2022年医药物理学课后习题答案 .pdf

医药物理学课后计算题答案第一章1-8 在边长为2.010-2m 的立方体的两平行表面上，各施加以9.8102N 的切向力，两个力方向相反，使两平行面的相对位移为1.010-3m，求其切变模量？解：由切应力SF和切应变dx的关系式G可得切变模量为2732222109.4100.1)100.2(100.2108.9mNxSFdG1-9 有一根 8.0m 长的铜丝和一根4.0m 长的钢丝，横截面积均为0.50cm2。将它们串联后加 500N 的张力，求每根金属丝的长度改变了多少？解：由于是串联，铜丝和钢丝受力均为500N，由杨氏模量lSFlllSFE00/可得长度的改变量SEFll0，代入求得铜丝的长度改变量为0.727mmm107.27101.1100.585004-114-铜=0SEFll钢丝的长度改变量为0.2mmm102102100.545004-114-钢=0SEFll1-10 试计算横截面积为5.0cm2的股骨：（1）在拉力作用下骨折将发生时所具有的张力。（骨的抗张强度为1.2108Pa）（2）在 4.5104N 的压力作用下它的应变。（骨的杨氏模量为9109Pa）解：（1）骨的抗张强度就是骨折将发生时所受的应力SF=，则所受的张力为NSF448106=105102.1=（2）有E=可知其应变01.0=95105.4=/=494-1010SEFESFE1-11 设某人下肢骨的长度约为0.60m，平均横截面积6.0cm2，该人体重900N。问此人单腿站立时下肢骨缩短了多少。解：由题意可知骨的杨氏模量为9109Pa，由lSFlllSFE00/可得长度的改变量SEFll0，代入已知条件可得0.1mmm1011091060.69004-94-=0SEFll1-12 松弛的肱二头肌伸长2.0cm 时，所需要的力为10N，当它处于挛缩状态而主动收缩时，产生同样的伸长量则需要200N 的力，若将它看成是一条长0.20m、横截面积为50cm2的均匀柱体，求上述两种状态下它的弹性模量。解：此弹性模量为杨氏模量由杨氏模量公式lSFlllSFE00/可得PalSlFE4101100.2=0.=2-4-10210500.210PalSlFE52102100.4=0.=2-4-10210500.2200第二章2-3 有人认为，计算粘滞流体的平均流速时，从连续性方程来看，管子愈粗流速愈小，而从泊肃叶公式来看，管子愈粗流速俞大，两者看似有矛盾。你怎样看等？答：对于一定的管子，在流量一定的情况下，管子愈粗流速愈慢；在管子两端压强差一定的情况下，管子愈粗流速愈快。2-4 水在粗细不均匀的水平管中作稳定流动，已知截面S1处的压强为110Pa，流速为0.2ms-1，截面 S2处的压强为5Pa，求 S2处的流速（内摩擦不计）。解：由伯努利方程在水平管中的应用2222112121vPvP代入数据22323102152.01021110v得)(5.012smv2-5 水在粗细不均匀的水平管中作稳定流动，出口处的截面积为管最细处的3 倍，若出口处的流速为12sm，问最细处的压强为多少？若在此最细处开一小孔，水会不会流出来？解：由连续性方程2211vSvS，得最细处的流速)(612smv根据伯努利方程在水平管中的应用2222112121vPvP代入数据63223561021210211001.1P得K P aPaP85105.842最细处压强为KPa85，因为02PP，所以水不会流出来。文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B32-6 在水管的某一点，水的流速为2 ms-1，高出大气压的计示压强为104Pa，设水管的另一点的高度比第一点降低了1m，如果在第二点处水管的横截面是第一点的1/2，求第二点的计示压强。解：由连续性方程2211vSvS，得第二点的流速)(412smv根据伯努利方程222221112121vghPvghP有)(21)(2221210102vvhhgPPPP代入数据得)(1038.1)42(102118.9101042233402PaPP2-7 一直立圆柱形容器，高m2.0，直径为m1.0，顶部开启，底部有一面积为2410m的小孔。若水以每秒134104.1sm的流量自上面放入容器中，求容器内水可升的最大高度。解：（1）设容器内水面可上升的高度为H，此时放入容器的水流量和从小孔流出的水流量相等，由连续性方程有2211vSvSQ得144224.110104.1smSQv因为21SS，所以可将容器中水面处流速1v近似为零，水面处和出水处压强均为大气压强。运用伯努利方程有gHv2221得mgvH1.08.924.122222-8 一硬斑部分阻塞半径为mm3的小动脉，阻塞后小动脉的有效半径为mm2，血流的平均速度为150scm，求：（1）未变窄处的血流平均速度；（2）阻塞处会不会发生湍流；（3）阻塞处的动压强（血液密度为331005.1mkg，粘滞系数sPa3103）解：（1）由连续性方程2211vSvS得文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3122212221122122.035.02smrvrvSvSv（2）10003501031025.01005.1333vrRe不会发生湍流（3）PavP25.1315.01005.121212322动2-9 设某人的心输出量为135103.8sm，体循环的总压强差为kPa0.12，此人体循环的总流阻是多少？