2022年数列高考复习题 .pdf

数列1 an是首项 a11，公差为d3 的等差数列，如果an2 005，则序号n 等于()A667 B668 C669 D670 2在各项都为正数的等比数列 an中，首项a13，前三项和为21，则 a3a4a5()A33 B72 C84 D189 3如果 a1，a2，a8为各项都大于零的等差数列，公差d0，则()Aa1a8a4a5 Ba1a8a4a5Ca1 a8a4a5Da1a8a4a54已知方程(x2 2xm)(x22xn)0 的四个根组成一个首项为41的等差数列，则mn等于()A1 B43C21D835等比数列 an 中，a29，a5243，则 an的前 4 项和为().A81 B120 C168 D192 6若数列 an 是等差数列，首项a10，a2 003a2 0040，a2 003a2 0040，则使前 n 项和 Sn0 成立的最大自然数n是()A4 005 B4 006 C4 007 D4 008 7已知等差数列 an的公差为2，若 a1，a3，a4成等比数列,则 a2()A 4 B 6 C 8 D 10 8设 Sn是等差数列 an 的前 n 项和，若35aa95，则59SS()A1 B 1 C2 D219已知数列1，a1，a2，4 成等差数列，1，b1，b2，b3，4 成等比数列，则212baa的值是()A21B21C21或21D4110在等差数列an中，an0，an12na an1 0(n2)，若 S2n138，则 n()A38 B20 C10 D9 二、填空题11 设 f(x)221x，利用课本中推导等差数列前n 项和公式的方法，可求得 f(5)f(4)f(0)f(5)f(6)的值为.12已知等比数列an 中，(1)若 a3a4a58，则 a2a3a4a5 a6(2)若 a1a2324，a3a436，则 a5a6(3)若 S42，S86，则 a17a18a19a20.13在38和227之间插入三个数，使这五个数成等比数列，则插入的三个数的乘积为14在等差数列an中，3(a3a5)2(a7a10a13)24，则此数列前13 项之和为.15在等差数列an中，a53，a6 2，则 a4a5 a10.16设平面内有n 条直线(n 3)，其中有且仅有两条直线互相平行，任意三条直线不过同一点若用f(n)表示这 n条直线交点的个数，则f(4)；当 n4 时，f(n)三、解答题17(1)已知数列 an的前 n 项和 Sn3n22n，求证数列 an 成等差数列.(2)已知a1，b1，c1成等差数列，求证acb，bac，cba也成等差数列.18设 an是公比为q 的等比数列，且a1，a3，a2成等差数列(1)求 q 的值；(2)设 bn 是以 2 为首项，q 为公差的等差数列，其前n 项和为 Sn，当 n2 时，比较Sn与 bn的大小，并说明理由文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N619数列 an的前 n 项和记为Sn，已知 a11，an1nn2Sn(n1，2，3)求证：数列 nSn是等比数列20已知数列 an是首项为a 且公比不等于1 的等比数列，Sn为其前 n 项和，a1，2a7，3a4成等差数列，求证：12S3，S6，S12S6成等比数列.第二章数列参考答案一、选择题1C 文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6解析：由题设，代入通项公式ana1(n1)d，即 2 00513(n1)，n6992C 解析：本题考查等比数列的相关概念，及其有关计算能力设等比数列 an的公比为q(q0)，由题意得a1a2 a321，即 a1(1qq2)21，又 a1 3，1qq27解得 q2 或 q 3(不合题意，舍去)，a3a4a5a1q2(1qq2)322 7843B解析：由 a1 a8a4a5，排除C又 a1a8a1(a17d)a127a1d，a4a5(a1 3d)(a14d)a127a1d 12d2a1 a84C 解析：解法 1：设 a141，a241d，a3412d，a4413d，而方程 x22xm0 中两根之和为2，x22xn0 中两根之和也为2，a1a2a3a416d4，d21，a141，a447是一个方程的两个根，a143，a345是另一个方程的两个根167，1615分别为 m 或 n，mn21，故选 C解法 2：设方程的四个根为x1，x2，x3，x4，且 x1x2x3x42，x1x2m，x3x4n由等差数列的性质：若 spq，则 a asapaq，若设 x1为第一项，x2必为第四项，则x247，于是可得等差数列为41，43，45，47，m167，n1615，mn215B 解析：a29，a5243，25aaq3924327，q3，a1q9，a13，文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6S43133522401206B 解析：解法 1：由 a2 003a2 0040，a2 003a2 004 0，知 a2 003和 a2 004两项中有一正数一负数，又a10，则公差为负数，否则各项总为正数，故a2 003a2 004，即 a2 0030，a2 0040.S4 0062006400641)(aa2006400420032)(aa0，S4 00720074(a1a4 007)200742a2 0040，故 4 006 为 Sn0 的最大自然数.选 B解法 2：由 a10，a2 003a2 0040，a2 003a2 0040，同解法 1 的分析得a2 0030，a2 0040，S2 003为 Sn中的最大值Sn是关于 n 的二次函数，如草图所示，2 003 到对称轴的距离比2 004 到对称轴的距离小，20074在对称轴的右侧根据已知条件及图象的对称性可得4 006 在图象中右侧零点 B 的左侧，4 007，4 008都在其右侧，Sn0 的最大自然数是4 0067B 解析：an是等差数列，a3a14，a4a16，又由 a1，a3，a4成等比数列，(a14)2a1(a16)，解得 a1 8，a2 82 68A 解析：59SS2)(52)(95191aaaa3559aa59951，选 A9A 解析：设 d 和 q 分别为公差和公比，则4 13d 且 4(1)q4，d 1，q22，(第 6 题)文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6212baa2qd2110C 解析：an为等差数列，2na an1an1，2na 2an，又 an0，an2，an为常数数列，而 an1212nSn，即 2n123819，n10二、填空题1123解析：f(x)221x，f(1x)2211xxx2222xx22221，f(x)f(1x)x221xx22221xx222211xx22)22(2122设 Sf(5)f(4)f(0)f(5)f(6)，则 Sf(6)f(5)f(0)f(4)f(5)，2S f(6)f(5)f(5)f(4)f(5)f(6)62，Sf(5)f(4)f(0)f(5)f(6)32 12（1）32；（2）4；（3）32解析：（1）由 a3a524a，得 a42，a2a3a4a5a654a 32（2）9136)(324222121qqaaaa，a5a6(a1 a2)q44（3）224444821843214qqSSaaaSaaaaS，a17a18a19a20S4q163213216文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6解析：本题考查等比数列的性质及计算，由插入三个数后成等比数列，因而中间数必与38，227同号，由等比中项的中间数为227386，插入的三个数之积为3822762161426解析：a3a52a4，a7a132a10，6(a4a10)24，a4a104，S13213131)(aa213104)(aa2413 2615 49解析：da6a5 5，a4a5 a10 27104)(aa25755)(dada7(a52d)49165，21(n1)(n 2)解析：同一平面内两条直线若不平行则一定相交，故每增加一条直线一定与前面已有的每条直线都相交，f(k)f(k1)(k1)由 f(3)2，f(4)f(3)3235，f(5)f(4)42349，f(n)f(n1)(n1)，相加得 f(n)234(n1)21(n1)(n2)三、解答题17分析：判定给定数列是否为等差数列关键看是否满足从第2 项开始每项与其前一项差为常数证明：（1）n1 时，a1S1321，当 n2 时，anSnSn13n22n 3(n 1)22(n1)6n5，n1 时，亦满足，an6n 5(nN*)文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D2D6D1 HJ4Y4R6R3K7 ZO10K3R3W9N6文档编码:CH5A10D