2022年人教A版高中数学必修1过关测试卷 .pdf
人教 a版数学必修 1 模块过关测试卷(150 分,120 分钟)一、选择题(每题5 分,共 60 分)1.长沙模拟设全集 U=MN=1,2,3,4,5,M?UN=2,4,则 N=()A.1,2,3 B.1,3,5 C.1,4,5 D.2,3,4 2.函数xxxylg1的定义域为()A.x|x1 B.x|x1 C.x|x0 D.x|x10 3.函数 f(x)=256xx的零点是()A.2,3 B.2,3 C.2,3 D.1,3 4.南京部分学校高一统考题已知函数f(x)的定义域为A,如果对于属于定义域内某个区间I 上的任意两个不同的自变量12,x x都有1212fxfxxx0,则()A.f(x)在这个区间上为增函数B.f(x)在这个区间上为减函数C.f(x)在这个区间上的增减性不变D.f(x)在这个区间上为常函数5.已知定义域为 R 的函数 f(x)在(8,+)上为减函数,且函数 y=f(x+8)为偶函数,则()A.f(6)f(7)B.f(6)f(9)C.f(7)f(9)D.f(7)f(10)6.江西理观察下列各式:553125,6515625,7578125,,则20115的末四位数字为()A.3 125 B.5 625 C.0 625 D.8 125 7.唐山高一考题若函数f(x)=12xa在实数集 R 上是减函数,则实数 a 的取值范围是()A.1,2B.21,0C.21,D.21,218.江苏淮安高一检测函数y=x2(x0)的反函数为()A.y=24x(xR)B.y=24x(x0)C.y=24x(xR)D.y=24x(x0)9.设 a=5log 4,b=25log 3,c=4log 5,则()A.acbB.bcaC.abcD.bac10.对于集合 M,N,定义 MN=x|xM 且 x?N,MN=(MN)(NM).设 M=y|y=24xx,xR,N=y|y=2x,xR,则 MN=()A.(4,0B.4,0)C.(,4)0,+)D.(,4)(0,+)11.定义在 R 上的奇函数 f(x)满足:当 x0 时,f(x)=20102010logxx,则方程 f(x)=0 的实数根的个数是()A.1 B.2 C.3 D.5 文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 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y=f(x)的图象大致是图 2 中的()图 2 二、填空题(每题4 分,共 16 分)13.已知1C:y=logax,2C:y=logbx,3C:y=logcx,4C:y=logdx四个函数在同一平面直角坐标系中的图象如图3,其中 a,b,c,d 均为不等于 1 的正数,则将 a,b,c,d,1按从小到大的顺序排列为_.图 3 14.已知函数 f(x)=ex a(a 为常数).若 f(x)在区间1,+)上是增函数,则 a 的取值范围是 _.15.已知函数(23)43(1),()(1)xaxaxf xax在(,+)上是增函数,文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 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ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6则 a 的取值范围是 _.16.山东潍坊高三联考某工厂某种产品的年固定成本为250 万元,每生产 x 千件,需另投入成本为C(x)万元,当年产量不足80 千件时,C(x)=21103xx(万元);当年产量不小于80 千件时,C(x)=51x+x100001 450(万元).每件商品售价为 0.05万元,通过市场分析,该厂生产的商品能全部售完.则年利润 L(x)(万元)关于年产量 x(千件)的函数解析式为 _.三、解答题(22题 14 分,其余每题 12 分,共 74 分)17.湖北宜昌统考已知集合A=x|x1 或 x4,B=x|2axa+3,若 BA,求实数 a 的取值范围.文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M618.黄冈模拟已知函数f(x+3)的定义域为5,2,求函数f(x+1)+f(x1)的定义域.19.成都高一联考题已知函数y=f(x)在(0,+)上为增函数,且f(x)0(x0),试判断 F(x)=)(1xf在(0,+)上的单调性并给出证明过程.文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M620.已知 f(x)=2+3log x,x1,3,求 y=2fx+f(x)的最大值及相应的x的值.21.设 a0,f(x)=eexxaa是定义在 R 上的偶函数.(1)求 a 的值;(2)证明:f(x)在(0,+)上是增函数.文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M622.山东德州一模某家庭进行理财投资,根据长期收益率市场预测,投资债券等稳健型产品的收益与投资额成正比,投资股票等风险型产品的收益与投资额的算术平方根成正比.已知投资 1 万元时两类产品的收益分别为0.125万元和 0.5万元.(1)分别写出两类产品的收益与投资的函数关系式;(2)该家庭有 20万元资金,全部用于理财投资,问:怎么分配资金能使投资获得最大收益,其最大收益是多少万元?文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6参考答案及点拨一、1.B 点拨:如答图 1 所示,可知 N=1,3,5.答图 1 2.A 点拨:x 应满足(1)0,10,10,1,00 x xxxxxxx 或 即,定义域为 x|x1.3.B 4.A 点拨:当1x2x时,1x2x0,则 f(1x)f(2x)0,即 f(1x)f(2x),f(x)在区间 I 上是增函数;当1x2x时,1x2x0,则 f(1x)f(2x)0,即 f(1x)f(2x),f(x)在区间 I 上是增函数.综合可知,f(x)在区间 I 上是增函数.5.D 点拨:方法一:y=f(x+8)为偶函数.f(x+8)=f(x+8).可知函数 y=f(x)的图象关于直线x=8 对称.f(7)=f(1+8)=f(1+8)=f(9).又 f(x)在(8,+)上为减函数.f(9)f(10),即 f(7)f(10),故选 D.方法二:y=f(x+8)的图象关于 y 轴对称,故由图象向右平移8 个单位长度可知 y=f(x)的图象关于直线x=8 对称.其他同上.6.D 7.B 点拨:由已知得 012a1,解得 0a21,即实数 a 的取值范围是210,.文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5M1 HV6S6H5U2C4 ZR8J9R4A6M6文档编码:CS9A3O10G5