浙大C语言答案(全).docx

浙大春季C语言程序编程目录第2周(M2) 220011求华氏温度100°F对应的摄氏温度。220012求华氏温度150 对应的摄氏温度。320013求摄氏温度26。(3对应的华氏温度。320015当n为152时,分别求出n的个位数字(digiti)、卜位数字(digit2)和百位数字(digit3) 的值。320026输入2个整数num!和num2,计算并输出它们的和、差、积、商与余数。4第3周(M3) 520031 求 1+2+3+.+ 100 (调试示例 error02_5) 520032 求 m+(m+l)+(m+2)+.+100 520033 求 l/m+ l/(m+l)+ l/(m+2)+.+ l/n620034 求 1 + 1/3 + 1/5 + .的前 n 项和 ?20035求1-1/4+1/7 10+的前n项之和720036输出华氏摄氏温度转换表(改错题error02_6) 820038求x的n次裏920041生成3的乘方表1020044 求 100Ao.5+101 0.5 + 1000Ao.5 1020053计算物体自由下落的距离1120056计算分段函数1120061阶梯电价1220062 求 m*m+ l/m+(m+l)*(m+l)+ l/(m+l)+(m+2)*(m+2)+ l/(m+2)+n*n+1/n 1320063 求 1-2/3+3/5-4/7+5/9-6/11+1420064 求 2A1+2A2+2A3 +2An 15第4周(M4) 1510007显示图案(复习prin氓)的字符串输出)1520042生成阶乘表1620043 使用函数求 n! /(m!* (n-m)!) 1620054求平均值1720057 求 1 + 1/2+1/3 +.+ l/n 1820065 求 0! + 1!+2! +n! 1840015求最小值!940018 求 a+aa+aaa+aa.a 20第 5 周(M5) 2130001求一元二次方程的根2130002求分段函数的值2330003分类统计字符2330004显示五级记分制成绩所对应的百分制成绩区间(使用switch) 2430005显示水果的价格(使用switch) 2530007求三角形的面积和周长2730008计算个人所得税2830051判断闰年2930052统计学生平均成绩与及格人数3030053分段计算水费（使用嵌套的i任else语句）31第 6 周（M6） 3240011求最小公倍数和最大公约数（调试示例error04_l） 3240012 求 1-1/4+1/7-1/10+1/13-1/16+3340014求整数的位数3440023换硬币3540024找出各位数字的立方和等于它本身的数3640025找完数（改错题error04_2） 3840027从高位开始逐位输出个整数的各位数字（选作）3940052判断素数4040053逆序输出整数4140054输出斐波那契序列42第 7 周（M7） 4250002使用函数判断数的符号4250003使用函数求奇数和4350005使用函数统计素数并求和4450006使用函数统计个整数中数字的个数4550007使用函数找水仙花数4650009使用函数求余弦函数的近似值4850052使用函数找最大值4950062使用函数输出指定范围内的Fibonacci数5050063使用函数找出指定范围内的完数51第 8 周（M8） 5240013求奇数和5240062 求 x+x*x/2!+x*x*x/3!+x*x*x*x/4! +的值 5350004使用函数计算两点间的距离5450061 使用函数求2+22 + 222 + 22-2 5560002整数的十进制、进制和十六进制表现形式5660003分类统计字符5760006验证歌德巴赫猜想5860007使用函数输出整数的逆序数5960009统计单词6060062简单计算器61第2周（M2）20011求华氏温度100叩对应的摄氏温度。计算公式如,c=5*（f-32）/9,式中:c表示摄氏温度,f表示华氏温度。（源程序error02.cpp）输入输出示例:fahr=100,celsius=37#include <stdio.h> int main(void) int Celsius, fahr;fahr=100;celsius=5*(fahr-32)/9;printf(Mfahr = %d, Celsius = %dnM, fahr, Celsius);return 0;20012求华氏温度150°F对应的摄氏温度。计算公式:C = 5*F/9-5*32/9.式中:C表示摄氏温度,F表示华氏温度。输入输出示例：fahr=150, celsius=66#include <stdio.h>int main(void)int Celsius, fahr;fahr=150;celsius=5*fahr/9-5*32/9;printf(nfahr = %d, Celsius = %dnn,fahr, Celsius);return 0;20013求摄氏温度26对应的华氏温度。计算公式如下,六9*c/5+32,式中：c表示摄氏温度,f表示华氏温度。