C语言大作业学生成绩查询系统源代码(5页).doc

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1、-C语言大作业学生成绩查询系统源代码-第 5 页#include#includestruct student char name20; char speciality10; int C; int math; int English; int PE; int Chinese;student13=zhangting,通信工程,85,80,90,80,88,zhangsan,通信工程,90,91,89,87,88,wangwu,通信工程,90,90,90,90,90,zhouyue,通信工程,90,89,98,88,90,zhangjiabang,通信工程,88,98,90,90,88,tianfu

2、,通信工程,90,97,86,87,56,wudong,通信工程,89,87,86,85,84,luhuiping,通信工程,87,81,90,80,81,zhafengyun,通信工程,90,89,87,86,85,wulin,通信工程,90,90,89,81,72,wangyun,通信工程,87,78,69,89,90,yangyu,通信工程,90,78,67,82,83,lili,通信工程,80,86,83,84,78;void main() struct student *p; p=student; int i,j,temp,sum,sum1=0,sum2=0,sum3=0,sum4=

3、0,sum5=0,sum6=0,count=0; double ave1,ave2,ave3,ave4,ave5,ave6; char xname10; printf(t*学生成绩查询系统*t); printf(n请务必确认你输入的名字是正确的,否则将无法输出你的个人成绩,只能显示班内的成绩总况n); printf(你的名字是:); scanf(%s,xname); printf(你的专业是通信工程n); for(i=0;iname)=0) printf(你的各科成绩如下:); printf(n C:%d,(*p).C); printf(n math:%d,(*p).math); printf

4、(n English:%d,(*p).English); printf(n PE:%d,(*p).PE); printf(n Chinese:%dn,(*p).Chinese); sum1=(*p).C+(*p).math+(*p).English+(*p).PE+(*p).Chinese; ave1=sum1/5.0; printf(n你的总分为:%dn平均分为:%fn,sum1,ave1); for(i=0;i13;i+) sum2=sum2+studenti.C; ave2=sum2/13.0; printf(nC语言的总分为:%dn平均分为:%fn,sum2,ave2); for(i=

5、0;i13;i+) sum3=sum3+studenti.math; ave3=sum3/13.0; printf(n数学的总分为:%dn平均分为:%fn,sum3,ave3); for(i=0;i13;i+) sum4=sum4+studenti.English; ave4=sum4/13.0; printf(n英语的总分为:%dn平均分为:%fn,sum4,ave4); for(i=0;i13;i+) sum5=sum5+studenti.PE; ave5=sum5/13.0; printf(n体育的总分为:%dn平均分为:%fn,sum5,ave5); for(i=0;i13;i+) s

6、um6=sum6+studenti.Chinese; ave6=sum6/13.0; printf(n语文的总分为:%dn平均分为:%fn,sum6,ave6); for(i=0;i13;i+) if(studenti.C60) count+=1; printf(nC语言不及格人数为%dn,count); for(i=0;i13;i+) if(studenti.math60) count+=1; printf(n数学不及格人数为%dn,count); for(i=0;i13;i+) if(studenti.English60) count+=1; printf(n英语不及格人数为%dn,cou

7、nt); for(i=0;i13;i+) if(studenti.PE60) count+=1; printf(n体育不及格人数为%dn,count); for(i=0;i13;i+) if(studenti.Chinese60) count+=1; printf(n语文不及格人数为%dn,count); for(i=0;i13;i+) for(j=i+1;j13;j+) if(studenti.Cstudentj.C) temp=studenti.C; studenti.C=studentj.C; studentj.C=temp; printf(nC语言的成绩由高到低排列为:n); for(

8、i=0;i13;i+)printf(%4d,studenti.C); for(i=0;i13;i+) for(j=i+1;j13;j+) if(studenti.mathstudentj.math) temp=studenti.math; studenti.math=studentj.math; studentj.math=temp; printf(n数学的成绩由高到低排列为:n); for(i=0;i13;i+)printf(%4d,studenti.math); for(i=0;i13;i+) for(j=i+1;j13;j+) if(studenti.Englishstudentj.En

9、glish) temp=studenti.English; studenti.English=studentj.English; studentj.English=temp; printf(n英语的成绩由高到低排列为:n); for(i=0;i13;i+)printf(%4d,studenti.English); for(i=0;i13;i+) for(j=i+1;j13;j+) if(studenti.PEstudentj.PE) temp=studenti.PE; studenti.PE=studentj.PE; studentj.PE=temp; printf(n体育的成绩由高到低排列为:n); for(i=0;i13;i+)printf(%4d,studenti.PE); for(i=0;i13;i+) for(j=i+1;j13;j+) if(studenti.Chinesestudentj.Chinese) temp=studenti.Chinese; studenti.Chinese=studentj.Chinese; studentj.Chinese=temp; printf(n语文的成绩由高到低排列为:n); for(i=0;i13;i+) printf(%4d,studenti.Chinese); printf(n);