2022年2022年拱坝ansys命令流 .pdf

《2022年2022年拱坝ansys命令流 .pdf》由会员分享，可在线阅读，更多相关《2022年2022年拱坝ansys命令流 .pdf（11页珍藏版）》请在淘文阁 - 分享文档赚钱的网站上搜索。

1、某砌石拱坝位于U 型河谷中，坝高55.5m，为单曲等厚拱坝，顶宽5m，底宽 16m，坝顶弧长 115.65m，弧高比 2.1。首先输入基本参数，自底向上生成坝体。!坐标系原点位于拱坝轴线与拱坝参考面的交点在坝基的投影， X轴指向右岸，Y轴指向下游，Z轴铅直向上 ! 单位 :长度 -M,力-KN,加速度 -M/S, 密度 -KN/M3 ! ! FINI!退出当前处理器/CLEAR,START /FILNAME,ARCHDAM,1!指定新的工作文件名/PLOPTS,DATE,0 /TRIAD,LBOT /VIEW,1,1,1,1 /VUP,1,Z *AFUN,DEG Z_UP=53 !上游水位Z_

2、DOWN=0 !下游水位Z_SAND=38 ! 泥沙淤积水位DENS_SAND=0.6 ! 淤积泥沙浮容重ANG_FRI=16 !淤积泥沙内摩擦角LAYER_NUM=8 ! 定义拱层数*DIM,ELEVATION,ARRAY,LAYER_NUM ! 定义拱圈高程*DIM,T_ARCH,ARRAY ,LAYER_NUM ! 定义拱厚*DIM,ARCH_RAD,ARRAY ,LAYER_NUM,2 ! 定义圆弧半径，上下游*DIM,RAD_CEN,ARRAY ,LAYER_NUM ! 定义圆弧中心Y值*DIM,ARCH_ANGLE,ARRAY,LAYER_NUM,2 ! 定义圆弧左右中心角ELEV

3、ATION(1)=55.5,47,39,29,24,19,9,0 ! 拱圈高程H_DAM=ELEVATION(1)-ELEVATION(LAYER_NUM) !坝高T_ARCH(1)=5.00,6.68,8.27,10.25,11.24,12.23,14.22,16.00 ! 拱厚ARCH_RAD(1,1)=68.00,68.00,68.00,68.00,68.00,68.00,68.00,68.00 ! 外半径*VOPER,ARCH_RAD(1,2),ARCH_RAD(1,1),SUB,T_ARCH(1) !计算内半径RAD_CEN(1)=68.00,68.00,68.00,68.00,68

4、.00,68.00,68.00,68.00 ! 圆心位置 ,Y坐标ARCH_ANGLE(1,1)=-47.72,-46.36,-45.06,-43.36,-41.88,-40.38,-37.32,-34.48 !左中心角ARCH_ANGLE(1,2)=49.73,47.13,44.68,41.57,40.44,39.29,36.92,35.72 !右中心角W_DAM1=-ARCH_RAD(1,1)*SIN(ARCH_ANGLE(1,1) ! 坝顶左弦长W_DAM2=ARCH_RAD(1,1)*SIN(ARCH_ANGLE(1,2) ! 坝顶右弦长LOCAL,11,1,0,RAD_CEN(1),

5、ELEVATION(1),-90 !局部柱面坐标,原点位于顶拱圆心,X 轴为拱坝中心线 ,指向上游 ,Y轴为中心角!为查值计算坝体温度，重新定义一套数组*DIM,TEMPUP,TABLE,LAYER_NUM ! 上游面温度*DIM,TEMPDOWN,TABLE,LAYER_NUM ! 下游面温度*DIM,T2_ARCH,TABLE,LAYER_NUM !拱厚*DIM,Y_RAD,TABLE,LAYER_NUM !圆心到坝轴线距离*DIM,RADUP,TABLE,LAYER_NUM ! 外半径名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - -

