论文资料-梁悬臂施工仿真分析ansys（word）可编辑.doc

资源ID：62692570 资源大小：31KB 全文页数：7页
资源格式： DOC 下载积分：15金币

快捷下载

会员登录下载

微信登录下载

三方登录下载：

微信扫一扫登录

下载资源需要15金币

邮箱/手机：
温馨提示：	快捷下载时，用户名和密码都是您填写的邮箱或者手机号，方便查询和重复下载（系统自动生成）。如填写123，账号就是123，密码也是123。
支付方式：
验证码：	换一换

账号：
密码：
验证码：	换一换
当日自动登录忘记密码？

友情提示

1、下载资料失败解决办法

2、PDF文件下载后，可能会被浏览器默认打开，此种情况可以点击浏览器菜单，保存网页到桌面，就可以正常下载了。

3、本站不支持迅雷下载，请使用电脑自带的IE浏览器，或者360浏览器、谷歌浏览器下载即可。

4、本站资源下载后的文档和图纸-无水印,预览文档经过压缩，下载后原文更清晰。

5、试题试卷类文档，如果标题没有明确说明有答案则都视为没有答案，请知晓。

网站客服

侵权投诉

论文资料-梁悬臂施工仿真分析ansys（word）可编辑.doc

Õ×½ü×öµÄ»øöäü±©¹¤·Õ·ÖöµÄÄ£,æ¶²»´ó,45+80+45,æ¼µ½¤Ó¦¦øÖ½,øÕæ¼Óøå´×öøÖ½,×ö³ö´µÄÄ£µ«´ó,0Åæé¾Ó10øö×ÓÉ¶,×öÕÅµÄ©¹¤·Öö¾²»,×öµÄ»øö¼»ÆµÄÄ£,¼·: 1:ÓSOLID65´×ö»Ä,LINK8´Ä£Ä¤Ó¦¦½. 2:½Ø¢Õ÷½,°ä¼»Æ³É¼øøö²,Ø¹»·É³ÉÕÅ 3:»®·ÖÕ÷½µÄµ,æÖøµÄÉ³É,Ø¹ÉØÓ´ÅµÄÓÄ£ 4:æ¼Õ÷½ÉµÄ½Óµ¹¶ØøÖ½,»·É³Éø÷©¹¤¶µÄøÖ½. ü÷,ø÷»¦Öø½ fini /clear /prep7 /title,BRIDGE DAM SIMULATION,DEVELOPED BY YIFEICHONGTIAN ET,1,SOLID65 ET,2,LINK8 MP,PRXY,1,0.1667 MP,DENS,1,2600 MP,EX,1,3.5E10 MP,EX,2,1.95E11 MP,DENS,2,7800 MP,PRXY,2,0.3 !¤Ó¦¦øÖ½µÄ !×øÖ½,Ö±¾¶15.24mm,±×¼æ¶1860MPA£¬µøÕÅæÖ¶Ö»195.5kN areagjx=1.81e-4 !×£¬µøøÖ½» areahgjx=8.038e-4 !µøøÖ½» *dim,gjarea,array,3 gjarea(1)=16*areagjx gjarea(2)=3*areagjx gjarea(3)=areahgjx *dim,F,array,3 F(1)=195.5e3 F(2)=586e3 F(3)=480e3 E=1.95E11 L=0.5 *dim,delt,array,3 delt(1)=F(1)*L/(E*areagjx) delt(2)=F(2)*L/(E*gjarea(2) delt(3)=F(3)*L/(E*gjarea(3) *dim,istrn,array,3 istrn(1)=delt(1)/(delt(1)+L) istrn(2)=delt(2)/(delt(2)+L) istrn(3)=delt(3)/(delt(3)+L) r,2,gjarea(1),istrn(1) r,3,gjarea(2),istrn(2) r,4,gjarea(3),istrn(3) V_NUM=46 DUN_NUM=2 *DIM,DUN_BEGIN,ARRAY,DUN_NUM *DIM,DUN_END,ARRAY,DUN_NUM DUN_BEGIN(1)=9,33, DUN_END(1)=13,37, !ä½µÄ¼ø² *DIM,B1,ARRAY,V_NUM+1 *DIM,B2,ARRAY,V_NUM+1 *DIM,B3,ARRAY,V_NUM+1 *DIM,B4,ARRAY,V_NUM+1 *DIM,H1,ARRAY,V_NUM+1 *DIM,H2,ARRAY,V_NUM+1 *DIM,H3,ARRAY,V_NUM+1 *DIM,H4,ARRAY,V_NUM+1 *DIM,H5,ARRAY,V_NUM+1 *DIM,H6,ARRAY,V_NUM+1 *DIM,Z0,ARRAY,V_NUM+1 *DO,I,1,47,1 B1(I)=3 B3(I)=1.3 H1(I)=0.2 H2(I)=0.37 H4(I)=0.32 H5(I)=0.35 *ENDDO