解：因为RPQ所以58531045.1103.8100.12msNQPR2-10 设橄榄油的粘滞系数为1.8P，流过长度为0.5m，半径为 1.0cm 的管子，管两端的压强差为 2 104，求其体积流量。解：根据泊肃叶公式lPRQ84得体积流量1344424107.85.018.08102)10(14.38smlPRQ2-11 设排尿时尿从计示压强为mmHg40的膀胱经过尿道后由尿道口排出，已知尿道长为cm4，流量为1321scm，尿的粘滞系数为sPa4109.6，求尿道的有效直径。解：根据泊肃叶公式lPRQ84得mPlQR44/15644/1102.7)10013.1760/4014.3102104.0109.68()8(mmmRD44.11044.1102.722342-12 设血液的粘度为同温度下水的5 倍（37），如以 72cm s-1 的平均流速通过主动脉，试用雷诺数为1000 来计算产生湍流时的半径。设37水的粘度为6.910-4Pa s，密度为1050kgm3）。解：由于血液的粘度是水的粘度的5 倍，可知血液的粘度为文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3sPa331045.31069.05由雷诺数vrRe可得mmmvRre56.41056.472.01005.110001045.33332-13 直径为 0.01mm 的水滴在速度为2cm/s 的上升气流中，是否可向地面落下（设空气的粘度为 1.810-5Pa s）解：水滴的收尾速度为scmscmsmgRv/2/31.0/101.38.9)11000(108.19)105(2)(9235262此水滴的下降收尾速度小于上升气流的速度，则会随着气流上升，不向地面落下。2-14 液体中一空气泡，直径为1mm，液体的粘度为0.15Pa s，密度为 9000kg m-3，求：（1）空气泡在此液体中上升时的收尾速度为多少?（2）如果这个空气泡在水中上升，其收尾速度又是多少？解：（1）气泡在液体中的收尾速度为gRv)(922，代入已知条件可得空气泡在此液体中收尾速度为smsmgRv/033.0/1033.310)90001(15.09)105(2)(922242即气泡运动是上升。（2）如其气泡在水中运动，则smsmgRv/555.0/1055.510)10001(1019)105(2)(9213242即气泡运动是上升。文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3第三章3-4 试指出下列各式所表示的物理意义（1）kT21；（2）kT23（3）kTi2（4）2RTiMm；（5）RTi2（6）RT23解：(1)在平衡态下，分子热运动能量平均地分配在分子每一个自由度上的能量均为kT21(2)在平衡态下，分子平均平动动能均为kT23.(3)在平衡态下，自由度为i的分子平均总能量均为kTi2.(4)由质量为m，摩尔质量为M，自由度为i的分子组成的系统的内能为RTiMm2.(5）1摩尔自由度为i的分子组成的系统内能为RTi2.（6）1 摩尔单原子分子组成的系统内能为RT23.3-5 若室内因生起炉子后，温度从15oC 升高到 27oC，而室内气压不变，问此时室内的气体减少了百分之几？解：由理想气体物态方程RTMmPV，室内气压P 不变，为定值则有30028827273152732121TTVV12288300VV，即体积变大，则变大的体积占原来的体积比为%2.428812288300111112VVVVVV这一部分气体就是室内减少的那部分气体，即室内的气体减少了4.2%。3-6 湖面下 50m 深处，温度为C04，有一体积为310cm的气泡，若湖面的温度为C017，求此气泡升到湖面时的体积。解：在湖底)(10913.5508.91010013.153501PaghPPKTcmV2774273,10131文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3在湖面)(10013.1502PaPPKT2 9 0172732由222111TVPTVP得)(1.6127710013.11029010913.5355212112cmPTTVPV3-7 一容器内储有气体，压强为1.33Pa，温度为300K，问单位容积内有多少分子？这些分子的总平动动能是多少？解：由nkTP可得kTPn1231038.1KJk，T=300K，P=1.33Pa 代入可得20231021.33001038.133.1kTPn个/m3 这些分子的总平动动能为JPkTkTPnE995.133.1232323总3-8 2g 氢气装再 20L 的容器内，当容器内的压强为4.0104pa时，氢气分子的平均平动动能是多少？解：容器中共有2g 氢气，则氢气的摩尔数为molMm122，即容器中的总分子数为2310022.6ANN个从而可知分子数密度为253231001.3102010022.6VNn个/m3由压强公式kenP32可知氢气分子的平均平动动能为JnPek2125410993.11001.321043233-9 毛细管的半径为4100.2m，将它插入试管中的血液中。如果接触角为零，求血液在管中上升的高度。（血液的密度3/1050mKg，表面张力系数mN/108.52）文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R2J1O4W4 ZO2Z2U10C10B3文档编码:CV4U10Y8W1A7 HA1R