最新CCF部分真题代码(Java).doc

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1、精品资料CCF部分真题代码(Java).2013-12-1/出现次数最多的数package demo;import java.util.*;public class Test2public static void main(String args)new Test2().run();public void run()System.out.println(请输入：);SuppressWarnings(resource)Scanner fin = new Scanner(System.in);int N =fin.nextInt();intcount = new int10001;for(int

2、i=0;iN;+i)+countfin.nextInt();int maxCount =-1;int result = 0;for (int i=1;imaxCount)maxCount=counti;result = i;System.out.println(result);2014-03-01/相反数package demo;import java.util.*;public class Test3 public static void main(String args) new Test3().run();public void run() SuppressWarnings(resour

3、ce)/ 输入一个正整数 1500Scanner input = new Scanner(System.in);System.out.println(请输入一个1500的整数:);int N = input.nextInt();int value = new intN;int count = 0;System.out.println(请输入 + N + 个正整数，且每个数绝对值不超过1000，不同的数);/ 加入数组for (int i = 0; i N; +i) valuei = input.nextInt();/ 双层循环查找for (int i = 0; i N; i+) for (in

4、t j = i + 1; j N; j+) if (valuei = (-valuej) count+;System.out.println(count);201309-3/字符串匹配package demo;import java.util.Scanner;public class Test4 public static void main(String args) SuppressWarnings(resource)Scanner reader = new Scanner(System.in);String str = reader.next();int p = reader.nextIn

5、t();int n = reader.nextInt();int d = 0;String re = new Stringn;for (int t = 0; t n; t+) String s = reader.next();if (p = 0) s = s.toLowerCase();str = str.toLowerCase();if (s.contains(str) red = s;d = d + 1;for (int i = 0; i d; i+)System.out.println(rei);2014-09-1 /相邻数对package demo;import java.util.*

6、;public class Test5 public static void main(String args) new Test5().run();public void run() / 输入System.out.println(请输入);SuppressWarnings(resource)Scanner input = new Scanner(System.in);int N = input.nextInt();int count = 0;int value = new intN;/ 加入数组for (int i = 0; i N; i+) valuei = input.nextInt()

7、;/ 双循环查找for (int i = 0; i N; i+) for (int j = i + 1; j N; j+) int s = valuei - valuej;if (Math.abs(s) = 1)count+;System.out.println(count);201503-1 /图像反转package demo;import java.util.*; public class Test7 public static void main(String args) new Test7().run(); public void run() SuppressWarnings(reso

8、urce)Scanner sc=new Scanner(System.in); int M= sc.nextInt(); int N=sc.nextInt(); /int arr=new intMN; int arr=new intNM; for(int i=0;iM;i+) for(int j=0;jN;j+) arrN-j-1i=sc.nextInt(); /需要找的规律，归纳法 for(int i=0;iN;i+) for(int j=0;jM;j+) System.out.print(arrij+ ); System.out.println(); 201312-03/最大的矩形pack

9、age demo;import java.util.*;public class Test9 public static void main(String args) new Test9().run();public void run() SuppressWarnings(resource)Scanner fin = new Scanner(System.in);int N = fin.nextInt();int height = new intN;for (int i = 0; i N; +i)heighti = fin.nextInt();int result = 0;for (int i

10、 = 0; i = 0; -j) if (heightj heighti)break;+width;/ 向第i个矩形的右边寻找for (int j = i + 1; j N; +j) if (heightj heighti)break;+width;int area = width * heighti;/ 包含当前第i个矩形框的最大面积result = Math.max(result, area);/ max(a1,a2)取两个数的最大值System.out.println(result);201409-2/画图package demo;import java.util.Scanner;imp

11、ort java.util.HashSet;public class Test10 public static void main(String args) SuppressWarnings(resource)Scanner sc = new Scanner(System.in); int n = sc.nextInt(); /要画矩形的个数 HashSet set = new HashSet(); int axis = new int4; for(int i = 1; i = n; i+) for(int j = 0; j 4; j+) axisj = sc.nextInt(); set.a

