SQLServer实例.docx

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1、题目11、学校图书馆借书信息管理系统建立三个表：学生信息表：student字段名称数据类型说明stuIDchar(10)学生编号，主键stuNameVarchar(10)学生名称majorVarchar(50)专业图书表：book字段名称数据类型说明BIDchar(10)图书编号，主键titlechar(50)书名authorchar(20)作者借书信息表：borrow字段名称数据类型说明borrowIDchar(10)借书编号，主键stuIDchar(10)学生编号，外键BIDchar(10)图书编号，外键T_timedatetime借书日期B_timedatetime还书日期请编写SQL语

2、句完成以下的功能：1) 查询“计算机”专业学生在“2007-12-15”至“2008-1-8”时间段内借书的学生编号、学生名称、图书编号、图书名称、借出日期；参考查询结果如下图所示：2) 查询所有借过图书的学生编号、学生名称、专业；参考查询结果如下图所示：3) 查询借过作者为“安意如”的图书的学生姓名、图书名称、借出日期、归还日期；参考查询结果如下图所示：4) 查询目前借书但未归还图书的学生名称及未还图书数量；参考查询结果如下图所示：附加：建表语句:USE masterGO/*$建库$*/-检验数据库是否存在，如果为真，删除此数据库-IF exists(SELECT * FROM sysdat

3、abases WHERE name=BOOK) DROP DATABASE BOOKGOCREATE DATABASE BOOKGO-建数据表-USE BOOKGOCREATE TABLE student -学生信息表( stuID CHAR(10) primary key, -学生编号 stuName CHAR(10) NOT NULL , -学生名称 major CHAR(50) NOT NULL -专业)GOCREATE TABLE book -图书表( BID CHAR(10) primary key, -图书编号 title CHAR(50) NOT NULL, -书名 author

4、 CHAR(20) NOT NULL, -作者)GOCREATE TABLE borrow -借书表( borrowID CHAR(10) primary key, -借书编号stuID CHAR(10) foreign key(stuID) references student(stuID), -学生编号BID CHAR(10) foreign key(BID) references book(BID),-图书编号 T_time datetime NOT NULL, -借出日期 B_time datetime -归还日期)GO-学生信息表中插入数据-INSERT INTO student(s

5、tuID,stuName,major)VALUES(1001,林林,计算机)INSERT INTO student(stuID,stuName,major)VALUES(1002,白杨,计算机)INSERT INTO student(stuID,stuName,major)VALUES(1003,虎子,英语)INSERT INTO student(stuID,stuName,major)VALUES(1004,北漂的雪,工商管理)INSERT INTO student(stuID,stuName,major)VALUES(1005,五月,数学)-图书信息表中插入数据-INSERT INTO b

6、ook(BID,title,author)VALUES(B001,人生若只如初见,安意如)INSERT INTO book(BID,title,author)VALUES(B002,入学那天遇见你,晴空)INSERT INTO book(BID,title,author)VALUES(B003,感谢折磨你的人,如娜)INSERT INTO book(BID,title,author)VALUES(B004,我不是教你诈,刘庸)INSERT INTO book(BID,title,author)VALUES(B005,英语四级,白雪)-借书信息表中插入数据-INSERT INTO borrow(

7、borrowID,stuID,BID,T_time,B_time)VALUES(T001,1001,B001,2007-12-26,null)INSERT INTO borrow(borrowID,stuID,BID,T_time,B_time)VALUES(T002,1004,B003,2008-1-5,null)INSERT INTO borrow(borrowID,stuID,BID,T_time,B_time)VALUES(T003,1005,B001,2007-10-8,2007-12-25)INSERT INTO borrow(borrowID,stuID,BID,T_time,B

8、_time)VALUES(T004,1005,B002,2007-12-16,2008-1-7)INSERT INTO borrow(borrowID,stuID,BID,T_time,B_time)VALUES(T005,1002,B004,2007-12-22,null)INSERT INTO borrow(borrowID,stuID,BID,T_time,B_time)VALUES(T006,1005,B005,2008-1-6,null)INSERT INTO borrow(borrowID,stuID,BID,T_time,B_time)VALUES(T007,1002,B001,

