2022年假设检验习题及答案 .pdf

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1、relationship, establishe d equivalent relationship 14, and subject: appli cation problem (4)-scores and percentage application problem review content overview answers scores, and percentage application problem of key is: according to meaning, (1) determine standard volume (units 1) (2) find associat

2、e volume rate corresponds to relationship, Then in -line sol ution. Category fraction multiplication word problem score Division applications engineeri ng problem problem XV, a subject: review of the measurement of the amount of capacity, measurement and units of measurement of common units of measu

3、rement and their significa nce in rate 1, currency, length, area, volume, unit size, volume, weight and rate. (Omitted) 2, commonly use d time units and their relationships. (Slightly) with a measurement units Zhijian of of poly 1, and of method 2, and poly method 3, and of method and poly method of

4、 relationship measurement distance of method 1, and tool measurement 2, and estimates 16, and subject: geometry preliminary knowledge (1)-line and angle review content line, and segment, and Ray, and vertical, and parallel, and angle angle of classification (slightly) 17, and subject: geometry preli

5、minary knowledge (2)-plane graphi cs review conte nt triangle, and edges shaped, a nd round, and fan axisymmetric graphics perimeter and area com bination graphics of area subject : Preliminary knowledge (3)-review of solid content category 1-d shapes are divided into: cyli nder and cone 2, column i

6、s divided into: cuboi d, square 3, cone cone of the features of cuboids and cubes relationship between characteristics of circular cone is slightly solid surface area and volume 1, size 2, table .和第三章假设检验3.2 一种元件 ,要求其使用寿命不低于1000（小时） ,现在从一批这种元件中随机抽取 25 件,测得其寿命平均值为950（小时） 。已知这种元件寿命服从标准差100 （小时）的正态分布，试

7、在显著水平0.05下确定这批元件是否合格。0100001:1000, H :1000X u=950 100 n=25 1000950-1000 u=2.510025 V= u0.05Hnxu提出假设：构造统计量：此问题情形属于u检验，故用统计量：此题中：代入上式得：拒绝域：本题中：0.950.950 u1.64u0.0uH即，拒绝原假设认为在置信水平5下这批元件不合格。3.4 某批矿砂的五个样品中镍含量经测定为（%） ：3.25 3.27 3.24 3.26 3.24 设测定值服从正态分布，问在0.01下能否接受假设，这批矿砂的镍含量为01011020:3.25 H:tX t=13.252,

8、S=0.0117, n=53.252-3.25 t= 0.34190.011751HSnx提出假设：构造统计量：本题属于未知的情形，可用检验，即取检验统计量为：本题中，代入上式得：否定域为：1-20.995120 V=tt(1)0.01,(4)4.6041,3.25ntttHQ本题中，接受认为这批矿砂的镍含量为。精选学习资料 - - - - - - - - - 名师归纳总结 - - - - - - -第 1 页，共 10 页relationship, establishe d equivalent relationship 14, and subject: appli cation probl

9、em (4)-scores and percentage application problem review content overview answers scores, and percentage application problem of key is: according to meaning, (1) determine standard volume (units 1) (2) find associate volume rate corresponds to relationship, Then in -line sol ution. Category fraction

10、multiplication word problem score Division applications engineeri ng problem problem XV, a subject: review of the measurement of the amount of capacity, measurement and units of measurement of common units of measurement and their significa nce in rate 1, currency, length, area, volume, unit size, v

11、olume, weight and rate. (Omitted) 2, commonly use d time units and their relationships. (Slightly) with a measurement units Zhijian of of poly 1, and of method 2, and poly method 3, and of method and poly method of relationship measurement distance of method 1, and tool measurement 2, and estimates

12、16, and subject: geometry preliminary knowledge (1)-line and angle review content line, and segment, and Ray, and vertical, and parallel, and angle angle of classification (slightly) 17, and subject: geometry preliminary knowledge (2)-plane graphi cs review conte nt triangle, and edges shaped, a nd

13、round, and fan axisymmetric graphics perimeter and area com bination graphics of area subject : Preliminary knowledge (3)-review of solid content category 1-d shapes are divided into: cyli nder and cone 2, column is divided into: cuboi d, square 3, cone cone of the features of cuboids and cubes rela