12、ddAll(transferToUniteGrid(axis0, axis1, axis2, axis3); System.out.println(set.size(); private static HashSet transferToUniteGrid(int x1, int y1, int x2, int y2) HashSet set = new HashSet(); /对两个点进行排序，以保证x1x2,y1 x2) temp = x1; x1 = x2; x2 = temp; if(y1 y2) temp = y1; y1 = y2; y2 = temp; for(int i = x

13、1; i x2; i+)/不包括上界 for(int j = y1; j y2; j+) set.add(new UnitGrid(i,j); return set; class UnitGrid int x, y; /用左下角的坐标来代表一个UnitGrid public UnitGrid(int x, int y) this.x = x; this.y = y; /重写equals方法，若左下角坐标一致，则相等 Override public boolean equals(Object o) if(o = null) return false; if(!(o instanceof Unit

14、Grid) return false; UnitGrid ug = (UnitGrid)o; if(this.x = ug.x) & (this.y = ug.y) return true; return false; /重写hashCode方法。 Override public int hashCode() /如果两个UnitGrid的x,y相等，则为同一元素 int result = 17; return (37*result + this.x)*37+this.y; 201403-4 /窗口package demo;import java.util.Scanner;public clas

15、s Test11 public static void main(String args) System.out.println(输入N和M:); SuppressWarnings(resource)Scanner input = new Scanner(System.in); int n = input.nextInt(); int m = input.nextInt(); /给出N个窗口位置 /每个给出四个数，并且x1x2,y1y2 /创建二维数组 int values = new intn4; for(int i = 0;in;i+) System.out.println(n+个窗口:)

16、; for(int j = 0;j4;j+) valuesij = input.nextInt(); /分别是最下层到顶层的次序 /用一个数组存储他们的次序 /初始化顺序 int num = new intn; for(int i = 1;i = n;i+) numi-1 = i; /接下来进行M次点击事件 /每行包含两个非负整数x,y /输出结果存储 String results = new Stringm; /0 for IGNORED /进行点击 /先判断点击的位置落在哪些窗口，然后判断顺序,顺序在最上面的就是我们的点击相应窗口 /m次点击 /点击后要改变顺序 for(int i = 0

17、;im;i+) /每次操作 System.out.println(进行点击:); int x = input.nextInt(); int y = input.nextInt(); for(int j = 0;j= valuesj0 & x=valuesj1 &y=valuesj3) if(resultsi = null | numInteger.parseInt(resultsi) numj) resultsi = String.valueOf(j); System.out.println(第+(j+1)+个窗口显示 + resultsi); /被点击的置于顶层 交换顺序 /n个窗口判断哪个

18、是最上面的 int top = 0; for(int k = 0;kn;k+) if(numk = n) top = k; if(resultsi = null) resultsi = IGNORED; else int temp = numInteger.parseInt(resultsi); numInteger.parseInt(resultsi) = n; numtop = temp; for(int i = 0;in;i+) if(resultsi != null) resultsi = String.valueOf(Integer.parseInt(resultsi)+1); Sy

19、stem.out.println(结果：); for(int i = 0;im;i+) System.out.println(resultsi); 201412-2/Z字形扫描package demo;/*1.根据上一步的方向以及是否到达边界位置来决定下一步方向； 2.根据步骤1得到的方向前进一步，读取该位置的数字。 循环直至到达终点(n-1, n-1) */import java.util.Scanner;public class Test12 /下面四个变量代表四个方向 public static final int RIGHT = 1; /向右走 public static final

20、int DOWN = 2; /向下走 public static final int LEFTDOWN = 3; /向做下走 public static final int RIGHTUP = 4; /向右上走 public static int data; /矩 public static void main(String args) new Test12().run(); public void run() /接收输入 SuppressWarnings(resource)Scanner scanner = new Scanner(System.in); int n = scanner.ne