6、 - - 名师精心整理 - - - - - - - 第 1 页，共 11 页 - - - - - - - - - TEMPUP(1)=-8.84,-7.30,-5.66,-4.94,-4.99,-5.17,-5.73,-6.25 TEMPUP(1,0)=0,6,14,24,29,34,44,53 TEMPDOWN(1)=-8.84,-8.21,-7.36,-6.32,-5.86,-5.45,-4.72,-6.71 TEMPDOWN(1,0)=0,6,14,24,29,34,44,53 T2_ARCH(1)=5.00,6.68,8.27,10.25,11.24,12.23,14.22,16.00

7、 T2_ARCH(1,0)=0,6,14,24,29,34,44,53 Y_RAD(1)=68.00,68.00,68.00,68.00,68.00,68.00,68.00,68.00 Y_RAD(1,0)=0,6,14,24,29,34,44,53 RADUP(1)=68.00,68.00,68.00,68.00,68.00,68.00,68.00,68.00 RADUP(1,0)=0,6,14,24,29,34,44,53 CSYS,0 !/PNUM,KP,1 !/PNUM,LINE,1 /PREP7 KNN=0 *DO,II,1,LAYER_NUM !生成拱坝控制关键点,每层 6 个点

8、,上下游个三个点PX1=ARCH_RAD(II,1)*SIN(ARCH_ANGLE(II,1) PY1=RAD_CEN(II)-ARCH_RAD(II,1)*COS(ARCH_ANGLE(II,1) PX2=ARCH_RAD(II,1)*SIN(ARCH_ANGLE(II,2) PY2=RAD_CEN(II)-ARCH_RAD(II,1)*COS(ARCH_ANGLE(II,2) K,KNN+1,PX1, PY1,ELEVATION(II) K,KNN+2,0,RAD_CEN(II)-ARCH_RAD(II,1),ELEVATION(II) K,KNN+3,PX2, PY2,ELEVATION

9、(II) PX3=ARCH_RAD(II,2)*SIN(ARCH_ANGLE(II,1) PY3=RAD_CEN(II)-ARCH_RAD(II,2)*COS(ARCH_ANGLE(II,1) PX4=ARCH_RAD(II,2)*SIN(ARCH_ANGLE(II,2) PY4=RAD_CEN(II)-ARCH_RAD(II,2)*COS(ARCH_ANGLE(II,2) K,KNN+4,PX3, PY3,ELEVATION(II) K,KNN+5,0,RAD_CEN(II)-ARCH_RAD(II,2),ELEVATION(II) K,KNN+6,PX4, PY4,ELEVATION(II

10、) KNN=6*II *ENDDO LARC,1,3,2 !生成拱圈线*REPEAT,LAYER_NUM*2,3,3,3 L,1,4 *REPEAT,LAYER_NUM,6,6 L,3,6 *REPEAT,LAYER_NUM,6,6 ASKIN,1,3,5,7,9,11,13,15 !生成上游面ASKIN,2,4,6,8,10,12,14,16 !生成下游面ASKIN,17,18,19,20,21,22,23,24 !生成侧面ASKIN,25,26,27,28,29,30,31,32 AL,1,17,2,25 AL,15,24,16,32 名师资料总结 - - -精品资料欢迎下载 - - -

11、- - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 2 页，共 11 页 - - - - - - - - - VA,6,1,3,2,4,5 = 拉伸坝体侧面、底面，并进行切割，生成坝基!拉伸生成坝基ASEL,S,AREA,4 ! 选择右侧面VEXT,ALL,4*H_DAM ! 拉伸成基岩ASEL,S,AREA,3 ! 选择左侧面VEXT,ALL,-4*H_DAM ! 拉伸成基岩ALLSEL ASEL,S,LOC,Z,ELEVATION(LAYER_NUM)-1,ELEVATION(LAYER_NUM)+1 !选择底面VEXT,ALL,-NI

12、NT(H_DAM /10)*10 ASEL,S,AREA,10,20,5 ASEL,A,AREA,23,27,4 VEXT,ALL,4*H_DAM ASEL,S,AREA,8,18,5 ASEL,A,AREA,25,29,4 VEXT,ALL,-4*H_DAM ALLSEL,ALL SAVE WPROTA,90 WPOFFS,NINT(H_DAM*1.5/10)*10 VSBW,ALL,DELETE VSEL,S,LOC,Y,-200,-H_DAM*1.4 VDEL,ALL,1 VSEL,ALL WPOFFS,-NINT(H_DAM*3.5/10)*10 VSBW,ALL,DELETE VSE

