山东省潍坊市2023年高三二模考前适应性练习（二）数学试题含答案.pdf

高三二模考前适应性练习（二）数 学 满分 150 分，考试时间：120 分钟 8540.1.=Ax xx22=Bxxlog112)(=ABA.xx12B.xx03C.xx23D.xx022.z1 i2zA.+1 iB.1 iC.1 iD.+1 i 3x=3sin3+=cos()A1 B31C31D1 43.SA=82.8ASAS50003.125A35000B40000C45000D500005=+f xxxm nNmn()(21)(61)(,)x24x2A83 B90 C96 D100 6ABC8PACEFB3PE PFA28,46B32,58C39,55D42,607M+=C xyx:4022+=l xy:20 xyABMABA12B4C3D68abc=+acac2ln=+balog215)(abcAabcBabc Cacb2Dacb24520.,520.2023.4.15数学试题 第1 页 共 4 页山东省潍坊市2023年高三二模考前适应性练习（二）数学试题 910.A400 B C D 10=+f xxx462sin3sin 212)(Af x)(2 Bf x)(12 12,5 Cf x)(=x12 Df x)(3,02 11“”.ABCD4 A BPQABCDPQ4 CABCD8 6 DABCD46 12+=Cxy43:122F1F2B=l ykx k:(0)CMNFMF12xEyGm(0,)()AMFNF128 B+MFNF|14119 CBMBN43 D=m21=FEF E|:|2:112 4520.13f x)(R+=f xf x20)()(=f x)(x xxx2sin,1,221,0,1)(=f 2023)(_ 14.E)(D)(0PED2)()()(.2023150500=E80)(=D42)(100_.数学试题 第2 页 共 4 页 15=C ypx p:2(0)2FlF33CABDABDMlMABxNDMFN32 3=p .16.abL=a=b=2 m .（第一个空 2 分，第二个空 3 分）670.17.10 ABCA B C,a b c,.+=bcaB2 cos.1=B12A 2+acbcabca)()(.1812 an=a11=+aann4111Nn*.(1)=abnn212bn.(2)1=+cnnnbn6(1)21Nn*+ccnn1.19.12 ABCDEF=ACBCEFDEADBECF4,2,1,5,.1ABEDABC 2BCDF2EBDF.2012 202311112100 1 2 3 4 5 6 7 8 9 10 11 12 x/C 10 11 13 12 8 10 9 11 13 10 12 9 y/21 24 28 28 15 22 17 22 30 18 27 18=xii128112=yii270112=x yiii2965112=xii13941212 数学试题 第3 页 共 4 页 yx122102 122 216yx=+ybxa（精确到1)322 参考公式：回归方程=+ybxa 中斜率和截距的最小二乘估计公式分别为=xxbxxyyiiniiin()()()121，=aybx 2112 C+=ababxy102222)(BOPa2,0C=BPO45OPB21(1)C(2)CxAAAMANCMNAMANkAMkAN=kkAMAN121MNAMN 22.12=f xg xxxe,ln)()(.1af xg xf ag a)()()()(+x0,)(f ag a)()(2xx112=xxxxkkf xf xg xg x,1212121212)()()()(xx x,012)(=kxkxe2010+x xkkf xf x21121212)()(.数学试题 第4 页 共 4 页座号18.(12 分)19.(12 分).装订线一.选择题（每小题 5 分，共 60 分）题号123456789101112答案二.填空题（每小题 5 分，共 20 分）考号13.14.15.16.17.(10 分)姓名班级高三二模适应性考试（二）高三二模适应性考试（二）20.(12 分)21.(12 分)22.(12 分)1 高三二模考前适应性练习（二）数学参考答案 1.A 2.D 3C 4B 5C 6C 7A 8D2lnccaa=+2ln2lnccaa=()()2ln0f xxx x=()221xfxxx=()0fx2x()0fx02x()f x()0,2()f x()2,+()()()min22 1 ln20f xf=102a2c215ba+=()2155xxg x=+()2155xxg x=+()0,+()21g=()()212155aag ag=+=5215baa=+ba 2521215ba=+=2b 2cba2acb 202c2a 215ba+=()2155xxg x=+()2155xxg x=+()0,+()21g=()()212155aag ag=+=5215baa=+ab 2521215ba=+=2b 2abc2acb 2acb.D 9BD 10BCD 11BDABCD1A,4B;2,OABCD BO E,OE.3,2 ABCDM BCDO ABCD BMBOAM O AM.4AB=,2224 342,33BM=224 34 6433AM=.2222()BOBMOMAMOM=+=22224 34 633BOOMOM=+=6BO=,ABCD 3344(6)8 633R=.ABCD,C.4BEAB=,46OE=,D.3 4520 131 14.10 152 2 16.,0,sincos2baL=+4 2m 670.17.1sinsin2sin cosBCAB+=()()sin2sin cossinsinBABABAB=+=,2BAB AB=2 12B=6A=4 2()22222()2cos()bcbcbcAbcaacac+=()()()21 cos2sin1 cos2sin1 cos22cossinsin2bABABBBaAB+=6 