14、tionship between characteristics of circular cone is slightly solid surface area and volume 1, size 2, table .和3.5确定某种溶液中的水分，它的10 个测定值0.452%,0.035%,XS2N(,),设总体为正态分布试在水平 5%检验假设：0101( ) H :0.5% H :0.5%( ) H :0.04% H :0.0.4%iii00.95( )10.452% S=0.035%-4.1143(1)0.05 n=10 t(9)1.833itSnXn1-构造统计量：本文中未知，可用

15、检验。取检验统计量为X t=本题中，代入上式得：0.452%-0.5% t=0.035%10-1拒绝域为： V=t t本题中，014.1143Ht拒绝22200222212210.952( )nSS0.035% n=10 0.04%100.035%7.65630.04% V=(1)(1)(9)16.919iinnQ2构造统计量：未知，可选择统计量本题中，代入上式得：（）（）否定域为：本题中，210(1)nH接受3.9 设总体116( ,4),XNXX:K为样本，考虑如下检验问题：精选学习资料 - - - - - - - - - 名师归纳总结 - - - - - - -第 2 页，共 10 页r

16、elationship, establishe d equivalent relationship 14, and subject: appli cation problem (4)-scores and percentage application problem review content overview answers scores, and percentage application problem of key is: according to meaning, (1) determine standard volume (units 1) (2) find associate

17、 volume rate corresponds to relationship, Then in -line sol ution. Category fraction multiplication word problem score Division applications engineeri ng problem problem XV, a subject: review of the measurement of the amount of capacity, measurement and units of measurement of common units of measur

18、ement and their significa nce in rate 1, currency, length, area, volume, unit size, volume, weight and rate. (Omitted) 2, commonly use d time units and their relationships. (Slightly) with a measurement units Zhijian of of poly 1, and of method 2, and poly method 3, and of method and poly method of

19、relationship measurement distance of method 1, and tool measurement 2, and estimates 16, and subject: geometry preliminary knowledge (1)-line and angle review content line, and segment, and Ray, and vertical, and parallel, and angle angle of classification (slightly) 17, and subject: geometry prelim

20、inary knowledge (2)-plane graphi cs review conte nt triangle, and edges shaped, a nd round, and fan axisymmetric graphics perimeter and area com bination graphics of area subject : Preliminary knowledge (3)-review of solid content category 1-d shapes are divided into: cyli nder and cone 2, column is

21、 divided into: cuboi d, square 3, cone cone of the features of cuboids and cubes relationship between characteristics of circular cone is slightly solid surface area and volume 1, size 2, table .和01123:0 H :1( ) =0.05 V =2X-1.645 V = 1.502X2.125 V = 2X1.962X1.96(ii) Hi试证下述三个检验（否定域）犯第一类错误的概率同为或通过计算他们

22、犯第二类错误的概率，说明哪个检验最好？解：00.97512012( )0.050.05:02*1.960.0521.645021.6451.645( 1.645)1(1.645) =1-0.95=0.05V1.5022.iP xV HXUUHXVXXPXPnX即， PU这里P2033011101251.502.120(2.215)(1.50)0.980.930.05021.9621.9621.961.96P( VH )=1-P21.962(1(1.96)0.05ii:21.645XnP VHXVXXXnXHVX或（ ）犯第二类错误的概率=P-V=P1精选学习资料 - - - - - - - -

23、 - 名师归纳总结 - - - - - - -第 3 页，共 10 页relationship, establishe d equivalent relationship 14, and subject: appli cation problem (4)-scores and percentage application problem review content overview answers scores, and percentage application problem of key is: according to meaning, (1) determine standard

24、 volume (units 1) (2) find associate volume rate corresponds to relationship, Then in -line sol ution. Category fraction multiplication word problem score Division applications engineeri ng problem problem XV, a subject: review of the measurement of the amount of capacity, measurement and units of m

25、easurement of common units of measurement and their significa nce in rate 1, currency, length, area, volume, unit size, volume, weight and rate. (Omitted) 2, commonly use d time units and their relationships. (Slightly) with a measurement units Zhijian of of poly 1, and of method 2, and poly method

26、3, and of method and poly method of relationship measurement distance of method 1, and tool measurement 2, and estimates 16, and subject: geometry preliminary knowledge (1)-line and angle review content line, and segment, and Ray, and vertical, and parallel, and angle angle of classification (slight

