2022年天津大学版工程力学习题答案 .pdf
3-10 求图示多跨梁支座A、C 处的约束力。已知M=8 kN m，q=4 kN/m，l=2 m。解：（1）取梁 BC 为研究对象。其受力如图(b)所示。列平衡方程（2）取整体为研究对象。其受力如图(c)所示。列平衡方程3-11 组合梁AC 及 CD 用铰链C 连接而成，受力情况如图(a)所示。设F=50 kN，q=25 kN/m，力偶矩 M=50 kN m。求各支座的约束力。Bq 2l l C FB FC(b)M(c)Bq A 2l l 2lC FC MA FA M（a）Bq A 2l l 2lC 习题 3-10 图kN1842494902332,0qlFllqlFMCCBkN624318303,0qlFFlqFFFCACAymkN32245.10241885.10405.334,022qllFMMllqlFMMMCACAA解：（1）取梁 CD 为研究对象。其受力如图(c)所示。列平衡方程（2）取梁 AC 为研究对象。其受力如图(b)所示，其中FC=FC=25kN。列平衡方程习题 3-11 图2m 2mC DM qFC FD 2m 1m 2m2m1mC BDAM F(a)q(b)一(c)一FC1m 2m1mBAF FA FB qC kN25450252420124,0MqFMqFMDDCkN25450256460324,0MqFMqFMCCD)kN(25225225250222021212,0CACABFqFFFqFFMkN150225425650246043212,0CBCBAFqFFFqFFM文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y86-1 作图示杆件的轴力图。解：在求 AB 段内任一截面上的轴力时，在任一截面1-1 处截断，取左段为脱离体（图 c），并设轴力FN1为拉力。由平衡方程求出：kN201NF同理，可求得BC 段任一截面上的轴力（图d）为kN204020N2F求 CD 段内的轴力时，将杆截开后取右段为脱离体，并设轴力FN 3为拉力（图e）。由kN002525,0N3N3FFFx同理，可得DE 段内任一横截面上的轴力FN 4为（图 f）kN254N4FF按轴力图作图规则，作出杆的轴力图（图g）。6-8 图示钢杆的横截面面积为200mm2，钢的弹性模量E=200GPa，求各段杆的应变、600 300 500 400 A B C D E 40kN 20kN 25kN 25kN（a）A B C D E 40kN 20kN 25kN 25kN 20kN1 1 FN2A B 40kN 2 2 2 2 3 3 4 4 FN325kN 25kN D 3 3（b）（c）（d）（e）20 20 20 FN图（kN）（g）习题 6-1 图FN420kN4 41 1（f）20kNFN1A 20kN20kN文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8伸长及全杆的总伸长。解：（1）由截面法直接作轴力图（2）计算各段截面的应力(1)计算各段截面的应变(2)计算各段截面的的伸长(3)计算杆件总伸长6-9 图示一阶梯形截面杆，其弹性模量E=200GPa，截面面积 A=300mm2，A=250mm2，A=200mm2，作用力F1=30kN，F2=15kN，F3=10kN，F4=25kN。试求每段杆的内力、应力、应变、伸长及全杆的总伸长。解：（1）由截面法直接作轴力图（2）计算各段截面的应力1.2m 0.6m 1m 0.8m A B C D E40kN 55kN 25kN 20kN 习题 6-8 图轴力图10kN 5kN 50kN20kN 2m1.5m1mF2 F3 FF习题 6-9 图轴力图30kN 15kN25kN 文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8（3）计算各段截面的应变（4）计算各段截面的的伸长（5）计算杆件总伸长6-11 图示一三角架，在节点 A 受 F 力作用。设 AB为圆截面钢杆，直径为d，杆长为 l1；AC 为空心圆管，截面积为A2，杆长为l2。已知：材料的容许应力=160MPa，F=10mm，A2=5010-8m2，l1=2.5m，l2=1.5m。试作强度校核。解：(1)求各杆的轴力，取A 节点为脱离体，并由（2）计算各杆截面的应力故满足强度条件，结构是安全的。8-12 传动轴的转速为n=500r/min，主动轮 1输入功率P1=500kW，从动轮2、3 分别输出功率P2=200 kW，P3=300 kW。已知材料的许用切应力=70MPa，材料切变模量G=79GPa，轴的单位长度许用扭转角=1/m。习题 6-11 图l2l2l1B C A F A 点受力图FNAC FNAA F 0.4m A0.5m 习题 8-12 图P1 CP3 BP2 文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8（1）试确定 AB 端的直径 d1和 BC 端的直径 d2。（2）若 AB 和 BC 两端选用同一直径，试确定直径d。（3）主动轮和从动轮应如何安排才比较合理？解：（1）圆轴上的外力偶分别为mN95505005009550955011nPMmN38205002009550955011nPMmN57305003009550955011nPM作圆轴的扭矩图。（2）根据强度条件确定AB 段和 BC 段的直径，AB 段:311P11max16dTWT得 AB 段的直径为mm6.8810709550161636311TdBC 段:322P22max16dTWT得 AB 段的直径为mm7.7410705730161636322Td(3)根据刚度条件确定AB 段和 BC 段的直径，AB 段:411P1132dGTGIT得 AB 段的直径为mm6.9110791809550323249411GTdBC 段:文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8422P2232dGTGIT得 BC 段的直径为mm7.8010791805730323249422GTd(3)若选同一直径,应取mm6.91d.(4)将主动轮置于中间比较合理,此时maxT最小.9-5 试列出下列梁的剪力方程和弯矩方程，并画出剪力图和弯矩图。解：支反力1211FFA，12FFC内力方程：AC 段1211SFFxFA（0 x3l）xFxFxMA1211.（0 x3l）CD 段121211SFFFFFxFA（3lx32l）3123.12113.FlFxFlxFxFlxFxFxMA（3lx32l）DB 段12SFFxFB（32lxl）3lA B(c)F Fl/4 3l3lC D F Fl/4 FAFB文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y81212FxFlxlFxMB（32lxl）内力图FS图M 图解：支反力FC=28kN，FD=29kNFS图M 图1211F12F3611Fl185Fl36Flq=6kN/mA B C D(g)2mF=9kN2m6mq=6kN/mA B F=9kNFCFD9kN19kN17kN12kN18kN.m12kN.m12.08kN.m5.167m文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5H8J6O1O8 HI1W2A6L1C1 ZR10E9Y8M1Y8文档编码:CV5
