《C语言程序设计》课后习题答案(第四版)谭浩强(共66页).docx

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1、精选优质文档-倾情为你奉上1-5 #include int main ( ) printf (*nn); printf( Very Good!nn); printf (*n); return 0;1-6#include int main()int a,b,c,max; printf(please input a,b,c:n); scanf(%d,%d,%d,&a,&b,&c); max=a; if (maxb) max=b; if (maxc) max=c; printf(The largest number is %dn,max); return 0;4-4-1#include int ma

2、in() int a,b,c; printf(请输入三个整数:); scanf(%d,%d,%d,&a,&b,&c); if (ab) if (bc) printf(max=%dn,c); else printf(max=%dn,b); else if (ac) printf(max=%dn,c); else printf(max=%dn,a); return 0;4-6.#include int main() int x,y; printf(输入x:); scanf(%d,&x); if(x1) /* x1 */ y=x; printf(x=%3d, y=x=%dn ,x,y); else

3、if(x10) /* 1=x=10 */ y=3*x-11; printf(x=%d, y=3*x-11=%dn,x,y); return 0;4-7-1#include int main() int x,y; printf(enter x:); scanf(%d,&x); y=-1; if(x!=0) if(x0) y=1; else y=0; printf(x=%d,y=%dn,x,y); return 0;4-7-2#include int main() int x,y; printf(please enter x:); scanf(%d,&x); y=0; if(x=0) if(x0)

4、 y=1; else y=-1; printf(x=%d,y=%dn,x,y); return 0;4-8#include int main() float score; char grade; printf(请输入学生成绩:); scanf(%f,&score); while (score100|score0)printf(n 输入有误,请重输);scanf(%f,&score); switch(int)(score/10) case 10:case 9: grade=A;break;case 8: grade=B;break;case 7: grade=C;break;case 6: gr

5、ade=D;break;case 5:case 4:case 3:case 2:case 1:case 0: grade=E; printf(成绩是 %5.1f,相应的等级是%cn ,score,grade);return 0;4-11#include int main() int t,a,b,c,d; printf(请输入四个数:); scanf(%d,%d,%d,%d,&a,&b,&c,&d); printf(a=%d,b=%d,c=%d,d=%dn,a,b,c,d); if (ab) t=a;a=b;b=t; if (ac) t=a;a=c;c=t; if (ad) t=a;a=d;d=

6、t; if (bc) t=b;b=c;c=t; if (bd) t=b;b=d;d=t; if (cd) t=c;c=d;d=t; printf(排序结果如下: n); printf(%d %d %d %d n ,a,b,c,d); return 0; 4-12#include int main() int h=10; float x1=2,y1=2,x2=-2,y2=2,x3=-2,y3=-2,x4=2,y4=-2,x,y,d1,d2,d3,d4; printf(请输入一个点(x,y):); scanf(%f,%f,&x,&y); d1=(x-x4)*(x-x4)+(y-y4)*(y-y4)

7、; /*求该点到各中心点距离*/ d2=(x-x1)*(x-x1)+(y-y1)*(y-y1); d3=(x-x2)*(x-x2)+(y-y2)*(y-y2); d4=(x-x3)*(x-x3)+(y-y3)*(y-y3); if (d11 & d21 & d31 & d41) h=0; /*判断该点是否在塔外*/ printf(该点高度为 %dn,h); return 0; 5-3#include int main() int p,r,n,m,temp; printf(请输入两个正整数n,m:); scanf(%d,%d,&n,&m); if (nm) temp=n; n=m; m=temp

8、; p=n*m; while(m!=0) r=n%m; n=m; m=r; printf(它们的最大公约数为:%dn,n); printf(它们的最小公约数为:%dn,p/n); return 0; 5-4#include int main() char c; int letters=0,space=0,digit=0,other=0; printf(请输入一行字符:n); while(c=getchar()!=n) if (c=a & c=A & c=0 & c=9) digit+; else other+; printf(字母数:%dn空格数:%dn数字数:%dn其它字符数:%dn,let

9、ters,space,digit,other); return 0; 5-5#include int main() int a,n,i=1,sn=0,tn=0; printf(a,n=:); scanf(%d,%d,&a,&n); while (i=n) tn=tn+a; /*赋值后的tn为i个 a组成数的值*/ sn=sn+tn; /*赋值后的sn为多项式前i项之和*/ a=a*10; +i; printf(a+aa+aaa+.=%dn,sn); return 0; 5-6#include int main() double s=0,t=1; int n; for (n=1;n=20;n+)

10、 t=t*n; s=s+t; printf(1!+2!+.+20!=%22.15en,s); return 0;5-7#include int main() int n1=100,n2=50,n3=10; double k,s1=0,s2=0,s3=0; for (k=1;k=n1;k+) /*计算1到100的和*/ s1=s1+k; for (k=1;k=n2;k+) /*计算1到50各数的平方和*/ s2=s2+k*k; for (k=1;k=n3;k+) /*计算1到10的各倒数和*/ s3=s3+1/k; printf(sum=%15.6fn,s1+s2+s3); return 0;

11、5-8#include int main() int i,j,k,n; printf(parcissus numbers are ); for (n=100;n1000;n+) i=n/100; j=n/10-i*10; k=n%10; if (n=i*i*i + j*j*j + k*k*k) printf(%d ,n); printf(n); return 0; 5-10#include int main() int i,n=20; double a=2,b=1,s=0,t; for (i=1;i=n;i+) s=s+a/b; t=a, a=a+b, b=t; printf(sum=%16.