输入输出示例：celsius=26,fahr=78#include <stdio.h>int main(void)int Celsius, fahr;celsius=26;fahr=9*celsius/5+32;printff'celsius = %d, fahr = %dn”, Celsius, fahr);return 0;20015当n为152时,分别求出n的个位数字(digiti)、十位数字(digit2)和百位数字(digit3) 的值。输入输出示例：整数152的个位数字是2,十位数字是5,百位数字是1#includc <stdio.h>int main(void)int n,digitI,digit2,digit3;n=152;digit l=n;digit2=(n/10);digit3=n/100;printf("整数d的个位数字是%d,卜位数字是d,百位数字是dn”, n, digiti, digit2, digit3);return 0;)20026输入2个整数num!和num2,计算并输出它们的和、差、积、商与余数。输出两个整数的余数可以用 printf("%d % %d = %dn", numl, num2, numl%num2);输入输出示例:括号内是说明输入5 3 (numl=5,num2=3)输出5 + 3 = 85-3 = 25 *3 = 155/3=15%3 = 2#include <stdio.h>int main(void)int numl,num2;scanff%d%d”,&numl ,&num2);printff'%d + %d = %dnH,num 1 ,num2,num 1 +num2);printf("d %d = %dnM,num 1 ,num2,num 1 -num2);printff%d *%d = %dnM,num 1 ,num2,num 1 *num2);printf(n%d / %d = %dnM,numl,num2,numl/num2);printff'%d % % %d = %dn",num 1 ,num2,num 1 %num2);return 0;第3周(M3)20031 求 1+2+3+ 100 (调试示例 error02_5) 计算表达式1+2 + 3 + .+ 100的值。输出示例:sum = 5050#include <stdio.h>int main(void)(int i, sum;sum=0;fbr(i=l;i<=100;i+)sum=sum+i;printftnsum = %dnM, sum);20032 求 m+(m+1 )+(m+2)+100输入个正整数repeat (0<repeat<10)»做repeat次下列运算:输入个正整数m(0<=m<=100)»计算表达式m + (m+1) + (m+2) + 100的值。输入输出示例:括号内为说明输入3 (repeat=3)0(计算 0+1+2+.+100)10(计算 10+11+12+.+100)50 (计算 50+51+52+100)输出sum = 5050sum = 5005sum = 3825#include <stdio.h>int main(void)int i, m, sum;int repeat, ri;scand”, &repeat);fbr(ri = 1; ri <= repeat; ri+)scanR"d”, &m);sum=0;fbr(i=m;i<= 100;i+)sum=sum+i;printff'sum = %dn", sum);20033 求 l/m+l/(m+l)+l/(m+2)+.+ l/n输入个正整数repeat (0<repeat<10).做repeat次下列运算:输入2个正整数m和n(m<=n).计算表达式l/m+ l/(m+l)+ l/(m+2) +1/n的值,输出时保留3位小数。输入输出示例:括号内为说明输入3 (repeat=3)5 15(计算 1/5+1/6+1/7+.+1/15)10 20(计算 1/10+1/11+1/12+.+1/20)1 3 (计算 1+1/2+1/3)输出sum = 1.235sum = 0.769sum = 1.833#include <stdio.h>int main(void)(int i, m, n;int repeat, ri;double sum;scanff'%d”，&repeat);fbr(ri = 1; ri <= repeat; ri+)scanff'%d%d"，&m, &n);sum=0;for (i=m; i<=n; i+)sum=sum+1.0/i;printff'sum = %.3fnH, sum);20034 求 1 + 1/3 + 1/5 + .的前 n 项和输入个正整数repeat (0<repeat<10),做repeat次下列运算:输入个正整数n,计算表达式1 + 1/3+ 1/5 + .的前n项之和,输出时保留6位小数。输入输出示例:括号内为说明输入2 (repeat=2)5(计算 1+1/3+1/5+1/7+1/9)23(计算 1+1/3+1/5+.