13、L,S,LOC,Y,NINT(H_DAM*2/10)*10,NINT(H_DAM*2/10)*100 VDEL,ALL,1 VSEL,ALL WPCSYS,0 WPROTA,90 WPOFFS,NINT(W_DAM2+H_DAM)/10)*10 VSBW,ALL,DELETE VSEL,S,LOC,X,NINT(W_DAM2+H_DAM)/10)*10,NINT(W_DAM2+H_DAM)/10)*50 VDEL,ALL,1 VSEL,ALL WPOFFS,-NINT(W_DAM2+W_DAM1+2*H_DAM)/10)*10 VSBW,ALL,DELETE VSEL,S,LOC,X,-NIN

14、T(W_DAM1+H_DAM)/10)*50,-NINT(W_DAM1+H_DAM)/10)*10 VDEL,ALL,1 WPCSYS,0 VSEL,ALL SAVE 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 3 页，共 11 页 - - - - - - - - - = 用各控制高程切割整个模型，便于划分单元及计算成果和拱梁法比较*DO,II,LAYER_NUM,3,-1 WPOFFS,ELEVATION(II-1)-ELEVATION(II) VSBW,ALL,DELETE

15、*ENDDO WPCSYS,0 ALLSEL WPROTA,90 VSBW,ALL,DELETE WPCSYS,0 NUMMRG,ALL NUMCMP,ALL PX1=ARCH_RAD(1,1)*SIN(ARCH_ANGLE(1,1) PX2=ARCH_RAD(1,1)*SIN(ARCH_ANGLE(1,2) VSEL,S,LOC,X,PX1,PX2 VSEL,R,LOC,Z,ELEVATION(LAYER_NUM),ELEVATION(1) CM,DAM,VOLU VSEL,INVE CM,BEDROCK,VOLU ALLSEL = 生成溢流堰CMSEL,S,DAM VSEL,R,LOC,Z

16、,ELEVATION(1)-0.1,ELEVATION(2)+0.1 /VIEW,1,1,1,1 VPLOT !生成溢流堰 ,为便于建模和施加荷载,与实际不太相符,根据圣维南原理,对大坝的总体应力不会有太大影响W_WEIR=8 !溢流堰单孔宽(坝轴线处 ) NUM_WEIR=5 !溢流堰孔数W_WALL=2.5 !溢流堰闸墩宽 (坝轴线处 ) WPOFFS,ELEVATION(1)-ELEVATION(LAYER_NUM) WPOFFS,RAD_CEN(1) WPROTA,90 *AFUN,RAD PI=2*ACOS(0) SITTA1=(W_WEIR*NUM_WEIR+W_WALL*(NUM

17、_WEIR+1)/68*180/PI ! 溢流堰总中心角SITTA2=W_WEIR/ARCH_RAD(1,1)*180/PI ! 溢流堰单孔中心角SITTA3=W_WALL/ARCH_RAD(1,1)*180/PI ! 溢流堰单个闸墩中心角WPROTA,-SITTA1/2 VSBW,ALL,DELETE *DO,II,1,NUM_WEIR WPROTA,SITTA3 VSBW,ALL,DELETE 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 4 页，共 11 页 - - - -

18、- - - - - WPROTA,SITTA2 VSBW,ALL,DELETE *ENDDO WPROTA,SITTA3 VSBW,ALL,DELETE SAVE CMSEL,S,BEDROCK VSEL,INVE VSEL,R,LOC,Z,ELEVATION(1),ELEVATION(2) CSYS,11 VSEL,R,LOC,Y,-SITTA1/2,SITTA1/2 CM,YLYY ,VOLU *DO,II,1,NUM_WEIR CMSEL,S,YLYY VSEL,R,LOC,Y,-SITTA1/2+II*SITTA3+(II-1)*SITTA2,-SITTA1/2+II*SITTA3+I