B4(1)=2.21,2.21,2.188,2.167,2.145,2.123,2.101,2.08,2.063,2.047, B4(11)=2.02,2.02,2.02,2.047,2.063,2.08,2.101,2.123,2.145,2.167, B4(21)=2.188,2.21,2.21,2.21,2.21,2.21,2.188,2.167,2.145,2.123, B4(31)=2.101,2.08,2.063,2.047,2.02,2.02,2.02,2.047,2.063,2.08, B4(41)=2.101,2.123,2.145,2.167,2.188,2.21,2.21, B2(1)=0.36,0.36,0.382,0.403,0.425,0.447,0.469,0.49,0.507,0.523, B2(11)=0.55,0.55,0.55,0.523,0.507,0.49,0.469,0.447,0.425,0.403, B2(21)=0.382,0.36,0.36,0.36,0.36,0.36,0.382,0.403,0.425,0.447, B2(31)=0.469,0.49,0.507,0.523,0.55,0.55,0.55,0.523,0.507,0.49, B2(41)=0.469,0.447,0.425,0.403,0.382,0.36,0.36, H3(1)=1.467,1.467,1.499,1.592,1.748,1.967,2.249,2.593,2.893,3.228, H3(11)=3.867,3.867,3.867,3.228,2.893,2.593,2.249,1.967,1.748,1.592, H3(21)=1.499,1.467,1.467,1.467,1.467,1.467,1.499,1.592,1.748,1.967, H3(31)=2.249,2.593,2.893,3.228,3.867,3.867,3.867,3.228,2.893,2.593, H3(41)=2.249,1.967,1.748,1.592,1.499,1.467,1.467, H6(1)=0.26,0.26,0.264,0.276,0.296,0.324,0.36,0.405,0.444,0.487, H6(11)=0.57,0.57,0.57,0.487,0.444,0.405,0.36,0.324,0.296,0.276, H6(21)=0.264,0.26,0.26,0.26,0.26,0.26,0.264,0.276,0.296,0.324, H6(31)=0.36,0.405,0.444,0.487,0.57,0.57,0.57,0.487,0.444,0.405, H6(41)=0.36,0.324,0.296,0.276,0.264,0.26,0.26, !æøöä½Ö¶µZµÄ×± Z0(1)=0,3,7,11,15,19,23,27,30,33, Z0(11)=38,39,40,45,48,51,55,59,63,67, Z0(21)=71,75,78,79,80,83,87,91,95,99, Z0(31)=103,107,110,113,118,119,120,125,128,131, Z0(41)=135,139,143,147,151,155,158, !æøöä½Ö¶µX,YµÄ×± X0=0 Y0=4.537 K_NUM=24 !* *DO,J,0,V_NUM,1 !³Éµ K,1+J*K_NUM,XO-(B1(J+1)+B2(J+1)+B3(J+1)+B4(J+1),Y0-H1(J+1),Z0(J+1) K,2+J*K_NUM,XO-(B1(J+1)+B2(J+1)+B3(J+1)+B4(J+1),Y0,Z0(J+1) K,3+J*K_NUM,XO-(B2(J+1)+B3(J+1)+B4(J+1),Y0,Z0(J+1) K,4+J*K_NUM,XO-(B3(J+1)+B4(J+1),Y0,Z0(J+1) K,5+J*K_NUM,XO-B4(J+1),Y0,Z0(J+1) K,6+J*K_NUM,XO+B4(J+1),Y0,Z0(J+1) K,7+J*K_NUM,XO+(B3(J+1)+B4(J+1),Y0,Z0(J+1) K,8+J*K_NUM,XO+(B2(J+1)+B3(J+1)+B4(J+1),Y0,Z0(J+1) K,9+J*K_NUM,XO+(B1(J+1)+B2(J+1)+B3(J+1)+B4(J+1),Y0,Z0(J+1) K,10+J*K_NUM,XO+(B1(J+1)+B2(J+1)+B3(J+1)+B4(J+1),Y0-H1(J+1),Z0(J+1) K,11+J*K_NUM,XO+(B2(J+1)+B3(J+1)+B4(J+1),Y0-H1(J+1)-H2(J+1),Z0(J+1) K,12+J*K_NUM,XO+(B2(J+1)+B3(J+1)+B4(J+1),Y0-H1