《C程序设计》课后习题答案(4-6章.doc

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1、C程序设计课后习题答案(4-6章)第四章8、#define PI 3.#includevoid main()float h,r,l,s,sq,vq,vz;printf(please input r,h:);scanf(%f,%f,&r,&h);l=2*PI*r;s=r*r*PI;sq=4*PI*r*r;vq=4.0/3.0*PI*r*r*r;vz=PI*r*r*h;printf(l=%6.2fn,l);printf(s=%6.2fn,s);printf(sq=%6.2fn,sq);printf(vq=%6.2fn,vq);printf(vz=%6.2fn,vz);9、#includevoid

2、main()float c,f;printf(please input f:);scanf(%f,&f);c=(5.0/9.0)*(f-32);printf(c:%6.2fn,c);第五章5、#includevoid main()int x,y;printf(please input x:);scanf(%d,&x);if(x1) y=x; printf(x=%d,y=x=%dn,x,y);else if(x10) y=2*x-1; printf(x=%d,y=2*x-1=%dn,x,y); else y=3*x-11; printf(x=%d,y=3*x-11=%dn,x,y);6、#inc

3、ludevoid main()float score;char grade;printf(please input the student score:);scanf(%f,&score);while(score100)|(score0) printf(error,please input again!n); printf(please input the student score:); scanf(%f,&score); switch(int)(score/10) case 10: case 9:grade=A;break; case 8:grade=B;break; case 7:gra

4、de=C;break; case 6:grade=D;break; case 5: case 4: case 3: case 2: case 1: case 0:grade=E;printf(score is %f,grade is %cn,score,grade);7、#include#includevoid main()long int num;int indiv,ten,hundred,thousand,ten_thousand,place;printf(please input an integer(0-99999):);scanf(%ld,&num);if(num9999) plac

5、e=5;else if(num999) place=4; else if(num99) place=3; else if(num9) place=2; else place=1;printf(Total digits:%dn,place);printf(For each number:);ten_thousand=num/10000;thousand=(int)(num-ten_thousand*10000)/1000;hundred=(int)(num-ten_thousand*10000-thousand*1000)/100;ten=(int)(num-ten_thousand*10000

6、-thousand*1000-hundred*100)/10;indiv=(int)(num-ten_thousand*10000-thousand*1000-hundred*100-ten*10);if(ten_thousand!=0) printf(%d,%d,%d,%d,%d,ten_thousand,thousand,hundred,ten,indiv);else if(thousand!=0) printf(%d,%d,%d,%d,thousand,hundred,ten,indiv); else if(hundred!=0) printf(%d,%d,%d,hundred,ten,

7、indiv); else if(ten!=0) printf(%d,%d,ten,indiv); else printf(%d,indiv);printf(nThe reverse number:);switch(place)case 5:printf(%d%d%d%d%d,indiv,ten,hundred,thousand,ten_thousand);break; case 4:printf(%d%d%d%d,indiv,ten,hundred,thousand);break; case 3:printf(%d%d%d,indiv,ten,hundred);break; case 2:pr

8、intf(%d%d,indiv,ten);break; case 1:printf(%d,indiv);break;8、（1）#includevoid main()long i;float bonus,bon1,bon2,bon3,bon4,bon6,bon10;bon1=*0.1;bon2=bon1+*0.075;bon4=bon2+*0.05;bon6=bon4+*0.03;bon10=bon6+*0.015;printf(please input bonus:);scanf(%ld,&i);if(i=) bonus=i*0.1;else if(i=) bonus=bon1+(i-)*0.

9、075; else if(i=) bonus=bon2+(i-)*0.05; else if(i=) bonus=bon4+(i-)*0.03; else if(i=) bonus=bon6+(i-)*0.015; else bonus=bon10+(i-)*0.01;printf(bonus:%10.2fn,bonus);（2）#includevoid main()long i;float bonus,bon1,bon2,bon4,bon6,bon10;int branch;bon1=*0.1;bon2=bon1+*0.075;bon4=bon2+*0.05;bon6=bon4+*0.03;

10、bon10=bon6+*0.015;printf(please input bonus:);scanf(%ld,&i);branch=i/;if(branch10) branch=10;switch(branch)case 0:bonus=i*0.1; break;case 1:bonus=bon1+(i-)*0.075; break;case 2:case 3:bonus=bon2+(i-)*0.05; break;case 4:case 5:bonus=bon4+(i-)*0.03; break;case 6:case 7:case 8:case 9:bonus=bon6+(i-)*0.0

11、15; break;case 10:bonus=bon10+(i-)*0.01;printf(bonus is %fn,bonus);9、#includevoid main()int a,b,c,d,t;printf(please input four number:);scanf(%d,%d,%d,%d,&a,&b,&c,&d);printf(a=%d,b=%d,c=%d,d=%dn,a,b,c,d);if(ab) t=a;a=b;b=t;if(ac) t=a;a=c;c=t;if(ad) t=a;a=d;d=t;if(bc) t=b;b=c;c=t;if(bd) t=b;b=d;d=t;i