9、2007-9-11,null)INSERT INTO borrow(borrowID,stuID,BID,T_time,B_time)VALUES(T008,1005,B004,2007-12-10,null)INSERT INTO borrow(borrowID,stuID,BID,T_time,B_time)VALUES(T009,1004,B005,2007-10-16,2007-12-18)INSERT INTO borrow(borrowID,stuID,BID,T_time,B_time)VALUES(T010,1002,B002,2007-9-15,2008-1-5)INSERT

10、 INTO borrow(borrowID,stuID,BID,T_time,B_time)VALUES(T011,1004,B003,2007-12-28,null)INSERT INTO borrow(borrowID,stuID,BID,T_time,B_time)VALUES(T012,1002,B003,2007-12-30,null)标准答案:- 1)查询“计算机”专业学生在“2007-12-15”至“2008-1-8”时间段内借书的学生编号、学生名称、图书编号、图书名称、借出日期select 学生编号=stuID,学生名称=(select stuName from student

11、 where stuID=borrow.stuID),图书编号=BID,图书名称=(select title from book where BID=borrow.BID),借出日期=T_time from borrow where stuID in (select stuID from student where major=计算机) and T_time2007-12-15 and T_time2*(select count(*) from ProWage where Wage=PWage)update ProWage set total=total+AWage,Wage=Wage+AWa

12、geelsebreakendprint一共加薪：+convert(varchar,total)+元print加薪后的程序员工资列表：select * from ProWage-调用存储过程1-exec Sum_wage PWage=2000,AWage=100,total=0exec Sum_wage PWage=2200,AWage=100,total=0exec Sum_wage PWage=3000,AWage=100,total=0exec Sum_wage PWage=4000,AWage=100,total=0exec Sum_wage PWage=5000,AWage=100,t

13、otal=0exec Sum_wage PWage=6000,AWage=100,total=0-2、创建存储过程2-if exists (select * from sysobjects where name=Avg_wage)drop procedure Avg_wageGOcreate procedure Avg_wage PWage int,AWage int,total intas while (1=1)beginif (select Avg(Wage) from ProWage)=PWage)update ProWage set total=total+AWage,Wage=Wag

14、e+AWageelsebreakendprint一共加薪：+convert(varchar,total)+元print加薪后的程序员工资列表：select * from ProWage-调用存储过程-exec Avg_wage PWage=3000,AWage=200,total=0exec Avg_wage PWage=4500,AWage=200,total=0题目3：学生成绩信息三个表，结构如下： 学生表：Member字段名称数据类型说明MIDChar(10)学生号，主键MNameChar(50)姓名课程表：字段名称数据类型说明FIDChar(10)课程，主键FNameChar(50)课

15、程名成绩表：Score字段名称数据类型说明SIDint自动编号，主键，成绩记录号FIDChar(10)课程号，外键MIDChar(10)学生号，外键Scoreint成绩请编写T-SQL语句来实现如下功能：1) 查询各个学生语文、数学、英语、历史课程成绩，例如下表：姓名语文数学英语历史张萨78 678976王强 89 67 84 96李三70 87 92 56李四 8078 97662) 查询四门课中成绩低于70分的学生及相对应课程名与成绩。3) 统计各个学生参加考试课程的平均分，且按平均分数由高到底排序。4) 创建存储过程，分别查询参加1、2、3、4门考试及没有参加考试的学生名单，要求显示姓名

16、、学号。建表语句:USE masterGO/*$建库$*/-检验数据库是否存在，如果为真，删除此数据库-IF exists(SELECT * FROM sysdatabases WHERE name=Student) DROP DATABASE StudentGOCREATE DATABASE StudentGO-建数据表-USE StudentGOCREATE TABLE Member -学生表( MID char(10) primary key, -学生号 MName CHAR(50) NOT NULL -姓名)GOCREATE TABLE F -课程表( FID char(10) pri

17、mary key, -课程号FName CHAR(50) NOT NULL -课程名)GOCREATE TABLE score -学生成绩表( SID int identity(1,1) primary key, -成绩记录号 FID char(10) foreign key(FID) references F(FID) , -课程号 MID char(10) foreign key(MID) references Member(MID) , -学生号 Score int NOT NULL -成绩)GO-课程表中插入数据-INSERT INTO F(FID,FName)VALUES(F001,