12、10fn,s); return 0; 5-11#include int main() double sn=100,hn=sn/2; int n; for (n=2;n=10;n+) sn=sn+2*hn; /*第n次落地时共经过的米数*/ hn=hn/2; /*第n次反跳高度*/ printf(第10次落地时共经过%f米n,sn); printf(第10次反弹%f米n,hn); return 0; 5-12#include int main() int day,x1,x2; day=9; x2=1; while(day0) x1=(x2+1)*2; /*第1天的桃子数是第2天桃子数加1后的2倍

13、.*/ x2=x1; day-; printf(total=%dn,x1); return 0; 5-13#include #include int main() float a,x0,x1; printf(enter a positive number:); scanf(%f,&a); x0=a/2; x1=(x0+a/x0)/2; do x0=x1; x1=(x0+a/x0)/2; while(fabs(x0-x1)=1e-5); printf(The square root of %5.2f is %8.5fn,a,x1); return 0; 5-15#include #include

14、 int main() float x0,x1,x2,fx0,fx1,fx2; do printf(enter x1 & x2:); scanf(%f,%f,&x1,&x2); fx1=x1*(2*x1-4)*x1+3)-6; fx2=x2*(2*x2-4)*x2+3)-6; while(fx1*fx20); do x0=(x1+x2)/2; fx0=x0*(2*x0-4)*x0+3)-6; if (fx0*fx1)=1e-5); printf(x=%6.2fn,x0); return 0; 5-16#include int main() int i,j,k; for (i=0;i=3;i+)

15、 for (j=0;j=2-i;j+) printf( ); for (k=0;k=2*i;k+) printf(*); printf(n); for (i=0;i=2;i+) for (j=0;j=i;j+) printf( ); for (k=0;k=4-2*i;k+) printf(*); printf(n); return 0; 6-1#include #include int main()int i,j,n,a101; for (i=1;i=100;i+) ai=i; a1=0; for (i=2;isqrt(100);i+) for (j=i+1;j=100;j+) if(ai!=

16、0 & aj!=0) if (aj%ai=0) aj=0; printf(n); for (i=2,n=0;i=100;i+) if(ai!=0) printf(%5d,ai); n+; if(n=10) printf(n); n=0; printf(n); return 0;6-2#include int main()int i,j,min,temp,a11; printf(enter data:n); for (i=1;i=10;i+) printf(a%d=,i); scanf(%d,&ai); printf(n); printf(The orginal numbers:n); for

17、(i=1;i=10;i+) printf(%5d,ai); printf(n); for (i=1;i=9;i+) min=i; for (j=i+1;jaj) min=j; temp=ai; ai=amin; amin=temp; printf(nThe sorted numbers:n); for (i=1;i=10;i+) printf(%5d,ai); printf(n); return 0; 6-3#include int main()int a33,sum=0;int i,j; printf(enter data:n); for (i=0;i3;i+) for (j=0;j3;j+

18、) scanf(%3d,&aij); for (i=0;i3;i+) sum=sum+aii; printf(sum=%6dn,sum); return 0;6-4#include int main() int a11=1,4,6,9,13,16,19,28,40,100; int temp1,temp2,number,end,i,j; printf(array a:n); for (i=0;iend) a10=number; else for (i=0;inumber) temp1=ai;ai=number;for (j=i+1;j11;j+) temp2=aj; aj=temp1; tem

19、p1=temp2; break; printf(Now array a:n); for (i=0;i11;i+) printf(%5d,ai); printf(n); return 0; 6-5#include #define N 5int main() int aN,i,temp; printf(enter array a:n); for (i=0;iN;i+) scanf(%d,&ai); printf(array a:n); for (i=0;iN;i+) printf(%4d,ai); for (i=0;iN/2;i+) /循环的作用是将对称的元素的值互换 temp=ai; ai=aN

20、-i-1; aN-i-1=temp; printf(nNow,array a:n); for (i=0;iN;i+) printf(%4d,ai); printf(n); return 0; 6-6#include #define N 10int main() int i,j,aNN; for (i=0;iN;i+) aii=1; ai0=1; for (i=2;iN;i+) for (j=1;j=i-1;j+) aij=ai-1j-1+ai-1j; for (i=0;iN;i+) for (j=0;j=i;j+) printf(%6d,aij); printf(n); printf(n);

