第3章 理想气体的性质与热力过程精选PPT.ppt

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1、第3章 理想气体的性质与热力过程第1页，本讲稿共75页Chapter 3 The Properties of Ideal-Gas and Ideal-Gas Processes ContentsvThe Ideal-Gas Equation of Statevc，cv，cp，u，h，s of Ideal-GasvIdeal-Gas Processes（Four Basic Processes,Polytropic Processes)第2页，本讲稿共75页 3-1-1 Ideal-Gas 1.Real Gas（实际气体）实际气体）cant neglect the volume of molec

2、ulesthere are attraction among molecule of real gas 2.Ideal-Gas（理想气体）（理想气体）An Ideal gas is an imaginary substance that obeys these conditions:The molecules of ideal-gas have no volumeThere are no attraction among molecules of ideal-gas3-1 The Ideal-Gas Equation of State （理想气体状态方程式）（理想气体状态方程式）第3页，本讲稿

3、共75页N2,H2,O2,CO2,CO（1）The behavior of real gas:high temperature,low pressure,low density(high specific volume),far from a state of condensation-treated as an ideal gas.（2）The behavior of real gas:low temperature,high pressure,high density(low specific volume),not far from a state of condensation-tre

4、ated as a real gas.Steam power plants-water vapor Refrigerator-ammonia,freonnotes（3）Water Vapor an Ideal Gas?Water vapor exists in the air Working substance in the steam power plant第4页，本讲稿共75页 3-1-2 Ideal-Gas Equation of State （理想气体状态方程式）理想气体状态方程式）1.Ideal-Gas Equation of State For Ideal-Gas 1kg:pv=R

5、gT For Ideal-Gas mkg:pV=mRgT（1）Clapeyrons equation(In 1834)（2）At any equilibrium state:the p-v-T behavior of ideal-gas（3）Where:pabsolute pressure T Kelvin temperature RgThe gas constantnotes第5页，本讲稿共75页 2.Alternative Forms of the Ideal-Gas Equation of State(不同物量的理想气体状态方程式不同物量的理想气体状态方程式)1kg:p v=Rg T m

6、kg:pV=m Rg T 1mol:P Vm=R T nmol:p V=n R T Rg-gas constant 气体常数气体常数 R-universal gas constant 通用气体常数通用气体常数notes第6页，本讲稿共75页理想气体状态方程式的应用理想气体状态方程式的应用 某蒸汽锅炉燃煤需要的标准状况下，空气量某蒸汽锅炉燃煤需要的标准状况下，空气量 为为 qV=66000m3/h，若鼓风炉送入的热空气温度为，若鼓风炉送入的热空气温度为t1=250C，表压力，表压力 pg1=20.0kpa。当时当地的大气。当时当地的大气压力压力 pb=101.325kpa。求实际的送风量为多少？

7、求实际的送风量为多少？例题例题说明说明标准状态下，标准状态下，第7页，本讲稿共75页其中其中：故故实际实际的送的送风风量：量：简单求解过程简单求解过程：解：按理想气体状态方程式，解：按理想气体状态方程式，可得：可得：第8页，本讲稿共75页 3-2 Specific Heat,Internal Energy,Enthalpy and Entropy of Ideal-Gas （理想气体的热容，热力学能，焓和熵）理想气体的热容，热力学能，焓和熵）3-2-1 Heat Capacity（热容的定义）热容的定义）1.Heat Capacity：The energy required to raise

8、the temperature of substance by one degree.Denoted by C,unit J/K.1kg Iron20C-30C4.5kJ1kg Water20C-30C41.8kJ第9页，本讲稿共75页（3）Volume Heat（体积热容）（体积热容）Relationship among C，c，Cm，CV 3.Influence Factors（1）Substances（2）Thermal processes（3）Temperature（2）Molar heat（摩尔热容）摩尔热容）2.C,c,Cm,CV（1）Specific heat（比热容）（比热容）

9、第10页，本讲稿共75页 3-2-2 The Specific Heat at Constant Volume and at Constant Pressure（比定容热容和比定压热容）（比定容热容和比定压热容）1.Specific heat at constant volume cv:The energy required to raise the temperature of the unit mass of a substance by one degree as the volume is maintained constant.Specific heat at constant pr

10、essure cp:The energy required to raise the temperature of the unit mass of a substance by one degree as the pressure is maintained constant.2.Specific Heats cv,cp in Reversible ProcessesHow to express du,dh?第11页，本讲稿共75页 For constant volume ConditionReversible ProcessesAny Substance For constant pres

