动力学几个实例.pdf

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1、动学个实例问题：悬臂梁受重作发变形，求其固有频率。基本过程：1、建模2、静分析NLGEOM,ONSTRES,ON3、求静解4、开始新的求解：modalSTRES,ONUPCOORD,1,ON 修正坐标SOLVE.5、扩展模态解6、察看结果/PREP7ET,1,BEAM189!使beam189梁单元MPTEMP,MPTEMP,1,0MPDATA,EX,1,210e9MPDATA,PRXY,1,0.3MPDATA,DENS,1,7850SECTYPE,1,BEAM,RECT,secA,0!定义梁截secA SECOFFSET,CENTSECDATA,0.005,0.01,0,0,0,0,0,0,0

2、,0K,!建模与分K,2,K,2,1,LSTR,1,2LATT,1,1,3,1LESIZE,1,20,1LMESH,1FINISH/SOL!静变形求解ANTYPE,0NLGEOM,1PSTRES,ON!计及预应效果DK,1,0,ALL,ACEL,0,9.8,0,!只考虑重作TIME,1AUTOTS,1NSUBST,20,1KBC,0SOLVEFINISH/SOLUTIONANTYPE,2!进模态求解MSAVE,0MODOPT,LANB,10MXPAND,10,0!取前阶模态PSTRES,1!打开预应效应MODOPT,LANB,10,0,0,OFFUPCOORD,1,ON!修正坐标以得到正确的应

3、PSOLVE,TRIANG!三化矩阵PSOLVE,EIGLANB!提取特征值和特征向量FINISH/SOLUEXPASS,1!扩展模态解PSOLVE,EIGEXPFINISH/POST1SET,LIST!观察结果FINISH问题：循环对称结构模态分析这是ANSYS HELP的例，但那个命令流似乎有些问题，下是整理过的命令流。基本过程：1、建模2、define cyclic3、定义约束4、求模态解5、展开并察看结果r1=5!建模r2=10d1=2nsect=24alpha_deg=360/nsectalpha_rad=2*acos(-1)/nsect/prep7csys,1k,1,0,0,0k,

4、2,0,0,d1k,3,r1,0,0k,4,r1,0,d1l,3,4arotat,1,1,2,alpha_deg/2k,7,r2,0,0k,8,r2,0,d1l,7,8arotat,5,1,2,alpha_deg/2arotat,2,1,2,alpha_deg/2arotat,6,1,2,alpha_deg/2a,5,6,10,9mshkey,1et,1,181r,1,0.20r,2,0.1mp,ex,1,10e6mp,prxy,1,0.3mp,dens,1,1e-4esize,0.5asel,1,4aatt,1asel,5aatt,2allselCYCLIC,CYCLIC!定义基本扇区AME

5、SH,all!分FINISH/SOL!求模态解ANTYPE,2MODOPT,LANB,10MXPAND,10,0PSTRES,0MODOPT,LANB,10,0,0,OFFDK,5,0,UZ,SOLVEFINISH/POST1SET,LISTSET,1,4,/CYCEXPAND,ONPLNS,U,SUM!观察扩展模态FINISH问题三：三平台受谐波载荷作,求结构响应谐波载荷为作在平台上点的集中，幅值为10N，频率范围5Hz70Hz基本过程：1、建模2.求模态解3、模态叠加法作谐分析4.观察结果/PREP7!建模ET,1,BEAM189ET,2,SHELL93R,1,0.01,MP,EX,1,2

6、10e9MP,PRXY,1,0.3MP,DENS,1,7850SECTYPE,1,BEAM,RECT,secA,0 SECOFFSET,CENTSECDATA,0.005,0.008,0,0,0,0,0,0,0,0K,-0.5,K,0.5,K,1,K,1,1,K,-0.5,1,K,0.5,1,K,0.5,A,4,5,6LSTR,1,5LSTR,3,4LSTR,2,6LSEL,S,LINE,4,6LATT,1,1,1,7,1LSEL,ALLLESIZE,ALL,10,1LMESH,4,6TYPE,2MSHAPE,0,2DMSHKEY,1AMESH,1FINISH/SOL!为了使模态叠加法谐分析A

