BJT双极型晶体管.ppt
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1、Slide 8-28.1 Introduction to the BJTIC is an exponential function of forward VBE and independent of reverse VCB.Modern Semiconductor Devices for Integrated Circuits (C. Hu)N+ PNemittercollector base VBEVCB-EfnEfpVCBVBE(a)(b)(c)VBE IC0VCBBCEEcEvEfnNPN BJT:N+ PNECB VBEVCBEmitterBaseCollectorSlide 8-3C
2、ommon-Emitter ConfigurationQuestion: Why is IB often preferred as a parameter over VBE? Modern Semiconductor Devices for Integrated Circuits (C. Hu)Slide 8-4Semiconductor Devices for Integrated Circuits (C. Hu)8.2 Collector CurrentBBBBDLLndxnd222 B : base recombination lifetime DB : base minority ca
3、rrier (electron) diffusion constant Boundary conditions :) 1()0(/0kTqVBBEenn0) 1()(0/0BkTqVBBnenWnBCN+ PN emitter basecollectorx0 W depletion layersBSlide 8-5BBBBkTqVBLWLxWenxnBE/sinhsinh) 1()(/0) 1(/2kTqVBiBBBEBECBEeNnWDqAdxdnqDAI) 1(/kTqVSCBEeIIBBEWBiBiBkTqVBiECdxDpnnGeGqnAI022/2) 1(It can be show
4、nGB (scm4) is the base Gummel number8.2 Collector Currentni2NB-eqVBEkT1nn 0-)0(/ )(nxn011) 1()(/2kTqVBiBBEeNnxn x/x/WB)/1)(1()/1)(0()(/2BkTqVBiBBWxeNnWxnxnBEModern Semiconductor Devices for Integrated Circuits (C. Hu)Slide 8-6At low-level injection, inverse slope is 60 mV/decadeHigh-level injection
5、effect :8.2.1 High Level Injection Effect00.2 0.4 0.6 0.8 1.0 10-12 10-10 10-8 10-6 10-410-2 VBEIC (A)IkF60 mV/decadeAt large VBE, BNpnpnpnkTqViBEenpn2/kTqViBBEenpG2/kTqViBEenI2/CWhen p NB , inverse slope is 120mV/decade.kTqVikTEEqiBEFpFnenennp/2/ )(2Modern Semiconductor Devices for Integrated Circu
6、its (C. Hu)Slide 8-78.3 Base CurrentSome holes are injected from the P-type base into the N+ emitter.The holes are provided by the base current, IB .pE nBWE WB(b) emitter basecollectorcontact IE ICelectron flow +hole flowIB(a)contactModern Semiconductor Devices for Integrated Circuits (C. Hu)Slide 8
7、-8EBEWEiEiEkTqVEiEBdxDnnnGeGqnAI022/2) 1(Is a large IB desirable? Why?8.3 Base Current emitter basecollectorcontact IE ICelectron flow +hole flowIB(a)contactModern Semiconductor Devices for Integrated Circuits (C. Hu) 1(/2kTqVEEiEEEBBEeNWnDqAIFor a uniform emitter,Slide 8-98.4 Current GainBCFIIHow c
8、an F be maximized?Common-emitter current gain, F :Common-base current gain:FFBCBCCBCECFEFCIIIIIIIIIII1/1/It can be shown that FFF122iEBBEiBEEBBEFnNWDnNWDGGModern Semiconductor Devices for Integrated Circuits (C. Hu)Slide 8-10EXAMPLE: Current GainA BJT has IC = 1 mA and IB = 10 mA. What are IE, F and
9、 F?Solution: 9901. 0mA 01. 1/mA 1/100A 10/mA 1/mA 01. 1A 10mA 1ECFBCFBCEIIIIIIIWe can confirm FFF1FFF1andModern Semiconductor Devices for Integrated Circuits (C. Hu)Slide 8-118.4.1 Emitter Bandgap NarrowingEmitter bandgap narrowing makes it difficult to raise F by doping the emitter very heavily.Mod
10、ern Semiconductor Devices for Integrated Circuits (C. Hu)22iEiBBEnnNNTo raise F, NE is typically very large. Unfortunately, large NE makes22iiEnn(heavy doping effect).kTEVCigeNNn/2Since ni is related to Eg , this effect is also known as band-gap narrowing. kTEiiEgEenn/22EgE is negligible for NE 1018
11、 cm-3, is 50 meV at 1019cm-3, 95 meV at 1020cm-3, and 140 meV at 1021 cm-3.Slide 8-1222iEiBBEnnNNTo further elevate F , we can raise niB by using an epitaxial Si1-hGeh base.With h = 0.2, EgB is reduced by 0.1eV and niE2 by 30 x.8.4.2 Narrow-Bandgap Base and Heterojuncion BJTModern Semiconductor Devi