21、return 0;6-7#include int main() int a1515,i,j,k,p,n; p=1; while(p=1) printf(enter n(n=1-15):); scanf(%d,&n); if (n!=0) & (n=15) & (n%2!=0) p=0; for (i=1;i=n;i+) for (j=1;j=n;j+) aij=0; j=n/2+1; a1j=1; for (k=2;k=n*n;k+) i=i-1; j=j+1; if (in) i=i+2; j=j-1; else if (in) j=1; if (aij=0) aij=k; else i=i

22、+2; j=j-1; aij=k; for (i=1;i=n;i+) for (j=1;j=n;j+) printf(%5d,aij); printf(n); return 0; 6-8#include #define N 4#define M 5 /* 数组为4行5列 */int main() int i,j,k,aNM,max,maxj,flag; printf(please input matrix:n); for (i=0;iN;i+) /* 输入数组 */ for (j=0;jM;j+) scanf(%d,&aij); for (i=0;iN;i+) max=ai0; /* 开始时假

23、设ai0最大 */ maxj=0; /* 将列号0赋给maxj保存 */ for (j=0;jmax) max=aij; /* 将本行的最大数存放在max中 */ maxj=j; /* 将最大数所在的列号存放在maxj中 */ flag=1; /* 先假设是鞍点，以flag为1代表 */ for (k=0;kakmaxj) /* 将最大数和其同列元素相比 */ flag=0; /* 如果max不是同列最小，表示不是鞍点令flag1为0 */ continue; if(flag) /* 如果flag1为1表示是鞍点 */printf(a%d%d=%dn,i,maxj,max); /* 输出鞍点的

24、值和所在行列号 */ break; if(!flag) /* 如果flag为0表示鞍点不存在 */ printf(It is not exist!n); return 0; 6-9#include #define N 15int main() int i,number,top,bott,mid,loca,aN,flag=1,sign; char c; printf(enter data:n); scanf(%d,&a0); i=1; while(i=ai-1) i+; else printf(enter this data again:n); printf(n); for (i=0;iN;i+

25、) printf(%5d,ai); printf(n); while(flag) printf(input number to look for:); scanf(%d,&number); sign=0; top=0; /top是查找区间的起始位置 bott=N-1; /bott是查找区间的最末位置 if (numberaN-1) /要查的数不在查找区间内 loca=-1; / 表示找不到 while (!sign) & (top=bott) mid=(bott+top)/2; if (number=amid) loca=mid; printf(Has found %d, its positi

26、on is %dn,number,loca+1); sign=1; else if (numberamid) bott=mid-1; else top=mid+1; if(!sign|loca=-1) printf(cannot find %d.n,number); printf(continu or not(Y/N)?); scanf( %c,&c); if (c=N|c=n) flag=0; return 0; 6-10#include int main() int i,j,upp,low,dig,spa,oth; char text380; upp=low=dig=spa=oth=0;

27、for (i=0;i3;i+) printf(please input line %d:n,i+1); gets(texti); for (j=0;j=A& textij=a & textij=0 & textij=9) dig+; else if (textij= ) spa+; else oth+; printf(nupper case: %dn,upp); printf(lower case: %dn,low); printf(digit : %dn,dig); printf(space : %dn,spa); printf(other : %dn,oth); return 0;6-12

28、a-c#include int main() int j,n; char ch80,tran80; printf(input cipher code:); gets(ch); printf(ncipher code :%s,ch); j=0; while (chj!=0) if (chj=A) & (chj=a) & (chj=z) tranj=219-chj; else tranj=chj; j+; n=j; printf(noriginal text:); for (j=0;jn;j+) putchar(tranj); printf(n); return 0; 6-12b#include

29、int main() int j,n; char ch80; printf(input cipher code:n); gets(ch); printf(ncipher code:%sn,ch); j=0; while (chj!=0) if (chj=A) & (chj=a) & (chj=z) chj=219-chj; else chj=chj; j+; n=j; printf(original text:); for (j=0;jn;j+) putchar(chj); printf(n); return 0; 6-13#include int main() char s180,s240;

30、 int i=0,j=0; printf(input string1:); scanf(%s,s1); printf(input string2:); scanf(%s,s2); while (s1i!=0) i+; while(s2j!=0) s1i+=s2j+; s1i=0; printf(nThe new string is:%sn,s1); return 0; 7-1-1#include int main() int hcf(int,int); int lcd(int,int,int); int u,v,h,l; scanf(%d,%d,&u,&v); h=hcf(u,v); prin

31、tf(H.C.F=%dn,h); l=lcd(u,v,h); printf(L.C.D=%dn,l); return 0; int hcf(int u,int v)int t,r; if (vu) t=u;u=v;v=t; while (r=u%v)!=0) u=v; v=r; return(v);int lcd(int u,int v,int h) return(u*v/h); 7-3#include int main() int prime(int); int n; printf(input an integer:); scanf(%d,&n); if (prime(n) printf(%d is a prime.n,n); else printf(%d is not a prime.n,n); return 0; int prime(int n) int flag=1,i; for (i=2;in/2 & flag=1;i+) if (n%i=0)