7、NTYPE,2MODOPT,LANB,20!先取结构前20阶模态MXPAND,20,0MODOPT,LANB,20,0,0,OFFKSEL,S,KP,1,3DK,ALL,0,ALL,SOLVEFINISH!/POST1!最好事先看下模态结果!SET,LIST!以了解模态频率范围!FINISH/SOL!模态叠加法谐响应分析ANTYPE,3HROPT,MSUPHROUT,ONHROPT,MSUP,20,HROUT,ON,OFF,0F,177,FY,-10,!施加10N的在节点177的负Y向HARFRQ,5,70,!载荷的强制频率范围NSUBST,200,KBC,1ALPHAD,5,SOLVEFIN

8、ISH/POST26!察看位移响应FILE,rfrqNUMVAR,20NSOL,2,139,U,Y,PLVAR,2FINISH问题四：三平台受地震谱激励,求应分布和反基本过程：1、建模2、求模态解3、求谱解4、扩展模态5、模态合并6、观察结果/PREP7!建模ET,1,BEAM189ET,2,SHELL93R,1,0.01,MP,EX,1,210e9MP,PRXY,1,0.3MP,DENS,1,7850SECTYPE,1,BEAM,RECT,secA,0 SECOFFSET,CENTSECDATA,0.005,0.008,0,0,0,0,0,0,0,0K,-0.5,K,0.5,K,1,K,1,

9、1,K,-0.5,1,K,0.5,1,K,0.5,A,4,5,6LSTR,1,5LSTR,3,4LSTR,2,6LSEL,S,LINE,4,6LATT,1,1,1,7,1LSEL,ALLLESIZE,ALL,10,1LMESH,4,6TYPE,2MSHAPE,0,2DMSHKEY,1AMESH,1FINISH/SOL!取前阶模态ANTYPE,2MODOPT,LANB,10KSEL,S,KP,1,3DK,ALL,0,ALL,SOLVEFINISH/SOL!谱分析ANTYPE,8SPOPT,SPRS,10,1SVTYP,3SED,0,1,0,!给出激励向FREQ,0.25,1.34,6.73,14

10、.6,28.9,0,0,0,0!激励谱SV,0,0.00073,0.00016,0.00034,0.00034,0.00052,SOLVEFINISH/SOL!扩展模态ANTYPE,2EXPASS,1MXPAND,10,0,0,1,0.001,SOLVEFINISH/SOL!模态合并ANTYPE,8SRSS,0.001,DISPSOLVE/POST1!观察结果SET,LIST/INPUT,mcomPRRSOL,FFINISH问题五：三平台受时程载荷作,求应分布和变形过程基本过程：1、建模2.施加随时间变化载荷，定义载荷步3、求解4.在POST1和POST26中观察结果/PREP7!建模ET,1

11、,BEAM189ET,2,SHELL93R,1,0.01,MP,EX,1,210e9MP,PRXY,1,0.3MP,DENS,1,7850SECTYPE,1,BEAM,RECT,secA,0 SECOFFSET,CENTSECDATA,0.005,0.008,0,0,0,0,0,0,0,0K,-0.5,K,0.5,K,1,K,1,1,K,-0.5,1,K,0.5,1,K,0.5,A,4,5,6LSTR,1,5LSTR,3,4LSTR,2,6LSEL,S,LINE,4,6LATT,1,1,1,7,1LSEL,ALLLESIZE,ALL,10,1LMESH,4,6TYPE,2MSHAPE,0,2D

12、MSHKEY,1AMESH,1FINISH/SOLANTYPE,4TRNOPT,FULL!完全法瞬态分析KSEL,S,KP,1,3DK,ALL,0,ALL,OUTRES,ALL,1ALPHAD,5,!阻尼TIME,2!定义载荷曲线AUTOTS,1NSUBST,50,1KBC,0SFA,ALL,1,PRES,500LSWRITE,1,TIME,3LSWRITE,2,TIME,4SFA,ALL,1,PRES,150KBC,1LSWRITE,3,TIME,5SFA,ALL,1,PRES,LSWRITE,4,LSSOLVE,1,4,1,!求解FINISH/POST26!观察变形随时间的变化NSOL,2,177,U,Y,uyyPLVAR,2 FINISH