11、sure=the change in internal energy with temperature at constant volume=the change in enthalpy with temperature at constant pressure第12页，本讲稿共75页 3.Specific Heats cv,cp of Ideal-Gases（理想气体的（理想气体的cv,cp）For ideal gasConditionAny process for ideal-gasConstant volume process for real gasConstant pressure

12、process for real gas For ideal gas,the specific heats cv,cp depend on temperature only.notes第13页，本讲稿共75页 4.Specific-Heat Relations of Ideal Gases （理想气体的理想气体的 c cv v 和和 c cp p 的关系）的关系）（1）迈耶公式迈耶公式：（2）Specific heat ratio （比热容比）比热容比）How to obtain?Why cp cv at the same temperature?Analysis第14页，本讲稿共75页 Sp

13、ecific heats cp,cv,cp-cv,cp/cv depend on substance or state?思考思考题题 How to determine heat transferred by virtue of specific heats?(利用比热容，如何求解热量利用比热容，如何求解热量?)第15页，本讲稿共75页 cp，cv，cp-cv，cp/cv与物质的种类是否有关？与物质的种类是否有关？与气体的状态是否有关？与气体的状态是否有关？思考思考题题 利用比热容，如何求解热量？利用比热容，如何求解热量？解：解：cp，cv：与物质的种类和状态都有关系；：与物质的种类和状态都有关

14、系；cp-cv=Rg：与物质的种类有关，与状态无关；：与物质的种类有关，与状态无关；cp/cv=：与物质的种类和状态都有关系。与物质的种类和状态都有关系。第16页，本讲稿共75页 3-2-3 The calculation of Heat （利用理想气体的比热容计算热量）利用理想气体的比热容计算热量）1.The real specific heat capacity（真实比热容）真实比热容）The specific heat in the state of instantaneous temperature.Heat第17页，本讲稿共75页So Specific heat at constan

15、t pressure cp Specific heat at constant volume cv Heat transferred in a constant pressure process Heat transferred in a constant volume process第18页，本讲稿共75页 2.The average specific heats（平均比热容）平均比热容）Average value of specific heat at a temperature interval t1 to t2.（某一温度间隔内比热容的平均值）某一温度间隔内比热容的平均值）Heat:c

16、0tt1t2dtqGeometric significancy第19页，本讲稿共75页 Table of average specific heats（平均比热容图表）平均比热容图表）Where average specific heat from 0 to t temperature interval.Same as第20页，本讲稿共75页 平均比定压热容图表：平均比定压热容图表：Table2（P360）第21页，本讲稿共75页 平均比定容热容图表：平均比定容热容图表：Table 3（P361）第22页，本讲稿共75页 3.Specific Heats Vary Linearly with

17、Temperature （平均比热容直线关系式）平均比热容直线关系式）Heat Average specific heatc0tt1t2dtq第23页，本讲稿共75页 4.Constant Specific Heats（定值比热容）定值比热容）In the cursory calculation of specific heat,if the precision required is not strict the change in temperature is not big Principles Kinetic theory of gases（气体分子运动论）（气体分子运动论）Princ

18、iple of Equipartition of Energy （能量按自由度均分）（能量按自由度均分）Principle of equipartition of energy:The gases of having the same amount of atomics have the same value molar specific heat capacity.第24页，本讲稿共75页 The internal energy for ideal gas per unit molar The molar specific heat at constant volume Specific h

19、eat ratioI-degrees of freedom（分子运动自由度）分子运动自由度）Kinetic theory of gases The molar specific heat at constant pressure第25页，本讲稿共75页 Heat1.291.401.67Cp,mCV,m753ipolyatomicdiatomicmonatomicThe fixed value molar specific heats of ideal gases第26页，本讲稿共75页例题例题理想气体的比热容理想气体的比热容 在燃气轮机动力装置的回热器中，将空气在燃气轮机动力装置的回热器中，将

20、空气从从150C定压加热到定压加热到350C，试按下列比热容值，试按下列比热容值计算对每公斤空气所加入的热量。计算对每公斤空气所加入的热量。（1）按真实比热容计算；）按真实比热容计算；（2）按平均比热容表计算（附表）按平均比热容表计算（附表2，3）；）；（3）按定值比热容计算；）按定值比热容计算；（4）按空气的热力性质表计算（附表）按空气的热力性质表计算（附表4）；）；第27页，本讲稿共75页 3-2-4 Internal energy,Enthalpy of ideal-gas （理想气体的热力学能，焓）理想气体的热力学能，焓）1.Internal Energy,Enthalpy For a