19、I*SITTA2 VDEL,ALL,1,1 *ENDDO CSYS,0 CMSEL,S,BEDROCK VSEL,INVE CM,DAM,VOLU CMSEL,S,DAM VSEL,R,LOC,Z,ELEVATION(1),ELEVATION(2) CSYS,11 VSEL,R,LOC,Y,-SITTA1/2,SITTA1/2, CM,ZHADUN,VOLU CSYS,0 WPCSYS,0 VSEL,ALL NUMMRG,ALL NUMCMP,ALL SAVE = 划分单元!定义单元性质和材料ET,1,SOLID95 MP,EX,1,1E7 MP,NUXY ,1,0.25 MP,DENS,1,

20、23 !坝体容重MP,ALPX,1,0.7E-5 MP,REFT,1,0 MP,EX,2,0.8E7 MP,NUXY ,2,0.21 MP,ALPX,2,0.0 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 5 页，共 11 页 - - - - - - - - - MP,REFT,2,0 !坝体单元划分CMSEL,S,DAM CMSEL,U,ZHADUN ASLV,S LSLA,S *AFUN,DEG PX1=ARCH_RAD(1,1)*SIN(ARCH_ANGLE(1,1) PX

21、2=ARCH_RAD(1,1)*SIN(ARCH_ANGLE(1,2) PX3=ARCH_RAD(LAYER_NUM,2)*SIN(ARCH_ANGLE(LAYER_NUM,1) PX4=ARCH_RAD(LAYER_NUM,2)*SIN(ARCH_ANGLE(LAYER_NUM,2) LSEL,U,LOC,X,PX3,PX1 LSEL,U,LOC,X,PX4,PX2 LSEL,U,LOC,X,0 LSEL,U,LOC,Z,ELEVATION(1),ELEVATION(2) LESIZE,ALL, , ,20, CM,LTEMP1,LINE CSYS,0 CMSEL,S,DAM ASLV,S

22、LSLA,S CMSEL,U,LTEMP1 CM,LTEMP2,LINE LSEL,U,LENGTH,T_ARCH(LAYER_NUM)+0.1,1000 LSEL,R,TAN1,Z CSYS,11 LSEL,U,LOC,X,ARCH_RAD(1,1) LSEL,U,LOC,X,ARCH_RAD(1,1)-T_ARCH(1) LSEL,U,LOC,X,ARCH_RAD(1,1)-T_ARCH(2) CSYS,0 CM,LTEMP3,LINE LESIZE,ALL, , ,5, ALLSEL CMSEL,S,LTEMP2 CMSEL,U,LTEMP3 LSEL,U,TAN1,Z CM,LTEMP

23、4,LINE LESIZE,ALL, , ,3, CMSEL,S,DAM CMSEL,U,ZHADUN ASLV,S LSLA,S LSEL,R,LOC,Z,ELEVATION(1),ELEVATION(2) CSYS,11 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 6 页，共 11 页 - - - - - - - - - LSEL,U,LOC,Y,-SITTA1/2-1,SITTA1/2+1 LSEL,U,LENGTH,0,T_ARCH(1)+0.1 CSYS,0 CMSEL

24、,U,LTEMP3 CMSEL,U,LTEMP4 LESIZE,ALL, , ,10, CM,LTEMP5,LINE CMSEL,S,DAM CMSEL,U,ZHADUN ASLV,S LSLA,S LSEL,R,LOC,Z,ELEVATION(1),ELEVATION(2) CMSEL,U,LTEMP3 CMSEL,U,LTEMP4 CMSEL,U,LTEMP5 LSEL,U,LENGTH,0,3 CM,LTEMP6,LINE LESIZE,ALL, , ,4, CSYS,0 ALLSEL MSHAPE,0 CMSEL,S,DAM VSWEEP ,ALL SAVE !坝基单元划分CMSEL,

25、S,BEDROCK ASLV,S LSLA,S LSEL,U,TAN1,X LSEL,U,LOC,X,PX2,PX1 CM,LTEMP7,LINE LESIZE,ALL, , ,5, , , ,1 CMSEL,S,BEDROCK ASLV,S LSLA,S LSEL,U,TAN1,Y PY4=RAD_CEN(LAYER_NUM)-ARCH_RAD(LAYER_NUM,2)*COS(ARCH_ANGLE(LAYER_NUM,2)+20 LSEL,U,LOC,Y,-10,PY4 CM,LTEMP8,LINE LESIZE,ALL, , ,6,4, , , ,1 CMSEL,S,BEDROCK AS

