2022年完整word版,《自动控制原理》试卷及答案 .pdf
《2022年完整word版,《自动控制原理》试卷及答案 .pdf》由会员分享,可在线阅读,更多相关《2022年完整word版,《自动控制原理》试卷及答案 .pdf(29页珍藏版)》请在淘文阁 - 分享文档赚钱的网站上搜索。
1、AUTOMATIC CONTROL THEOREM (1) Derive the transfer function and the differential equation of the electric network shown in Fig.1. (12% ) Consider the system shown in Fig.2. Obtain the closed-loop transfer function)()(SRSC, )()(SRSE. (12%)Fig.2 The characteristic equation is given 010)6(5)(123KSKSSSGH
2、. Discuss the distribution of the closed-loop poles. (16%) There are 3 roots on the LHP There are 2 roots on the LHP There are 1 roots on the LHP There are no roots on the LHP . K=? Consider a unity-feedback control system whose open-loop transfer function is )6.0(14 .0)(SSSSG. Obtain the response t
3、o a unit-step input. What is the rise time for this system? What is the maximum overshoot? (10%)C G1 G2 G3 G4 H2 H1 R E C2 R2 V2(S) R1 C1 V1(S) Fig.1 精选学习资料 - - - - - - - - - 名师归纳总结 - - - - - - -第 1 页,共 29 页5. Sketch the root-locus plot for the system )1()(SSKSGH. ( The gain K is assumed to be posit
4、ive.) Determine the breakaway point and K value. Determine the value of K at which root loci cross the imaginary axis. Discuss the stability. (12%) 6. The system block diagram is shown Fig.3. Suppose )2(tr, 1n. Determine the value of K to ensure 1SSe. (12%) Fig.3 7. Consider the system with the foll
5、owing open-loop transfer function: )1)(1()(21STSTSKSGH. Draw Nyquist diagrams. Determine the stability of the system for two cases, the gain K is small, K is large. (12%) 8. Sketch the Bode diagram of the system shown in Fig.4. (14%) 2SK)3(4SSR E N C 32SS)10)(5()2(SSSR(S) C(S) Fig.4 精选学习资料 - - - - -
6、 - - - - 名师归纳总结 - - - - - - -第 2 页,共 29 页212121121212)()()(CCSCCRRCSCCRSVSV2423241321121413211)()(HGHGGGGGGGHGGGGGGGSRSC 0K6 K0 K6 no answer the breakaway point is 1 and 1/3; k=4/27 The imaginary axis S=j; K=25.75. 3K) 154.82)(181.34)(1481. 3)(1316.0() 11 .0(62.31)(SSSSSSGH精选学习资料 - - - - - - - - - 名
7、师归纳总结 - - - - - - -第 3 页,共 29 页AUTOMATIC CONTROL THEOREM (2) Derive the transfer function and the differential equation of the electric network shown in Fig.1. (12% ) Consider the equation group shown in Equation.1. Draw block diagram and obtain the closed-loop transfer function)()(SRSC. (16% )Equat
8、ion.1 )()()()()()()()()()()()()()()()()()()()(3435233612287111SXSGSCSGSGSCSXSXSXSGSXSGSXSCSGSGSGSRSGSX Use Routh s criterion to determine the number of roots in the right-half S plane for the equation 0400600226283)(12345SSSSSSGH. Analyze stability.(12% ) Determine the range of K value ,when )1 (2tt
9、r, 5.0SSe. (12% )Fig.2 C1 C2 V2(S) R1 R1 V1(S) Fig.1 R E ) 2(4322SSKSSC 精选学习资料 - - - - - - - - - 名师归纳总结 - - - - - - -第 4 页,共 29 页Fig.3 shows a unity-feedback control system. By sketching the Nyquist diagram of the system, determine the maximum value of K consistent with stability, and check the resu
10、lt using Routh s criterion. Sketch the root-locus for the system (20%)Fig.3 Sketch root-locus diagram. (18% ) Determine the transfer function. Assume a minimum-phase transfer function.(10% )Im Re Im Re Im Re Im Re Im Re Im Re 0.1 1 2 3 4 L(dB) 40 30 20 5 0 20 0 20 40 -60 C R R E )54(2SSSK精选学习资料 - -
11、- - - - - - - 名师归纳总结 - - - - - - -第 5 页,共 29 页1)(1)()(2122112221112SCRCRCRSCRCRSVSV)(1)()(8743215436324321GGGGGGGGGGGGGGGGSRSC There are 4 roots in the left-half S plane, 2 roots on the imaginary axes, 0 root in the RSP. The system is unstable. 208KK=20 ) 154.82)(181.34)(1481. 3)(1316.0() 11 .0(62.3
12、1)(SSSSSSGH精选学习资料 - - - - - - - - - 名师归纳总结 - - - - - - -第 6 页,共 29 页AUTOMATIC CONTROL THEOREM (3) List the major advantages and disadvantages of open-loop control systems. (12% )Derive the transfer function and the differential equation of the electric network shown in Fig.1.(16% )Consider the syste
13、m shown in Fig.2. Obtain the closed-loop transfer function)()(SRSC, )()(SRSE, )()(SPSC. (12%) The characteristic equation is given 02023)(123SSSSGH. Discuss the distribution of the closed-loop poles. (16%) 5. Sketch the root-locus plot for the system )1()(SSKSGH. (The gain K is assumed to be positiv