+1/45)输出sum= 1.787302sum = 2.549541/include <stdio.h>int main(void)(int i, n;int denominator;int repeat, ri;double sum;scanff%d”，&repeat);fbr(ri = 1; ri <= repeat; ri+) scanff%d”, &n);sum=0;denominator=l;fbr(i=l;i<=n;i-H-)(sum=sum+1.0/denominator;denominator=denominator+2;printfV'sum = %.6fnH, sum);20035求1-1/4+1/7-10+的前n项之和输入个正整数repeat (0<repeat<10)»做repeat次下列运算:读入个正整数n,计算1 - 1/4+1/7 10+的前n项之和,输出时保留3位小数。输入输出示例:括号内是说明输入2 (repeat=2)310输出sum = 0.893sum = 0.819#include <stdio.h>int main(void)int flag, i, n, t;int repeat, ri;double item, sum;scanfi("d"，&repeat);fbr(ri = 1; ri <= repeat; ri-H-) scanR"d”, &n);sum=0;flag=l;t=l；fbr(i=l；i<=n；i+) item=flag*1.0/t; sum=sum+item; flag=-flag;t=t+3;printf(Hsum = %.3fn", sum);20036输出华氏摄氏温度转换表(改错题error02_6)输入个正整数repeat (0<rcpcat<10)»做repeat次下列运算:读入2个整数lower和upper,输出张华氏摄氏温度转换表,华氏温度的取值范围是lower, upper»每次增加 2F。计算公式:c = 5*(f-32)/9,其中:c表示摄氏温度,f表示华氏温度。输出请使用语句 printf("3.0f%6.lfn"，fahr, Celsius);输入输出示例:括号内是说明输入2 (repeat=2)32 35 (lower=32,upper=35)40 30 (lower=40,upper=30)输出fahr Celsius32 0.034 1.1fahr Celsius#include <stdio.h>int main(void)int lower, upper;int repeat, ri;double Celsius, fahr;scanff'%d”，&repeat);fbr(ri = 1; ri <= repeat; ri+) scanfi("d%d"，& lower, &upper);printf(Mfahr celsiusn");fbr(fahr= lower; fahr<=upper; fahr-H-, fahri-+)(celsius=5*(fahr-32)/9;printf(H%3.0f%6.1 fnM,fahr,Celsius);20038求x的n次累输入个正整数repeat (0<repeat10),做repeat次下列运算:读入1个实数x和正整数n(n<=50),计算并输出x的n次壽(保留2位小数),不允许调 用pow函数求事。输入输出示例:括号内是说明输入2 (repeat=2)1.5 2 (x=1.5,n=2)2 7 (x=2,n=7)输出2.25128.00#include <stdio.h>int main(void)(int i, n;int repeat, ri;double mypow, x;scanfi("d"，&repeat);fbr(ri = 1; ri <= repeat; ri+)scanflf%d”, &x, &n);mypow=l;fbr(i=l ;i<=n;i-H")mypow=mypow * x;printff%.2fn“，mypow);20041生成3的乘方表输入个正整数n,生成一张3的乘方表,输出33八n的值,可调用基函数计算3的乘 方。输出使用语句 prin氓"pow(3,%d) = %.Ofn", i, mypow);输入输出示例:括号内是说明输入3(n=3)输出pow(3,0) = 1pow(3,l) = 3pow(3,2) = 9pow(3,3) = 27#include <stdio.h>#include <math.h>int main(void)|int i, n;double mypow;scanff%d”, &n);fbr(i=O;i<=n;i-H-) mypow=pow(3,i)；printffpow(3,%d) = %.0fn i, mypow);20044 求 1000.5+101 0.5 + 1000A0.5计算100八0.5+101八0.5 + 1000八0.5的值(保留2位小数),可调用sqi!函数计算平方根。 