SPSS第二次作业.doc

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1、1.SPSS规定：当样本含量时，结果以Shapiro-Wilk为准。当样本含量时，结果以K-S为准。正态性检验结果显示,其中粤东对应的Shapiro-Wilk检验P值为0.005，所以，粤东的数据分布不服从正态的。同理，粤西的数据也不服从正态分布。Case Processing Summary地区CasesValidMissingTotalNPercentNPercentNPercent降雨量粤东12100.0%0.0%12100.0%粤西12100.0%0.0%12100.0%Descriptives地区StatisticStd. Error降雨量粤东Mean1617.85883.53029

2、5% Confidence Interval for MeanLower Bound1434.010Upper Bound1801.7075% Trimmed Mean1597.287Median1499.450Variance83727.544Std. Deviation289.3571Minimum1369.1Maximum2236.9Range867.8Interquartile Range449.7Skewness1.348.637Kurtosis.4871.232粤西Mean1851.433136.919195% Confidence Interval for MeanLower B

3、ound1550.076Upper Bound2152.7905% Trimmed Mean1855.265Median1922.800Variance224962.059Std. Deviation474.3017Minimum1222.6Maximum2411.3Range1188.7Interquartile Range926.9Skewness-.147.637Kurtosis-2.0071.232M-Estimators地区Hubers M-EstimatoraTukeys BiweightbHampels M-EstimatorcAndrews Waved降雨量粤东1506.267

4、1464.4891485.2661464.489粤西1862.4581860.4691851.4331860.534a. The weighting constant is 1.339.b. The weighting constant is 4.685.c. The weighting constants are 1.700, 3.400, and 8.500d. The weighting constant is 1.340*pi.Extreme Values地区Case NumberValue降雨量粤东Highest132236.9262040.93101947.9471593.6581

5、517.4Lowest111369.1251409.03121409.64111409.7521481.3粤西Highest1142411.32182344.33222314.54132274.05232263.3Lowest1171222.62191266.43241372.44201392.65151510.2Tests of Normality地区Kolmogorov-SmirnovaShapiro-WilkStatisticdfSig.StatisticdfSig.降雨量粤东.30212.003.77512.005粤西.22412.098.84912.036a. Lilliefors

6、Significance Correction2.个案处理结果Case Processing SummaryCasesValidMissingTotalNPercentNPercentNPercent升学 * 计数4100.0%0.0%4100.0%交叉表升学 * 计数 Crosstabulation计数Total16276131143升学0Count11002% within 升学50.0%50.0%.0%.0%100.0%升学Count00112% within 升学.0%.0%50.0%50.0%100.0%TotalCount11114% within 升学25.0%25.0%25.0

7、%25.0%100.0%3不同性别学生之间成绩分析，F统计量的Sig值为0.529大于0.10，所以不可否认方差相等的假设，第一行t检验的值为0.064小于0.10，所以在显著性水平0.10下，认为该班高考不同性别学生成绩无明显差异。Group Statistics性别NMeanStd. DeviationStd. Error Mean高考数学成绩男16126.8811.4542.863女16119.889.0182.254Independent Samples TestLevenes Test for Equality of Variancest-test for Equality of M

8、eansFSig.tdfSig. (2-tailed)Mean DifferenceStd. Error Difference95% Confidence Interval of the DifferenceLower高考数学成绩Equal variances assumed.407.5291.92130.0647.0003.644-.443Equal variances not assumed1.92128.434.0657.0003.644-.4605.描述性统计量Descriptive StatisticsNPercentiles25th50th (Median)75th成绩2838.2

9、50062.500078.5000国家281.252.503.75频数表Frequencies国家A国B国C国D国成绩 Median7700 Median105093105= Median0510179105最后是检验统计量,可以得到卡方统计量为43.275,其对应的P值小于0.05 所以拒绝原假设,即认为这八种饮料的顾客喜爱程度具有显著的差异.Test Statisticsb喜爱程度N80Median7.0000Chi-Square43.275adf7Asymp. Sig.000a. 8 cells (50.0%) have expected frequencies less than 5.