14、e.) Determine the breakaway point and K value. Determine the value of K at which root loci cross the imaginary axis. Discuss the stability. (14%) Fig.1 R2 C2 R1 C1 U1 U2 P C G1 G2 G3 G5 H1 R G4 H2 H3 Fig.2 E 精选学习资料 - - - - - - - - - 名师归纳总结 - - - - - - -第 7 页,共 29 页6. The system block diagram is show
15、n Fig.3. 21SKG, )3(42SSG. Suppose )2(tr, 1n. Determine the value of K to ensure 1SSe. (15%) 7. Consider the system with the following open-loop transfer function: )1)(1()(21STSTSKSGH. Draw Nyquist diagrams. Determine the stability of the system for two cases, the gain K is small, K is large. (15%) N
16、 R E C G1 G2 Fig.3 精选学习资料 - - - - - - - - - 名师归纳总结 - - - - - - -第 8 页,共 29 页Solution: The advantages of open-loop control systems are as follows: Simple construction and ease of maintenance Less expensive than a corresponding closed-loop system There is no stability problem Convenient when output is
17、 hard to measure or economically not feasible. (For example, it would be quite expensive to provide a device to measure the quality of the output of a toaster.) The disadvantages of open-loop control systems are as follows: Disturbances and changes in calibration cause errors, and the output may be
18、different from what is desired. To maintain the required quality in the output, recalibration is necessary from time to time. 1)(1)()()(2122112221122112221112SCRCRCRSCRCRSCRCRSCRCRSUSU351343212321215143211)()(HGGHGGGGHGGHGGGGGGGGSRSC35134321232121253121431)1 ()()(HGGHGGGGHGGHGGHGGHGGGGSPSCR=2, L=1 S
19、:the breakaway point is 1 and 1/3; k=4/27 The imaginary axis S=j; K=2 5.75. 3K精选学习资料 - - - - - - - - - 名师归纳总结 - - - - - - -第 9 页,共 29 页AUTOMATIC CONTROL THEOREM (4) Find the poles of the following )(sF: sesF11)(12%) Consider the system shown in Fig.1,where6.0and 5nrad/sec. Obtain the rise timert, pe
20、ak timept, maximum overshootPM, and settling timestwhen the system is subjected to a unit-step input. (10%)Consider the system shown in Fig.2. Obtain the closed-loop transfer function)()(SRSC, )()(SRSE, )()(SPSC. (12%) The characteristic equation is given 02023)(123SSSSGH. Discuss the distribution o
21、f the closed-loop poles. (16%) C(s) Fig.1 )2(2nnssR(s) P C G1 G2 G3 G5 H1 R G4 H2 H3 Fig.2 E 精选学习资料 - - - - - - - - - 名师归纳总结 - - - - - - -第 10 页,共 29 页5. Sketch the root-locus plot for the system )1()(SSKSGH. (The gain K is assumed to be positive.) Determine the breakaway point and K value. Determin
22、e the value of K at which root loci cross the imaginary axis. Discuss the stability. (12%) 6. The system block diagram is shown Fig.3. 21SKG, )3(42SSG. Suppose )2(tr, 1n. Determine the value of K to ensure 1SSe. (12%) 7. Consider the system with the following open-loop transfer function: )1)(1()(21S
23、TSTSKSGH. Draw Nyquist diagrams. Determine the stability of the system for two cases, the gain K is small, K is large. (12%) 8. Sketch the Bode diagram of the system shown in Fig.4. (14%) 32SS)10)(5()2(SSSR(S) C(S) Fig.4 N R E C G1 G2 Fig.3 精选学习资料 - - - - - - - - - 名师归纳总结 - - - - - - -第 11 页,共 29 页
24、Solution: The poles are found from 1seor 1)sin(cos)(jeejFrom this it follows that n2,0),2, 1 ,0(n. Thus, the poles are located at njs2Solution: rise timesec55.0rt, peak timesec785.0pt, maximum overshoot095.0PM, and settling timesec33.1stfor the%2criterion, settling timesec1stfor the %5criterion. 351
25、343212321215143211)()(HGGHGGGGHGGHGGGGGGGGSRSC35134321232121253121431)1 ()()(HGGHGGGGHGGHGGHGGHGGGGSPSCR=2, L=1 5. S:the breakaway point is 1 and 1/3; k=4/27 The imaginary axis S=j; K=2 5.75. 3K精选学习资料 - - - - - - - - - 名师归纳总结 - - - - - - -第 12 页,共 29 页AUTOMATIC CONTROL THEOREM (5) Consider the syste
- 配套讲稿:
如PPT文件的首页显示word图标,表示该PPT已包含配套word讲稿。双击word图标可打开word文档。
- 特殊限制:
部分文档作品中含有的国旗、国徽等图片,仅作为作品整体效果示例展示,禁止商用。设计者仅对作品中独创性部分享有著作权。
- 关 键 词:
- 自动控制原理 2022年完整word版 自动控制原理试卷及答案 2022 完整 word 自动控制 原理 试卷 答案
限制150内