21、ny substance u/h is a property u/h is a function of two independent propertiespv0T1T212V2p2 u1-2 and h1-2 depend on the ends states only,no relevantwith processes.notes第28页，本讲稿共75页 For ideal gas u/h is a function of temperature alone（1）u1-2,h1-2 depend on temperature only,no relevant with processes

22、and states.（2）Three lines have the same meaning for ideal gases constant temperature line constant internal energy line constant enthalpy linepv0T1T212v2p2notes第29页，本讲稿共75页ConditionAny process for ideal-gasConstant volume process for real gasConstant pressure process for real gas 2.Calculation of u,

23、h According to cv,cp Three ways for calculating u and h Table4（P362）第30页，本讲稿共75页 3-2-5 Entropy of Ideal-Gas（理想气体的熵）理想气体的熵）1.Definition（1）Specific entropy change is a property of substance（2）Condition:reversible processes （3）To indicate the direction of heat transfer for a reversible processnotesIf d

24、s 0,then q 0,heat is added into the systemIf ds 0,then q 0,heat is rejected from the systemIf ds=0,then q=0,the process is an adiabatic process,also called constant entropy process.第31页，本讲稿共75页 2.The Calculation of Entropy Changes（熵变的计算）熵变的计算）The first law of thermodynamics Ideal gas Entropy change

25、in reversible process The calculation of entropy changes Condition Ideal gas Any process Fixed value specific heat第32页，本讲稿共75页思考思考题题Statement the valid conditions for each stepof the equations 任意气体任意微元过程任意气体任意微元过程 任意气体微元可逆过程任意气体微元可逆过程 任意气体微元定压过程任意气体微元定压过程 任意气体微元定压过程任意气体微元定压过程 焓的定义焓的定义 理想气体任意过程理想气体任意

26、过程第33页，本讲稿共75页例题例题 已知某理想气体的比定容热容已知某理想气体的比定容热容cv=a+bT,其中其中a，b为常数，试导出其热力学能，焓为常数，试导出其热力学能，焓和熵变的计算式。和熵变的计算式。解：解：第34页，本讲稿共75页 3-4 The Process of the Ideal Gas （理想气体的基本热力过程）理想气体的基本热力过程）3-4-1 Purpose and Method 1.Purpose 2.Basic Task （1）To determine the change of properties during the process （2）To analysi

27、s the relationship of energy transfer 3.Theories （1）The first law of thermodynamics （2）The Ideal-Gas Equation of State （3）Expressions of reversible process第35页，本讲稿共75页 4.Assumptions and idealizations （1）Irreversible processes-Reversible processes （2）Complex processes-Simple processes Constant volume

28、 process（定容过程）（定容过程）Constant pressure process（定压过程）（定压过程）Isothermal process（定温过程）（定温过程）Reversible adiabatic process（可逆绝热过程）（可逆绝热过程）第36页，本讲稿共75页 5.Contents（研究内容）研究内容）（1）Process equation（过程方程式）（过程方程式）（2）Relationships between the initial and final states （3）Determine the change of internal energy,entha

29、lpy,entropy:u,h,s （4）Analysis of p-v diagram,T-s diagram （5）Determine the work transferred:w，wt （6）Determine the heat transferred:q第37页，本讲稿共75页 3-4-2 The Basic Thermal Processes of Ideal-Gases （理想气体的基本热力过程）（理想气体的基本热力过程）1.The Constant-Volume Processes（定容过程）定容过程）(Isochoric Processes)（1）Process equatio

30、n（2）Relationships of p,v,T（3）u,h,s第38页，本讲稿共75页（4）p-v and T-s diagrams p-v diagram:vertical straight lines T-s diagram:Exponential shape curves（指数曲线）（指数曲线）p2210vvvT2210s.vv第39页，本讲稿共75页（5）Work W Wt（6）Heat At constant volume processes:q=u,T.The preparation process that heat convert into work.notes第40页，

31、本讲稿共75页 2.The Constant-Pressure Processes（定压过程）定压过程）(Isobaric processes)（2）Relationships of p,v,T（1）Process equation（3）u,h,s第41页，本讲稿共75页vv p-v diagram：Horizontal straight lines T-s diagram：Exponential shape curves（指数曲线）（指数曲线）vcontrast（4）p-v and T-s diagramsp210v2ppT2210s.pp第42页，本讲稿共75页（5）Work W Wt（6