18、语文)INSERT INTO F(FID,FName)VALUES(F002,数学)INSERT INTO F(FID,FName)VALUES(F003,英语)INSERT INTO F(FID,FName)VALUES(F004,历史)-学生表中插入数据-INSERT INTO Member(MID,MName)VALUES(M001,张萨)INSERT INTO Member(MID,MName)VALUES(M002,王强)INSERT INTO Member(MID,MName)VALUES(M003,李三)INSERT INTO Member(MID,MName)VALUES(M0

19、04,李四)INSERT INTO Member(MID,MName)VALUES(M005,阳阳)INSERT INTO Member(MID,MName)VALUES(M006,虎子)INSERT INTO Member(MID,MName)VALUES(M007,夏雪)INSERT INTO Member(MID,MName)VALUES(M008,璐璐)INSERT INTO Member(MID,MName)VALUES(M009,珊珊)INSERT INTO Member(MID,MName)VALUES(M010,香奈儿)-成绩表中插入数据-INSERT INTO Score(F

20、ID,MID,Score)VALUES(F001,M001,78)INSERT INTO Score(FID,MID,Score)VALUES(F002,M001,67)INSERT INTO Score(FID,MID,Score)VALUES(F003,M001,89)INSERT INTO Score(FID,MID,Score)VALUES(F004,M001,76)INSERT INTO Score(FID,MID,Score)VALUES(F001,M002,89)INSERT INTO Score(FID,MID,Score)VALUES(F002,M002,67)INSERT

21、INTO Score(FID,MID,Score)VALUES(F003,M002,84)INSERT INTO Score(FID,MID,Score)VALUES(F004,M002,96)INSERT INTO Score(FID,MID,Score)VALUES(F001,M003,70)INSERT INTO Score(FID,MID,Score)VALUES(F002,M003,87)INSERT INTO Score(FID,MID,Score)VALUES(F003,M003,92)INSERT INTO Score(FID,MID,Score)VALUES(F004,M00

22、3,56)INSERT INTO Score(FID,MID,Score)VALUES(F001,M004,80)INSERT INTO Score(FID,MID,Score)VALUES(F002,M004,78)INSERT INTO Score(FID,MID,Score)VALUES(F003,M004,97)INSERT INTO Score(FID,MID,Score)VALUES(F004,M004,66)INSERT INTO Score(FID,MID,Score)VALUES(F001,M006,88)INSERT INTO Score(FID,MID,Score)VAL

23、UES(F002,M006,55)INSERT INTO Score(FID,MID,Score)VALUES(F003,M006,86)INSERT INTO Score(FID,MID,Score)VALUES(F004,M006,79)INSERT INTO Score(FID,MID,Score)VALUES(F002,M007,77)INSERT INTO Score(FID,MID,Score)VALUES(F003,M008,65)INSERT INTO Score(FID,MID,Score)VALUES(F004,M007,48)INSERT INTO Score(FID,M

24、ID,Score)VALUES(F004,M009,75)INSERT INTO Score(FID,MID,Score)VALUES(F002,M009,88)标准答案:- 1)查询各个学生语文、数学、英语、历史课程成绩-SELECT Member.MName AS 姓名,英语 = SUM(CASE F.FName WHEN 语文 THEN Score.Score END), 数学 = SUM(CASE F.FName WHEN 数学 THEN Score.Score END), 语文 = SUM(CASE F.FName WHEN 英语 THEN Score.Score END), 历史

25、= SUM(CASE F.FName WHEN 历史 THEN Score.Score END) FROM Score, Member,F WHERE F.FID = Score.FID AND Member.MID =Score.MID GROUP BY Member.MName - 2)查询四门课中成绩低于70分的学生及相对应课程名与成绩-select 姓名=(select MName from Member where MID=Score.MID),课程名=(select FName from F where FID=Score.FID),成绩=Score from Score wher

26、e Score70- 3)统计各个学生四课程的平均分，且按平均分数由高到底排序-select 姓名=(select MName from Member where MID=Score.MID),平均分=Avg(Score) from Score group by MID order by 平均分 desc- 4)创建存储过程-if exists (select * from sysobjects where name=P_stu)drop procedure P_stuGOcreate procedure P_stunum intAsprint参加+convert(varchar(5),num)+门课考试的学生姓名及学号：select 姓名=(select MName from Member where MID=Score.MID),学号=MID from Score group by MID having count(*)=num -调用存储过程-exec P_stu num=2第 21 页