3ABB+=0,3B8()2cos1,2B()()()1,2bcabcaac+.10 1811142222222212121212121112 1124nnnnnnnnnnabaaaaabaa+=2 112221ba=nb224 2()2122nbnn=+=5 4 16(1)26(4)nbnnnnnc=+=12216(1)264(46)nnnnnnc+=+=+1126(54)()536nnnnnncc+=7*nN1nncc+1(5102)36nnnncc+=021()3n+*nNn240,39nmax92(14)3n=9 n22,033nmin32(12)3n=.11 9 3,4 2*nN1nncc+.12 19.1PPAPBPC=,D E F.ABMPMAB 222,ACBCABCACB+=.2 AMCM=PAMPCM 90PMAPMC=PMMCPM ABC4 PM ABEDABEDABC.5 2ABCDEF,h DEF1S ABC2SF BCDDEFABCB DEFD ABCVVVV=()()1122121211123333h SS SSh SSh S Sh+=3h=.6 FFHDEHFH ADE HHGBDGFG FGHEBDF.7 22 54 53 59,95522FHDHBD=+=8 5 32sinsin932HDGDBA=9 8 53,tan154FHHGFGHGH=4cos5FGH=11 EBDF45.12 1112244D BCFD BCPA BCPP ABCVVVV=6PM=CCA CBxy()()132,1,6,0,2,0,3,3,1,322PBDF6()()4,2,02,1,6ABAP=EBD()11,2,0n=8 31,3233,32BFBD=FBD()20,2,1n=10 124cos,5n n=11 EBDF45.12 201122212C2211 21211111666PC=4 2101(u1)v2(u2)v10(u10)v1012111021 102229654302535iiiiiiu vx y=5 12121111(20)10.8,(43)22.71010iiiiuxvy=1010 10.8 22.72451.6uv=1012222112 1013942001194iiiiux=221010 10.81166.4u=6 6 101102211025352451.63.011941166.4iiiiiu vuvbunu=7 22.73 10.89.710avbu=8 310yx=9 310 x=3 101020y=10 212012=22202=212 211()0,0,452aBbPBPO=2ab=2ab=1 12OPBS=111222ab=2ab=22abab=2,1ab=3 C2214xy+=.4 2MN0()()1122,M x yN xyMNxmyn=+2214xmynxy=+=x()2224240mymnyn+=5()()22222244441616640m nmnmn=+=+212122224,44mnnyyy ymm+=+6()()22221212121212228442,44nnmxxm yynx xm y ymn yynmm+=+=+=+112AMANkk=121212212yyxx=+()12121212412y yx xxx=+7 22222222222244414441644164164161612444nnnmnmnnmnmnnmm+=+220nn+=1n=2n=8 2n=MN2xmy=MN()2,0A 7 1n=0 MN1xmy=+MN()1,0 MNxDD()1,0 1n=12122223,44myyy ymm+=+()()()22212121222222133412346222444AMNmmSADyyyyy ymmm+=+=+=+9 23,3tmt=+()13yttt=+2110yt=1ytt=+)3,+2113 366611(1)22323AMNtSttt=+11 233tm=+=0m=AMN3 32.12 22.1()()()()11ln,xxxxeh xf xg xex h xexx=()1xu xxe=()u x()0,+()11 0,11 022euue=1,12a()10au aae=()h x()0,a(),a+()()h xh a()0,x+()()()1ln1af ag aeaaa=.3 2121212lnlnxxkeeAkxx=0A1212lnlnxxeA xeA x=.()lnxp xeA x=()xxAxeApxexx=5()xv xxeA=()0,+0 x+();v xA x+()v x+00 x()0v x=6 000 xx eA=.()p x()00,x()0,x+.()()12p xp x=()012,xx x.7()()12121212f xf xkkx x+8()()()()()()112212121212f xg xf xg xf xf xxxx x+8 12121112xxx x+()()()()()()11221212121122f xg xf xg xf xf xxxxx+()()()()()()1211221212112f xf xf xg xf xg xxxxx+()()()()()()()()11221122122f xg xf xg xfxgxfxgxxx+9()()()lnxh xf xg xex=()()()()1212122h xh xh xh xxx+()()()()()()121212*2h xh xh xh xxx+1xx=21xx.()()()()()()2222h xh xq xh xh xxx+=10()()()()()()2222hxh xh xqxh xxx+=()()()()()()()()222222hxhxhxhxqxhxxxxx=()()3220,0 xhxeeqxx=()()20q xq x=()()20q xq x=()*.12