输入输出示例:括号内是说明 输出sum = 20435.99#include <stdio.h>#include <math.h> int main(void) int i;double sum;sum=0;fbr(i=100;i<=1000;i+)sum=sum+sqrt(i);printf(Msum = %.2fnn,sum);20053计算物体自由下落的距离个物体从100m的高空自由落下,编写程序,求它在前3s内下落的垂直距离(结果保留 2位小数)。设重力加速度为10米/秒A2。#include <stdio.h>int main(void)double height;height=0.5 *10*3* 3;printf(Hheight = %.2fnM, height);20056计算分段函数输入个正整数repeat (0<repeat<10),做repeat次下列运算:编写程序,输入x,计算并输出下列分段函数f(x)的值(保留2位小数),请调用sqrt()函数求 平方根,调用pow()函数求暴。当 x>=0 时,f(x) = xA0.5,当 x 小于 时,f(x) = xA5 + 2x + l/Xo 输入输出示例:括号内是说明 输入3 (repeat=3)10(x=10)-0.5 (x=-0.5)0 (x=0) 输出 f(10.00) = 3.16£(-0.50) = -3.03RO.OO) = 0.00include <stdio.h>#include <math.h> int main(void) (int repeat, ri;double x, y;scanR”d”, &rcpeat);fbr(ri = 1; ri <= repeat; ri-H-)scanftM%lf',&x);iflx>=0) y=sqrt(x);else y=pow(x,5)+2*x+l.0/x;printfC砥 .2f) = %.2fn", x, y);2006I阶梯电价输入个正整数repeat (0<rcpcat<10)»做repeat次下列运算:为了提倡居民节约用电,某省电公司执行“阶梯电价”,安装户表的居民用户电价分为 两个”阶梯”:月用电量50千瓦时以内的,电价为0.53元千瓦时;超过50千瓦时的用电量, 电价上调0.05元/千瓦时。输入用户的月用电量e(千瓦时),计算并输出该用户应支付的电费(元),结果保留2位小数。 输入输出示例:括号内是说明输入2 (repeat=2)10(e=10)100 (e=100)输出cost = 5.30cost = 55.50#include <stdio.h>int main(void)Iint repeat, ri;double cost, e;scanfi(”d”, &repeat);fbr(ri = 1; ri <= repeat; ri-H-) scanfi(,%lf, &e);if(e<=50)cost=e*0.53;elsecost=0.53*50+(e-50)*0.58;printffcost = %.2fnn, cost);20062 求 m*m+ l/m+(m+l)*(m+l)+ l/(m+l)+(m+2)*(m+2)+ l/(m+2)+n*n+ 1/n输入个正整数repeat (0<repeat<10),做repeat次下列运算:输入两个正整数 m 和 n(m<=n),求 sum = m*m + 1/m + (m+l)*(m+l) + l/(m+l) +(m+2)*(m+2)+l/(m+2)+n*n+l/n,结果保留 6 位小数。输入输出示例:括号内为说明输入3 (repeat=3)1 2 (m=l,n=2)2 5 (m=2,n=5)5 10 (m=5,n=10)输出sum = 6.500000sum = 55.283333sum = 355.845635#include <stdio.h>int main(void)int i, m, n;int repeat, ri;double sum;scan d”,&repeat);fbr(ri = 1; ri <= repeat; ri-H-)scanf("d%d”, &m, &n);sum=0;fbr(i=m; i<=n;i-H-)sum=sum+i*i+l .0/i;printf(Hsum = %.6fn"，sum);20063 求 1 -2/3+3/54/7+5/9641+输入个正整数repeat (0<repeat<10)»做repeat次列运算:输入个正整数n,计算1 -2/3+3/54/7+5/961+的前n项之和,输出时保留3位 小数。