2022年人教版必修一4.3《牛顿第二定律》WORD教案9 .pdf

名师精编优秀教案教学设计牛顿第二定律（人教版新教材第四章第三节）李中京安徽省潜山中学安 庆 市 省 教 坛名师精编优秀教案二 OO 八年十二月十一日4.3 牛顿第二定律（人教版新教材第四章第三节）教学目标：知识与技能1、能准确表述牛顿第二定律2、理解数学表达式中各物理量的意义及相互关系3、知道在国际单位制中力的单位“牛顿”是怎样定义的4、能运用牛顿第二定律分析和处理简单的问题过程与方法通过对上节课实验结论的归纳，培养学生概括和分析推理能力情感与态度1、渗透物理学研究方法的教育由实验归纳总结物理规律2、让学生感受到物理学在认识自然上的本质性、深刻性、有效性教学重点：牛顿第二定律教学难点：1、牛顿第二定律公式的理解2、理解 k=1 时，F=ma 文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7文档编码:CE6L8K10H8K5 HE5H2X6N2U10 ZI8T2E3O2C7名师精编优秀教案教学方法：探讨、归纳、多媒体辅助教学过程：新课引入在上节课的实验探究中，我们采取了控制变量的思想探讨了力、加速度、质量三个量之间的关系。当物体的质量不变时，探究了物体的加速度与所受的作用力之间关系，存在什么关系呢？（引起学生回顾）课件展示a F 当物体所受的力不变时，探究了物体的加速度与质量之间关系，又是怎样的关系呢？（学生回答）课件展示a 1/m 我们能不能把这两种关系进行进一步的归纳和提升呢？a F/m 新课教学一、牛顿第二定律从我们的探究实验知道：物体的加速度与它所受的力成正比，与它的质量成反比，大量的实验和观察到的事实也都得出了相同的结论。文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3名师精编优秀教案1、内容表述：物体加速度的大小跟作用力成正比，跟物体的质量成反比，加速度的方向跟作用力的方向相同。这里所表述的定量关系，我们不难用a来表示或者F ma 写成等式F=kma（这里引入比例系数，k 究竟取多少能使该式简化呢？）如果规定：1N=1kg m/s2，则 k=1，上式就可以简化为F=ma 事实上，力的单位牛顿就是这样定义的：质量为 1kg 的物体，获得 1m/s2的加速度时，受到的外力1N 所以，数学表达式可以简化为F=ma 2、数学表达式F=ma 共同探究讨论：（）一个物体静止在光滑水平面上，只受向右大小不变的力F1的作用，那么，物体加速度a1方向如何？（）一段时间后，撤去 F1，施加 F2，这时速度 V 方向如何？加速度 a2的方向怎样？（）如果同时受到F1、F2的作用，小车所受合力为多少？加速度 a 由什么力来决定？沿什么方向？大小为多少？作用一段时间后，撤去外力，物块的运动情况如何？文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3名师精编优秀教案探讨后总结：3、公式理解同一性：三个物理量同属一个物体的，式中F 是指合外力向量性：加速度的方向与合外力的方向始终一致，F 合=ma是向量式瞬时性：加速度与力是瞬时对应关系，即同时产生、同时变化、同时消失辨析巩固：下列说法正确的是：A、物体合外力减小时，加速度一定减小（）B、物体合外力减小时，速度一定减小C、物体的运动方向一定跟合外力的方向相同D、物体的加速度方向一定跟合外力的方向相同（）E、做匀加速运动的物体合外力突然变为零时，速度一定突变为零F、受恒力作用的物体加速度大小一定不变（）G、物体的速度大小不变一定受恒力作用H、物体的速度方向发生改变时力的方向也一定发生改变二、应用牛顿第二定律解题课件展示例题1 某质量为1000kg的汽车在平直路面汽车，当达到72km/h 的速度时关闭发动机，经过20s 停下来，汽车受到的阻力是多大?重新起步加速时牵引力为2000N，产生的加速度应为多大?假定试车过程中汽车受到的阻力不变。文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3名师精编优秀教案分析（略）解：v0=72km/h=20m/s 关闭发动机a1=-=-1m/s2汽车受到的阻力F阻=ma=-1000N 阻力方向与速度反向重新起步a2=1m/s2方向与速度方向相同引导学生总结应用牛顿第二定律的解题步骤：、确定研究对象、分析物体的受力情况和运动情况，画出对象的受力分析图、求出合力、根据牛顿第二定律和运动学规律建立方程求解例题 2 一个物体，质量为 kg，受到互成 120角的两个力F、F的作用，此外没有其它的力。这两个力的大小都是10N，这个物体产生的加速度是多大？Ov0 t v0 t F+F阻m 文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3名师精编优秀教案平行四边形法正交分解法分析（略）解：建立如图坐标系：把F、F分别沿轴、轴分解F合=F1x+F2x=F1cos60+F2cos60 =10N 由牛顿第二定律得到a=5m/s2加速度方向与 F合方向相同。复习小结与学生边共同回顾总结，边课件展示、牛顿第二定律F合=ma、牛顿第二定律同一性、向量性、瞬时性。、牛顿第二定律解决问题的一般方法确定对象受力分析求出合力建方程求解布置作业教材第 71 页问题与练习板书设计：F合m 10N 2kg 文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3名师精编优秀教案牛顿第二定律一、牛顿第二定律、内容、表达式F合=ma、理解：（1）同一性（2）向量性（3）瞬时性二、应用牛顿第二定律解题一般步骤：1、确定研究对象；2、分析物体的受力情况；3、求出合力；4、根据牛顿第二定律和运动学规律建立方程求解教学反思：文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 ZK5T2W10X9I3文档编码:CP1Y5Z5V3Q6 HN8Z2I1J9B4 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