26、LV,S LSLA,S LSEL,U,TAN1,Z 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 7 页，共 11 页 - - - - - - - - - LSEL,R,LOC,Z,ELEVATION(LAYER_NUM),ELEVATION(LAYER_NUM)-200 LESIZE,ALL, , ,5,5, , , ,1 CMSEL,S,BEDROCK ASLV,S LSLA,S LSEL,U,TAN1,Z LSEL,R,LOC,Z,ELEVATION(1),ELEVATION

27、(LAYER_NUM) LESIZE,ALL, , ,3, CMSEL,S,BEDROCK ASLV,S LSLA,S LSEL,R,LOC,Z,-50,-1000 LSEL,R,LOC,Y,-10,PY4 CSYS,11 LSEL,U,LOC,X,ARCH_RAD(1,1) LSEL,U,LOC,X,ARCH_RAD(1,1)-T_ARCH(LAYER_NUM) CSYS,0 LSEL,R,LENGTH,T_ARCH(LAYER_NUM)-5,T_ARCH(LAYER_NUM)+3, LESIZE,ALL, , ,5, CSYS,0 CMSEL,S,BEDROCK ASLV,S LSLA,S

28、 LSEL,R,LOC,Z,ELEVATION(LAYER_NUM)-50,ELEVATION(LAYER_NUM)-1000 LSEL,R,LOC,X,PX2,PX1 LESIZE,ALL, , ,20, CMSEL,S,BEDROCK MAT,2 VMESH,ALL !单元划分完毕ALLSEL NUMMRG,ALL NUMCMP,ALL SAVE = 定义边界条件，顺河向约束Y向位移，横河向约束X向位移，底面约束竖向Z 位移FINI /SOLU !边界位移条件*GET,NXMAX,NODE,MXLOC,X *GET,NXMIN,NODE,MNLOC,X *GET,NYMAX,NODE,MX

29、LOC,Y *GET,NYMIN,NODE,MNLOC,Y *GET,NZMIN,NODE,MNLOC,Z 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 8 页，共 11 页 - - - - - - - - - NSEL,S,LOC,X,NXMAX NSEL,A,LOC,X,NXMIN D,ALL,UX,0 ! 约束上下游边界X向位移NSEL,S,LOC,Y,NYMAX NSEL,A,LOC,Y,NYMIN D,ALL,UY ,0 !约束左右边界Y向位移NSEL,S,LOC,Z,N

30、ZMIN D,ALL,ALL,0 ! 约束底面边界Z向位移NSEL,ALL = 施加水荷载，淤沙压力，坝体自重!大坝荷载ALLSEL CMSEL,S,DAM CMSEL,U,ZHADUN ASLV,S CSYS,11 ASEL,R,LOC,X,ARCH_RAD(1,1)-0.1,ARCH_RAD(1,1)+0.1 NSLA,S,1 CM,N_DAMUP,NODE !定义大坝上游面节点CSYS,0 ALLSEL CMSEL,S,DAM ASLV,S ASEL,R,EXT LSLA,S LSEL,R,LOC,X,0 LSEL,U,LOC,Y,-0.1,0.1 LSEL,U,LOC,Z,ELEVAT

31、ION(2) LSEL,U,LOC,Z,ELEVATION(LAYER_NUM) ASLL,S ASEL,U,LOC,X,0 LSLA,S NSLA,S,1 CM,N_DAMDOWN,NODE !定义大坝下游面节点ALLSEL CMSEL,S,YLYY ASLV,S CSYS,11 ASEL,R,LOC,X,ARCH_RAD(1,1)-0.1,ARCH_RAD(1,1)+0.1 ASEL,U,291,326,326-291 NSLA,S,1 CM,N_ZHADUN1,NODE ! 定义溢流坝中墩节点ASEL,S,291,326,326-291 名师资料总结 - - -精品资料欢迎下载 - -