输入输出示例:括号内是说明输入3 (repeat=3)1 (n=l)3 (n=3)5 (n=5)输出sum = 1.000sum = 0.933sum = 0.917#includc <stdio.h> int main(void) int flag, i, n;float denominator;int repeat, ri;double item, sum;scanfV%d”, &rcpeat);fbr(ri = 1; ri <= repeat; ri-H-) scanR"d”, &n);sum=0;flag=l;denominator =1.0;fbr(i=l; i<=n; i卄)item=flag* i *1.0/ denominator; sum=sum+item;flag=-flag;denominator = denominator +2;)printfV'sum = %.3fnH, sum);20064 求 2人 1+2A2+23+2An#include <stdio.h>#include <math.h>int main(void)int i,n;int repeat, ri;double sum;scan%d”, &repeat);fbr(ri = 1; ri <= repeat; ri-H") scanf(M%dM, &n);sum=0;fbr(i=l ;i<=n;i-H-)sum=sum+pow(2,i)；printffsum = %.0fn”，sum);第4周（M4）10007显示图案（复习prints）的字符串输出） 编写程序,在屏幕上显示如下图案。* * * * * * *#include <stdio.h> int main(void) (printf(H* * * *nM* * * *"*nM);20042生成阶乘表输入个正整数n,生成一张阶乘表,输出l!n!的值,要求定义和调用函数fact(n)计算n!, 函数类型为double。输出使用语句 prin氓"d! = %.0fn", i, myfact);输入输出示例:括号内是说明输入3 (n=3)输出1! = 12! = 23! = 6#include <stdio.h>int main(void)int i, n;double myfact;double fact(int n);scanfi("%d”, &n);fbr(i=l;i<=n;i-H-) myfact=fact(i);printf("d! = %.OfnH, i, myfact);double fact(int n)double result;intj;result=l;for(j=lij<=nij-H-) result=result*j;return result;20043 使用函数求 n! /(m!* (n-m)!)输入个正整数repeat (0<repcat< 10)»做repeat次列运算:输入2个正整数m和n(m<=n),计算n!/(m!* (n-m)!) 要求定义并调用函数fact(n)计算n的阶乘,其中n的类型是int,函数类型是double。 例:括号内是说明输入:2 (repeat=2)2 7 (m=2, n=7)5 12 (m=5, n=12)输出:result = 21result = 792#include "stdio.h"int main(void)int m, n;int repeat, ri;double s;double fact(int n);scanff%d”，&repeat);fbr(ri = 1; ri <= repeat; ri+)scanfifH%d%dn, &m, &n);fact(n);fact(m);fact(n-m);s=l;s=s*fact(n)/(fact(m)*fact(n-m);printf("result = %.0fn"，s);double fact(int n)(double result;int i;result=l;fbr(i=l；i<=n；i+) result=result*i;return result;20054求平均值编写程序,输入3个整数,计算并输出它们的平均值(结果保留2位小数)。输入输出示例:输入123输出average = 2.00#include <stdio.h>int main(void)(int a, b, c;double average;scan d%d%d”,&a,&b,&c);average= (a+b+c )/3.0;printff'average = %.2fnn, average);20057 求 ! + 1/2+1/3+l/n输入个正整数repeat (0<repeat<10)»做repeat次下列运算:编写程序,输入个正整数n,求1 + 1/2+1/3 +的前n项之和,输出时保留6位小数。输入输出示例:括号内为说明输入2 (repeat=2)6(计算 1+1/2+1/3+1/4+1/5+1/6)2(计算 1+1/2)输出sum = 2.450000sum = 1.500000#include <stdio.h>int main(void)int i, n;int repeat, ri;double sum;scanff%d"，&repeat);fbr(ri = 1; ri <= repeat; ri+) scanff%d”, &n);sum=0;for(i=l;i<=n;i+)sum=sum+1.0/i;printff'sum = %.6fn", sum);20065 求0!+l!+2! +n!输入个正整数repeat (0<repeat<10)»做repeat次下列运算:编写个程序,输入个正整数n,计算e = 0! + l!+2! +n!,要求定义和调用函数 fhct(n)计算n!»