(J+1)-H2(J+1)-H3(J+1)+H6(J+1),Z0(J+1) K,13+J*K_NUM,XO+(B2(J+1)+B3(J+1)+B4(J+1),Y0-H1(J+1)-H2(J+1)-H3(J+1),Z0(J+1) K,14+J*K_NUM,XO+(B3(J+1)+B4(J+1),Y0-H1(J+1)-H2(J+1)-H3(J+1),Z0(J+1) K,15+J*K_NUM,XO-(B3(J+1)+B4(J+1),Y0-H1(J+1)-H2(J+1)-H3(J+1),Z0(J+1) K,16+J*K_NUM,XO-(B2(J+1)+B3(J+1)+B4(J+1),Y0-H1(J+1)-H2(J+1)-H3(J+1),Z0(J+1) K,17+J*K_NUM,XO-(B2(J+1)+B3(J+1)+B4(J+1),Y0-H1(J+1)-H2(J+1)-H3(J+1)+H6(J+1),Z0(J+1) K,18+J*K_NUM,XO-(B2(J+1)+B3(J+1)+B4(J+1),Y0-H1(J+1)-H2(J+1),Z0(J+1) K,19+J*K_NUM,XO-(B3(J+1)+B4(J+1),Y0-H4(J+1)-H5(J+1),Z0(J+1) K,20+J*K_NUM,XO-B4(J+1),Y0-H4(J+1),Z0(J+1) K,21+J*K_NUM,XO+B4(J+1),Y0-H4(J+1),Z0(J+1) K,22+J*K_NUM,XO+(B3(J+1)+B4(J+1),Y0-H4(J+1)-H5(J+1),Z0(J+1) K,23+J*K_NUM,XO+(B3(J+1)+B4(J+1),Y0-H1(J+1)-H2(J+1)-H3(J+1)+H6(J+1),Z0(J+1) K,24+J*K_NUM,XO-(B3(J+1)+B4(J+1),Y0-H1(J+1)-H2(J+1)-H3(J+1)+H6(J+1),Z0(J+1) !³Éß L_NUM=36 L,1+J*K_NUM,2+J*K_NUM,2 L,2+J*K_NUM,3+J*K_NUM,4 L,3+J*K_NUM,4+J*K_NUM,2 L,4+J*K_NUM,5+J*K_NUM,2 L,5+J*K_NUM,6+J*K_NUM,4 L,6+J*K_NUM,7+J*K_NUM,2 L,7+J*K_NUM,8+J*K_NUM,2 L,8+J*K_NUM,9+J*K_NUM,4 L,9+J*K_NUM,10+J*K_NUM,2 L,10+J*K_NUM,11+J*K_NUM,4 L,11+J*K_NUM,12+J*K_NUM,5 L,12+J*K_NUM,13+J*K_NUM,2 L,13+J*K_NUM,14+J*K_NUM,2 L,14+J*K_NUM,15+J*K_NUM,5 L,15+J*K_NUM,16+J*K_NUM,2 L,16+J*K_NUM,17+J*K_NUM,2 L,17+J*K_NUM,18+J*K_NUM,5 L,18+J*K_NUM,19+J*K_NUM,2 L,19+J*K_NUM,20+J*K_NUM,2 L,20+J*K_NUM,21+J*K_NUM,4 L,21+J*K_NUM,22+J*K_NUM,2 L,22+J*K_NUM,23+J*K_NUM,5 L,23+J*K_NUM,24+J*K_NUM,5 L,24+J*K_NUM,19+J*K_NUM,5 L,18+J*K_NUM,1+J*K_NUM,4 *DO,I,26,30,1 L,I-23+J*K_NUM,I-8+J*K_NUM,2 *ENDDO L,11+J*K_NUM,8+J*K_NUM,2 L,23+J*K_NUM,12+J*K_NUM,2 L,23+J*K_NUM,14+J*K_NUM,2 L,24+J*K_NUM,15+J*K_NUM,2 L,24+J*K_NUM,17+J*K_NUM,2 L,11+J*K_NUM,22+J*K_NUM,2 *ENDDO !½Ø¢A_LINEß¼Æ£¬ CM,A_LINE,LINE !½ÉåµÄøö VV_NUM=12 !