32、）Heat At constant pressure processes,the heat absorbed equals to the change of enthalpy.notes第43页，本讲稿共75页 一容积为一容积为 0.15m3 的储气罐，内装氧气，其初始的储气罐，内装氧气，其初始压力压力 p1=0.55MPa，温度，温度 t1=38C。若对氧气加热，。若对氧气加热，其温度，压力都升高。储气罐上装有压力控制阀，其温度，压力都升高。储气罐上装有压力控制阀，当压力超过当压力超过 0.7MPa 时，阀门便自动打开，放走部时，阀门便自动打开，放走部分氧气，即储气罐中维持的最大压力为分氧气

33、，即储气罐中维持的最大压力为 0.7MPa。问当罐中氧气温度为问当罐中氧气温度为285C时，对罐中氧气共加入时，对罐中氧气共加入了多少热量？设氧气的比热容为定值。了多少热量？设氧气的比热容为定值。例题例题第44页，本讲稿共75页简单求解过程简单求解过程：这一问题包含了两个过程这一问题包含了两个过程：过程过程1-2:是由压力为是由压力为 被定容加热被定容加热到到 ，该过程中氧气质量不变；，该过程中氧气质量不变；过程过程2-3:是压力由是压力由 被定压加热到被定压加热到 ，该过程是一个质量不断变化，该过程是一个质量不断变化的定压过程。的定压过程。（1）首先分析）首先分析1-2定容过程：定容过程：温

34、度变化：温度变化：1-2中吸收热量：中吸收热量：第45页，本讲稿共75页在在2-3过程中的吸热量：过程中的吸热量：（3）共加入热量为：）共加入热量为：微元变化过程吸热量：微元变化过程吸热量：（2）2-3为变质量的定压过程：为变质量的定压过程：第46页，本讲稿共75页 3.The Isothermal Processes（定温过程）定温过程）（Hyperbolic Processes）（1）Process equation（2）Relationships of p,v,T（3）u,h,s第47页，本讲稿共75页 p-v diagram:rectangular hyperbola（等边双曲线）等边

35、双曲线）T-s diagram:horizontal lines（4）p-v and T-s diagrams.p2210vTTT2210sTT第48页，本讲稿共75页（5）Work w wt Relationship of w,wt第49页，本讲稿共75页（6）HeatAnalysis Can we use to calculate heat at isothermal process?T2210sTs During an isothermal expansion,all the heat transferred is converted into external work.Convers

36、ely,during an isothermal compression,all the work done on the gas is rejected by the gas as heat transfer.notes第50页，本讲稿共75页 4.The Reversible Adiabatic Process（可逆绝热过程）可逆绝热过程）Derivation Entropy ds Reversible adiabatic process Assume=constant k:Adiabatic index（绝热指数）（绝热指数）（1）Process equation Hence第51页，本

37、讲稿共75页（2）Relationships of p,v,T（3）u,h,s Negligible k change with temperature k=1.67（monatomic gases）k=1.40（diatomic gases）k=1.29（polyatomic gases）第52页，本讲稿共75页TT p-v diagram:Hyperbolas of higher order（高次双曲线）高次双曲线）T-s diagram:Vertical lines（4）p-v and T-s diagrams.p2210vssTcontrast1T220sss第53页，本讲稿共75页（

38、5）Heat（6）Work W Any substances,adiabatic processes Ideal gases,cv=constant,adiabatic processes Ideal gases,reversible adiabatic processes第54页，本讲稿共75页 Wt Any substances,any adiabatic processes Ideal gases,cv=constant,adiabatic processes Ideal gases,reversible adiabatic processes第55页，本讲稿共75页 Relations

39、hip of W,Wt During adiabatic processes,no heat transfer,the work done by system is from the total energy of substance.notes第56页，本讲稿共75页例题例题已知已知2kg空气分别经过定温膨胀和绝热膨胀的空气分别经过定温膨胀和绝热膨胀的可逆过程，从初态压力为可逆过程，从初态压力为 p1=9.807bar，t1=300 C膨胀到终态容积为初态容积的膨胀到终态容积为初态容积的5倍。倍。试计算不同过程中空气的终态参数，对外界所作的试计算不同过程中空气的终态参数，对外界所作的功和交换

40、的热量，过程中热力学能，焓和熵的变化功和交换的热量，过程中热力学能，焓和熵的变化量。量。(设空气的设空气的cp=1.004kJ/(kg.K)，Rg=0.287kJ/(kg.K)，k=1.4)第57页，本讲稿共75页简单求解过程简单求解过程：取空气作热力系取空气作热力系（1）可逆定温过程）可逆定温过程1-2:由参数间的相互关系得：由参数间的相互关系得：按理想气体状态方程式得按理想气体状态方程式得:定温过程：定温过程：T1=T2=573K，第58页，本讲稿共75页气体对外所作的膨胀功及交换的热量：气体对外所作的膨胀功及交换的热量：过程中热力学能，焓，熵的变化为：过程中热力学能，焓，熵的变化为：第5