10、 The minimum expected cell frequency is 4.1.b. Grouping Variable: 饮料种类7.描述性的统计量Descriptive StatisticsNMeanStd. DeviationMinimumMaximum每加仑汽油行驶英里数1520.1472.227416.023.1游程检验结果显示,每加仑汽油行驶英里数标志值的游程为5,由样本计算的检验统计量Z为-1.597,P值为0.110,大于0.05,接受原假设, 即认为这5种的差异不明显。Runs Test每加仑汽油行驶英里数Test Valuea20.147Cases = Test V

11、alue8Total Cases15Number of Runs5Z-1.597Asymp. Sig. (2-tailed).110a. Mean8. K-S检验结果的KOS统计量为1.200，对应的P值为0.112大于0.05，所以接受原假设，认为这50名高二学生身高服从正态分布。Descriptive StatisticsNMeanStd. DeviationMinimumMaximum身高50169.726.993154181One-Sample Kolmogorov-Smirnov Test身高N50Normal Parametersa,bMean169.72Std. Deviatio

12、n6.993Most Extreme DifferencesAbsolute.170Positive.078Negative-.170Kolmogorov-Smirnov Z1.200Asymp. Sig. (2-tailed).112a. Test distribution is Normal.b. Calculated from data.9.有单因素方差分析检验不同包装对饮料销售水平的影响。Levene统计量取值为0.031，Sig取值为0.862，大于0.05，所以认为各组的方差相等。方差分析表显示Sig取值为0.512，即假设成立，认为各组均值没有差异。Descriptivesvol

13、umeNMeanStd. DeviationStd. Error95% Confidence Interval for MeanMinimumMaximumLower BoundUpper Bound包装a11034.000021.187006.6999218.843749.156310.0070.00包装a21040.000018.856185.9628526.511153.488910.0070.00Total2037.000019.761744.4188627.751246.248810.0070.00Test of Homogeneity of VariancesvolumeLeven

14、e Statisticdf1df2Sig.031118.862ANOVAvolumeSum of SquaresdfMean SquareFSig.Between Groups180.0001180.000.448.512Within Groups7240.00018402.222Total7420.00019由单因素方差分析检验不同口味对饮料销售水平的影响。Levene统计量取值为0.015，Sig取值为0.904，大于0.05，所以认为各组的方差相等。方差分析表显示Sig取值为0.009，即假设不成立，认为各组均值有差异。所以认为饮料口味对销售水平影响更大。Descriptivesvolu

15、meNMeanStd. DeviationStd. Error95% Confidence Interval for MeanMinimumMaximumLower BoundUpper Bound口味b11026.000016.465455.2068314.221337.778710.0050.00口味b21048.000016.865485.3333335.935260.064830.0070.00Total2037.000019.761744.4188627.751246.248810.0070.00Test of Homogeneity of VariancesvolumeLevene

16、 Statisticdf1df2Sig.015118.904ANOVAvolumeSum of SquaresdfMean SquareFSig.Between Groups2420.00012420.0008.712.009Within Groups5000.00018277.778Total7420.000191016规 0本. 量 结0.以 0 0 .0.0 当 本 结 0 正 性 结 示 其 东 00 0验0 为00. 0 以 粤 00 据 0布0 从 的0 理00 的 也 服 布布 大更水对味认。异值为成设 .值 显分方差组为，0大 0值 0值量 响平料味同析差 00 0. 0.0.

17、 00 00 00 00 00 0 00 异有均为立假， 为 显表差相组为， 大 0值 0值计 影水销对不检方素 ( 0 , 身 - . 身 布分服身学 这，接，.大 0值，0.计 果 - . = . 里英汽 显不差这即设受接.于 0, 量验检样 为志里英仑,示. . 里驶行 . 计性种饮 %0( 0 -00 程 异差显度喜料种为设绝所0于 应 .为计卡以计验 程料料料料料料料料种 数0 0000 种0 000 程 计统国 . )0( 0 00 -0 成 性性显具的国认假原所 0的应, 量统到,计检 成 国 数 国0 000 成 ( 计计 0 . 0 0 成学数 - . . 成成 . 性 异显绩生性考该下.水显所 于小0为 行假等认可，.大 为 统，成学同0.0000升升 0.0000升升 升0.0000升升 升 计 叉0.00.0计 结结 粤0 0 0粤雨 - 地 .0 . . . . . . . . . 粤. . . . . . . . .0. 粤雨 地 * 0. 0 , . . 粤 . .粤雨 地 00. . . . . . 0 00 . . . 粤 . . . . . . 0. 0 0 . 粤雨 . 地 0. 000 粤0.0 00. 粤雨 地