21、xtInt(); data = new intnn for(int i = 0; i n; i+) for(int j = 0; j = 0 & y+1 = 0 & y+1 n) /左下可走 direction = LEFTDOWN; else /只能走右上了 direction = RIGHTUP; else if(direction = LEFTDOWN) /上一次向左下，如果可以，下一步应该继续向左下，否则 向右或者向下走 if(y+1 = 0) /先判断能否继续向左下 direction = LEFTDOWN; else if(y+1 n) /然后判断能否向下走 direction =

22、 DOWN; else /最后只能向右走了 direction = RIGHT; else if(direction = RIGHTUP) /上一次向右上，如果可以，下一步应该继续向右上，否则向右或者下走 if(x+1 =0) /先判断能否继续向右上 direction = RIGHTUP; else if(x+1 n) /然后判断能否向右走 direction = RIGHT; else /最后只能向下走了 direction = DOWN; /根据上面确定的方向来走出下一步 switch(direction) case RIGHT: x = x+1; break; case DOWN: y

23、 = y+1; break; case LEFTDOWN: x = x-1; y = y+1; break; case RIGHTUP: x = x+1; y = y-1; break; /读取当前走到位置的数字.注意x和y的位置 result += datayx + ; /输出结果（这里需不需要去掉最后的空格？没怎么玩过ACM，不记得了acc格式控制会不会这么严） System.out.println(result); 10.import java.io.BufferedReader;import java.io.InputStreamReader;/ISBN号码public class T

24、est13 public static void main(String args) BufferedReader bin = new BufferedReader(new InputStreamReader(System.in); try int sum=0; char cc=0; String isbn_0= bin.readLine(); String isbn=isbn_0.replace(-, );for (int i=0; i9;i+)int ii=(int)isbn.charAt(i)-48;sum +=ii*(i+1);sum = sum % 11;if(sum = 10)cc

25、 = X;else cc = (char)(sum+48);if(cc = isbn.charAt(9) System.out.println(Right);elseisbn_0 = isbn_0.substring(0,12) + cc; System.out.println(isbn_0); catch(Exception e) e.printStackTrace();201412-03 /集合竞价package demo;import java.text.DecimalFormat;import java.util.Arrays;import java.util.Comparator;i

26、mport java.util.Scanner;class StockArray String SBC; float price; int number;public class Test14 public static void main(String args) System.out.println(please input data); Scanner scanner=new Scanner(System.in); StockArray ss=new StockArray5002; for (int i = 0; i 5002; i+) ssi=new StockArray(); int

27、 num=1; while(scanner.hasNext() ssnum.SBC=scanner.next(); if (ssnum.SBC.equals(buy)|ssnum.SBC.equals(sell) ssnum.price=scanner.nextFloat(); ssnum.number=scanner.nextInt(); else if (ssnum.SBC.equals(cancel) ssscanner.nextInt().SBC=CANCEL; /如果取消，则将相应行标记为CANCEL num+; System.out.println(aaa); StockArray

28、 n1=new StockArraynum; /买方 for (int i = 0; i num; i+) n1i=new StockArray(); StockArray n2=new StockArraynum; /卖方 for (int i = 0; i num; i+) n2i=new StockArray(); int num1=0; int num2=0; int ans_num=0; float ans_price=0; for(int i=1;inum;i+) if (ssi.SBC.equals(buy) /放入Buy的出价和交易量 n1num1.price=ssi.pric

29、e; n1num1.number=ssi.number; num1+; if (ssi.SBC.equals(sell) /放入sell的出价和交易量 n2num2.price=ssi.price; n2num2.number=ssi.number; num2+; Arrays.sort(n1,0,num1,new MyComprator1(); Arrays.sort(n2,0,num2,new MyComprator2(); int sum1=0, sum2; float p; for (int i = 0; i num1; i+) /n1买方,n2卖方 p=n1i.price; sum1+=n1i.number; sum2=0; for (int j = 0; j n1i.price) break; sum2+=n2j.number; int min_sum=Math.min(sum1, sum2); if (ans_nummin_sum) ans_num=min_sum; ans_price=p; Syste