谭浩强《C++面向对象程序设计》第二章答案.doc

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1、【精品文档】如有侵权，请联系网站删除，仅供学习与交流谭浩强C+面向对象程序设计第二章答案.精品文档.第二章1#include using namespace std;class Timepublic:void set_time();void show_time();private: /成员改为公用的 int hour; int minute; int sec;void Time:set_time() /在main函数之前定义 cinhour; cinminute; cinsec;void Time:show_time() /在main函数之前定义 couthour:minute:secendl

2、;int main()Time t1;t1.set_time(); t1.show_time(); return 0; 2：#include using namespace std;class Time public: void set_time(void) cinhour; cinminute; cinsec; void show_time(void) couthour:minute:secendl; private: int hour; int minute; int sec;Time t;int main() t.set_time(); t.show_time(); return 0;

3、3：#include using namespace std;class Time public: void set_time(void); void show_time(void); private: int hour; int minute; int sec;void Time:set_time(void) cinhour; cinminute; cinsec;void Time:show_time(void)couthour:minute:secendl;Time t;int main() t.set_time(); t.show_time(); return 0;4：/xt2-4-1.

4、cpp(main.cpp)#include using namespace std;#include xt2-4.hint main()Student stud; stud.set_value(); stud.display(); return 0;/xt2-4-2.cpp(即student.cpp)#include xt2-4.h /在此文件中进行函数的定义#include using namespace std; /不要漏写此行void Student:display( ) coutnum:numendl; coutname:nameendl; coutsex:sexnum; cinnam

5、e; cinsex;5：/xt2-5-1.cpp(file1.cpp)#include #include xt2-5.hint main() Array_max arrmax; arrmax.set_value(); arrmax.max_value(); arrmax.show_value(); return 0;/xt2-5-2.cpp(arraymax.cpp)#include using namespace std;#include xt2-5.hvoid Array_max:set_value() int i; for (i=0;iarrayi;void Array_max:max_

6、value() int i; max=array0; for (i=1;imax) max=arrayi;void Array_max:show_value() coutmax=maxendl;6：解法一#include using namespace std;class Boxpublic: void get_value(); float volume(); void display(); public: float lengh; float width; float height;void Box:get_value() coutlengh; cinwidth; cinheight;flo

7、at Box:volume() return(lengh*width*height);void Box:display() coutvolume()endl;int main()Box box1,box2,box3; box1.get_value(); coutvolmue of bax1 is ; box1.display(); box2.get_value(); coutvolmue of bax2 is ; box2.display(); box3.get_value(); coutvolmue of bax3 is ; box3.display(); return 0;解法二：#inc

8、lude using namespace std;class Boxpublic: void get_value(); void volume(); void display(); public: float lengh; float width; float height; float vol;void Box:get_value() coutlengh; cinwidth; cinheight;void Box:volume() vol=lengh*width*height;void Box:display() coutvolendl;int main()Box box1,box2,box3; box1.get_value(); box1.volume(); coutvolmue of bax1 is ; box1.display(); box2.get_value(); box2.volume(); coutvolmue of bax2 is ; box2.display(); box3.get_value(); box3.volume(); coutvolmue of bax3 is ; box3.display(); return 0;