27、ly) 17, and subject: geometry preliminary knowledge (2)-plane graphi cs review conte nt triangle, and edges shaped, a nd round, and fan axisymmetric graphics perimeter and area com bination graphics of area subject : Preliminary knowledge (3)-review of solid content category 1-d shapes are divided i

28、nto: cyli nder and cone 2, column is divided into: cuboi d, square 3, cone cone of the features of cuboids and cubes relationship between characteristics of circular cone is slightly solid surface area and volume 1, size 2, table .和223310.3551(0.355)0.36:11.5022.125114.125:21.96110.043.96nVPXnVPXnX

29、=PX =1-P3.50 =1-(4.125)+(3.50) =1X =P11 =(3.96)-(0.04) =0.99996092-0.516=0.48396092V出现第二类错误的概率最小，即V最好。3.10 一骰子投掷了 120次，得到下列结果：点数1 2 3 4 5 6 出现次数23 26 21 20 15 15 问这个骰子是否均匀？(0.05)解：22i 122i 11:620()()20ikiiikiiiPnnpnpnnpnpLL0i2222本题原假设为： H i=1,2,6这里 n=120,nP本题采用的统计量为Pearson 统计量即，代入数据为：（23-20 ） （26-20

30、 ）（15-20 ）=4.8精选学习资料 - - - - - - - - - 名师归纳总结 - - - - - - -第 4 页，共 10 页relationship, establishe d equivalent relationship 14, and subject: appli cation problem (4)-scores and percentage application problem review content overview answers scores, and percentage application problem of key is: accordin

31、g to meaning, (1) determine standard volume (units 1) (2) find associate volume rate corresponds to relationship, Then in -line sol ution. Category fraction multiplication word problem score Division applications engineeri ng problem problem XV, a subject: review of the measurement of the amount of

32、capacity, measurement and units of measurement of common units of measurement and their significa nce in rate 1, currency, length, area, volume, unit size, volume, weight and rate. (Omitted) 2, commonly use d time units and their relationships. (Slightly) with a measurement units Zhijian of of poly

33、1, and of method 2, and poly method 3, and of method and poly method of relationship measurement distance of method 1, and tool measurement 2, and estimates 16, and subject: geometry preliminary knowledge (1)-line and angle review content line, and segment, and Ray, and vertical, and parallel, and a

34、ngle angle of classification (slightly) 17, and subject: geometry preliminary knowledge (2)-plane graphi cs review conte nt triangle, and edges shaped, a nd round, and fan axisymmetric graphics perimeter and area com bination graphics of area subject : Preliminary knowledge (3)-review of solid conte

35、nt category 1-d shapes are divided into: cyli nder and cone 2, column is divided into: cuboi d, square 3, cone cone of the features of cuboids and cubes relationship between characteristics of circular cone is slightly solid surface area and volume 1, size 2, table .和2210.9521k-15k-1H20（）=（ ）=11.071

36、由于（） 所以接受即认为这个是均匀的。3.11 某电话站在一小时内接到电话用户的呼唤次数按每分钟记录的如下表：呼吸次数0 1 2 3 4 5 6 =7 频数8 16 17 10 6 2 1 0 试问这个分布能看作为泊松分布吗？ （=0.05）解：0221122222233224H :()!81610Xn01*6*7*260606060200.13530!212*0.27071!222*0.27072!231.5*0.23!keP xkkpePP XeePP XeePP XeePP XeLL0检验问题为：参数为已知 的最大似然估计4225522662278222221030224*0.09024

37、!3245* 0.03615!15246* 0.01206!457160()(860*0.1353)(1660*0.2707)(1 60*0.0120)60*0.135360*0.270760*0kiiiiePP XeePP XeePP XePP XP XnnpnpL.01200.6145 =21210k-1k-1,HQ20.952由于（）=（5）=11.071（）接受即分布可以看作为泊松分布。3.13 从一批滚珠中随机抽取了50个，测得他们的直径为（单位：mm）: 精选学习资料 - - - - - - - - - 名师归纳总结 - - - - - - -第 5 页，共 10 页relatio