³Éå *DO,K,0,V_NUM-1,1 V,1+K*K_NUM,2+K*K_NUM,3+K*K_NUM,18+K*K_NUM,1+(K+1)*K_NUM,2+(K+1)*K_NUM,3+(K+1)*K_NUM,18+(K+1)*K_NUM V,3+K*K_NUM,4+K*K_NUM,19+K*K_NUM,18+K*K_NUM,3+(K+1)*K_NUM,4+(K+1)*K_NUM,19+(K+1)*K_NUM,18+(K+1)*K_NUM V,4+K*K_NUM,5+K*K_NUM,20+K*K_NUM,19+K*K_NUM,4+(K+1)*K_NUM,5+(K+1)*K_NUM,20+(K+1)*K_NUM,19+(K+1)*K_NUM V,5+K*K_NUM,6+K*K_NUM,21+K*K_NUM,20+K*K_NUM,5+(K+1)*K_NUM,6+(K+1)*K_NUM,21+(K+1)*K_NUM,20+(K+1)*K_NUM V,6+K*K_NUM,7+K*K_NUM,22+K*K_NUM,21+K*K_NUM,6+(K+1)*K_NUM,7+(K+1)*K_NUM,22+(K+1)*K_NUM,21+(K+1)*K_NUM V,7+K*K_NUM,8+K*K_NUM,11+K*K_NUM,22+K*K_NUM,7+(K+1)*K_NUM,8+(K+1)*K_NUM,11+(K+1)*K_NUM,22+(K+1)*K_NUM V,8+K*K_NUM,9+K*K_NUM,10+K*K_NUM,11+K*K_NUM,8+(K+1)*K_NUM,9+(K+1)*K_NUM,10+(K+1)*K_NUM,11+(K+1)*K_NUM V,11+K*K_NUM,12+K*K_NUM,23+K*K_NUM,22+K*K_NUM,11+(K+1)*K_NUM,12+(K+1)*K_NUM,23+(K+1)*K_NUM,22+(K+1)*K_NUM V,23+K*K_NUM,12+K*K_NUM,13+K*K_NUM,14+K*K_NUM,23+(K+1)*K_NUM,12+(K+1)*K_NUM,13+(K+1)*K_NUM,14+(K+1)*K_NUM V,23+K*K_NUM,14+K*K_NUM,15+K*K_NUM,24+K*K_NUM,23+(K+1)*K_NUM,14+(K+1)*K_NUM,15+(K+1)*K_NUM,24+(K+1)*K_NUM V,15+K*K_NUM,16+K*K_NUM,17+K*K_NUM,24+K*K_NUM,15+(K+1)*K_NUM,16+(K+1)*K_NUM,17+(K+1)*K_NUM,24+(K+1)*K_NUM V,17+K*K_NUM,18+K*K_NUM,19+K*K_NUM,24+K*K_NUM,17+(K+1)*K_NUM,18+(K+1)*K_NUM,19+(K+1)*K_NUM,24+(K+1)*K_NUM *ENDDO CMSEL,U,A_LINE LSEL,ALL LESIZE,ALL,6 ALLSEL VATT,1,1,1 *DO,I,1,V_NUM*VV_NUM,1 VSWEEP,I *ENDDO !¶Øå¤Ó¦¦½* *GET,LMAX,LINE,NUM,MAX *DO,I,0,V_NUM,1 LSEL,NONE L,4+K_NUM*I,15+K_NUM*I,1 !¬½ÓÉ³É¤Ó¦¦½ L,7+K_NUM*I,14+K_NUM*I,1 LATT,2,4,2 LESIZE,ALL,1 LMESH,ALL LSEL,NONE L,1+K_NUM*I,10+K_NUM*I,1 !¬½ÓÉ³É¤Ó¦¦½ LATT,2,4,2 LESIZE,ALL,1 LMESH,ALL LSEL,NONE *ENDDO !°´©¹¤½¶·½°ø¶Øåæ»½×¶µÄ×¤Ó¦¦øÖ÷£¬£¬¤Ó¦¦øÖ½¼Æ !æ8½½×¢»¶»Ää£¬É×¤Ó¦¦øÖ÷»´ ALLSEL *DO,BADAY,0,9,1 LSEL,NONE ESEL,NONE *DO,I,1,2,1 L,18+(DUN_BEGIN(I)-BADAY)*K_NUM,18+(DUN_END(I)+BADAY)*K_NUM, L,11+(DUN_BEGIN(I)-BADAY)*K_NUM,11+(DUN_END(I)+BADAY)*K_NUM, *ENDDO LATT,2,2,2 LESIZE,ALL,1 LMESH,ALL, *DO,I,1,2 LSEL,A,LMAX+3*(DUN_BEGIN(I)-BADAY)-2,LMAX+3*(DUN_BEGIN(I)-BADAY+1),1 LSEL,A,LMAX+3*(DUN_END(I)+BADAY)-2,LMAX+3*(DUN_END(I)+BADAY+1),1 *ENDDO ESLL,A CM,Z_REBAR%BADAY%,ELEM *ENDDO ALLSEL NUMMRG,NODE SAVE,MODEL

注意事项

本文（论文资料-梁悬臂施工仿真分析ansys（word）可编辑.doc）为本站会员（e****s）主动上传，淘文阁 - 分享文档赚钱的网站仅提供信息存储空间，仅对用户上传内容的表现方式做保护处理，对上载内容本身不做任何修改或编辑。若此文所含内容侵犯了您的版权或隐私，请立即通知淘文阁 - 分享文档赚钱的网站（点击联系客服），我们立即给予删除！

温馨提示：如果因为网速或其他原因下载失败请重新下载，重复下载不扣分。