2022年电力拖动自动控制系统-第四版-课后答案 .pdf

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1、习题解答 ( 供参考)习题二r/min An = % (_$) = 1000 x0.02/(10 x 0.98) = 2.04r/mi 2.04rp/n Ce = (UN 一/v/?J/nv = (220-378 x 0.023)/1430 = 0.1478V/pm A/2 = I NR/Ce = 378 x (0.023 + 0.022)/0.1478 = 1 5rprn D = n NS/A/Z(I- s) = 1430 x 0.2/115x(1-0.2) = 3D = n NS/A(I-S) = 1430 x0.3/115x (1-0.3) = 5.33 ?omax =1500r/min

2、 =150r/min A/g = 15r/min 为=?max/%in ?max = % max - = 1500-15 = 1485 Hmin = /70min 一=150-15 = 135 D = max /min =】485/135 = 11 s = A/i v/n0 = 15/150 = 10% 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 1 页，共 25 页 - - - - - - - - - nN = I N xR/Ce = 305x0.18/0.2 = 274.5r

3、/min SN = 2 卞/no = 274.5/(1000 + 274.5) = 21.5% An = n NS/D(-S) = 1000 x0.05/20 x0.95 = 2.63 ” minA*=8.8V Kp = 2Ks=5Ud U d U: Ud = K pKsU(/(I + KpKsy = 2x 15x &8/(1 + 2 x 15 x 0.7) = 1 2V Ud =8.8x2x15 = 264V q； =Ud(l + K/,Ky)/K K$ =12x(l + 2xl5x0.35)/(2xl5)=4.6U $55% D = n Ns/Aii N(-S) 10 = 1500X2%/

4、A x98% 沁=1500X2%/98%X10= 3.06r / min K =(4 切/4 如)一1 = 100 /3.06 -1 = 31.7 M 仲=(1 + K)g = (1 + 15)x8 = 128 Ancl = f /(1 + K)= 128 /(1 + 30) = 4A3rpm % /A/i d2 = 1.937 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 2 页，共 25 页 - - - - - - - - - =C = (220-12.5x1.5)/1500

5、= 201.25/1500 = 0.134Vmin/ r n = (U N-lNxRz)/Cf名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 3 页，共 25 页 - - - - - - - - - A?jv = nNs/(D(1-5) = 1500X10%/(20 * 90%) = 8.33r / min A/ic/ =8.33/7 min n =( K “KQ -胡/(Ce(l + K )= KU : /a(l + K)-l dR/(Ce(l + K) 1500 = 35.955

6、 xl5/a(l + 35.955)-12.5 x 3.3 / ( 0.134(1 + 35.955) =a = 0.0096V min/ r =35.955534 十.34 35*0.0096 小匕=3牛二禽“01K = (s / /) 1 = 307.836 / 8.33 -1 二35.955 -J.R 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 4 页，共 25 页 - - - - - - - - - Kc = KCe/K、a Kp = 35.955x0.134/(35x0

7、.01) = 13.76 hbl - 21N her - l ? 2g 【dbl 21N = 25A ? 2IN = 154 dcr = U com / R$ 15 = U com / R$ 1 血也+/ 舄/ 心=25 = (15 + / M/& nR, =1.5Q % = 15x1.5 = 22.5V (冬/3) = (1? 0 + 1? 5 + 0? 8)/3 = 1C, 7?v(/?z/3) 不符合要求，取R, =1.10需加电流反馈放大器/?v=l.lQt/_ =/dirx/?f=15xLl = 16.5V名师资料总结 - - -精品资料欢迎下载 - - - - - - - - -

8、- - - - - - - - - 名师精心整理 - - - - - - - 第 5 页，共 25 页 - - - - - - - - - 1 d dcr =K pK5U ; ICeA+ K) _KpK5KXRsId -%)/C (l + K)-弘?(1 + K ) =k , K$(S ; + KQs )/3, (l + K) (/? + K “K$KR(Q(l + K)G = K$ (U ; + / (R + KpK、KK)w(U : + K,U cafi)/K,A 25 = (I5 + 16? 5Kr)/lKr=&15/(22? 5-13.5) = l? 36 GD2 = 1.6Nm2L