38、nship, establishe d equivalent relationship 14, and subject: appli cation problem (4)-scores and percentage application problem review content overview answers scores, and percentage application problem of key is: according to meaning, (1) determine standard volume (units 1) (2) find associate volum

39、e rate corresponds to relationship, Then in -line sol ution. Category fraction multiplication word problem score Division applications engineeri ng problem problem XV, a subject: review of the measurement of the amount of capacity, measurement and units of measurement of common units of measurement

40、and their significa nce in rate 1, currency, length, area, volume, unit size, volume, weight and rate. (Omitted) 2, commonly use d time units and their relationships. (Slightly) with a measurement units Zhijian of of poly 1, and of method 2, and poly method 3, and of method and poly method of relati

41、onship measurement distance of method 1, and tool measurement 2, and estimates 16, and subject: geometry preliminary knowledge (1)-line and angle review content line, and segment, and Ray, and vertical, and parallel, and angle angle of classification (slightly) 17, and subject: geometry preliminary

42、knowledge (2)-plane graphi cs review conte nt triangle, and edges shaped, a nd round, and fan axisymmetric graphics perimeter and area com bination graphics of area subject : Preliminary knowledge (3)-review of solid content category 1-d shapes are divided into: cyli nder and cone 2, column is divid

43、ed into: cuboi d, square 3, cone cone of the features of cuboids and cubes relationship between characteristics of circular cone is slightly solid surface area and volume 1, size 2, table .和15.0 15.8 15.2 15.1 15.9 14.7 14.8 15.5 15.6 15.3 15.1 15.3 15.0 15.6 15.7 14.8 14.5 14.2 14.9 14.9 15.2 15.0

44、15.3 15.6 15.1 14.9 14.2 14.6 15.8 15.2 15.9 15.2 15.0 14.9 14.8 14.5 15.1 15.5 15.5 15.1 15.1 15.0 15.3 14.7 14.5 15.5 15.0 14.7 14.6 14.2 是否可认为这批滚珠直径服从正态分布？(0.05)解：2123( ),H :( )()H0.1833()(-1.1163)0.1321 0.428214.8 15.078p()(-1.1163)(-0.6492)(-1.1163)0.12600.4282pXF xxF xp020设为滚球的直径，其分布函数为则检验问题为在

45、成立的条件下，参数，的最大似然估计为=15.078，14.6-15.07815.1 15.078()(-0.6492)(0.0514)(-0.6492)0.26240.42824512340.952015.415.078p()(-0.6492)(0.7520)(0.0514)0.25350.4282p10.2260k-m-12k-m-1,ppppHQ221-21-（）=（ ）=5.991（）=5.991接受认为滚珠直径服从正态分布。3-13 表i 1(,)iiaainipinp2()iiinnpnp1 (0,14.6) 6 0.1321 6.6061 0.0556 2 14.6,14.8) 5

46、 0.1260 6.2976 0.2674 3 14.8,15.1) 13 0.2624 13.1209 0.0011 4 15.1,15.4) 14 0.2535 12.6752 0.1385 5 15.4,) 12 0.2260 11.3003 0.0433 0.5059 精选学习资料 - - - - - - - - - 名师归纳总结 - - - - - - -第 6 页，共 10 页relationship, establishe d equivalent relationship 14, and subject: appli cation problem (4)-scores and

47、percentage application problem review content overview answers scores, and percentage application problem of key is: according to meaning, (1) determine standard volume (units 1) (2) find associate volume rate corresponds to relationship, Then in -line sol ution. Category fraction multiplication wor

48、d problem score Division applications engineeri ng problem problem XV, a subject: review of the measurement of the amount of capacity, measurement and units of measurement of common units of measurement and their significa nce in rate 1, currency, length, area, volume, unit size, volume, weight and

49、rate. (Omitted) 2, commonly use d time units and their relationships. (Slightly) with a measurement units Zhijian of of poly 1, and of method 2, and poly method 3, and of method and poly method of relationship measurement distance of method 1, and tool measurement 2, and estimates 16, and subject: g

50、eometry preliminary knowledge (1)-line and angle review content line, and segment, and Ray, and vertical, and parallel, and angle angle of classification (slightly) 17, and subject: geometry preliminary knowledge (2)-plane graphi cs review conte nt triangle, and edges shaped, a nd round, and fan axi