E的度数为()A70B 80C90D1004.(20XX 年达州)长度为2、3、4、5 的四条线段,从中任取三条线段能组成三角形的概率是 _.5.在 ABC 中,若 A C13 B,则 A,B,这个三角形是 .6.(20XX年扬州市)一副三角板如图所示叠放在一起,则图中的度数是 _。7(20XX年湖北十堰市)下列命题中,错误的是()A三角形两边之和大于第三边B三角形的外角和等于360C三角形的一条中线能将三角形面积分成相等的两部分D等边三角形既是轴对称图形,又是中心对称图形文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5名师整理精华知识点8.如图,ABC中,A=40,B=72,CE平分 ACB,CD AB于 D,DFCE,则CDF=度.EDCBAF9.(20XX年沈阳市)已知ABC中,60A,ABC,ACB的平分线交于点O,则BOC的度数为10.如图,要在河边修建一个水泵站,分别向张村,李村送水修在河边什么地方,可使所用的水管最短?(写出已知,求作,并画图)答案:1.D 2.D 3.B 4.34 5.360,1080,钝角三角形 6.750 7.D8.解0000687240180ACB,03421ACBBCE,001890BBCD000161834DCE,007490DCECDF9.解)180(211802121180000AACBABCBOC=900+A21=1200 10.作法:(1)作点 A关于直线a 的对称点A(2)连结 AB 交 a 于点 C则点 C就是所求的点证明:在直线a 上另取一点C,连结 AC,AC,AC,CB直线 a 是点 A,A 的对称轴,点 C,C 在对称轴上AC=AC,AC=ACAC+CB=AC+CB=AB 在 ACB 中,AB AC+CB AC+CB AC+CB 即 AC+CB 最小文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 ZS9S5N1M1L5文档编码:CK1M5J3B10S4 HM3I9T4I1M4 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