12、f(cd) t=c;c=d;d=t;printf(%d %d %d %dn,a,b,c,d);10、#include#includevoid main()int h=10;float x1=2,y1=2,x2=-2,y2=2,x3=-2,y3=-2,x4=2,y4=-2,x,y,d1,d2,d3,d4;printf(please input (x,y):);scanf(%f,%f,&x,&y);d1=sqrt(x-x4)*(x-x4)+(y-y4)*(y-y4);d2=sqrt(x-x1)*(x-x1)+(y-y1)*(y-y1);d3=sqrt(x-x2)*(x-x2)+(y-y2)*(y-

13、y2);d4=sqrt(x-x3)*(x-x3)+(y-y3)*(y-y3);if(d11&d21&d31&d41) h=0;printf(height %dn,h);第六章1、#includevoid main()int p,r,n,m,temp;printf(please input two integer:);scanf(%d,%d,&n,&m);if(nm)temp=n;n=m;m=temp;p=n*m;r=n%m;while(r!=0)n=m;m=r;r=n%m;printf(max gongyueshu:%dn,m);printf(min gongbeishu:%dn,p/m);2

14、、#includevoid main()char c;int letters=0,space=0,digit=0,other=0;printf(please input string:n);while(c=getchar()!=n)if(c=a&c=A&c=0&c=9) digit+; else other+;printf(letters:%dn space:%dn digit:%dn other:%dn,letters,space,digit,other);3、#includevoid main()int a,n;int i=1,sn=0,tn=0;printf(please input a

15、,n:);scanf(%d,%d,&a,&n);while(i=n)tn=tn+a;sn=sn+tn;a=a*10;+i;printf(a+aa+aaa+=%dn,sn);4、#includevoid main()float s=0,t=1;int n;for(n=1;n=20;n+)t=t*n;s=s+t;printf(1!+2!+20!=%en,s);5、#includevoid main()int n1=100,n2=50,n3=10;float k;float s1=0,s2=0,s3=0;for(k=1;k=n1;k+) s1=s1+k;for(k=1;k=n2;k+) s2=s2+

16、k*k;for(k=1;k=n3;k+) s3=s3+1/k;printf(sum=%fn,s1+s2+s3);6、#includevoid main()int i,j,k,n;printf(nnarcissus number are);for(n=100;n1000;n+)i=n/100;j=(n-100*i)/10;k=n-100*i-10*j;if(n=i*i*i+j*j*j+k*k*k)printf(%d ,n);7、#includevoid main()int m,s,i;for(m=2;m1000;m+) s=0; for(i=1;im;i+) if(m%i=0) s=s+i; （

17、注意逗号，下面的if不用逗号） if(s=m)与上面的if语句不同这又是一个分支，大括号是此语句的管辖范围。 printf(%d,its factors are,m); for(i=1;im;i+) if(m%i=0) printf(%d ,i); printf(n); 8、#includevoid main()int i,t,n=20;float a=2,b=1,s=0;for(i=1;i=n;i+)s=s+a/b;t=a;a=a+b;b=t;printf(sum=%fn,s);9、#includevoid main()float sn=100,hn=sn/2;int n;for(n=2;n

18、=10;n+)sn=sn+2*hn;hn=hn/2;printf(tenth arrive at %f meter.n,sn);printf(tenth %f meter.n,hn);10、#includevoid main()int day,x1,x2;day=9;x2=1;while(day0)x1=(x2+1)*2;x2=x1;day-;printf(total=%dn,x1);11、#include#includevoid main()float a,x0,x1;printf(Enter a positive number:);scanf(%f,&a);x0=a/2;x1=(x0+a/

19、x0)/2;dox0=x1;x1=(x0+a/x0)/2;while(fabs(x0-x1)=1e-5);printf(The square root of %f is %fn,a,x1);12、#include#includevoid main()float x1,x0,f,f1;x1=1.5;dox0=x1;f=(2*x0-4)*x0+3)*x0-6;f1=(6*x0-8)*x0+3;x1=x0-f/f1;while(fabs(x1-x0)=1e-5);printf(The root of equation is %fn,x1);13、#include#includevoid main()

20、float x0,x1,x2,fx0,fx1,fx2;doprintf(Enter x1 and x2:);scanf(%f,%f,&x1,&x2);fx1=x1*(2*x1-4)*x1+3)-6;fx2=x2*(2*x2-4)*x2+3)-6;while(fx1*fx20);dox0=(x1+x2)/2;fx0=x0*(2*x0-4)*x0+3)-6;if(fx0*fx1)=1e-5);printf(x=%fn,x0);14、#includevoid main()int i,j,k;for(i=0;i=3;i+) for(j=0;j=2-i;j+) printf( ); for(k=0;k=2*i;k+) printf(*); printf(n);for(i=0;i=2;i+)for(j=0;j=i;j+) printf( ); for(k=0;k=4-2*i;k+) printf(*); printf(n);15、#includevoid main() char i,j,k; /*i是A的对手；j是B的对手；k是C的对手*/ for(i=X;i=Z;i+) for(j=X;j=Z;j+) for(k=X;kZ;k+) if(i!=j&i!=k&j!=k) if(i!=X&k!=X&k!=Z) printf(A-%ctB-%ctC-%cn,i,j,k);