12、ces for Integrated Circuits (C. Hu)Slide 8-13Assume DB = 3DE , WE = 3WB , NB = 1018 cm-3, and niB2 = ni2. What is F for (a) NE = 1019 cm-3, (b) NE = 1020 cm-3, and (c) NE = 1020 cm-3 and a SiGe base with EgB = 60 meV ?(a) At NE = 1019 cm-3, EgE 50 meV,(b) At NE = 1020 cm-3, EgE 95 meV(c) 292. 12meV
13、26/meV 502/228 . 6iiikTEiiEnenenenngE138 . 61010921821922iiiEBiEBEEBFnnnNnNWDWD2238iiEnn24F2meV 26/meV 602/2210iikTEiiBnenenngB237FEXAMPLE: Emitter Bandgap Narrowing and SiGe BaseModern Semiconductor Devices for Integrated Circuits (C. Hu)Slide 8-14A high-performance BJT typically has a layer of As-
14、doped N+ poly-silicon film in the emitter. F is larger due to the large WE , mostly made of the N+ poly-silicon. (A deep diffused emitter junction tends to cause emitter-collector shorts.) N-collector P-baseSiO2 emitter N+-poly-Si8.4.3 Poly-Silicon EmitterModern Semiconductor Devices for Integrated
15、Circuits (C. Hu)Slide 8-15Why does one want to operate BJTs at low IC and high IC?Why is F a function of VBC in the right figure?FFrom top to bottom:VBC = 2V, 1V, 0V8.4.4 Gummel Plot and F Fall-off at High and Low IcHint: See Sec. 8.5 and Sec. 8.9.SCR BE currentModern Semiconductor Devices for Integ
16、rated Circuits (C. Hu)Slide 8-168.5 Base-Width Modulation by Collector VoltageOutput resistance :CACECIVVIr10Large VA (large ro ) is desirable for a large voltage gainIB3ICVCE0VAVA : Early VoltageIB2IB1Modern Semiconductor Devices for Integrated Circuits (C. Hu)Slide 8-17How can we reduce the base-w
17、idth modulation effect?8.5 Base-Width Modulation by Collector VoltageN+ PN emitter basecollector VCE WB3WB2WB1 xn VCE1 VCE2VCE3 VBEModern Semiconductor Devices for Integrated Circuits (C. Hu)Slide 8-18The base-width modulation effect is reduced if we(A) Increase the base width,(B) Increase the base
18、doping concentration, NB , or(C) Decrease the collector doping concentration, NC .Which of the above is the most acceptable action? 8.5 Base-Width Modulation by Collector VoltageN+ PN emitter basecollector VCE WB3WB2WB1 xn VCE 1 VCE2VCE3 VBEModern Semiconductor Devices for Integrated Circuits (C. Hu
19、)Slide 8-198.6 Ebers-Moll ModelThe Ebers-Moll model describes both the active and the saturation regions of BJT operation.Modern Semiconductor Devices for Integrated Circuits (C. Hu) IB IC0VCEsaturationregionactive regionSlide 8-20IC is driven by two two forces, VBE and VBC .When only VBE is present
20、 : ) 1() 1(/kTqVFSBkTqVSCBEBEeIIeIINow reverse the roles of emitter and collector.When only VBC is present :) 1)(11 () 1() 1(/kTqVRSBECkTqVRSBkTqVSEBCBCBCeIIIIeIIeIIR : reverse current gainF : forward current gain8.6 Ebers-Moll ModelICVBCVBEIB E BCModern Semiconductor Devices for Integrated Circuits
21、 (C. Hu)Slide 8-21) 1() 1() 1)(11 () 1(/kTqVFSkTqVFSBkTqVRSkTqVSCBCBEBCBEeIeIIeIeIIIn general, both VBE and VBC are present :In saturation, the BC junction becomes forward-biased, too. VBC causes a lot of holes to be injected into the collector. This uses up much of IB. As a result, IC drops.VCE (V)
22、8.6 Ebers-Moll ModelModern Semiconductor Devices for Integrated Circuits (C. Hu)Slide 8-228.7 Transit Time and Charge Storage CFFIQWhen the BE junction is forward-biased, excess holes are stored in the emitter, the base, and even in the depletion layers. QF is all the stored excess hole charge F det
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