9、= 50mH GD 2 =.6Nm2饨=3? 3G Ce =QA?AV I rpm + 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 6 页，共 25 页 - - - - - - - - - 7; = 口？，=0.05/33 = 0.0155 7; =GD2/?X/(375C,CW) = 1.6X33/(375X0.134X0.134X30/3.14) =5.28/64.33 = 0.082$ Ti =0.003335 K 7; (7; 4-T) + T2/TT = 0.082X(

10、0.015 + 0.00333) + O.OO333 2/(0.0151*0.00333) = 0.0015 + 0.003332 / 0.00004983 = 30.52 PN = 2.8MV UN = 22(V IN = 15.6A nN =1500 Ra Rtec RL Ks = 35 D = 30s D = 305 = 10% D = 30 5 = 10% Un = 10V I & = I & 奸=N a K p Ce =(220-15.6X1.5)/1500 = 0.1311Vnin/ r % = 7vx/?z/q, = 15.6X3.3/0.1311= 392.68r / min

11、怙=1500/30 = 50 s = An? / A/? Omin = 392.68 / (392.68 + 50) = 88.7% 0=A/z / (A/t + 50) An = 5/0.9 = 5.56/7 min “=K pKsU ; /Q( l + K)-RzId/Ce(l + K) K = K paKs/Ce 1500 =KpKQ; /C,(1 + K)-(饨15.6)/C。(1 + K) K = ( %, / )-1 =(297.48/5.56)-1=52.5 f= 1MHz n = 1500i7min n = 150r/min 60 60 = - =1.465 r / nin 1

12、024 X4X0.01名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 7 页，共 25 页 - - - - - - - - - nZT(? _ 1500 x4x 1024x0.01 - =-=1UZ4 60 60ZTc n = 150/7 n = 150/7 min nZT(. _ 150 x4x1024x0.01 - = - 60 60 =1 UZ.4 1500,7mh1A% = Xxi0 0% = i xlOO% = 0.098% 15Or/mmJnHx% = Axioo% =

13、_A_xlOO% = O.98% n = 1500/7 min Q = Zn26O.fo Z 1024x4x150()2 . - - =171/7 min 60 xlxl06-1025x4xl500 g 工 工一102tx4xl5()2= 1.55r/min 60/o-Zn 60 xlxl0 6-1024x4x150 /Z=604A=604 ZM2 一Zn n 二二1500/7min M. = - =9.77 ? 1024 x4x1500 n = 二150/7 min M = = - =97.7 -1024 x4xl50 n = 二1500/7 min % =! x 100 % = ! - x

14、 100 % = 11.4% 60 x 106叽-1 9/77-1 n 二150/7 min % = 一! x 100 % = !- - x 100 % = 二,mxMA-| 97.7-1 习题二n = 1500/7 mill 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 8 页，共 25 页 - - - - - - - - - Hep$ II3.75b IIIIK, K, o.olv 盲丁0.3751 IIId CUiIS 375 rpm all 15V 20 127 500 1

15、0 175v 500w= 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 9 页，共 25 页 - - - - - - - - - c n m U c U c U + d e H E uu y 7 M Udo 0aH40A* HOu ? L 2 o 厂V/ AUMM. w 5QH60v Q U N L P N U U OC U 3II * 40 5 OC A F 5 0 ?Hudo/KS o H looow* u H 60*40 , 0 udoHE U . OC H 5 + 0 0

16、W LR W . N 1.5V 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 10 页，共 25 页 - - - - - - - - - r) trKT = 0.69,农=0.6, T% = 9.5% (1) K = 0.69 / T = 0.69/0.1 = 6.9(1 / s) (2) tr = 3.3T = 0.33S r5 A = 67 = 6x0.1 = 0.65 现6.9 tr 0.25s KT = 1 = 0.5 tr = 2AT = 2.4*0.1 = 0.245

17、K = 1 /T = 10 K 0.015+1 l匕引 )= zs +1 10 KT = 0.5, t =0.707. 查表3-1,得|n% 9ZH?OS.OX-.OX8.OXOX-.OXO-.OXOOS.OX1H室o.9g9NoH(z999ZOOX6Xz)f寸七_Jez&f(一+goo66zooH_NHqHut-gNzHCOCOCOL0XZ00039LH。蓄NLOX96MLOIX9COIW/寸6.9H60X9E(L+只)00爵TPLOHuzHljHuloHcrEjzHqIIs999zoongLOo+99LLOonE)H+wlruzHosg5o&S99LOOHcooogoooxvNHvW gE

18、ZHxrxA(e名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 13 页，共 25 页 - - - - - - - - - b ” = 2 x 72.2% xl.lx (308 x0.18/0.196xl 000) x (0.02666 / 0.12) = 9.97% 10%R = 40K Rn = Kn XRQ = 7.6x40 = 304AT C, = r, / Rti =0.07998/310 x10 =0.258 “FCon =4: /他=4x0.015/40 x10 =1?