函数类型是double例:括号内是说明输入3 (repeat=3)124输出sum = 2sum = 4sum = 34#include <stdio.h>int main(void)|int i,n;int repeat, ri;double sum;double fact(int n);scanR"d”, &repeat);fbr(ri = 1; ri <= repeat; ri-H-)scanf("d”，&n);sum= 1;fbr(i= 1 ;i<=n;i-H-) fact(i);sum=sum+fact(i);printffsum = %.OfnH, sum);double fact(int n)(double result;intj;result=l;fbr(j=lj<=nj-H-) result=result*j;return result;40015求最小值输入个正整数repeat (0<repeat<10),做repeat次下列运算: 输入个正整数n,再输入n个整数,输出最小值。输入输出示例:括号内是说明输入3 (repeat=3)4-2-123 100 04-9-11 -83 5 3 1输出min = -123min = -9min = 1#include <stdio.h>int main(void)(int i, min, n, x;int repeat, ri;scanf("d”, &repeat);fbr(ri = 1; ri <= repeat; ri-H-)scand”, &n);scanf("d”，&x);min=x;fbr(i=l;i<n;i-H-) scanff%d”，&x); ifimin>x) min=x;printffmin = %dnM, min);40018 求 a+aa+aaa+aaa提示:第 i 项通项:tn = a + a* 10 + a * 100 . +a * 10A( n-1)= t(n-l) + a* 10A(n-l)#include <stdio.h>#include <math.h>int main(void)int a, i, n, sn, tn;int ri, repeat;scanff%d"，&repeat);fbr(ri = 1; ri <= repeat; ri+)scanff%ld%d”，&a, &n);sn=0;tn=O;fbr (i=0; i<n; i+)tn=tn+a*pow( 10,i);sn=sn+tn;printf("suni = %dn", sn);第5周(M5)3000I求一元二次方程的根输入个正整数repeat (0<repeat<10),做repeat次下列运算:输入参数a,b,c,求一元二次方程a*x*x+b*x+c=0的根,结果保留2位小数。输出使用以下语句:printff参数都为零,方程无意义!n");printf(Ha和b为, c不为0»方程不成立n")；printff'x = %0.2fnn, -c/b);printff'xl = %0.2fnM, (-b+sqrt(d)/(2*a);printf(Mx2 = %0.2fnM, (-b-sqrt(d)/(2*a);printf(Mxl =%0.2fF%0.2finM, -b/(2*a), sqrt(-d)/(2*a);printf(Mx2 = %0.2l%0.2fin”, b/(2*a), sqrt(-d)/(2*a); 输入输出示例:括号内为说明 输入:5 (repeat=5)000 (a=O,b=O,c=O)0 0 1 (a=O,b=O,c=l)024 (a=0,b=2,c=4)2.1 8.9 3.5 (a=2.1,b=8.9,c=3.5)1 2 3 (a=l,b=2,c=3)输出:参数都为零,方程无意义!a和b为, c不为,方程不成立x = -2.00xl =-0.44x2 = -3.80xl =-1.00+1.41ix2 = -1.00-1.41i/include <stdio.h>#include <math.h>int main(void)(int repeat, ri;double a, b, c, d;scanf("d"，&repeat);fbr(ri = 1; ri <= repeat; ri-H-)scanff%lf%lf%lF, &a, &b, &c);d=b*b-4*a*c;if(a=O)if(b=O)if(c=O)printff参数都为零,方程无意义!n”)；else(printf(Ha和b为, c不为0,方程不成立n")； else printffx = %0.2fn", -c/b);elseif(d>=0)printf(Mxl = %0.2fnM, (-b+sqrt(d)/(2*a);printf(nx2 = %0.2fnH, (-b-sqrt(d)/(2*a);elseprintf(Mxl =%0.2件0.2fin”, b/(2*a), sqrt(-d)/(2*a);printf(nx2 = %0.2f-%0.2finH, -b/(2*a), sqrt(-d)/(2*a);30002求分段函数的值输入个正整数repeat (0<repeat<10)»做repeat次下列运算: 输入个整数x»计算并输出下列分段函数sign(x)的值。-1 x<0y = sig