41、9页，本讲稿共75页过程中热力学能，焓，熵的变化为过程中热力学能，焓，熵的变化为：（2）可逆绝热过程）可逆绝热过程：按可逆绝热过程参数间关系可得：按可逆绝热过程参数间关系可得：气体对外所作膨胀功及交换的热量气体对外所作膨胀功及交换的热量：第60页，本讲稿共75页 3-4-3 The polytropic Processes（多变过程）多变过程）n:Polytropic exponent（多变指数）（多变指数）In theory,the range of the value of the index n is from-to+.Different polytropic process has d

42、ifferent polytropic exponent.For four basic processes:（1）Process equation第61页，本讲稿共75页 The calculation of the index n For any polytropic processes Integral above Then If the properties of initial(p1,v1)and final(p2,v2)states are known,the value of index n can be calculated in terms of the formula abo

43、ve.第62页，本讲稿共75页（2）Relationships of p,v,T（3）u,h,s第63页，本讲稿共75页 p-v diagram Slope（多变过程的斜率）（多变过程的斜率）Where（4）p-v and T-s diagrams-isobaric processes-isothermal processes-constant entropy processes-isochoric processes第64页，本讲稿共75页.p2210vTsvp绘制空气绘制空气n=1.6的膨胀过程，的膨胀过程，判断判断q,w,u的正的正负.p0v-n=kn=1n=0+n=1.6n=1.6膨胀

44、过程膨胀过程 Determine the value of n Determine q,w,u Distribution ruleThe value of index n：Starting from constant volume process Increase clockwise Value of n:-00 1 k+.第65页，本讲稿共75页 T-s diagram Slope Cn:Polytropic specific heat capacity（多变比热）（多变比热）Heat at polytropic processes Definition of entropy Entropy

45、 change of ideal gases第66页，本讲稿共75页 Where:-isobaric processes-isothermal processes-constant entropy processes-isochoric processes第67页，本讲稿共75页绘制空气绘制空气n=1.6的膨胀过程，的膨胀过程，判断判断q,w,u的正的正负T20s.pv21TsT20s.21n=kn=1n=0-+n=1.6n=1.6膨胀过程膨胀过程 Starting from constant volume process:n:-00 1 k+Increase clockwise Starti

46、ng from constant entropy process:Cn:0ccV V cp Increase clockwise Distribution rule第68页，本讲稿共75页（5）Work W Wt第69页，本讲稿共75页（6）Heat When n=1,Isothermal processes When n1,and cn=constant第70页，本讲稿共75页（7）Coordinate diagram analysis of polytropic processesT20s.pv21Ts.p2210vTsvp Work-isochoric processes Heat-co

47、nstant entropy processes Internal energy,enthalpy-isothermal processes Wt-isobaric processes第71页，本讲稿共75页1.将满足下列要求的理想气体多变过程表示将满足下列要求的理想气体多变过程表示 在在p-v图和图和T-s图上。图上。（1）工质又升压，又升温，又放热的过程。）工质又升压，又升温，又放热的过程。（2）工质又膨胀，又降温，又放热的过程。）工质又膨胀，又降温，又放热的过程。2.试分析多变指数在试分析多变指数在 1nk 范围内的膨胀范围内的膨胀 过程特点。过程特点。思考思考题题第72页，本讲稿共75

48、页（1）工质又膨胀，又升温，又吸热的过程。）工质又膨胀，又升温，又吸热的过程。（2）工质又膨胀，又降温，又放热的过程。）工质又膨胀，又降温，又放热的过程。第73页，本讲稿共75页2.试分析多变指数在试分析多变指数在 1nk 范围内的膨胀范围内的膨胀 过程特点。过程特点。思考题思考题答：答：过程特点为过程特点为 吸热，降温，膨胀，压力减小。吸热，降温，膨胀，压力减小。.p2210vTsvp第74页，本讲稿共75页若上例改为若上例改为 n=1.3 的多变过程，则各项结果的多变过程，则各项结果 又如何？将定温过程，定熵过程及此多变又如何？将定温过程，定熵过程及此多变 过程分析比较。过程分析比较。例题例题第75页，本讲稿共75页