19、 5 F 6 % = 2 x 72.2% x (1 ? 1 一0.4) x (308 x0.18/0.196xl00)x (0.02666 /0.12) = 63.5% 根据电机=CJJE U = CJmn 0,196* 0.12*1 0.385. 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 14 页，共 25 页 - - - - - - - - - 10 ?75 aut=0.0267V min/ r %名师资料总结 - - -精品资料欢迎下载 - - - - - - - - -

20、 - - - - - - - - - 名师精心整理 - - - - - - - 第 15 页，共 25 页 - - - - - - - - - a) Ts =0.001765 b) Toi = 0.0025 c) 7L. = 0.003675 T/Tzi=n Amax 心(q$ + l)/(福 $ + 1)名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 17 页，共 25 页 - - - - - - - - - 习题五叫号(2 1) SUA UB s 叫Us =(UA + UnelY

21、 +Ucd2/) 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 18 页，共 25 页 - - - - - - - - - “Cwo Ud 2 _匕2 2 W1 Ud 2 一经2 Ud 2 匕2 5 2 5 2 怜?3 ( 匕2 Ud 2 Ud 2 W4匕2 Ud 2 ? Ud 2 加W5 匕2 一冬2 匕2 W6 匕2 _匕2 匕2 M7 A 匕2 Ud 2 5 2 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - -

22、名师精心整理 - - - - - - - 第 19 页，共 25 页 - - - - - - - - - zod(_*由)-J名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 20 页，共 25 页 - - - - - - - - - 开关周期7;)= 一T, 3Nw) Us l,? .? Us = -?! + + 上Si?上? I J * I if U* FW* * (0 *0 *0 (0 .f2 T习题六上2 V3 T 2 T. SeOS?) iB =人S (期一斗 )ic = I

23、 m cos ( 期+ 年)isa iifi输出频率州? 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 21 页，共 25 页 - - - - - - - - - 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 22 页，共 25 页 - - - - - - - - - 匚+y=o cos? sin o = d(p Jq 不=? =叫i、q 1 . 21, cos? 0

24、x/3. ，-c cos(co t) 2 ：2*2JF-eos(cot) 2 V t丰e同一厂g e A?-sinV 3 0 /3. 3 z、3 广cos( Q/) 2 、in(兰)sin(如=11/ ( 期)V2 mLsin(twz) ha 2Ac 0 L 2 1 2 V3 2 J co st cot)B2/T-co s(在V I2cos( Cdt +名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 23 页，共 25 页 - - - - - - - - - A. - 忖COS( Q

25、/- 0) sin(M - 0). 0 PN=3kW /7jv =380V g =6.9 A Z7jv = 1400 r/min /jv =50 Hz & =1 ? 85C 15005 Rr = 2.658Q L、= 0.294 H Lr= 0.2898 H Lm = 0.2838 H J=0.1284kg ? m2如一工R4A i dt Tr 1 Tr w =丛s T亦警i = 0 咖=L,uismCOS0 sin 二巨电8s(pcC0( 翳)+ nrLn( er) d(p H=JI4_ 忍力)+ si n 0 si cos 0wi n( ef) - si n( pcOc cot) sin?

26、 J cos(a) t) cos? *1 魏涉一P) sin 伽一0) 矿？I15 i sm i5l |z,=/3x6.9A 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 24 页，共 25 页 - - - - - - - - - nwx 2.2835H1007TX0.2898152.658JUnJ-+2.28352WH2.4931X6.9 TVG3X6.9一s- 2.2835、H2.2835X4.79H1P937A亏LmismnP2838X479H1?359wb名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 25 页，共 25 页 - - - - - - - - -