32、- - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 9 页，共 11 页 - - - - - - - - - NSLA,S,1 CM,N_ZHADUN2,NODE ! 定义溢流坝边墩节点CSYS,0 *IF,Z_UP ,NE,ELEVATION(LAYER_NUM),THEN CMSEL,S,N_DAMUP NSEL,R,LOC,Z,0,Z_UP /PSF,PRES,NORM,2,0.1 SFGRAD, PRES, 0, Z, 0,-9.81 SF,ALL,PRESS,Z_UP*9.81 !施加大坝上游面水压力*ENDIF *IF,Z_

33、UP ,GT,ELEVATION(2),THEN CMSEL,S,N_ZHADUN1 NSEL,R,LOC,Z,ELEVATION(2),Z_UP SFGRAD, PRES, 0, Z, 0,-(W_WEIR+W_WALL)/W_WALL*9.81 SF,ALL,PRESS,Z_UP*(W_WEIR+W_WALL)/W_WALL*9.81 !施加中墩水压力,包含闸门传递的水压力CMSEL,S,N_ZHADUN2 NSEL,R,LOC,Z,ELEVATION(2),Z_UP SFGRAD, PRES, 0, Z, 0,-(W_WEIR/2+W_WALL)/W_WALL*9.81 SF,ALL,P

34、RESS,Z_UP*(W_WEIR/2+W_WALL)/W_WALL*9.81 !施加边墩水压力,包含闸门传递的水压力*ENDIF *IF,Z_SAND,GT,ELEVATION(LAYER_NUM),THEN SFCUM,PRES,ADD ! 荷载为累加方式CMSEL,S,N_DAMUP NSEL,R,LOC,Z,0,Z_SAND *AFUN,DEG SAND_GRADS=DENS_SAND*(TA N(45-ANG_FRI/2)*2*9.81 ! 计算淤沙压力梯度SFGRAD, PRES, 0, Z, 0,-SAND_GRADS SF,ALL,PRESS,Z_SAND*SAND_GRADS

35、 !施加淤沙压力SFCUM,PRES,REPL !荷载为替代方式*ENDIF ALLSEL *IF,Z_DOWN,NE,ELEVATION(LAYER_NUM),THEN CMSEL,S,N_DAMDOWN NSEL,R,LOC,Z,0,Z_DOWN SFGRAD, PRES, 0, Z, 0,-9.81 SF,ALL,PRESS,Z_DOWN*9.81 !施加大坝下游面水压力*ENDIF ALLSEL ACEL,0,0,1 ! 施加大坝自重荷载SAVE = 名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - -

36、- - - - - 第 10 页，共 11 页 - - - - - - - - - 施加温度体荷载!施加大坝温度荷载CMSEL,S,DAM NSLV,S,1 *GET,NCOUNT_DAM, NODE, COUNT *GET,NMIN_DAM, NODE,NUM,MIN TUNIF,0, TREF,0, NTT=NMIN_DAM *DO,II,1,NCOUNT_DAM Z_NTT=NZ(NTT) !Z Z_TEMP=ELEVATION(1)-Z_NTT !到坝基高度TL_ARCH=T2_ARCH(Z_TEMP) !拱厚CSYS,11 X_NTT=NX(NTT) !X: 距顶拱圆心距离CSYS,

37、0 RAD0=Y_RAD(Z_TEMP) ! 圆心到坝轴线距离RAD1=RADUP(Z_TEMP) ! 外半径LXUP=RAD_CEN(1)-RAD0+RAD1-X_NTT TTT1=TEMPUP(Z_TEMP) TTT2=TEMPDOWN(Z_TEMP) TTT=TTT1+(TTT2-TTT1)/TL_ARCH*LXUP BF,NTT,TEMP,TTT *IF,II,LT,NCOUNT_DAM,THEN NTT=NDNEXT(NTT) *ENDIF *ENDDO = 计算求解，采用PCG求解器ALLSEL SAVE EQSLV,PCG,1E-8 SOLVE SAVE FINI 最大变形 2cm，位于拱冠梁顶，与拱梁分载法一致。名师资料总结 - - -精品资料欢迎下载 - - - - - - - - - - - - - - - - - - 名师精心整理 - - - - - - - 第 11 页，共 11 页 - - - - - - - - -